Academic Journal of Science and Technology ISSN: 2771-3032 | Vol. 10, No. 3, 2024 111 Construction of line Layout Model Based on Geometric Deduction and Constrained Heuristic Search Jinghao Deng, Shunjiao Xue, Yinghan Zhang, Qi Zhang North China Electric Power University, Department of Electrical Engineering, Baoding Hebei 071000, China Abstract: Based on problem B of the National Mathematical Contest in Modeling for College Students in 2023, this paper establishes a model through geometric deductive deduction, and establishes and solves an optimal model of survey line layout through constrained heuristic algorithm. In problem 1, a mathematical model of coverage width and overlap rate is established based on triangle relation and triangle sine theorem by finding the mathematical relationship between target quantity and known quantity. In problem 2, the angle between the known direction of the survey line and the projection of the normal direction of the submarine slope on the horizontal plane is 𝛽. We can imagine a surface perpendicular to the direction of the measurement line, and then find the slope of the imaginary surface according to the geometric relationship, and replace the slope Angle of problem 1 with the imaginary slope Angle to obtain the mathematical model of the coverage width. Based on this, the constraints of the Angle and overlap rate of the line are added, and the problem 3 is simplified into the optimization problem of multiple routes in problem 2. Finally, by changing the parameter setting of slope Angle in the model, the sensitivity analysis is carried out, and it is found that the model is stable and reliable.To sum up, the problems from one to four are gradually deepened and progressively advanced, and the development of Marine survey field is facilitated by establishing a model of depth survey line layout. Keywords: Geometric relation, heuristic algorithm multi-objective programming, overlay width, overlap rate, surface integral. 1. Introduction With the urgent need for high-precision seabed topographic survey, ocean exploration has developed from discrete, low- precision and low-efficiency to full coverage, high-precision and high-efficiency [1][2]. The traditional single beam sounding can not meet the requirement of high efficiency seabed exploration. On this basis, the multi-beam sounding system has been proposed and developed continuously, and has been widely used as a new technology of ocean exploration. The layout of line is a very important link in the technical design of sea area, but at present, the actual wiring design methods in China mostly rely on experience. Based on the current situation, the research of multi-beam line measurement is particularly important. There are two key problems in the layout of multi-beam line. The first is the survey line interval. Shallow water depth is used to design the survey line interval, and the problem of missing measurement may occur in the shallow place[3]. Using deep water depth design line interval, there will be more overlapping areas, and the data redundancy is large, which affects the efficiency of the line. The other is the selection of the direction of the measurement line. Different directions of the measurement line will affect the difficulty of the measurement line [4]. 2. Problem Restatement 2.1. Solution to Problem 1 Considering the existence of a certain slope on the sea floor, the slope 𝛼 is defined when the plane perpendicular to the direction of the survey line forms a diagonal line with an Angle of 𝛼 from the horizontal plane. To find the expression of the coverage width π‘Š and the overlap rate πœ‚ between adjacent strips of multi-beam sounding. According to the mathematical expression, the coverage width and overlap rate under the given parameters are solved by substitution [5]. 