Al-khwarizmi Engineering Journal Al-Khwarizmi Engineering Journal, Vol.4 , No.1 , pp 17- 26 (2008 ) Minimizing error in robot arm based on design optimization for high stiffness to weight ratio. Ahmed Abdul Hussain Ali University of Baghdad College of Engineering, Mech. department (Received 8 May 2007; accepted 3 December 2007) Abstract: In this work the effect of choosing tri-circular tube section had been addressed to minimize the end effector’s error, a comparison had been made between the tri-tube section and the traditional square cross section for a robot arm, the study shows that for the same weight of square section and tri- tube section the error may be reduced by about 33%. A program had been built up by the use of MathCAD software to calculate the minimum weight of a square section robot arm that could with stand a given pay load and gives a minimum deflection. The second part of the program makes an optimization process for the dimension of the cross section and gives the dimensions of the tri-circular tube cross section that have the same weight of the corresponding square section but with less deflection. Key word: robot arm stiffness, flexible manipulator, robot structure analysis, flexible link robot. Introduction: The links of serial manipulators are usually over designed in order to be able to support the subsequent links on the chain and the pay load to be manipulated. However, increasing the size of the links unnecessarily requires the use of larger actuators resulting in higher power requirements. Optimum robot design has been addressed by many researchers as found in the open literature; Shiakolas and koladiye [1] discuss the application and comparison of the evolutionary techniques for optimum design of serial link robot manipulators based on task specifications. The objective function minimizes the required torque for a defined motion subjected to various constraints which considering kinematics, dynamic and structural conditions. The design variables examined are the link parameters and the link cross sectional characteristics, the developed environment was employed in optimizing the design variables for a SCARA and an articulated 3-DOF PUMA type manipulators. In the work developed by Marcus Pettersson et al. [2] an optimization problem are formulated to minimize the weight of the gearboxes, by choosing different discrete gear boxes, and changing the lengths of the arms continuously, subjected to a few requirements on acceleration capability reach and pay load capacity. Analysis of stiffness of manipulator link can be found in Abdel malek, K. and Paul, B.[3] where aspects of the structural design of the manipulator arm are presented. Prismatic joints of manipulator arm are based upon a cross sectional design of the links that provides a high stiffness to weight ratio compared with a hollow round cross- section. The case that we study in this work is the robot that consists of three arms as shown in fig. (1). Where the first arm is vertical and the second and third arm are horizontal this gives the maximum reach (completely stretched out) for the robot arm and will yield the maximum deflection for the robot. Ahmed Abdul Hussain Ali Al-khwarizmi Engineering Journal, Vol.4 , No. 1 PP 17-26 (2008) 18 Prismatic joints: Most manipulator link cross- section are either hollow round or hollow rectangular. Hollow links provide convenient conduits for electric power and communication cables, hoses, power transmission members, etc. Rivin[4] has studied the influence of cross- sections on the deflections both in bending and torsion. He had compared hollow square with hollow circular cross sections. Rivin states that a square cross section can provide a 69 to 84 percent increase in bending stiffness over a circular hollow cross section with only a 27 percent increase in weight. In this paper a different cross-section is introduced, consisting of three tubes centered on the vertices of an equilateral triangle. This cross section is referred to as a tri-tube configuration the hollow square link will be referred to as a uni-tube configuration, as shown in fig. (2). Deflection due to pure bending: Links with an open end manipulator are normally modeled as cantilevers. Consider a simple cantilever with solid or hollow cross – section as shown in fig.(3).To study the proposed cross –section, we use the following equations for moments of inertia (2nd moment of area) about any diametrical axis through the centroid of area. Uni –tube: For the uni- tube depicted fig.