Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2612 https://internationalpubls.com Some Results on Partial Cone Metric Spaces with an Application Heeramani Tiwari1,*, Anil Mishra2 , Padmavati3 1,2,3Government V.Y.T. Autonomous P.G. College, Durg, Chhattisgarh, India toravi.tiwari@gmail.com, mshranil@gmail.com, padmavati.sudha62@gmail.com Article History: Received: 12-01-2025 Revised: 15-02-2025 Accepted: 01-03-2025 Abstract: The objective of this paper is to determine some fixed point theorems for generalized 𝛼 βˆ’ πœ“ contractive mappings in the framework of partial cone metric spaces. In addition, we prove a unique fixed point theorem using a rational contractive condition. Our findings align with previous research in this area. We also show that our result can be applied to the problem of determining the existence of solutions to second-order differential equations. Keywords: 𝛼 βˆ’ πœ“ contractive mappings, partial cone metric spaces, Ξ± admissible Mappings. 1. Introduction The Banach contraction principle [1] was a foundation for a development of metric fixed point theory which has been generalized by utilizing various contractive conditions in various contexts. In 1906, Frechet [2] introduced the notion of metric spaces. In 2007, Huang and Zhang [7] introduced the concept of cone metric space which is a generalization of metric space. Another generalization of metric spaces is partial metric spaces which was introduced by Matthews [3, 4] in which the self distance need not be equal to zero and proved the partial metric version of Banach fixed point theorem. Partial cone metric spaces have been investigated by Mahlotra et al. [10] and Sonmez. They proved some fixed point theorems in this space. Recently many papers on cone metric spaces and partial cone metric spaces have been appeared e.g. see . [8, 9, 13, 14, 15, 16, 17, 18]. On the other hand, Samet et al. [5] extended and generalized the Banach contraction principle by introducing a new class of contractive type mappings known as 𝛼 βˆ’ πœ“ contractive type mappings. Karapinar and Samet [6] generalized the 𝛼 βˆ’ πœ“ contractive type mappings and established various fixed point theorems. To begin, we will define partial metric spaces , cone metric spaces, and partial cone metric spaces as well as their properties: Definition 1.1. (Partial metric space) A partial metric on a non-empty set X is a function 𝜌: 𝑋 Γ— 𝑋 β†’ ℝ+ such that for all π‘₯, 𝑦, 𝑧 ∈ 𝑋 the following hold 1. π‘₯ = 𝑦 ⇔ 𝜌(π‘₯, π‘₯) = 𝜌(𝑦, 𝑦) = 𝜌(π‘₯, 𝑦); mailto:toravi.tiwari@gmail.com mailto:mshranil@gmail.com mailto:padmavati.sudha62@gmail.com Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2613 https://internationalpubls.com 2. 𝜌(π‘₯, π‘₯) ≀ 𝜌(π‘₯, 𝑦); 3. 𝜌(π‘₯, 𝑦) = 𝜌(𝑦, π‘₯); 4. 