Electronic Journal of Differential Equations, Vol. 2023 (2023), No. 19, pp. 1–14. ISSN: 1072-6691. URL: https://ejde.math.txstate.edu or https://ejde.math.unt.edu NON-RADIAL NORMALIZED SOLUTIONS FOR A NONLINEAR SCHRÖDINGER EQUATION ZHI-JUAN TONG, JIANQING CHEN, ZHI-QIANG WANG Abstract. This article concerns the existence of multiple non-radial positive solutions of the L2-constrained problem −∆u−Q(εx)|u|p−2u = λu, in RN ,∫ RN |u|2dx = 1, where Q(x) is a radially symmetric function, ε > 0 is a small parameter, N ≥ 2, and p ∈ (2, 2 + 4 N ) is assumed to be mass sub-critical. We are interested in the symmetry breaking of the normalized solutions and we prove the existence of multiple non-radial positive solutions as local minimizers of the energy functional. 1. Introduction We consider nonlinear Schrödinger equations with a L2 constraint, −∆u−Q(εx)|u|p−2u = λu, in RN ,∫ RN |u|2dx = 1, (1.1) where 2 < p < 2 + 4 N , N ≥ 2, the potential function Q(x) is radially symmetric, that is Q(|x|) = Q(x), and ε > 0 is a parameter. Many models of such type can be seen in the literature. It is especially important in theory and application to study the existence and properties of ground states and bound states solutions. The existence of solutions for nonlinear Schrödinger equation, including their properties, is of great interest in the field and has been studied extensively in the past (e.g., [1, 3, 8, 10, 11, 14, 15, 18]) and references therein. In addition, a growing number of articles considering the existence of multiple bound states of nonlinear Schrödinger equation, together with L2 constraint, have appeared in the field; see [4, 5, 6, 7, 12, 14, 17] and references therein. Let d > 0 and µ > 0 be constants. First consider a case of constant potential and define c(d, µ) = inf u∈H1(RN ),‖u‖22=µ (1 2 ∫ RN |∇u|2dx− d p ∫ RN |u|pdx ) . (1.2) 2020 Mathematics Subject Classification. 35J20, 35J60, 58E40. Key words and phrases. Symmetry breaking; local minimizer; concentration; nonlinear Schrödinger equations. ©2023. This work is licensed under a CC BY 4.0 license. Submitted January 16, 2023 Published February 27, 2023. 1 2 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 Here and after we use ‖ · ‖r to denote the Lr norm for r ≥ 1. Cazenave-Lions [5] proved that c(d, µ) < 0 and c(d, µ) are attained, up to a translation, by a radially symmetric minimizer. This minimizing feature leads to the orbital stability of the standing waves associated with the time-dependent nonlinear Schrödinger equation; see [5, 4]. Using the same method and being easier because of the compact embedding from H1 r into Lp for N ≥ 2, one can prove that when Q(x) = Q(|x|) is a radial function and replaces the constant d in the problem (1.2), the minimization problem is also solvable in the space of radial functions; see [17]. Here H1 r denotes the subspace of H1(RN ) of radially symmetric functions. A natural question is that when Q is a radial potential whether there exist non- radial solutions – symmetry breaking phenomenon. The question was studied by Yang [17] in which the authors give conditions under which a ground state solution is non-radial, i.e., symmetry