id	author	title	date	pages	extension	mime	words	sentence	flesch	summary	cache	txt
ejde-323	Feng, Sebert	Symmetry analysis for a second-order ordinary differential equation	2021	12	.pdf	application/pdf	4764	263	73	Hence, the general solution of the linearized symmetry condition is ξ = − (q + 2)c0 k2 e k2q q+2x + c1, η = c0e k2q q+2xy. (4.5) Substituting (4.5) into (4.2), we have η = − 2a(x)k1 (q + 1)(q + 2) yq+2 + {a′(x)− a(x)k2}y2 + c(x)y + d(x), (4.6) where q 6= −1 and q 6= −2.	cache/ejde-323.pdf	txt/ejde-323.txt