𝜌(π‘₯, 𝑦) ≀ 𝜌(π‘₯, 𝑧) + 𝜌(𝑧, 𝑦) βˆ’ 𝜌(𝑧, 𝑧). For all π‘₯, 𝑦, 𝑧 ∈ 𝑋. Then the pair (X, ρ) is called a partial metric space. It is clear that if ρ(x, y) = 0, then (1) and (2) imply that x = y. But if x = y, ρ(x, y) may not be 0. A basic example of partial metric space is the pair (ℝ+, 𝜌) where 𝜌(π‘₯, 𝑦) = π‘šπ‘Žπ‘₯{π‘₯, 𝑦} for all π‘₯, 𝑦 ∈ ℝ+. Let E be a real Banach space and P a subset of E. P is called a cone if it satisfies the following. (1) P is closed, non-empty, and 𝑃 β‰  0, (2) π‘Žπ‘₯ + 𝑏𝑦 ∈ 𝑃 for all π‘₯, 𝑦 ∈ 𝑃 and non-negative real numbers π‘Ž, 𝑏 ∈ ℝ, (3) 𝑃 ∩ (βˆ’π‘ƒ ) = {0}. For a specified cone 𝑃 βŠ‚ 𝐸, we can establish a partial ordering ≀ on E in relation to P by defining π‘₯ ≀ 𝑦 if and only if 𝑦 βˆ’ π‘₯ ∈ 𝑃 . The notation π‘₯ < 𝑦 is used to signify that π‘₯ ≀ 𝑦 and π‘₯ β‰  𝑦, while π‘₯ β‰ͺ 𝑦 indicates that 𝑦 βˆ’ π‘₯ ∈ 𝑖𝑛𝑑𝑃 , with 𝑖𝑛𝑑𝑃 representing the interior of P . The cone P is termed normal if there exists a constant K > 0 such that for all x, y ∈ E where 0 ≀ x ≀ y, it follows that ||x|| ≀ K||y||. The smallest positive value that satisfies this condition is referred to as the normal constant of P. Let E be a Banach space, P a cone in E with 𝑖𝑛𝑑𝑃 β‰  πœ™ and ≀ is partial ordering with respect to P. Definition 1.2 (Cone metric space) Let X be a non empty set. The mapping 𝑑𝑐 ∢ 𝑋 Γ— 𝑋 β†’ 𝐸 is said to be a cone metric on X if for all π‘₯, 𝑦, 𝑧 ∈ 𝑋. The followings hold: (1) 0 ≀ 𝑑𝑐(π‘₯, 𝑦) and 𝑑𝑐(π‘₯, 𝑦) = 0 if and only if π‘₯ = 𝑦, (2) 𝑑𝑐(π‘₯, 𝑦) = 𝑑𝑐(𝑦, π‘₯), (3) 𝑑𝑐(π‘₯, 𝑦) ≀ 𝑑𝑐(π‘₯, 𝑧) + 𝑑𝑐(𝑦, 𝑧). and (X, dc) is called a cone metric space. Mahlotra et al. [10] and Sonmez [11] introduced the notion of partial cone metric space and its topological characterization. We now state the definition of partial cone metric space. Definition 1.3 (Partial cone metric space) A partial cone metric on a non-empty set X is a function πœŒπ‘: 𝑋 Γ— 𝑋 β†’ 𝐸 such that for all π‘₯, 𝑦, 𝑧 ∈ 𝑋 (1) 0 ≀ πœŒπ‘(π‘₯, π‘₯) ≀ πœŒπ‘(π‘₯, 𝑦), (2) π‘₯ = 𝑦 if and only if πœŒπ‘(π‘₯, π‘₯) = πœŒπ‘(π‘₯, 𝑦) = πœŒπ‘(𝑦, 𝑦), Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2614 https://internationalpubls.com (3) πœŒπ‘(π‘₯, 𝑦) = πœŒπ‘(𝑦, π‘₯), (4) πœŒπ‘(π‘₯, 𝑦) ≀ πœŒπ‘(π‘₯, 𝑧) + πœŒπ‘(𝑧, 𝑦) βˆ’ πœŒπ‘(𝑧, 𝑧). A partial cone metric space is a pair (𝑋, πœŒπ‘) such that X is a non-empty set and πœŒπ‘ is a partial cone metric on X . It is clear that, if πœŒπ‘(π‘₯, 𝑦) = 0, then (1) and (2) imply that x = y. But the converse is not true in general. A cone metric space is a partial cone metric space, but there exist partial cone metric spaces which are not cone metric spaces. we give the following example from [11] Example 1.4 Consider a Banach space 𝐸 = ℝ2, 𝑃 = {(π‘₯, 𝑦) ∈ 𝐸 ∢ π‘₯, 𝑦 β‰₯ 0} and 𝑋 = ℝ+ and πœŒπ‘ ∢ 𝑋 Γ— 𝑋 β†’ 𝐸 defined 𝑏𝑦 πœŒπ‘(π‘₯, 𝑦) = (π‘šπ‘Žπ‘₯{π‘₯, 𝑦}, π‘˜π‘šπ‘Žπ‘₯{π‘₯, 𝑦}) where π‘˜ β‰₯ 0 is a constant. Then (𝑋, πœŒπ‘) is a partial cone metric space which is not a cone metric space. Remark 1.5 Suppose (𝑋, πœŒπ‘) is a partial cone metric space, then 𝑑𝑐(π‘₯, 𝑦) = 2πœŒπ‘(π‘₯, 𝑦) – πœŒπ‘(π‘₯, π‘₯) – πœŒπ‘(𝑦, 𝑦) For all π‘₯, 𝑦, 𝑧 ∈ 𝑋 defines a cone metric on X. Theorem1.6 Every partial cone metric space (𝑋, πœŒπ‘) is a topological space. Following, We give some properties of partial cone metric spaces, for more details see [11]. Definition 1.7 Let (𝑋, πœŒπ‘) be a partial cone metric space. Let {π‘₯𝑛} be a sequence in X and π‘₯ ∈ 𝑋 (1) {π‘₯𝑛} is said to be convergent to x and x is called a limit of {π‘₯𝑛} if lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, π‘₯) = lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, π‘₯𝑛) = πœŒπ‘(π‘₯, π‘₯) (2) {π‘₯𝑛} is Cauchy sequence if there is π‘₯ ∈ 𝑃 such that for every Ο΅ > 0 there is β„• such that for all 𝑛, π‘š > β„•, ||πœŒπ‘(π‘₯𝑛, π‘₯π‘š) βˆ’ π‘₯|| < πœ–. (3) (𝑋, πœŒπ‘) is said to be complete if every Cauchy sequence in (𝑋, πœŒπ‘) is convergent in (𝑋, πœŒπ‘). In 2012, Samet et al. [5] introduced Ξ±-admissible mapping as follows: Definition 1.8 [5] Let 𝑇 ∢ 𝑋 β†’ 𝑋 and 𝛼 ∢ 𝑋 Γ— 𝑋 β†’ [0, ∞). T is said to Ξ±-admissible if 𝛼(π‘₯, 𝑦) β‰₯ 1 β‡’ 𝛼(𝑇 π‘₯, 𝑇 𝑦) β‰₯ 1 for all π‘₯, 𝑦 ∈ 𝑋. Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2615 https://internationalpubls.com 2. Main Results [12] Let 𝛹 be the family of non-decreasing function πœ“ ∢ [0, ∞) β†’ [0, ∞) such that βˆ‘ πœ“π‘›(𝑑) <∞ 𝑛=1 ∞ for each 𝑑 > 0 where πœ“π‘› is nth iterate of ψ. Lemma 2.1 [12] For every function πœ“ ∢ [0, ∞) β†’ [0, ∞) the following holds: If ψ is non decreasing, then for each 𝑑 > 0, lim π‘›β†’βˆž πœ“π‘›(𝑑) = 0 implies πœ“(𝑑) < 𝑑 and πœ“(0) = 0. Definition 2.2 Let (𝑋, πœŒπ‘) be a partial cone metric space P is a normal cone with constant K. Let 𝑇 ∢ 𝑋 β†’ 𝑋 be a self mapping. Then T is said to be generalized 𝛼 βˆ’ πœ“ contractive mapping if there exists two functions 𝛼 ∢ 𝑋 Γ— 𝑋 β†’ [0, ∞) and πœ“ ∈ 𝛹 for all π‘₯, 𝑦 ∈ 𝑋 we have 𝛼(π‘₯, 𝑦)πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦) ≀ πœ“(𝑀 (π‘₯, 𝑦)) (2.1) where 𝑀 (π‘₯, 𝑦) = π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯, 𝑦), πœŒπ‘(π‘₯, 𝑇 π‘₯), πœŒπ‘(𝑦, 𝑇 𝑦)} (2.2) Theorem 2.3 Let (𝑋, πœŒπ‘ ) be a complete partial cone metric space and 𝑇 ∢ 𝑋 β†’ 𝑋 be self mapping. Suppose 𝛼 ∢ 𝑋 Γ— 𝑋 β†’ [0, ∞) be the mappings satisfying the conditions: (i) T is Ξ± admissible; (ii) T is generalized 𝛼 βˆ’ πœ“ contractive mapping; (iii) there exists π‘₯0 ∈ 𝑋 such that 𝛼(π‘₯0, 𝑇 π‘₯0) β‰₯ 1; (iv) T is continuous or if {π‘₯𝑛} be a sequence in X such that 𝛼(π‘₯𝑛, π‘₯𝑛+1) β‰₯ 1 for all n and π‘₯𝑛 β†’ π‘₯ as 𝑛 β†’ ∞ then 𝛼(π‘₯𝑛, π‘₯) β‰₯ 1 for all n. Then T has a fixed point in X. Proof: Let π‘₯0 be an arbitrary point such that 𝛼(π‘₯0, 𝑇 π‘₯0) β‰₯ 1. Suppose we have a sequence {π‘₯𝑛} in X such that π‘₯𝑛+1 = 𝑇 π‘₯𝑛 for all 𝑛 ∈ β„•. If π‘₯𝑛 = π‘₯𝑛+1 for some 𝑛 ∈ β„•, then π‘₯𝑛 is a fixed point of T and the existence part of the proof