(2,a) the moment of inertia about the neutral axis is tBb bB I tubeuni 2, 12 44    Where B, b is the outer and inner sides, respectively for the uni-tube construction, t is the thickness of the uni-tube and the area is 22 bBA tubeuni  Tri-tube: For the tri-tube depicted in fig.(2,b) the moment of inertia about the neutral axis is       2 22 2244 60sin 3 1 4 2 60sin 3 2 464 3               hdD hdDdDI tubetri   tDd 2 Where D and d are the out side and inside diameters, respectively, for each tube on the equilateral triangle, t is the thickness of each tube in the tri – tube construction. The area of each tube is   tDddDA tubetri 2, 4 22   To demonstrate the deflection due to loading, consider the third arm beam depicted in fig.(3,c).          83 1 4 33 3 33 3 3 LqLW EI  gmWA L ALg L gM q    ,  Where M is the mass of each arm, m is the mass of the gear box and the mass of the load to be manipulated at the end of the arm, q is the weight per unit length of the beam, W is the load in Newton, g is the gravitational acceleration and L is the length of the arm, A is the cross sectional area of the beam,  is the specific density. To get the reactions (force and moment) at the fixed end of the third arm we equate the summation of forces and moment to zero i.e.   33330 LqWFFy   33 2 33 3 2 0 LW Lq MOM The same thing may be said for the second arm (fig.3-b) taking in to account the effect of moment in calculating the deflection i.e.              283 1 3 23 4 22 3 223 2 2 LMOLqLWF EI  The reactions at the fixed end will be 32222 FWLqF  32322 2 22 2 2 MOLFLW Lq MO  For the first arm (fig.3-a) we assume that the deflection at the free end is due to bending moment only and the effect of compressive loads on the whole deflection is neglected therefore 1 2 11 1 2EI LMO  Ahmed Abdul Hussain Ali Al-khwarizmi Engineering Journal, Vol.4 , No. 1 PP 17-26 (2008) 19 The total deflection at the end effecter of the robot manipulator arm will be   21 2 23  total The sequence of analysis in this work is to calculate the weight of the lightest structure that has a square hollow section and with stand the given loading condition this may be achieved by letting the stress in each arm reaches the maximum allowable stress to avoid failure of the structure, the equation for calculating the stress in the third arm may be written as 12 2/* 4 3 4 3 33 3 bB BMO I YM   By letting the stress equal the allowable stress and assuming the thickness of the tube walls to be 2mm we may found the dimension of the third arm, this had been done by the aid of a program built up using MathCAD software. The stress in the second arm may also be calculated in the same way i.e. 12 2/* 4 2 4 2 22 2 bB BMO   The dimension of the first arm fig.(3.a) is calculated by equating the maximum stress induced in it with the maximum allowable, this maximum stress is found by the Rankine- Gorden formula [5] which is a combination of the Euler and crushing loads for a strut ceR FFF 111  For very short strut eF is very large, eF 1 can therefore be neglected and cR FF  , for very long struts eF is very small and eF 1 is very large so that cF 1 can be neglected. Thus eR FF  . The Rankine formula is therefore valid for extreme values of slenderness ratios. It is also found to be fairly accurate for the intermediate values. Thus, re – writing the formula in terms of stresses )/(1 111 111 eY Y Ye Ye R Ye Ye YeR YeR AAA                 For a strut with one end free and the other fixed 2 2 4 L IE Fe   and AL IE e 2 2 4    The crushing load on the first arm is 121 WFFFc  A Fc Y  The final stress  1 on the first arm is thus the sum of the direct stress calculated by Rankine formula and that due to bending generated by the exerted moment  2MO as was explained in figure (3-a and b)   1 12 1 2/* /! I BMO eY Y bendingR      From this equation we may find the dimension of the first arm. After knowing the dimension of each arm the weight of each arm may be found and also the total weight of the manipulator structure will be determined. The next step in the analysis is to input those information to the program to began the process of changing the dimension of the cross section to minimize the total error (deflection) at the end of the robot arm this process gives many generations of the dimensions of the arm cross section which satisfies the conditions specified for the maximum and minimum error allowed at the end effecter and also the permissible increase in the weight of the robot structure specified from us, from between all those generation the program select the best generation or probability that gives the lightest weight and the less deformation. The next step in the analysis is to input the new weight of the robot arms to the optimization process for