2.2. Solution to problem 2 In a rectangular sea area, when the Angle between the direction of the survey line and the projection of the normal direction of the submarine slope on the horizontal plane is arbitrarily determined (recorded as 𝛽 ), the mathematical expression of the coverage width is required, and the value of the coverage width is obtained with several groups of given parameters. 2.3. Solution to Problem 3 In a given rectangular sea area, a planning model is established, which can cover the entire sea area under the constraints required in the question, and the overlap rate between adjacent strips is between 10% and 20%. A set of optimal measuring lines is designed to make the total measuring line length shortest. 2.4. Solution to Problem 4 On the basis of some existing reference data, simulate the bottom of the sea area, and make appropriate simplified processing according to the bottom of the sea area. Under constrained conditions, cover the sea area to be measured as much as possible, keep the overlap rate of adjacent strips below 20%, minimize the total length of the side line as much as possible, search for the approximate optimal solution, and calculate relevant indicators according to the optimal solution: The total length of the measuring line, the proportion of the missing measuring area, the total length of the overlap of more than 20%. 3. Problem Analysis 3.1. Analysis of Problem 1 The first problem requires a mathematical model of coverage width and overlap rate. The key point of this 112 problem is to find the mathematical relationship between the target quantity and the known quantity in plane geometry problems. In this regard, according to the triangle relation and the sine theorem of triangle, the mathematical expressions for covering width π‘Š, overlap rate πœ‚, slope 𝛼, opening Angle of multi-beam converter πœƒ and seawater depth 𝐷 at the center of sea area are established respectively [6]. 3.2. Analysis of problem 2 Problem 2 is extended to some extent on the basis of problem 1. In problem 2, the angle between the direction of the survey line and the projection of the normal direction of the submarine slope on the horizontal plane is 𝛽 .In fact, problem 2 is reduced to the situation of problem one when 𝛽 90Β° or 𝛽 270Β° . Problem 1 gives a mathematical model of coverage width and overlap rate on the surface perpendicular to the direction of the measurement line. In problem 2, we can imagine a surface perpendicular to the direction of the measurement line, and then find the slope of the imaginary surface according to the geometric relationship, and replace the slope Angle of problem 1 with the imaginary slope Angle to obtain the mathematical model of coverage width. 3.3. Analysis of problem 3 Problem 3 is a problem on optimization, which needs to design a set of routes with the shortest measurement length, and can completely cover the entire sea area and meet the requirement of 10%~20% overlap rate. According to problem 2, a route can be determined by the Angle 𝛽 projected on the horizontal plane between the direction of the survey line and the normal direction of the submarine slope (hereinafter referred to as the direction of the route) and the interval d of the route. Therefore, the problem is simplified to the optimization problem of solving the two routes in multiple problems. (1) The total length of the survey lines is required to be the shortest. When the course direction is fixed, the survey line interval 𝑑 is as large as possible, and the number of survey lines is as small as possible. Therefore, the overlap rate of survey lines at the shallowest part of the sea water is at least 10%, and the overlap rate at the deepest part of the sea water is not more than 20%; When there is overlap between each line, it will definitely meet the complete coverage of the sea area between the survey lines, we only need to consider the interval from the most marginal survey line to the edge of the sea area 𝑑 When the first survey line is determined, the second survey line will be determined solely by the first survey line according to the maximum interval, and so on until all survey lines have scanned the entire sea area [7]. 