is finished. Suppose π‘₯𝑛 β‰  π‘₯𝑛+1for every 𝑛 ∈ β„• Now, since T is Ξ±-admissible, so 𝛼(𝑇 π‘₯0, 𝑇 π‘₯1) = 𝛼(π‘₯1, π‘₯2) β‰₯ 1 𝛼(𝑇 π‘₯1, 𝑇 π‘₯2) = 𝛼(π‘₯2, π‘₯3) β‰₯ 1 and using induction we have 𝛼(π‘₯𝑛, π‘₯𝑛+1) β‰₯ 1 for all 𝑛 ∈ β„•. Now, from (2.1) we have πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) = πœŒπ‘(𝑇 π‘₯π‘›βˆ’1, 𝑇 π‘₯𝑛) (2.3) ≀ 𝛼(π‘₯π‘›βˆ’1, π‘₯𝑛)πœŒπ‘(𝑇 π‘₯π‘›βˆ’1, 𝑇 π‘₯𝑛) ≀ πœ“(𝑀 (π‘₯π‘›βˆ’1, π‘₯𝑛)) (2.4) where 𝑀 (π‘₯π‘›βˆ’1, π‘₯𝑛) = π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛), πœŒπ‘(π‘₯π‘›βˆ’1, 𝑇 π‘₯π‘›βˆ’1), πœŒπ‘(π‘₯𝑛, 𝑇 π‘₯𝑛)} Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2616 https://internationalpubls.com = π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛), πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛), πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1)} (2.5) Now, if πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) > πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛). Then ||πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1))|| ≀ πœ“(||πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1))||) < ||πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1))|| (2.6) This is a contradiction. Thus for all 𝑛 β‰₯ 1 we have π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛), πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1)} = πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) (2.7) πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1)) ≀ πœ“(πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛)) (2.8) Continuing this process inductively, we obtain πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1)) ≀ πœ“π‘› (πœŒπ‘(π‘₯0, π‘₯1)) (2.9) Now for π‘š > 𝑛, using (2.9) and triangular inequality , we obtain πœŒπ‘(π‘₯π‘š, π‘₯𝑛) ≀ πœŒπ‘(π‘₯π‘š, π‘₯π‘šβˆ’1) + πœŒπ‘(π‘₯π‘šβˆ’1, π‘₯π‘šβˆ’2). . . . . . . . πœŒπ‘(π‘₯𝑛+1, π‘₯𝑛) – βˆ‘ πœŒπ‘(π‘₯π‘šβˆ’π‘˜, π‘₯π‘šβˆ’π‘˜) π‘šβˆ’π‘›βˆ’1 π‘˜=1 ≀ πœŒπ‘(π‘₯π‘š , π‘₯π‘šβˆ’1) + πœŒπ‘(π‘₯π‘šβˆ’1, π‘₯π‘šβˆ’2). . . . . . . . πœŒπ‘(π‘₯𝑛+1, π‘₯𝑛) ≀ (πœ“π‘šβˆ’1 + πœ“π‘šβˆ’2 + . . . . . . . πœ“π‘›)πœŒπ‘(π‘₯0, π‘₯1) = πœ“π‘› 1βˆ’πœ“ πœŒπ‘(π‘₯0, π‘₯1) (2.10) Since P is normal cone with normal constant K, we find that ||πœŒπ‘(π‘₯π‘š, π‘₯𝑛))|| ≀ 𝐾|| πœ“π‘› 1βˆ’πœ“ πœŒπ‘(π‘₯0, π‘₯1)|| (2.11) Which implies that πœŒπ‘(π‘₯π‘š, π‘₯𝑛) β†’ 0 as 𝑛, π‘š β†’ ∞. Hence {π‘₯𝑛} a Cauchy sequence in partial cone metric space which is complete hence it must be convergent in X, let lim π‘›β†’βˆž π‘₯𝑛 = 𝑧 therefore πœŒπ‘(𝑧, 𝑧) = lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, 𝑧) = lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, π‘₯𝑛) = 0 Case 1. T is continuous, then we have π‘₯𝑛+1 = 𝑇 π‘₯𝑛 β†’ 𝑇 𝑧 as 𝑛 β†’ ∞. By uniqueness of limit 𝑇 𝑧 = 𝑧. Hence z is a fixed point of T . Case 2 If {π‘₯𝑛} is a sequence in X such that 𝛼(π‘₯𝑛, π‘₯𝑛+1) β‰₯ 1 for all n and π‘₯𝑛 β†’ 𝑧 as 𝑛 β†’ ∞. Then 𝛼(π‘₯𝑛, 𝑧) β‰₯ 1 for all n. Now we show that ||πœŒπ‘(𝑇 𝑧, 𝑧)|| β‰₯ 0, On contrary, assume ||πœŒπ‘(𝑇 𝑧, 𝑧)|| > 0 we have πœŒπ‘(𝑇 𝑧, 𝑧) ≀ πœŒπ‘(𝑇 𝑧, 𝑇 π‘₯𝑛) + πœŒπ‘(𝑇 π‘₯𝑛, 𝑧) – πœŒπ‘(𝑇 π‘₯𝑛, 𝑇 π‘₯𝑛) ≀ 𝛼(π‘₯𝑛, 𝑧)πœŒπ‘(𝑇 𝑧, 𝑇 π‘₯𝑛) + πœŒπ‘(𝑇 π‘₯𝑛, 𝑧) – πœŒπ‘(𝑇 π‘₯𝑛, 𝑇 π‘₯𝑛) ≀ πœ“(𝑀 (π‘₯𝑛, 𝑧)) + πœŒπ‘(π‘₯𝑛+1, 𝑧) (2.12) Since P is normal cone with normal constant K, we have ||πœŒπ‘(𝑇 𝑧, 𝑧)|| ≀ 𝐾||πœ“(𝑀 (π‘₯𝑛, 𝑧)) + πœŒπ‘(π‘₯𝑛+1, 𝑧)|| (2.13) Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2617 https://internationalpubls.com where 𝑀 (π‘₯𝑛 , 𝑧) = π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯𝑛, 𝑧), πœŒπ‘(π‘₯𝑛, 𝑇 π‘₯𝑛), πœŒπ‘(𝑧, 𝑇 𝑧)} = π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯𝑛, 𝑧), πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1), πœŒπ‘(𝑧, 𝑇 𝑧)} (2.14) Taking 𝑛 β†’ ∞ we get 𝑀 (π‘₯𝑛, 𝑧) = πœŒπ‘(𝑧, 𝑇 𝑧) (2.15) Now, Taking 𝑛 β†’ ∞ in (2.12) we get that ||πœŒπ‘(𝑇 𝑧, 𝑧)|| ≀ 𝐾||πœ“(πœŒπ‘(𝑧, 𝑇 𝑧)||≀ 𝐾||πœŒπ‘(𝑧, 𝑇 𝑧)|| (2.16) which is not true for all 𝐾 > 0. So we get a contradiction. π‘‡β„Žπ‘’π‘Ÿπ‘’π‘“π‘œπ‘Ÿπ‘’ ||πœŒπ‘(𝑇 𝑧, 𝑧)|| β†’ 0 as 𝑛 β†’ ∞. It implies that 𝑇 𝑧 = 𝑧 and hence z is a fixed point of T .This completes the proof. Example 2.4 𝐿𝑒𝑑 𝑋 = [0, ∞) and πœŒπ‘(π‘₯, 𝑦) = (π‘šπ‘Žπ‘₯{π‘₯, 𝑦}, π‘˜ π‘šπ‘Žπ‘₯{π‘₯, 𝑦}). Then (𝑋, πœŒπ‘) is a complete partial cone metric space. Consider the mapping 𝑇 ∢ 𝑋 β†’ 𝑋defined by 𝑇(π‘₯) = { π‘₯ – 2 3 π‘₯ > 1 π‘₯ 3 0 ≀ π‘₯ ≀ 1 (2.17) and let πœ“ ∢ [0, ∞) β†’ [0, ∞) be such that πœ“(𝑑) = 𝑑 2 for all 𝑑 β‰₯ 0. If we define the functions 𝛼, 𝛽 ∢ 𝑋 Γ— 𝑋 β†’ [0, ∞) as 𝛼(π‘₯, 𝑦) = { 3 2 π‘₯, 𝑦 ∈ [0,1] 0 π‘œπ‘‘β„Žπ‘’π‘Ÿπ‘€π‘–π‘ π‘’ (2.18) We show that contractive condition of Theorem 2.3 is satisfied. Without loss of generality we assume that π‘₯ β‰₯ 𝑦. Then for π‘₯, 𝑦 ∈ [0, 1] we get 𝛼(π‘₯, 𝑦)πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦) = 𝛼(π‘₯, 𝑦)πœŒπ‘ ( π‘₯ 3 , 𝑦 3 ) = 3 2 ( π‘₯ 3 , π‘˜π‘₯ 3 ) = 1 4 (π‘₯, π‘˜π‘₯) ≀ 1 2 (π‘₯, π‘˜π‘₯) = 1 2 π‘šπ‘Žπ‘₯{(π‘₯, π‘˜π‘₯), (π‘₯, π‘˜π‘₯), (𝑦, π‘˜π‘¦)} = 1 2 π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯, 𝑦), πœŒπ‘(π‘₯, 𝑇 π‘₯), πœŒπ‘(𝑦, 𝑇 𝑦)} = πœ“(π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯, 𝑦), πœŒπ‘(π‘₯, 𝑇 π‘₯), πœŒπ‘(𝑦, 𝑇 𝑦)}) (2.19) Theorem 2.5 Let (𝑋, πœŒπ‘) be a complete partial cone metric space P is a normal cone with constant K. Suppose the mapping 𝑇 ∢ 𝑋 β†’ 𝑋 satisfies the contractive condition Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2618 https://internationalpubls.com πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦)) ≀ π‘Ž1 πœŒπ‘(π‘₯, 𝑦) + π‘Ž2 πœŒπ‘(π‘₯,𝑇 π‘₯)πœŒπ‘(𝑦,𝑇 𝑦) πœŒπ‘(π‘₯,𝑦)+ πœŒπ‘(𝑦,𝑇 π‘₯)+ πœŒπ‘(π‘₯,𝑇 𝑦) + π‘Ž3 πœŒπ‘(𝑦,𝑇 𝑦) πœŒπ‘(π‘₯,𝑇 π‘₯) πœŒπ‘(π‘₯,𝑦) + π‘Ž4 πœŒπ‘(π‘₯, 𝑇 𝑦) + π‘Ž5 πœŒπ‘(𝑦, 𝑇 π‘₯) (2.20) where π‘Ž1, π‘Ž2, π‘Ž3, π‘Ž4, π‘Ž5 β‰₯ 0 are constants such that π‘Ž1 + π‘Ž2 + π‘Ž3 + 2π‘Ž4 + π‘Ž5 < 1. Then T has a