the tri –tube cross section shown in figure(2-b) and trying to find the best dimensions that gives the highest moment of inertia for the cross section so as to minimize the deflection in each arm and also the total deflection of the robot at the end effecter, i.e. the mass of uni –tube section Ahmed Abdul Hussain Ali Al-khwarizmi Engineering Journal, Vol.4 , No. 1 PP 17-26 (2008) 20 found by the program should be equal to the mass of the tri –tube section which is equal to                ) 4 3 (2)( 4 3 2 222 3 3     D RSdDL VM 2/ 3 sin 3 2 DhR   Where  is the density of robot arm metal, R is the radius of the two flanges (stiffeners) welded at each end, S is the thickness of the flanges and h is the distance between the vertices of the equilateral triangle. The optimization problem is defined as follow tDDh Iimize MM tubetri tubeunitubetri 2, )(max     In the optimization problem the thickness of the tubes )(t and the thickness of the flanges )(S are assumed to be 2mm. The results of the optimization problem showed that the tri –tube section that have the same weight (mass) of a uni –tube may improve the stiffness of the robot and minimize the total deflection in about 33%, this results means that we may construct a robot having tri –tube section which is less in weight from that of uni –tube section and both of them having the same end effecter deformation. Results: In order to verify the analysis of the previous section a run had been done which has the following characteristics for the robot arm 29 /10200 mNE  26 /10120 mNall  , 2sec/81.9 mg  , mLmLmL 4.,45.,5. 321  , 3/7850 mkg , m0022.0max  , m0005.0min  , mT 002.0 ( tube thickness ), mS 002.0 (stiffener thickness), kgm 5.91  (mass of the first gear box), kgm 4.42  (mass of the second gear box), kgm 503  (manipulated mass). The available gear boxes for the application are given in the list of table 1 The results of the program shows that for the given configuration the minimum weight for the structure of the uni –tube robot is (Wmin=19.986 N), the robot with such structural weight could manipulate the load with out failure because the stress in each arm is less than or equal to the allowable stress, but the deflection of the end point effecter is very large. The iteration process for increasing the dimension of the section to minimize the deflection and letting it be within the range (0.0005< <0.0022) shows that there are 22 generation all of which has a deflection (0.0005< <0.0022) and also a weight (WFac.*Wmin Saving generations Finding minimum (VAR=Wrobot total ) 1 1 Optimization for tri-tube section h>D , Wtii-tube=Wuni-tube, D  2T Maximize (I), find h,D Finding: 123 ,,    21 2 23,  tubetritotal No No Yes Yes Ahmed Abdul Hussain Ali Al-khwarizmi Engineering Journal, Vol.4 , No. 1 PP 17-26 (2008) 26 على أساس التصمیم األمثل ولنسبة جساءة الى وزن ) الروبوت(تقلیل الخطاء في الذراع األلي .عالیة أحمد عبد الحسین علي. د كلیة الھندسة/ جامعة بغداد قسم المیكانیك :الخالصة لطرفي في الذراع األلي ، تم في ھذا البحث تم دراسة تاثیر استخدام المقطع الثالثي األنابیب الدائریھ ألجل تقلیل الخطاء ا اجراء مقارنھ بین المقطع الثالثي األنابیب و المقطع المربع التقلیدي للذراع األلي ، الدراسھ بینت بانھ لكال الذراعین ذات المقطع . ٣٣%الثالثي و المربع والذان لھما نفس الوزن ممكن تقلیل الخطاء بحدود ساب أقل وزن للذراع اآللي ذي المقطع المربع الذي یمكن أن یتحمل األوزان المسلطھ لح MathCADتم كتابة برنامج باستخدام .ویعطي أقل تشوه ي الجزء الثاني من البرنامج یقوم بعملیة األمثلیھ ألجل ایجاد ابعاد المقطع ذي األنابیب الثالثیھ الدائریھ والذي لھ نفس وزن الذراع ذ .المربعالمقطع المربع ولھ تشوه أقل من نضیره all s r min max , d d 2 q t B b b B I tube uni 2 , 12 4 4 - = - = - 2 2 b B A tube uni - = - ( ) ( ) ( ) 2 2 2 2 2 4 4 60 sin 3 1 4 2 60 sin 3 2 4 64 3 ÷ ø ö ç è æ - + ÷ ø ö ç è æ - + - = - h d D h d D d D I tube tri p p p t D d 2 - = ( ) t D d d D A tube tri 2 , 4 2 2 - = - = - p ÷ ÷ ø ö ç ç è æ + = 8 3 1 4 3 3 3 3 3 3 3 L q L W EI d g m W A L A L g L g M q = = = ´ = , g r g å + = = 3 3 3 3 0 L q W F F y å + = = 3 3 2 3 3 3 2 0 L W L q MO M ( ) ÷ ÷ ø ö ç ç è æ + + + = 2 8 3 1 3 2 3 4 2 2 3 2 2 3 2 2 L MO L q L W F EI d 3 2 2 2 2 F W L q F + + = 3 2 3 2 2 2 2 2 2 2 MO L F L W L q MO + + + = 1 2 1 1 1 2 EI L MO = d ( ) 2 1 2 2 3 d d d d + + = total 12 2 / * 4 3 4 3 3 3 3 b B B MO I Y M - = = s 12 2 / * 4 2 4 2 2 2 2 b B B MO - = s c e R F F F 1 1 1 + = e F e F 1 c R F F = e F e F 1 c F 1 e R F F = ) / ( 1 1 1 1 1 1 1 e Y Y Y e Y e R Y e Y e Y e R Y e R A A A s s s s s s s s s s s s s s s s s s + = + = + = + = + = 2 2 4 L I E F e p = A L I E e 2 2 4 p s = 1 2 1 W F F F c + = = A F c Y = s ( ) 1 s ( ) 2 MO ( ) 1 1 2 1 2 / * / ! I B MO e Y Y bending R + + = + = \ s s s s s s ú ú ú ú û ù ê ê ê ê ë é - + - = = ) 4 3 ( 2 ) ( 4 3 2 2 2 2 3 3 p p p r r D R S d D L V M 2 / 3 sin 3 2 D h R + = p r R S h t D D h I imize M M tube tri tube uni tube tri 2 , ) ( max ³ ³ = - - - ) ( t ) ( S 2 9 / 10 200 m N E ´ = 2 6 / 10 120 m N all ´ = s 2 sec / 81 . 