breaking occurs. Then Yang [17] also gives conditions which assure the existence of multiple non-radial bound state solutions. These solutions are constructed as global minimizers of the energy functional in some symmetric subspaces. More precisely it was proved that when N = 2 and N ≥ 4, (1.1) has radial and non-radial solutions. Furthermore, there exist multiple non- radial solutions [17] as ε → 0. However, the global minimization scheme may not work for the case N = 3. The reason for such circumstances is that in the three- dimensional case, multiple bumps may concentrate at the origin or concentrate along the z-axis and run to infinity in two opposite directions, i.e., the north and south poles (See Proposition 2.3 below for more details). Also for the existence of multiple non-radial solutions the condition on Q in [17] depends on the number of solutions, which is less desirable. This article gives a different method to settle the issues related to the above problem. We prove the existence of multiple non-radial positive solutions for all dimensions N ≥ 2 with conditions on Q independent of the number of solutions. The conclusion is much stronger than the original one. It is worth mentioning that solutions given in this paper are found to be local minimizers, while the solutions of [17] are global minimizers in symmetric subspaces. Under the conditions in this paper we do not know whether the global minimizers exist and whether they are non-radial solutions even if they do exist, yet local minimizers do exist under our conditions. To solve equation (1.1) we look for the critical points of the functional Jε(u) = 1 2 ∫ RN |∇u|2dx− 1 p ∫ RN Q(εx)|u|pdx, u ∈ H1(RN ) (1.3) under the assumption ‖u‖22 = 1. We use the following assumption (A1) Q ∈ C(RN ,R) is radially symmetric, i.e., Q(x) = Q(|x|), Q(x) achieves its maximum on {x : |x| = 1}, and there exist a > 0 and σ0 > 0 such that 0 < a ≤ Q(x) ≤ max RN Q(x) = 1, for x ∈ RN , (1.4) Q(|x|)−Q(1) < 0 for 0 < ‖x| − 1| ≤ 2σ0. (1.5) For convenience, and without loss of generality, we have set the maximum value of Q to be 1. Roughly speaking, Q is bounded from above and below by positive constants and has an isolated global maximum point at |x| = 1. Now we state the main theorem to be proved in this article. EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 3 Theorem 1.1. Assume N ≥ 2, p ∈ (2, 2 + 4 N ). Assume (A1) is satisfied. Let k ≥ 1 be an integer. Then there exists εk > 0 such that for all 0 < ε < εk, (1.1) has a non-radial positive solution uε,k satisfying limε→0 Jε(uε,k) = c(k 2−p 2 , 1). In particularly, as ε→ 0, (1.1) has more and more non-radial positive solutions. We remark that we can distinguish these solutions by separating their energies using the asymptotic limits c(k 2−p 2 , 1) which is proved to be different for different k in Lemma 2.1. Finally, we summarize our work in terms of results and methods. We give a new local minimization scheme which tracks down non-radial bound state solutions of multi-bump type. This is motivated by the fact that in general the known global minimization method cannot give these k-bump type concentrated solutions for k ≥ 3 (this is particularly true for the dimension N = 3 as will be discussed in Section 2). Our method allows to establish k-bump type solutions for any integer k by taking ε small. The article is organized as follows. In Section 2 we develop a basic formula for the minimization problem c(d, µ) which will be used frequently in our proof later.Then we introduce a local minimization scheme which will be used to construct k−bump solutions. In Section 3 we first prove several lemmas in preparation of the proof for the main theorem and we close with the proof of the main theorem. In the Appendix we give the proof of a result in Section 2 showing that the global minimization approach cannot give multi-bump type solutions in general. 2. Variational formulation and some technical results Using scalings we first give a formula for the ground state energy in the constant potential case. Here again for d > 0 and µ > 0, we define c(d, µ) = inf u∈H1(RN ),‖u‖22=µ ( 1 2 ∫ RN |∇u|2 − d p ∫ RN |u|pdx). (2.1) We formulate the dependency of c(d, µ) in terms of d and µ, using and extending the results of [13, 17]. Let ω > 0 be the unique positive radially symmetric solution of −∆ω + ω = ωp−1, ω > 0, in RN . (2.2) The ground state solution ω above is useful for the proof of the following lemma. Lemma 2.1. Let d > 0, µ > 0, 2 < p < 2 + 4 N . Then c(d, µ) = −c0d 4 4−N(p−2)µ 4−(N−2)(p−2) 4−N(p−2) , (2.3) where c0 = [4−N(p−2)]‖ω‖ −4 4−N(p−2) 2 4[4−(N−2)(p−2)] . Proof. First by [17, Proposition 2.3] we have c(d, 1) = c(1, 1)d 4 4−N(p−2) . Similar proof of this gives us c(d, µ) = c(1, µ)d 4 4−N(p−2) . For λ > 0, we use a scaling of w where uλ(x) = λ 2 p−2ω(λx). From (2.2) we have −∆uλ + λ2uλ = ( uλ )p−1 , (2.4) ‖uλ‖22 = λ 4−N(p−2) p−2 ‖ω‖22. (2.5) 4 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 Set µ = λ 4−N(p−2) p−2 ‖ω‖22. Then λ2 = ( µ ‖ω‖22 ) 2(p−2) 4−N(p−2) , i.e., uλ satisfies ‖uλ‖22 = µ and −∆uλ + ( µ ‖ω‖22 ) 2(p−2) 4−N(p−2)uλ = ( uλ )p−1 . (2.6) By [13], we have almost everywhere in µ > 0, ∂ ∂µ c(1, µ) = −1 4 ( µ ‖ω‖22 ) 2(p−2) 4−N(p−2) . (2.7) Then integrating (2.7) with respect to µ, we can obtain c(1, µ2)− c(1, µ1) = −1 4 ∫ µ2 µ1 ( µ ‖ω‖22 ) 2(p−2) 4−N(p−2) dµ. Using c(1, µ1)→ 0 as µ1 → 0, we obtain c(1, µ) = −1 4 ‖ω‖ −4 4−N(p−2) 2 µ 4−(N−2)(p−2) 4−N(p−2) 4−(N−2)(p−2) 4−N(p−2) = −c0µ 4−(N−2)(p−2) 4−N(p−2) . � Lemma 2.2. For k fixed there exists δk > 0, for every 0 < b ≤ δk, it holds c(1, b) + c(k 2−p 2 , 1− b) > c(k 2−p 2 , 1). (2.8) Proof. Consider a continuous function of b, f(b) = c(1, b) + c(k 2−p 2 , 1 − b), where 0 ≤ b ≤ 1. Then the result follows by a direct computation from (2.3). � Since in some cases the global minimizers do not produce multi-bump solutions, we introduce the method of local minimization to construct k-bump solutions. Be- fore presenting the results, we introduce some notation. Let k ≥ 2 be an integer, we define a subgroup of O(2) G̃k = { g, g2, · · ·, gk = Id : g = ( cos 2π k − sin 2π k sin 2π k cos 2π k )} . (2.9) Note that G̃k acts on R2 as rotation. Then to guarantee the invariance of the group in the three-dimensional or higher dimensional cases, a group G is defined as follows, G = G̃k × Z2. (2.10) Here Z2 