3.4. Analysis of Problem 4 Firstly, the data given in the question is visualized. In MATLAB, a three-dimensional map is made. Considering that the data is a plurality of data points, in order to make that undersea topography more intuitive and smooth, fitting the given data, a fitted surface equation is obtained. By looking at the contour plot and gradient plot of the surface, it is found that that contour line on both sides along the diagonal line are nearly parallel and approximately straight, and the gradient direction is basically the same. Considering that the sea floor on either side of the diagonal along the rectangular sea area is approximately planar, the original surface is then decomposed into two planes, and the question is reduced to question three. According to the title, the mathematical model of multi- objective programming is established and solved[8]. 4. Model Assumption 1. According to the relevant literature in the field of Marine survey, it is generally possible to arrange parallel routes. 2. The measurement lines laid out are straight lines. 3. The distance between the surveying ship and the center point of the sea area is only considered as the distance between the surveying ship and the center point of the sea area in the vertical direction of the surveying line, which means, the distance between the surveying ship and the center point of the sea area along the direction of the surveying line is not considered. 4. Since the propagation speed of sound wave in water is much higher than the speed of ship, it is considered that there is no time delay effect during each measurement. 5. Symbol Description Table 1. Symbol Description symbol Instructions unit π‘Š Covering width meter πœƒ Multi-beam transducer opening Angle Angle 𝛼 submarine slope Angle Angle πœ‚ Overlap rate β€”β€” 𝐷 Depth of sea water at the center point of sea area meter 𝑑 Distance between adjacent survey lines meter 𝑙 The i line 𝛼 Total length of measuring line Angle 𝐿 Article i Measuring line length meter Z Total length of measuring line meter π‘₯ Distance between survey line and center point of sea area meter 𝐷 Sea depth meter Note: Some length units in the question are in nautical miles, and all length units in this paper are in the International standard unit meter. The specific conversion method is given as 1 nautical mile =1852 meters according to the question. 113 6. Model Establishment and Solution 6.1. Establishment and solution of problem-1 model 6.1.1. Model establishment The first problem is to calculate the coverage width and overlap rate in a slanted case. Since the question does not specify the specific calculation method, we are analogous to the horizontal case. Define the coverage width as the length of the edge beam falling on the seafloor slope at the opening Angle of the transducer. As shown in Figure 1 below, it is defined as Covering width W= KB (1) Define the overlap ratio (denoted πœ‚) as 1 minus the ratio of the difference between the transducer coverage width and the overlap to the transducer coverage width. In Figure 1 below, it is defined as Figure 1. Illustration of the first question 6.1.2. Model solution Using the sine theorem of triangle and the relation of Angle between parallel lines, the mathematical relation is established. Using the sine theorem and triangle induction formula in the triangle AHK, we get: |𝐾𝐻| 𝑠𝑖𝑛 180Β° ∠1 |𝐾𝐻| 𝑠𝑖𝑛 ∠1 |π·π‘‘π‘Žπ‘› πœƒ 2 | 𝑠𝑖𝑛 ∠𝐴𝐾𝐻 (3) Using the sine theorem in the triangle BHL, we get: |𝐡𝐻| 𝑠𝑖𝑛 ∠1 |π·π‘‘π‘Žπ‘› πœƒ 2 | 𝑠𝑖𝑛 ∠𝐻𝐡𝐿 (4) From the parallel line theorem and the sum of the angles of a triangle being dark 180Β° : ∠1 90Β° πœƒ 2 (5) ∠𝐴𝐾𝐻 ∠1 βˆ π›Ό (6) ∠𝐻𝐡𝐿 180Β° ∠1 βˆ π›Ό (7) The quantitative relationships in length are: π‘Š |𝐴𝐡| |𝐾𝐻| |𝐻𝐡| (8) Combine formula (3) - (8) and simplify to obtain the mathematical expression of covering width άΉβ—Œ : π‘Š 2π·π‘‘π‘Žπ‘› πœƒ 2 π‘π‘œπ‘  πœƒ 2 𝑠𝑖𝑛 90Β° βˆ π›Ό 𝑠𝑖𝑛 90Β° βˆ π›Ό πœƒ 2 𝑠𝑖𝑛 90Β° βˆ π›Ό πœƒ 2 (9) Using the sine theorem in the triangle KEC, we get: |𝐾𝐢| 𝑠𝑖𝑛 ∠𝐾𝐸𝐢 |𝐸𝐢| 𝑠𝑖𝑛 ∠𝐸𝐾𝐢 |𝑑| 𝑠𝑖𝑛 ∠𝐸𝐾𝐢 (10) ∠𝐸𝐾𝐢 ∠𝐴𝐾𝐻 (11) ∠𝐾𝐸𝐢 180Β° ∠1 (12) Then substitute formula (9) - (12) into formula (2) to obtain the expression of overlap rate πœ‚ : πœ‚=1βˆ’π‘‘π‘ π‘–π‘› [90Β°βˆ’βˆ π›Ό+πœƒ2]2π·π‘ π‘–π‘›πœƒ2π‘π‘œπ‘ βˆ π›Ό (13) Formulas (9) and (13) give the expression when the measurement line is 0 from the center point of the sea area. When the surveying line moves, the surveying line and the center point of the sea area change, and only the seawater depth 𝐷 will change (become 𝐷 obscure). Assuming that the distance between the surveying line and the center point of the sea area is x, then: 𝐷 𝐷 π‘₯π‘‘π‘Žπ‘›βˆ π›Ό (14) By synthesizing formulas (9), (13) and (14), we can achieve the results obtained from the calculation of the given parameters in topic 1 through MATLAB programming (see Table 2): Table 2. The result of question 1 Measure the distance between the line and the center point /m -800 -600 -400 -200 0 200 400 600 800 Sea depth /m 49.051 54.288 59.526 64.763 70.000 75.237 80.474 85.712 90.949 Coverage width /m 170.32 188.51 206.69 224.88 243.07 261.25 279.44 297.62 315.81 Overlap rate with the previous line /% β€” -23.0% -11.2% -1.4% 6.8% 13.8% 19.8% 25.0% 29.6% Overlap rate πœ‚ 1 | | (2) 114 6.2. Establishment and solution of problem 2 model Problem 2 introduces a more complex scenario on the basis of problem 1. Since the beam surface is actually a plane perpendicular to the survey line, we are more concerned about the change of the vertical surface of the survey line in the following analysis. In problem 1, the vertical plane of the line is parallel to the horizontal component of the slope's normal direction, while in problem 2, there is a certain Angle between the vertical plane of the line and the horizontal component of the slope's normal direction. If the position of the vertical plane can be determined, we can imagine a slope formed by the vertical plane of the vertical line and the reference plane of the seabed, and then solve the slope Angle of the imaginary slope surface Ξ± Μƒ by using geometric relations. Then problem 2 can be simplified to problem 1. Therefore, the center point of the sea area (denoted C) is the vertical plane of the survey line and intersects it with the submarine reference plane. The intersection line is denoted b. Points O and B are at the intersection line b, connect C and O, so that CO is perpendicular to the submarine reference plane (denoted line segment CO is line h). Point B is at the intersection line between the submarine reference plane and the bottom slope of the real sea 7 (denoted l). Cross the center point C of the sea area to the intersection line of the submarine slope and the submarine reference plane as A vertical line. The intersection point is denoted as point A, connecting OA (denoted as line a), BC. The scenario diagram is shown in Figure 2 below Figure 2. It is easy to know from the figure that there is a trigonometric function relationship at this time: π‘‘π‘Žπ‘›βˆ π›Ό |𝐢𝑂| |𝐴𝑂| οΌŒπ‘‘π‘Žπ‘›βˆ π›Ό |𝐢𝑂| |𝐡𝑂| (15) Since 𝐢𝑂 is the reference plane of the ocean floor,𝐢𝑂 βŠ₯ 𝑙. And since 𝐢𝐴 βŠ₯ π‘™οΌŒπΆπ΄ ∩ 𝐢𝑂 𝐢. From the vertical theorem of line and plane, it can be concluded that 𝑙 βŠ₯ πΉπ‘Žπ‘π‘’ 𝑂𝐢𝐴. Since