unique fixed point in X. Proof Choose π‘₯0 ∈ 𝑋 such that 𝑇 π‘₯0 = π‘₯1, 𝑇 π‘₯1 = 𝑇2π‘₯0 = π‘₯2. . . π‘₯𝑛 = 𝑇 π‘₯π‘›βˆ’1 = 𝑇𝑛π‘₯0. Then πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) = πœŒπ‘(𝑇 π‘₯π‘›βˆ’1, 𝑇 π‘₯𝑛) ≀ π‘Ž1 πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž2 πœŒπ‘(π‘₯π‘›βˆ’1,𝑇 π‘₯π‘›βˆ’1)πœŒπ‘(π‘₯𝑛,𝑇 π‘₯𝑛) πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛)+ πœŒπ‘(π‘₯𝑛,𝑇 π‘₯π‘›βˆ’1) + πœŒπ‘(π‘₯π‘›βˆ’1,𝑇 π‘₯𝑛) + π‘Ž3 πœŒπ‘(π‘₯𝑛,𝑇 π‘₯𝑛)πœŒπ‘(π‘₯π‘›βˆ’1,𝑇 π‘₯π‘›βˆ’1) πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛) + π‘Ž4πœŒπ‘(π‘₯π‘›βˆ’1, 𝑇 π‘₯𝑛) + π‘Ž5πœŒπ‘(π‘₯𝑛, 𝑇 π‘₯π‘›βˆ’1) ≀ π‘Ž1 πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž2 πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛)πœŒπ‘(π‘₯𝑛,π‘₯𝑛+1) πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛)+ πœŒπ‘(π‘₯𝑛,π‘₯𝑛) + πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛+1) + π‘Ž3 πœŒπ‘(π‘₯𝑛,π‘₯𝑛+1)πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛) πœŒπ‘(π‘₯π‘›βˆ’1,π‘₯𝑛) + π‘Ž4πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛+1) + π‘Ž5πœŒπ‘(π‘₯𝑛, π‘₯𝑛) ≀ π‘Ž1πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž2πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž3πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) + π‘Ž4πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛+1) + π‘Ž5πœŒπ‘(π‘₯𝑛, π‘₯𝑛) ≀ π‘Ž1πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž2πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž3πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) + π‘Ž4πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + π‘Ž4πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) βˆ’ π‘Ž4πœŒπ‘(π‘₯𝑛, π‘₯𝑛) + π‘Ž5πœŒπ‘(π‘₯𝑛, π‘₯𝑛) = (π‘Ž1 + π‘Ž2 + π‘Ž4)πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + (π‘Ž3 + π‘Ž4)πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) + (π‘Ž5 – π‘Ž4)πœŒπ‘(π‘₯𝑛, π‘₯𝑛) = (π‘Ž1 + π‘Ž2 + π‘Ž4)πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) + (π‘Ž3 + π‘Ž4 + π‘Ž5)πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) ≀ (π‘Ž1 + π‘Ž2 + π‘Ž4) 1 βˆ’ (π‘Ž3 + π‘Ž4 + π‘Ž5) πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) (2.21) 𝐿𝑒𝑑 πœ† = (π‘Ž1 + π‘Ž2 + π‘Ž4) 1 βˆ’ (π‘Ž3 + π‘Ž4 + π‘Ž5) Since π‘Ž1 + π‘Ž2 + π‘Ž3 + 2π‘Ž4 + π‘Ž5 < 1 and π‘Ž3 + π‘Ž4 + π‘Ž5 < 1 implies that πœ† < 1. Hence πœŒπ‘(π‘₯𝑛, π‘₯𝑛+1) ≀ πœ†πœŒπ‘(π‘₯π‘›βˆ’1, π‘₯𝑛) (2.22) for all 𝑛 ∈ β„•. For any π‘š > 𝑛 where π‘š, 𝑛 ∈ β„• we have πœŒπ‘(π‘₯π‘š, π‘₯𝑛) ≀ πœŒπ‘(π‘₯π‘š, π‘₯π‘šβˆ’1) + πœŒπ‘(π‘₯π‘šβˆ’1, π‘₯π‘šβˆ’2). . . . . . . . πœŒπ‘(π‘₯𝑛+1, π‘₯𝑛) βˆ’ βˆ‘ πœŒπ‘(π‘₯π‘šβˆ’π‘˜, π‘₯π‘šβˆ’π‘˜) π‘šβˆ’π‘›βˆ’1 π‘˜ ≀ πœŒπ‘(π‘₯π‘š, π‘₯π‘šβˆ’1) + πœŒπ‘(π‘₯π‘šβˆ’1, π‘₯π‘šβˆ’2). . . . . . . . πœŒπ‘ (π‘₯𝑛+1, π‘₯𝑛) ≀ (πœ†π‘šβˆ’1 + πœ†π‘šβˆ’1 + . . . . . . . πœ†π‘›)πœŒπ‘(π‘₯0, π‘₯1) = πœ†π‘› 1 βˆ’ πœ† πœŒπ‘(π‘₯0, π‘₯1) (2.23) Since P is normal cone with normal constant K, we have Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2619 https://internationalpubls.com ||πœŒπ‘(π‘₯π‘š, π‘₯𝑛))|| ≀ 𝐾|| πœ†π‘› 1 βˆ’ πœ† πœŒπ‘(π‘₯0, π‘₯1)|| (2.24) Now since πœ† < 1, ||πœŒπ‘(π‘₯π‘š, π‘₯𝑛))|| ≀ 𝐾|| πœ†π‘› 1βˆ’πœ† πœŒπ‘(π‘₯0, π‘₯1)|| β†’ 0 as 𝑛 β†’ ∞ Hence {π‘₯𝑛} is a Cauchy sequence in a partial cone metric space which is complete hence it must be convergent in X, let lim π‘›β†’βˆž π‘₯𝑛 = 𝑧 therefore πœŒπ‘(𝑧, 𝑧) = lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, 𝑧) = lim π‘›β†’βˆž πœŒπ‘(π‘₯𝑛, π‘₯𝑛) = 0 Now we show that ||πœŒπ‘(𝑇 𝑧, 𝑧)|| β‰₯ 0, On contrary, assume ||πœŒπ‘(𝑇 𝑧, 𝑧)|| > 0 we have πœŒπ‘(𝑇 𝑧, 𝑧) ≀ πœŒπ‘(𝑇 𝑧, 𝑇 π‘₯𝑛) + πœŒπ‘(𝑇 π‘₯𝑛 , 𝑧) – πœŒπ‘(𝑇 π‘₯𝑛, 𝑇 π‘₯𝑛) β‰€π‘Ž1πœŒπ‘(𝑧, π‘₯𝑛) + π‘Ž2 πœŒπ‘(𝑧,𝑇 𝑧)πœŒπ‘(π‘₯𝑛,𝑇 π‘₯𝑛) πœŒπ‘(𝑧,π‘₯𝑛)+ πœŒπ‘(π‘₯𝑛,𝑇 𝑧)+ πœŒπ‘(𝑧,𝑇 π‘₯𝑛) + π‘Ž3 πœŒπ‘(π‘₯𝑛,𝑇 π‘₯𝑛)πœŒπ‘(𝑧,𝑇 𝑧) πœŒπ‘(𝑧,π‘₯𝑛) +π‘Ž4πœŒπ‘(𝑧, 𝑇 π‘₯𝑛) + π‘Ž5πœŒπ‘(π‘₯𝑛, 𝑇 𝑧) + πœŒπ‘(𝑇 π‘₯𝑛 , 𝑧) – πœŒπ‘(𝑇 π‘₯𝑛, 𝑇 π‘₯𝑛) β‰€π‘Ž1πœŒπ‘(𝑧, π‘₯𝑛) + π‘Ž2 πœŒπ‘(𝑧,𝑇 𝑧)πœŒπ‘(π‘₯𝑛,π‘₯𝑛+1) πœŒπ‘(𝑧,π‘₯𝑛)+ πœŒπ‘(π‘₯𝑛,𝑇 𝑧)+ πœŒπ‘(𝑧,π‘₯𝑛+1) + π‘Ž3 πœŒπ‘(π‘₯𝑛,π‘₯𝑛+1)πœŒπ‘(𝑧,𝑇 𝑧) πœŒπ‘(𝑧,π‘₯𝑛) +π‘Ž4πœŒπ‘(𝑧, 𝑇 π‘₯𝑛) + π‘Ž5πœŒπ‘(π‘₯𝑛, 𝑇 𝑧) + πœŒπ‘( π‘₯𝑛+1, 𝑧) ≀ π‘Ž1πœŒπ‘(𝑧, π‘₯𝑛) + +π‘Ž4πœŒπ‘(𝑧, π‘₯𝑛+1) + π‘Ž5πœŒπ‘(π‘₯𝑛, 𝑇 𝑧) + πœŒπ‘(π‘₯𝑛+1, 𝑧) ≀ π‘Ž1πœŒπ‘(𝑧, π‘₯𝑛) + +π‘Ž4 πœŒπ‘(𝑧, π‘₯𝑛+1) + π‘Ž5πœŒπ‘(𝑇 𝑧, 𝑧) + π‘Ž5πœŒπ‘(𝑧, π‘₯𝑛) – π‘Ž5πœŒπ‘(𝑧, 𝑧) + πœŒπ‘(π‘₯𝑛+1, 𝑧) ≀ (π‘Ž1 + π‘Ž5)πœŒπ‘(𝑧, π‘₯𝑛) + +[π‘Ž4πœŒπ‘(π‘₯𝑛+1, 𝑧) + πœŒπ‘(π‘₯𝑛+1, 𝑧)] + π‘Ž5πœŒπ‘(𝑇 𝑧, 𝑧) (2.25) So using (2.25) we have πœŒπ‘(𝑇 𝑧, 𝑧) ≀ (π‘Ž1 + π‘Ž5) 1 – π‘Ž5 πœŒπ‘(𝑧, π‘₯𝑛) + π‘Ž4 1 – π‘Ž5 πœŒπ‘(π‘₯𝑛+1, 𝑧) + 1 1 – π‘Ž5 πœŒπ‘(π‘₯𝑛+1, 𝑧) (2.26) Hence ||πœŒπ‘(𝑇 𝑧, 𝑧)|| ≀ (π‘Ž1 + π‘Ž5) 1 – π‘Ž5 𝐾||πœŒπ‘(𝑧, π‘₯𝑛)|| + π‘Ž4 1 – π‘Ž5 𝐾||πœŒπ‘(π‘₯𝑛+1, 𝑧)|| + 1 1 – π‘Ž5 𝐾||πœŒπ‘(π‘₯𝑛+1, 𝑧)|| β†’ 0 (2.27) So we have ||πœŒπ‘(𝑇 𝑧, 𝑧)|| = 0 therefore πœŒπ‘(𝑇 𝑧, 𝑧) = 0 or T z = z. Uniqueness If 𝑧1 is s another Fixed Point of T , Then 𝑇 𝑧1 = 𝑧1 replacing x by z and y by 𝑧1 in (2.1) we get πœŒπ‘(𝑧, 𝑧1) = πœŒπ‘(𝑇 𝑧, 𝑇 𝑧1) ≀ π‘Ž1πœŒπ‘(𝑧, 𝑧1) + π‘Ž2 πœŒπ‘(𝑧, 𝑇 𝑧)πœŒπ‘(𝑧1, 𝑇 𝑧1) πœŒπ‘(𝑧, 𝑧1) + πœŒπ‘(𝑧1, 𝑇 𝑧) + πœŒπ‘(𝑧, 𝑇 𝑧1) + π‘Ž3 πœŒπ‘(𝑧1, 𝑇 𝑧1)πœŒπ‘(𝑧, 𝑇 𝑧) πœŒπ‘(𝑧, 𝑧1) + π‘Ž4πœŒπ‘(𝑧, 𝑇 𝑧1) + π‘Ž5πœŒπ‘(𝑧1, 𝑇 𝑧) Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2620 https://internationalpubls.com ≀ π‘Ž1πœŒπ‘(𝑧, 𝑧1) + π‘Ž2 πœŒπ‘(𝑧,𝑧)πœŒπ‘(𝑧1,𝑧1) πœŒπ‘(𝑧,𝑧1) + πœŒπ‘(𝑧1,𝑧) + πœŒπ‘(𝑧,𝑧1) + π‘Ž3 πœŒπ‘(𝑧1,𝑧1)πœŒπ‘(𝑧,𝑧) πœŒπ‘(𝑧,𝑧1) + π‘Ž4πœŒπ‘(𝑧, 𝑧1) + π‘Ž5πœŒπ‘(𝑧1, 𝑧) (2.28) Therefore πœŒπ‘(𝑧, 𝑧1) = 0 or 𝑧 = 𝑧1 . 