is the reflection about the plane of x1, x2. In view of the above statement, we require to establish a function space as follows H1 G(RN ) = {u ∈ H1(RN ) : u is G-invariant}. (2.11) In other words, if u ∈ H1 G, then u is G̃k-invariant with respect to (x1, x2) and u is even in (x3, . . . , xN ). The solutions of (1.1) are constructed in G-invariant subspaces, so that they are G-invariant. To prove our main result, the existence of solutions in Theorem 1.1, we set up a local minimization scheme. Choose δ > 0 such that 0 < δ < min{δk 2 , σ0 2 }. (2.12) Here δk is from Lemma 2.2 and σ0 is from condition (A1). We define Oδ,ε = {u ∈ H1 G(RN ) : ∫ RN u2 = 1, γε(u) ≥ 1− δ} (2.13) EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 5 where γε(u) = ∫ T 1+σ0 ε \T 1−σ0 ε |u|2dx. (2.14) Here for R > 0, TR = {x ∈ RN : |Px| < R} and P : RN → R2 is the linear projection. Finally, we define a local minimization problem which will give us desired k-bump solutions c(Oδ,ε) = inf u∈Oδ,ε,‖u‖22=1 Jε(u). (2.15) We will locate k-bump solutions as minimizers in Oδ,ε of the energy functional Jε, therefore as local minimizers in the full space for Jε on the L2 constraint. More precisely, we will show that for ε > 0 small, c(Oδ,ε) is attained at an interior point uε of Oδ,ε, and therefore uε is a critical point of Jε on ‖u‖22 = 1 and a solution of (1.1). Then we establish an asymptotic energy estimate of Jε(uε) so we may distinguish these solutions in k for ε > 0 small. We finish this section by pointing out why a local minimization argument is necessary for constructing these k-bumped solutions. We show in general the global minimization cannot give k-bumped solutions. Proposition 2.3. Assume N = 3, Q(x) = Q(|x|) is continuous with 0 < a ≤ Q(x) ≤ 1, Q attains its maximum at |x| = 1, and lim sup |x|→∞ Q(x) := q∞ < 1. Then for ε > 0 small, the minimum of Jε with the constraint ‖u‖22 = 1 is achieved. If Q(0) > k 2−p 2 , then the minimizers uε concentrate at the origin as ε→ 0. The proof uses some results from [17] and is presented in the Appendix. 3. Asymptotic estimates and the proof of Theorem 1.1 Recall that for proving Theorem 1.1 we need to prove that the local minimization problem (2.15) is solvable. We first give an auxiliary result on another minimization problem. First define TR = {x ∈ RN : |Px| < R}, (3.1) where P : RN → R2 is the linear projection, and T cR = RN \ TR. (3.2) Base on the property of solutions to be constructed and to be compared, we establish a space for R > 0, X = XR = H1 0,G(T cR) = {u ∈ H1 0 (T cR) : gu = u,∀g ∈ G}. (3.3) For R > 0 and b > 0, set S(R, b) = inf u∈X,‖u‖22=b (1 2 ∫ RN |∇u|2 − 1 p ∫ RN |u|pdx ) . (3.4) Next we state some asymptotic estimates for S(R, b). Lemma 3.1. In the setting of (3.3) and (3.4), the following hold: 6 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 (i) Let Rn → ∞, as n → ∞ and (un) ⊂ XRn be such that limn→∞ ‖un‖22 = b and lim n→∞ (1 2 ∫ T cRn |∇un|2 − 1 p ∫ T cRn |un|pdx ) = A ≤ lim R→∞ S(R, b). (3.5) Then A = c(k 2−p 2 , b) and up to a subsequence, for every α > 0, there exists r > 0 and (yn) ⊂ T cRn such that lim inf n→∞ ∫ Br(yn) |un|2dx ≥ b k − α. (3.6) (ii) limR→∞ S(R, b) = c(k 