the line plane is perpendicular,𝑙 is perpendicular to any line in the face OCA, i.e. : βˆ€π‘™π‘–π‘›π‘’π‘₯ βŠ‚ π‘“π‘Žπ‘π‘’ π‘‚πΆπ΄οΌŒπ‘™ βŠ₯ π‘₯ (16) So the line OA is perpendicular to the intersection line 𝑙, i.e.,βˆ π‘‚π΄π΅ 90Β° In the triangle OAB,βˆ π‘‚π΄π΅ 90Β°οΌŒβˆ π΄π‘‚π΅ βˆ π›½ 90Β°, so π‘π‘œπ‘ βˆ π΄π‘‚π΅ π‘π‘œπ‘  βˆ π›½ 90Β° |𝐴𝑂| |𝐡𝑂| (17) By combining equations (14) and (16), the mathematical relationship of imaginary slope Angle can be obtained: βˆ π›Ό π‘Žπ‘Ÿπ‘π‘‘π‘Žπ‘› |π‘ π‘–π‘›βˆ π›½| π‘‘π‘Žπ‘›βˆ π›Ό (18) After the imaginary slope Angle is obtained, problem 2 is simplified to problem 1. βˆ π›Ό in formula (9) and formula (14) is replaced by βˆ π›Ό, and 𝐷 in formula (9) is replaced by𝐷 Μ΅ in formula (14). The total formula for the coverage width of problem 2 is as follows: π‘Š 2 𝐷 π‘₯π‘‘π‘Žπ‘›βˆ π›Ό π‘‘π‘Žπ‘› πœƒ 2 π‘π‘œπ‘  πœƒ 2 𝑠𝑖𝑛 90Β° βˆ π›Ό 𝑠𝑖𝑛 90Β° βˆ π›Ό πœƒ 2 𝑠𝑖𝑛 90Β° βˆ π›Ό πœƒ 2 (19) The formula (19) was programmed in MATLAB, and the parameters given in question 2 were substituted, and the results were obtained. 6.3. Establishment and solution of problem 3 model This problem is an optimization problem, which needs to design a set of routes with the shortest measurement length. It can completely cover the entire sea area, and meet the requirement of overlap rate between 10% and 20%. It can be seen from problem 2 that a route can be determined by the Angle 𝛽 projected on the horizontal plane between the direction of the survey line and the normal direction of the submarine slope (hereinafter referred to as the route direction) and the interval d of the route. The slope is 1.5Β° and the opening Angle of the multi-beam transducer is 120Β°, which is the same as problem 2. Therefore, the problem is simplified to the solution optimization problem of routes in problem 2. By searching the data, we learned that the survey lines need to be arranged in parallel in order to ensure that a set of survey lines can scan the entire sea area as fully as possible [9]. (1)The total length of the survey lines is required to be the shortest. When the course direction is fixed, the survey line interval d is as large as possible, and the number of survey lines is as small as possible. Therefore, the overlap rate of survey lines at the shallowest part of the sea water is at least 10%, and the overlap rate at the deepest part of the sea water is not more than 20%;(2) When there is overlap between each line, it will definitely meet the complete coverage of the sea area between the survey lines, we only need to consider the interval from the most marginal survey line to the edge of the sea area 𝑑 . When the first survey line is determined, the second survey line will be determined solely by the first survey line according to the maximum interval, and so on until all survey lines have scanned the entire sea area[10]. Step1. Solve for the initial interval 𝑑 115 Figure 3. Figure 3 shows the side view perpendicular to the direction of the survey line and passing the edge point C. As shown in Figure 3, when the scanning area of the edge survey line passes the most edge point C, the entire scanning of the edge area can be guaranteed. To maximize the spacing 𝑑 , we make the 𝑙 obscure right side scan width 𝑀 obscure exactly to the point C on the edge, where the deepest sea water is β„Ž , there is Step2. Establish a plane rectangular coordinate system for the top view of the entire sea area Figure 4 As shown in FIG. 4, the positive direction of the X-axis is set to be westward. According to the meaning of the question, in the rectangular sea area 2 nautical miles long from north to south and 4 nautical miles wide from east to west, the west is deep and the east is shallow. The Angle between the axis of the straight line 𝑙 and π‘₯ is the included Angle of the horizontal projection of