9 m g = m L m L m L 4 . , 45 . , 5 . 3 2 1 = = = 3 / 7850 m kg = r m 0022 . 0 max = d m 0005 . 0 min = d m T 002 . 0 = m S 002 . 0 = kg m 5 . 9 1 = kg m 4 . 4 2 = kg m 50 3 = d d total d ( ) 2 1 2 2 3 ) ( d d d d + + = - tube Tri Total 3 10 * 8725 . 1 - - = tube uni d d d 3 L d tube Tri - d tube Uni - d d 1 3 5 7 9 11 13 15 17 19 21 0.04 0.05 0.06 0.07 0.08 0.09 B1 B2 B3 B1 B2 B3 fig.(4) corrolation betwen inner side dimension and no. of generations generatons inner-side dimension (B) for uni-tube section in (mm) total d 0 2 4 6 8 10 12 14 16 18 20 22 0.0017 0.00176 0.00182 0.00188 0.00194 0.002 0.00206 0.00212 0.00218 0.00224 0.0023 fig.(5) corrolation betwenthe deflection and no. of generations generations total defflection (mm) 0 2 4 6 8 10 12 14 16 18 20 22 25.5 26 26.5 27 Fig.(6) corrolation betwen robot wight and no.of generations generations total weight (N) 0 2 4 6 8 10 12 14 16 18 20 22 0.05 0.055 0.06 generations vareant(VAR) 2 L 3 q 1 L 1 2 3 , , d d d ( ) 2 1 2 2 3 , d d d d + + = - tube tri total ³ total d ´ max min d d d á á total 3 2 1 , , d d d ( ) 2 3 2 2 3 d d d d + + = total Al-khwarizmi Ahmed abdul hussain ali Al-khwarizmi Engineering Journal, Vol.4 , No. 1 PP 17-26 (2008) Al-khwarizmi Engineering Journal Al-Khwarizmi Engineering Journal, Vol.4 , No.1 , pp 17- 26 (2008 ) Minimizing error in robot arm based on design optimization for high stiffness to weight ratio. Ahmed abdul hussain ali University of Baghdad College of engineering, Mech. department (Received 8 May 2007; accepted 3 December 2007) Abstract: In this work the effect of choosing tri-circular tube section had been addressed to minimize the end effector’s error, a comparison had been made between the tri-tube section and the traditional square cross section for a robot arm, the study shows that for the same weight of square section and tri-tube section the error may be reduced by about 33%. A program had been built up by the use of MathCAD software to calculate the minimum weight of a square section robot arm that could with stand a given pay load and gives a minimum deflection. The second part of the program makes an optimization process for the dimension of the cross section and gives the dimensions of the tri-circular tube cross section that have the same weight of the corresponding square section but with less deflection. Key word: robot arm stiffness, flexible manipulator, robot structure analysis, flexible link robot. Introduction: The links of serial manipulators are usually over designed in order to be able to support the subsequent links on the chain and the pay load to be manipulated. However, increasing the size of the links unnecessarily requires the use of larger actuators resulting in higher power requirements. Optimum robot design has been addressed by many researchers as found in the open literature; Shiakolas and koladiye [1] discuss the application and comparison of the evolutionary techniques for optimum design of serial link robot manipulators based on task specifications. The objective function minimizes the required torque for a defined motion subjected to various constraints which considering kinematics, dynamic and structural conditions. The design variables examined are the link parameters and the link cross sectional characteristics, the developed environment was employed in optimizing the design variables for a SCARA and an articulated 3-DOF PUMA type manipulators. In the work developed by marcus Pettersson et al. [2] an optimization problem are formulated to minimize the weight of the gearboxes, by choosing different discrete gear boxes, and changing the lengths of the arms continuously, subjected to a few requirements on acceleration capability reach and pay load capacity. Analysis of stiffness of manipulator link can be found in Abdel malek, K. and Paul, B.