16.dvi @ Applied General TopologyUniversidad Polit�ecnica de ValenciaVolume 2, No. 1, 2001pp. 33 - 37 F-points in countably compact spacesA. Bella and V. I. Malykhin�Abstract. Answering a question of A. V. Arhangel0ski��, weshow that any extremally disconnected subspace of a compactspace with countable tightness is discrete.2000 AMS Classi�cation: Primary 54A25; Secondary 54A10Keywords: F-point, extremal disconnectedness, compact, countably com-pact, pseudocompact, countable tightness.1. The resultsIn [1] Arhangel0ski�� noticed that under PFA any extremally disconnectedsubspace of a compact space with countable tightness is discrete. Then, heposed the natural question whether this result holds in ZFC.The aim of this short note is just to provide the full answer to such question.We actually manage to generalize the result by weakening the compactnessassumption.Henceforth, all space are assumed to be Tychono� spaces, unless otherwisespeci�ed.Recall that, for a given topological space X,the tightness at the point x 2 X,denoted by t(x;X), is the smallest cardinal � such that, whenever x 2 A � X,there exists a set B � A satisfying jBj � � and x 2 B.We say that x 2 X is a F-point if there are no disjoint open F�-sets U andV such that x 2 U \ V .It is evident that X is a F-space if and only if each x 2 X is a F-point in X.If Y is a subspace of the space X, we say that Y is countably compact inX provided that every in�nite subset of Y has an accumulation point in X.Of course, a space is countably compact if and only if it is countably compactin itself. If Y is countably compact in X, then Y is pseudocompact but notnecessarily countably compact.The next Lemma is essentially a combination of Theorem 1 in [2] and Propo-sition 3.1 in [3].�Work supported by the research project \Analisi Reale" of the Italian Ministero dell'Uni-versit�a e della Ricerca Scienti�ca e Tecnologica. 34 A. Bella and V. I. MalykhinLemma 1.1. Let X be a space, Y � X and y be a non-isolated point of Y . IfY is countably compact in X and t(y;X) � @0 then y is in the closure of somecountable discrete subspace of Y .Proof. Let A be a countable subset of Y n fyg such that y 2 A and �x afamily U = fUn : n 2 !g of closed neighbourhoods of y in X chosen so thatA \ TU = ?. Let S be the subset of X consisting of all points which are inthe closure of some countable set fzn : n 2 !g where zn 2 Un \ A for each n.Since Y is countably compact in X and y 2 Un \ A for each n, it easily followsthat y 2 S. As t(y;X) � @0, we may select a set fsn : n 2 !g � S so thaty 2 fsn : n 2 !g. Let fzin : n 2 !g be a sequence witnessing that si 2 S andput B = fzhj : 0 � h � j < !g. B is a subset of A which contains each si in itsclosure and so y 2 B. Furthermore, since B \TU = ? and B n Un is �nite forevery n, it follows that B is discrete. �Lemma 1.2. Let x be a F-point of the space X. If x is in the closure of somecountable discrete set N � X, then N [ fxg is homeomorphic to a subspace of�N.Proof. By contradiction, let us assume that there are two disjoint subset A;B �N such that x 2 A \ B. As N is discrete, for each y 2 N there is an openneighbourhood V (y) of y such that V (y) \ N = fyg. Let fai : i 2 !g andfbi : i 2 !g be enumerations of A and B. Let Pi be an open F�-set satisfyingai 2 Pi � V (ai) n SfV (bj) : j � ig and let Qi be an open F�-set satisfyingbi 2 Qi � V (bi) n SfV (aj) : j � ig. But now, letting P = SfPi : i 2 !g andQ = SfQi : i 2 !g, we get disjoint open F�-sets of X satisfying x 2 P \Q { incontrast with the fact that x is a F-point. �A crucial role is played here by the following result, which is a bit more generalversion than the one proved for countably compact spaces in [5], Corollary 4.Lemma 1.3. Let p 2 �N nN. If the subspace N [fpg is countably compact inthe space X, then t(p;X) > @0.Proof. Let us assume that N [ fpg is countably compact in the space X. Ofcourse, we may identify p with the trace in N of the family of all neighbourhoodsof p in X.Suppose �rst that p is a P-point. For any P 2 p, choose a partition ofP consisting of two in�nite sets P 0 and P 00 so that P 0 2 p and let x(P) be anaccumulation point of the set P 00 in X. The regularity of X guarantees that p isin the closure of the set A = fx(P) : P 2 pg � X. If X has countable tightnessat p, then we could �nd fPn : n < !g � p such that p 2 fx(Pn) : n < !g. But,since p is a P-point, there exists a neighbourhood U of p in X such that U \P 00nis �nite for each n < ! and so p =2 fx(Pn) : n < !g { a contradiction.If p is not a P-point, then there is a partition fAn : n < !g of N into in�nitesets such that for every n, An 62 p, and if P 2 p then jP \Anj = ! for in�nitely F-points in countably compact spaces 35many n. Now put T = f [n