the direction of the survey line and the normal direction of the submarine slope, 𝛽, and the Angle 𝛽 is arbitrary. Step3. Solve the upper intersection point 𝐴 and the lower intersection point 𝐴 of the survey line 𝑙 and the sea area to be measured We set intersection 𝐴 π‘₯ , 𝑦 , 𝐡 π‘₯ , 𝑦 when the initial interval grey is determined, then you can write in figure 4 𝑙 dark in the coordinate system for the linear equation π‘Œ π‘‘π‘Žπ‘›π›½ βˆ™ π‘₯ π‘₯ (21) Among them, The equation for line BC is The equation of line AB is If the equations (18) and (20) are combined, a point coordinate will be obtained, set as 𝐴 ; if the equations (18) and (21) are simultaneously combined, a point coordinate will be obtained, set as 𝐴 , which is obtained by comparing the horizontal coordinates of 𝐴 and 𝐴 π‘šπ‘–π‘› π‘₯ , π‘₯ (25) 𝐿 π‘₯ π‘₯ 𝑦 𝑦 (26) Then the upper intersection is the coordinate of the point with the smallest horizontal coordinate among the two points, and the upper intersection 𝐴 is obtained. Similarly, write the equation of a line AO and a line OC to obtain the coordinates of the lower intersection, then the length of the measurement line is the Euclidean distance between the upper and lower intersection points, that is, write the equation of a line AO and a line OC to obtain the coordinates of the lower intersection points, then the length of the measurement line is the Euclidean distance between the upper and lower intersection points, that is Step4. According to the measurement line 𝑙 obscurity and constraints, find out the interval 𝑑 with the next measurement line From the overlap rate formula (13) obtained in question 1, the relationship between interval d and overlap rate πœ‚ is 𝑑 2 βˆ™ 1 πœ‚ βˆ™ 𝐷 βˆ™ sin πœƒ/2 βˆ™ π‘π‘œπ‘ π›Ό sin 90Β° 𝛼 πœƒ/2 (27) Here is the hypothetical slope angle 𝛼 in Problem 2, and π‘‘π‘Žπ‘›π›Ό π‘‘π‘Žπ‘›π›Ό βˆ™ 𝑠𝑖𝑛𝛽 (28) As can be seen from the figure, the depth of the sea area at any point is only related to the abscissa of the point π‘₯, and the relation is satisfied 𝐷 𝑓 π‘₯ β„Ž β„Ž π‘‘π‘Žπ‘›π›Ό βˆ™ π‘₯ (29) When the route is obscure at the shallowest sea depth 𝐴 ,πœ‚ 10% can ensure that the route spacing is as large as possible, and 𝐡 should be satisfied when the route is obscure at the deepest sea depth πœ‚ 20%; Step5. Determine that the last route covers the diagonal edge point A Suppose there are n measuring lines to complete the full coverage, repeat Step1-4, and the expression of the 𝑖 measuring line is. 𝑑 β„Ž βˆ™ tanοΌˆπœƒ/2οΌ‰ (20) π‘₯ π‘₯ 𝑑 /𝑠𝑖𝑛𝛽 (22) π‘₯ 4 βˆ™ 1852 (23) 𝑦 2 βˆ™ 1852 (24) 116 Find the final interval 𝑑 on the basis of the last line𝑙 , if the last intersection 𝐴 and the abscissa π‘₯ are satisfied Then On the contrary, Finally, the total length Z of the whole group of measurement lines is Again according to question 2, when 0Β° 𝛽 180Β° with 180Β° 𝛽 360Β° when routes, is just the starting point is different, so the subject need to consider 0Β° 𝛽 180Β° situation, above all, kinds of optimization objective function for the model π‘šπ‘–π‘› 𝑍 𝐿 (35) The constraint condition is s.t. 10% πœ‚ 20% 0 π‘₯ 4 1852, 𝑖 1,2,3 … 0 𝑦 2 1852, 𝑖 1,2,3 … 0Β° 𝛽 180Β° (36) The final result is that the number of measured lines is 38, and the total length is 14,0752m. Draw the group of lines with the shortest total distance as follows Figure 5a Figure 5b 6.4. Establishment and solution of problem 4 model 6.4.1. Data Visualization We first visualized the data given in the question and made a three-dimensional diagram in MATLAB, as shown in Figure 5. Considering that the data are multiple data points, in order to make the submarine terrain more intuitive and smooth, cftool toolbox in MATLAB was used to fit the data given, and the surface diagram shown in Figure 6 can be obtained. Figure 6 And the equation of submarine surface is 𝑧 3.173 17.6 βˆ™ π‘₯ 4.491 βˆ™ 𝑦 6.4 βˆ™ π‘₯ 9.6 βˆ™ π‘₯ βˆ™ 𝑦 3.2 βˆ™ 𝑦^2 (37) And the correlation coefficient 𝑅 0.9648 and the goodness of fit is good. 6.4.2. Model establishment In the survey line group with the shortest total distance obtained from question 3, the direction of the survey line is parallel to the bottom edge of the rectangular sea area, that is, it runs along the contour line of the seabed. The feasibility of this operation is verified by searching data, and we specify the course direction of question 4 to run along the contour line of the coastal bottom [11]. According to the equation of the submarine surface obtained in z, we make the contour map and gradient line of the submarine surface as shown in FIG. 7. Figure 7 By analyzing the obtained contour map, we find that the π‘Œ 𝑑 π‘π‘œπ‘ π›½ π‘Œ (30) π‘₯ 𝑑 sin 𝛽 (31) 𝑛 𝑖 (32) 𝑛 𝑖 1 (33) 𝑍 𝐿 (34) 117 contour lines on the left and right sides of the diagonal line from southwest to northeast in the rectangular sea area are basically parallel and approximately straight. At the same time, we draw the gradient map and find that the direction of the gradients on both sides is basically the same along the main diagonal, indicating that the two sides can be regarded as planes approximately. Inspired by this, the seafloor surface can be divided into two planes along the southwest to northeast diagonal, so problem 4 is simplified to problem 3. The difference is that the seafloor slope of Problem 3 is a rectangular plane, while problem 4 is two triangular planes[12]. The seafloor plane above the diagonal from southwest to northeast is 𝑆 dark, and the seafloor plane below is 𝑆 . At the same time, the east direction is the positive direction of the x axis, the north direction is the positive direction of the y axis, and the upward direction is the positive direction of the z axis. The space rectangular coordinate system is established with the seabed in the southwest corner as the coordinate origin, as shown in Figure 8. Figure 8 As shown in the figure, βˆ†π΄π‘‚π΅ belongs to the plane 𝑆 , βˆ†π΄πΆπ΅ belongs to the plane 𝑆 . Since problem 3 is a rectangular slope and problem 4 is a triangle, it is considered to put the triangle into the rectangular slope to solve it. Taking the plane 𝑆 as the example βˆ†π΄π‘‚π΅, extend the base of AB to point E and connect to OE, where OE is the base edge of the rectangular slope to be obtained. Then the problem is simplified to problem 3. We arrange survey lines parallel to the base edge OE (that is, in the direction of contour lines), and finally increase the constraints that the total length of survey lines is as short as possible, the coverage area is as large as possible, and the overlap rate is as small as possible to establish a new optimization model. A rectangular area things for a long, north and south long b,,𝐴 π‘₯ , 𝑦 , 𝑧 ,𝐡 π‘₯ , 𝑦 , 𝑧 , 𝐢 π‘₯ , 𝑦 , 𝑧 , 𝐸 π‘₯ , 𝑦 , 𝑧 . Step1. Find the slope Angle Ξ± The direction of the vector 𝑂�⃗� is specified as the direction of the measurement line, then the Angle 𝛼 of slope is the dihedral Angle between the plane 𝑆 and the plane π‘₯𝑂𝑦, and a plane 𝑆 is set.If the normal vector of the plane π‘₯𝑂𝑦 is 𝒏, then there is π’Ž 𝑢𝑨 𝑢�⃗� (38) 𝒏 𝟎, 𝟎, 𝟏 (39) Dihedral Angle Ξ± is π‘π‘œπ‘  𝛼 π’Ž 𝒏 |π’Ž| |𝒏| (40) Step2. Find out the bottom width of the rectangular area According to the meaning of the question, OE is the base width of the corresponding rectangular area, and the schematic diagram of the rectangular sea area with S as the slope is shown in FIG. 9. Figure 9 Then there is, Step3. Find the bottom length of the rectangular area As shown in FIG. 10, the vertical line intersecting the base of xOy through point A meets the point P x , y , 0 , then the length of the base OM is the distance from point P to the straight line OE. In the coordinate system plane