[3] where aspects of the structural design of the manipulator arm are presented. Prismatic joints of manipulator arm are based upon a cross sectional design of the links that provides a high stiffness to weight ratio compared with a hollow round cross-section. The case that we study in this work is the robot that consists of three arms as shown in fig. (1). Where the first arm is vertical and the second and third arm are horizontal this gives the maximum reach (completely stretched out) for the robot arm and will yield the maximum deflection for the robot. Prismatic joints: Most manipulator link cross- section are either hollow round or hollow rectangular. Hollow links provide convenient conduits for electric power and communication cables, hoses, power transmission members, etc. Rivin[4] has studied the influence of cross-sections on the deflections both in bending and torsion. He had compared hollow square with hollow circular cross sections. Rivin states that a square cross section can provide a 69 to 84 percent increase in bending stiffness over a circular hollow cross section with only a 27 percent increase in weight. In this paper a different cross-section is introduced, consisting of three tubes centered on the vertices of an equilateral triangle. This cross section is referred to as a tri-tube configuration the hollow square link will be referred to as a uni-tube configuration, as shown in fig. (2). Deflection due to pure bending: Links with an open end manipulator are normally modeled as cantilevers. Consider a simple cantilever with solid or hollow cross – section as shown in fig.(3).To study the proposed cross –section, we use the following equations for moments of inertia (2nd moment of area) about any diametrical axis through the centroid of area. Uni –tube: For the uni- tube depicted fig.(2,a) the moment of inertia about the neutral axis is Where B, b is the outer and inner sides, respectively for the uni-tube construction, t is the thickness of the uni-tube and the area is Tri-tube: For the tri-tube depicted in fig.(2,b) the moment of inertia about the neutral axis is Where D and d are the out side and inside diameters, respectively, for each tube on the equilateral triangle, t is the thickness of each tube in the tri – tube construction. The area of each tube is To demonstrate the deflection due to loading, consider the third arm beam depicted in fig.(3,c). Where M is the mass of each arm, m is the mass of the gear box and the mass of the load to be manipulated at the end of the arm, q is the weight per unit length of the beam, W is the load in Newton, g is the gravitational acceleration and L is the length of the arm, A is the cross sectional area of the beam, is the specific density. To get the reactions (force and moment) at the fixed end of the third arm we equate the summation of forces and moment to zero i.e. The same thing may be said for the second arm (fig.3-b) taking in to account the effect of moment in calculating the deflection i.e. The reactions at the fixed end will be For the first arm (fig.3-a) we assume that the deflection at the free end is due to bending moment only and the effect of compressive loads on the whole deflection is neglected therefore The total deflection at the end effecter of the robot manipulator arm will be The sequence of analysis in this work is to calculate the weight of the lightest structure that has a square hollow section and with stand the given loading condition this may be achieved by letting the stress in each arm reaches the maximum allowable stress to avoid failure of the structure, the equation for calculating the stress in the third arm may be written as By letting the stress equal the allowable stress and assuming the thickness of the tube walls to be 2mm we may found the dimension of the third arm, this had been done by the aid of a program built up using MathCAD software. The stress in the second arm may also be calculated in the same way i.e. The dimension of the first arm fig.(3.a) is calculated by equating the maximum stress induced in it with the maximum allowable, this maximum stress is found by the Rankine-Gorden formula [5] which is a combination of the Euler and crushing loads for a strut For very short strut is very large, can therefore be neglected and , for very long struts is very small and is very large so that can be neglected. Thus . The Rankine formula is therefore valid for extreme values of slenderness ratios. It is also found to be fairly accurate for the intermediate values. Thus, re –writing the formula in terms of stresses For a strut with one end free and the other fixed and The crushing load on the first arm is The final stress on the first arm is thus the sum of the direct stress calculated by Rankine formula and that due to bending generated by the exerted moment as was explained in figure (3-a and b) From this equation we may find the dimension of the first arm. After knowing the dimension of each arm the weight of each arm may be found and also the total weight of the manipulator structure will be determined. The next step in the analysis is to input those information to the program to began the