3. Application This section is influenced by the findings presented in the papers [19, 20] which aims to offer an application of Theorem 2.3 to the solution of second order differential equation of the form π‘₯β€²β€²(𝑑) = βˆ’π‘“ (𝑑, π‘₯(𝑑)), 𝑑 ∈ 𝐼 π‘₯(0) = π‘₯(1) = 0 (3.1) π‘€β„Žπ‘’π‘Ÿπ‘’ 𝐼 = [0, 1], 𝑓 ∢ 𝐼 Γ— ℝ β†’ ℝ is a continuous function.Consider the space X = C(I) of continuous function defined on I. It is well-known that the Problem (3.1) is equivalent to the integral equation π‘₯(𝑑) = ∫ 𝑔(𝑑, 𝑠)𝑓 (𝑠, π‘₯(𝑠)) 𝑑𝑠 1 0 (3.2) for all 𝑑 ∈ [0, 1] where g is the Green function defined by 𝑔(𝑑, 𝑠) = { (1 βˆ’ 𝑠)𝑑 0 ≀ t ≀ s ≀ 1 (1 βˆ’ 𝑑)𝑠 0 ≀ s ≀ t ≀ 1 (3.3) Then solving problem (3.1) is equivalent to finding fixed point of T in C(I). Theorem 3.1 Let 𝑋 = 𝐢(𝐼) and 𝑇 ∢ 𝑋 β†’ 𝑋 be an operator given by 𝑇 π‘₯(𝑑) = ∫ 𝑔(𝑑, 𝑠)𝑓 (𝑠, π‘₯(𝑠)) 𝑑𝑠 1 0 (3.4) for all π‘₯ ∈ 𝑋 and 𝑑 ∈ 𝐼 = [0, 1]. Suppose the following conditions hold: (i) For all 𝑑 ∈ 𝐼, for all π‘Ž, 𝑏 ∈ ℝ π‘€π‘–π‘‘β„Ž ||π‘Ž||, ||𝑏|| ≀ 1, we have |𝑓 (𝑑, π‘Ž) βˆ’ 𝑓 (𝑑, 𝑏)| ≀ 8πœ‡(|π‘Ž βˆ’ 𝑏|) (3.5) (ii) there exists π‘₯0 ∈ 𝐢(𝐼) such that ||π‘₯0|| ∞ ≀ 1, (iii) for all π‘₯ ∈ 𝐢(𝐼) |π‘₯||∞ ≀ 1 β†’ || ∫ 𝑔(𝑑, 𝑠)𝑓 (𝑠, π‘₯(𝑠))𝑑𝑠|| 1 0 ∞ ≀ 1 ( 3.6) Then the second order differential equation (3.1) has a solution. Proof Consider C(I) endowed with the partial metric given by πœŒπ‘(π‘₯, 𝑦) = { ||π‘₯ βˆ’ 𝑦|| ∞ ||π‘₯|| ≀ 1, ||𝑦|| ≀ 1 ||π‘₯ βˆ’ 𝑦|| ∞ + 𝜏 π‘œπ‘‘β„Žπ‘’π‘Ÿπ‘€π‘–π‘ π‘’ (3.7) where 𝜏 > 0. Then (𝐢(𝐼), πœŒπ‘) is a partial metric space. Now we define partial cone metric as Communications on Applied Nonlinear Analysis ISSN: 1074-133X Vol 32 No. 10s (2025) 2621 https://internationalpubls.com πœŒπ‘(π‘₯, 𝑦) = (πœŒπ‘(π‘₯, 𝑦), π›½πœŒπ‘(π‘₯, 𝑦)) (3.8) where 𝛽 β‰₯ 0. Now, let π‘₯, 𝑦 ∈ 𝐢(𝐼) such that ||π‘₯|| ≀ 1, ||𝑦|| ≀ 1, then we have πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦) = (||𝑇 π‘₯ βˆ’ 𝑇 𝑦|| ∞ , 𝛽||𝑇 π‘₯ βˆ’ 𝑇 𝑦|| ∞ ) = ( sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠)|𝑓 (𝑠, π‘₯(𝑠)) βˆ’ 𝑓 (𝑠, 𝑦(𝑠))|𝑑𝑠 1 0 , 𝛽 sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠)|𝑓 (𝑠, π‘₯(𝑠)) βˆ’ 𝑓 (𝑠, 𝑦(𝑠))|𝑑𝑠 1 0 ) = ( sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠)8 πœ‡|π‘₯(𝑠) βˆ’ 𝑦(𝑠)|𝑑𝑠 1 0 , 𝛽 sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠)8 πœ‡|π‘₯(𝑠) βˆ’ 𝑦(𝑠)|𝑑𝑠 1 0 ) = ( sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠) Γ— (8 πœ‡||π‘₯ βˆ’ 𝑦|| ∞ )𝑑𝑠 1 0 , 𝛽 sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠) Γ— (8 πœ‡||π‘₯ βˆ’ 𝑦|| ∞ )𝑑𝑠 1 0 ) (3.9) Now, as we know sup π‘‘βˆˆ[0,1] ∫ 𝑔(𝑑, 𝑠)𝑑𝑠 1 0 = 1 8 and taking πœ“(𝑑) = πœ‡π‘‘ πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦) ≀ πœ‡(πœŒπ‘(π‘₯, 𝑦)), 𝛽(πœŒπ‘(π‘₯, 𝑦))) ≀ πœ‡πœŒπ‘(π‘₯, 𝑦) ≀ πœ“(πœŒπ‘(π‘₯, 𝑦)) ≀ πœ“(π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯, 𝑦), πœŒπ‘(π‘₯, 𝑇 π‘₯), πœŒπ‘(𝑦, 𝑇 𝑦)}) (3.10) Define the function 𝛼 ∢ 𝐢(𝐼) Γ— 𝐢(𝐼) β†’ [0, ∞) as 𝛼(π‘₯, 𝑦) = { 1 ||π‘₯|| ≀ 1, ||𝑦|| ≀ 1 0 π‘œπ‘‘β„Žπ‘’π‘Ÿπ‘€π‘–π‘ π‘’ (3.11) For all π‘₯, 𝑦 ∈ 𝐢(𝐼) 𝛼(π‘₯, 𝑦)πœŒπ‘(𝑇 π‘₯, 𝑇 𝑦) ≀ πœ“(π‘šπ‘Žπ‘₯{πœŒπ‘(π‘₯, 𝑦), πœŒπ‘(π‘₯, 𝑇 π‘₯), πœŒπ‘(𝑦, 𝑇 𝑦)}) (3.12) Clearly, all the conditions of Theorem 2.3 are satisfied and so Ξ“ has a fixed point. 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