2−p 2 , b). Proof. By using special testing functions, we can easily obtain that for any R > 0, S(R, b) ≤ c(k 2−p 2 , b). Since S(R, b) is non-decreasing as R → ∞, limR→∞ S(R, b) exists. Now choose a sequence Rn → ∞ and (un) ⊂ XRn , such that limn→∞ ‖un‖22 = b and A ≤ limR→∞ S(R, b). By the concentration-compactness principle [8, 9], we have three possibilities. If vanishing occurs, then for any r > 0, it holds lim n→∞ sup y∈RN ∫ Br(y) |un|2dx = 0. It follows from [8, 9] that un → 0 in Lp(RN ) for 2 < p < 2∗ = 2N N−2 . Then we obtain limn→∞( 1 2 ∫ RN |∇un| 2 − 1 p ∫ RN |un| pdx) ≥ 0. This is a contradiction with c(k 2−p 2 , 1) < 0. Next because of the symmetry we can only expect compactness of the sequence module the symmetry. If there exists b1 > 0 and (yn) ⊂ T cRn such that for any α > 0, there exists r > 0, lim inf n→∞ ∫ Br(yn) |un|2dx ≥b1 − α. (3.7) Since un is radial, one can get∫ Br(gyn) |un|2dx ≥b1 − α. Now we claim that kb1 = b. If kb1 < b, let η = η(t) be a smooth non-increasing function on [0,+∞) such that η(t) = 1 for t ∈ [0, 1], η(t) = 0 for t ≥ 2 and |η′(x)| ≤ 2. Write ηc(t) = 1− η(t). In (3.7) we choose αm → 0 and rm →∞. Then we we can find unm and ynm such that ∫ Br(yn) |unm |2dx ≥b1 − αm. We still name this subsequence unm as un for simplicity of notations. Define vn(x) = k∑ i=1 η ( |x− giyn| rn ) un(x), (3.8) ωn = un(x)− vn. (3.9) Hence, ‖vn(x)‖22 → kb1 and ‖ωn(x)‖22 → b− kb1, as n→∞. Then A+ o(1) EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 7 = 1 2 ∫ RN |∇un|2 − 1 p ∫ RN |un|pdx = (1 2 ∫ RN |∇vn|2 − 1 p ∫ RN |vn|pdx ) + (1 2 ∫ RN |∇ωn|2 − 1 p ∫ RN |ωn|pdx ) − C0 rn = (‖vn‖22 2b ∫ RN ∣∣√b∇vn ‖ vn‖2 ∣∣2 − ‖vn‖p2 pbp/2 ∫ RN ∣∣√bvn ‖vn‖ 2 ∣∣pdx) + (‖ωn‖22 2b ∫ RN ∣∣√b∇ωn ‖ωn‖2 ∣∣2 − ‖ωn‖p2 pbp/2 ∫ RN ∣∣√bωn ‖ωn‖ 2 ∣∣pdx)− C0 rn ≥ ‖vn‖ 2 2 b S(Rn, b) + (‖vn‖22 pb − ‖vn‖ p 2 pbp/2 )∫ RN ∣∣√bvn ‖vn‖2 ∣∣pdx+ ‖ωn‖22 b S(Rn, b)− C0 rn . Here C0 is independent of n. Sending n→∞, this implies A ≥ kb1 b A+ b− kb1 b A+ 1 p [kb1 b − (kb1 b )p/2] lim n→∞ ∫ RN ∣∣√bvn ‖vn‖2 ∣∣pdx. Then we deduce that kb1 = b, since otherwise using limn→∞ ∫ RN |un| p dx 6= 0 we obtain a contradiction with the last term in the formula above positive. Finally,choose αn → 0, rn → ∞,by doing a cut-off function which is similar to (3.8),we can get ‖vn‖22 → b, as n → ∞. We can repeat the method above, using limn→∞ ‖vn‖22 = b and Lemma 2.1 we obtain A+ o(1) = 1 2 ∫ RN |∇un|2 − 1 p ∫ RN |un|pdx+ o(1) ≥ 1 2 ∫ RN |∇vn|2 − 1 p ∫ RN |vn|pdx+ o(1) ≥ kc(1, b k ) + o(1) = c(k 2−p 2 , b) + o(1). Letting n→∞, o(1)→ 0, we obtain the result (i). The assertion (ii) follows from (i) readily. � For the minimization problem c(Oδ,ε), we will use the following asymptotic esti- mates. Lemma 3.2. (i) Let εn → 0 and (un) ⊂ Oδ,ε such that lim supn→∞ Jεn(un) ≤ c(k 2−p 2 , 1). Then there exists (yn) ⊂ R2×{−→0 } satisfying for any 0 < σ ≤ σ0 and lim sup n→∞ dist(yn, T 1+σ0 εn \ T 1−σ0 εn ) <∞ (3.10) and for any α > 0, there exists R > 0 such that lim n→∞ ∫ BR(yn) |un|2dx ≥ 1 k − α. (3.11) (ii) limε→0 c(Oδ,ε) = c(k 2−p 2 , 1). Proof. Let (un) ⊂ Oδ,εn be such that A = limn→∞ Jεn(un) ≤ c(k 2−p 2 , 1). Then for any 0 < t ≤ 1− σ0, we have lim sup n→∞ ∫ Tt/εn |un|2dx = lim sup n→∞ (1− ∫ T c t/εn |un|2dx) 8 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 = 1− lim inf n→∞ ∫ Tt/εn |un|2dx ≤ 1− (1− δ) = δ. Next we select a sequence Rm+1 = 2Rm → ∞, as m → ∞. Up to a subsequence, we suppose that bm = lim sup n→∞ ∫ TRm |un|2dx, b0 = lim m→∞ bm. Then using the fact that un ⊂ Oδ,εn we obtain b0 ≤ δ. Choose nm →∞, as m→∞ such that ∣∣bm − ∫ TRm |unm |2dx ∣∣ ≤ 1 m , ∣∣∣bm+1 − ∫ TRm+1 |unm |2dx ∣∣∣ ≤ 1 m . By doing a cut-off function which is similar to the proof of Lemma 3.1, we obtain two sequences vn and ωn satisfying lim n→∞ ∫ RN |vn|2dx = b0, lim n→∞ ∫ RN |ωn|2dx = 1− b0. Note that (ωn) ⊂ H1 0,G(T cRn). Then by Lemma 3.1, we obtain lim n→∞ Jεn(ωn) ≥ lim n→∞ S(Rn, 1− b0) = c(k 2−p 2 , 1− b0). Claim 1: b0 = 0. Direct computation shows that there exists some C > 0 be such that Jεn(un)− Jεn(vn)− Jεn(ωn) ≥ − C Rn . It follows that A = lim n→∞ Jεn(un) ≥ lim n→∞ (Jεn(vn) + Jεn(ωn)− C Rn ) ≥ c(1, b0) + c(k 2−p 2 , 1− b0) + o(1). This implies c(k 2−p 2 , 1) ≥ c(1, b0)+c(k 2−p 2 , 1−b0). By Lemma 2.2, since 0 < b0 ≤ δk, we have c(1, b0) + c(k 2−p 2 , 1− b0) > c(k 2−p 2 , 1), which is a contradiction. Thus, b0 = 0 and Claim 1 is proved. Using Lemma 3.1, we conclude that for any α > 0, there exists R > 0 and (yn) ⊂ RN be such that lim n→∞ inf yn∈RN ∫ BR(yn) |un|2dx ≥ 1 k − α. (3.12) Claim 2: limn→∞ |P⊥yn| ≤ C where P⊥ = Id − P . If this claim is not the case, then up to a subsequence, we can assume that limn→∞ |P⊥yn| = ∞. Since un is G-invariant, then there exists g ∈ G such that |gP⊥yn − P⊥yn| → ∞ as n → ∞. This gives a contradiction with the above estimate and ∫ RN |un| 2 dx = 1. EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 9 Claim 3: There exists constant C > 0 such that lim sup n→∞ dist(yn, εn −1(Aσ0 )) ≤ C, (3.13) where Aσ0 = {x : 1− σ0 ≤ |Px| ≤ 1 + σ0}. Assume the claim is not true, then up to a subsequence we have dist(yn, εn −1(Aσ0)) =∞. We consider two cases. The first is |yn| < 1−σ0 εn , then 1−σ0 εn −|yn| → ∞; it follows that ∫ T 1+σ0 εn \T 1−σ0 εn |un|2dx ≤ 1− k∑ i=1 ∫ BR(giyn) |un|2dx ≤ kα. Let α be sufficiently small, then it is a contradiction to γ(un) ≥ 1 − δ. For the other case we have |yn| > 1+σ0 εn . The proof is analogous to the above. Claim 4: For every σ0 > σ > 0, there exists Cσ > 0 be such that lim sup n→∞ dist(yn, εn −1(Aσ)) ≤ Cσ. (3.14) If the claim is not true, then there exists σ ∈ (0, σ0) and up to a subsequence, (yn) ⊂ εn −1(Aσ) such that lim supn→∞ dist(yn, εn −1(Aσ)) = ∞. Then we have |yn| − 1+σ εn →∞ or 1−σ εn − |yn| → ∞. Now we only consider the case |yn| − 1+σ εn → ∞, the proof of the other case is similar. Using condition (A1), and the continuity of Q(x), there exists 0 < a < 1 be such that Q(|x|) ≤ a, for σ ≤ ∣∣|x| − 1 ∣∣ ≤ 2σ0. i.e., Q(ε|y|) ≤ a, for σ ε ≤ ∣∣|y| − 1 ε ∣∣ ≤ 2σ0 ε . Then 1+σ ε ≤ |y| ≤ 1+2σ0 ε . Because of BR(yn) ⊂ (T 1+2σ0 εn \ T 1+σ εn ), we have Q(εnx) ≤ a, for x ∈ BR(yn). Next, set vn(x) = ∑k i=1 η( |x−g iyn| Rn )un(x) satisfying limn→∞ ‖vn‖22 = 1 and (vn) ⊂ H1 0,G(T 1+2σ0 εn ). Then c(k 2−p 2 , 1) ≥ lim n→∞ Jεn(un) = lim n→∞ Jεn(vn) + o(1) = lim n→∞ ( 1 2 ∫ RN |∇vn|2 − 1 p ∫ RN |vn|pdx) + lim n→∞ 1 p ∫ RN (1−Q(εx))|vn|pdx+ o(1) ≥ c(k 