xOy , the equation of the straight line OE is And Then the distance from point P to line OE is 𝑑 π‘˜π‘₯ 𝑦 βˆšπ‘˜ 1 (44) Step4. Regression problem 3 The expression formula of the overlapping area is as follows 𝑆 πœ‚ βˆ™ π‘Š βˆ™ 𝐿 (45) In summary, the newly obtained mathematical model S is ⎩ βŽͺ ⎨ βŽͺ ⎧min 𝑆 πœ‚ βˆ™ π‘Š βˆ™ 𝐿 min 𝑍 𝐿 (46) The constraint condition is |𝑂𝐸|= π‘₯ 𝑦 (41) 𝑦 π‘˜ βˆ™ π‘₯ (42) π‘˜ 𝑦 π‘₯ (43) 118 s.t. πœ‚ 20% 0 π‘₯ 𝑂𝐸, 𝑖 1,2,3 … 0 𝑦 𝑑, 𝑖 1,2,3 … 𝛽 90Β° (47) The procedure for S is the same as above and will not be described here. The result of question 4 is finally obtained, as shown in Table 3. Table 3. The result of question 4 As can be seen from the table, the final total number of measured lines is 50, the optimal length is 469255.51m, the area of overlapping area is 0. The area of unmeasured area is 17895500.19π‘š , accounting for 0.42% of the total surface area, and the result is good [13]. 7. Model Analysis and Test 7.1. Model sensitivity analysis Sensitivity analysis is one of the methods to evaluate the planning model, which is as follows[14] : (1) Set a bias for the required parameters of the model (take 3%, 6%, 9% as an example). (2) When the slope Angle of the parameter is changed, the remaining parameters are kept unchanged to observe whether the difference between the final results is significant. The results are as follows Table 4. The results The relationship between the change of slope Angle and the number of lines and the total length of lines is shown in Figure 10. Figure 10a Figure 10b The results show that when the parameters change, the model results will not change greatly, and the model stability is reliable. 7.2. Model error analysis The model assumes that the delay caused by the beam propagation time does not affect the results, which was reviewed: The propagation speed of sound waves in seawater. The main factors of the propagation speed of sound waves are temperature, salinity and pressure (depth). The change of temperature has the greatest influence on sound velocity. Due to the uneven distribution of temperature and salinity in the seawater medium, the distribution of sound velocity will be uneven, thus forming a sound velocity gradient in the ocean. The speed of sound wave propagating in the seawater is three and a half times faster than that in the air (about 1531 m/s)[15]. We estimate the speed of sound at 1 nautical mile per second, and the maximum time for the beam to sweep the rectangular sea area is not more than 5 seconds, so it is easy to know that this assumption will not introduce significant errors. 8. Evaluation, Improvement and Extension of The Model 8.1. Advantages of the model 1. The model is based on the integrity of hydrographic survey and has practical application prospects. 2. Some assumptions are made in the model to simplify the problem and reduce the amount of calculation. 3. The model is based on geometric ideas and simple to prove. 4. The model qualitatively analyzes the effects of acoustic wave propagation to simplify the problem. 8.2. Disadvantages of the model 1. Problem 4 model retains the integrity of measurement as much as possible, and the measurement line obtained is too long. 2. In the modeling of problem 4, we chose the fitting graph instead of the actual surface, which may result in the loss of some data points. 8.3. Model improvement The line spacing in the model can be assumed to be equal spacing, which can simplify the problem and be easy to implement, but will sacrifice the accuracy of the model. At the same time, for problem 4, we can further refine the segmentation of the slope bottom and divide it into more planes with different gradients for solving, so as to improve 119 the accuracy of the model. 8.4. Model promotion 1. 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