process of changing the dimension of the cross section to minimize the total error (deflection) at the end of the robot arm this process gives many generations of the dimensions of the arm cross section which satisfies the conditions specified for the maximum and minimum error allowed at the end effecter and also the permissible increase in the weight of the robot structure specified from us, from between all those generation the program select the best generation or probability that gives the lightest weight and the less deformation. The next step in the analysis is to input the new weight of the robot arms to the optimization process for the tri –tube cross section shown in figure(2-b) and trying to find the best dimensions that gives the highest moment of inertia for the cross section so as to minimize the deflection in each arm and also the total deflection of the robot at the end effecter, i.e. the mass of uni –tube section found by the program should be equal to the mass of the tri –tube section which is equal to Where is the density of robot arm metal, is the radius of the two flanges (stiffeners) welded at each end, is the thickness of the flanges and is the distance between the vertices of the equilateral triangle. The optimization problem is defined as follow In the optimization problem the thickness of the tubes and the thickness of the flanges are assumed to be 2mm. The results of the optimization problem showed that the tri –tube section that have the same weight (mass) of a uni –tube may improve the stiffness of the robot and minimize the total deflection in about 33%, this results means that we may construct a robot having tri –tube section which is less in weight from that of uni –tube section and both of them having the same end effecter deformation. Results: In order to verify the analysis of the previous section a run had been done which has the following characteristics for the robot arm , , , , , , ( tube thickness ), (stiffener thickness), (mass of the first gear box), (mass of the second gear box), (manipulated mass). The available gear boxes for the application are given in the list of table 1 The results of the program shows that for the given configuration the minimum weight for the structure of the uni –tube robot is (Wmin=19.986 N), the robot with such structural weight could manipulate the load with out failure because the stress in each arm is less than or equal to the allowable stress, but the deflection of the end point effecter is very large. The iteration process for increasing the dimension of the section to minimize the deflection and letting it be within the range (0.0005< <0.0022) shows that there are 22 generation all of which has a deflection (0.0005< <0.0022) and also a weight (WD , Wtii-tube=Wuni-tube, D� EMBED Equation.3 ���2T Maximize (I), find h,D 1 1 Finding minimum (VAR=Wrobot� EMBED Equation.3 ���) Saving generations If Wrobot>Fac.*Wmin If � EMBED Equation.3 ��� Calculation of: � EMBED Equation.3 ���,� EMBED Equation.3 ���,Wrobt For B1 =B1+0.001 For B2=B2+0.001 For B3=B3+0.001 Calculation of B3, B2, B1 and Wmin=q3*L3+q2*L2+q1*L1 PAGE 25 _1236645461.unknown _1238937592.unknown _1238977271.unknown _1239145252.unknown _1239587407.unknown _1257023452.unknown _1257176484.unknown _1257176901.unknown _1257176255.unknown _1239760023.unknown _1239585709.unknown _1239587255.unknown _1239584024.unknown _1239585314.unknown _1239583099.unknown _1239583266.unknown _1239051691.unknown _1239145002.unknown _1239145193.unknown _1239052851.unknown _1238980484.unknown _1239051232.unknown _1238978590.unknown _1238937862.unknown _1238938031.unknown _1238939508.unknown _1238937938.unknown _1238937717.unknown _1238937778.unknown _1238937650.unknown _1236726162.unknown _1238937241.unknown _1238937500.unknown _1238937518.unknown _1238937313.unknown _1236726579.unknown _1238937087.unknown _1236726483.unknown _1236725767.unknown _1236725952.unknown _1236725998.unknown _1236725854.unknown _1236645729.unknown _1236645868.unknown _1236645559.unknown _1236562568.unknown _1236644217.unknown _1236645198.unknown _1236645359.unknown _1236645100.unknown _1236641265.unknown _1236641354.unknown _1236641126.unknown _1236641014.unknown _1236641072.unknown _1236640860.unknown _1235773038.unknown _1235773823.unknown _1235774657.unknown _1236561856.unknown _1235774271.unknown _1235773440.unknown _1235773735.unknown _1235773154.unknown _1235691626.unknown _1235771993.unknown _1235772700.unknown _1235771805.unknown _1226829966.unknown _1235690633.unknown _1235691262.unknown _1235690109.unknown _1226830001.unknown _1226829657.unknown _1226829939.unknown _1226829543.unknown