2−p 2 , 1) + 1− a p lim n→∞ ∫ RN |vn|pdx > c(k 2−p 2 , 1). This is a contradiction. Thus, the proof of claim 4 is complete and the part (i) is proved. For part (ii), we note that it is easy to see using testing function, we have lim sup ε→0 c(Oδ,ε) ≤ c(k 2−p 2 , 1). Then the assertion (ii) follows from the assertion (i). � 10 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 We remark that for fixed varepsilon > 0, the function γε(u) is continuous in u, and limn→∞ γεn(un) = 1 for the sequence in Lemma 3.2. Lemma 3.3. For every α > 0, there exists R = R(α) > 0 and ε = ε(α) > 0 for any 0 < ε < ε(α), if (un) ⊂ Oδ,ε is a minimizing sequence for c(Oδ,ε), then lim inf n→∞ ∫ {x:ε−1(1− δ4 )≤|Px|≤ε−1(1+ δ 4 )}∩{x:|P⊥x|≤R} |un|2dx ≥ 1− α. (3.15) Proof. If the assertion is not true, then there exists α0 > 0 for any Rm → ∞ and εm → 0, a minimizing sequence (um,n)∞n=1 (of fixed m) for c(Oδ,εm) such that lim inf n→∞ ∫ {x | εm−1(1− δ4 )≤|Px|≤εm−1(1+ δ 4 )}∩{x |P⊥x|≤Rm} |um,n|2dx < 1− α0. Next, we choose a sequence nm →∞ such that lim m→∞ ∫ {x|εm−1(1− δ4 )≤|Px|≤εm−1(1+ δ 4 )}∩{x||P⊥x|≤Rm} |um,nm | 2 dx < 1− α0, (3.16) lim m→∞ Jεm(um,nm) = c(k 2−p 2 , 1). (3.17) For convenience, here we denote um,nm by um. Applying Lemma 3.2 to (um), then there exists (ym) ⊂ RN and εm|ym| → 1 for every α > 0, there exists R > 0 such that lim m→∞ ∫ BR(ym) |um|2dx ≥ 1 k − α 2k . Take α = α0, the above statement also holds for some R0 > 0. Using the fact that for any σ > 0, there exists Cσ > 0 such that lim sup m→∞ dist(ym, ε −1 m (Aσ)) ≤ Cσ <∞. Then we can assume that (ym) ⊂ { x : εm −1(1− δ 8 ) ≤ |Px| ≤ εm−1(1 + δ 8 ) } . It follows that BR0(ym) ⊂ { x : εm −1(1− δ 4 ) ≤ |Px| ≤ εm−1(1 + δ 4 ) } and lim inf n→∞ ∫ {x:ε−1 m (1− δ4 )≤|Px|≤ε −1 m (1+ δ 4 )}∩{x:|P⊥x|≤Rm} |um|2dx ≥ k∑ i=1 ∫ BR0 (giym) |um|2dx ≥ k( 1 k − α0 2k ) ≥ 1− α0 2 , which contradicts (3.16). Thus, the proof is complete. � Lemma 3.4. There exists εk > 0 such that for any 0 < ε < εk, c(Oδ,ε) is attained in the interior of Oδ,ε. EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 11 Proof. First we choose ε1 > 0 such that for any 0 < ε < ε1, it follows from Lemma 3.2 that c(Oδ,ε) ≤ 1 2c(k 2−p 2 , 1). Next, it follows from (2.3) that c(k 2−p 2 , µ) = c(k 2−p 2 , 1)µ1+θ, where θ = 2(p− 2) 4−N(p− 2) > 0. Then there exists µ0 > 0 such that µ0 θ ≤ 1/2. Furthermore, applying Lemma 3.3 with α0 = 1 2 min{µ0, δ}, there exists R0 > 0 and ε2 > 0, for all 0 < ε < ε2, if (un) ⊂ Oδ,ε is a minimizing sequence for c(Oδ,ε) such that lim inf n→∞ ∫ {x:ε−1(1− δ4 )≤|Px|≤ε−1(1+ δ 4 )}∩{x:|P⊥x|≤R0} |un|2dx ≥ 1− α0. Now, we set εk = min {ε1, ε2} > 0, then fix 0 < ε < εk and let (un) ⊂ Oδ,ε be a minimizing sequence of c(Oδ,ε). We will show this for a subsequence un → u in L2(RN ). Choose a sequence Rm+1 = 2Rm →∞, as m→∞. Then up to a subsequence, we obtain lim n→∞ ∫ BRm (0) |un|2dx = bm. It is noteworthy that bm ≥ 1− δ. Then it suffices to show limm→∞ bm = 1. To the contrary, we assume limm→∞ bm = b < 1, it may produce a contradiction as follows. Choose a sequence nm →∞, as m→∞ such that∣∣∣bm − ∫ BRm (0) |unm | 2 dx ∣∣∣ ≤ 1 m , ∣∣∣bm+1 − ∫ BRm+1 (0) |unm |2dx ∣∣∣ ≤ 1 m . For simplicity of notation, we denote the sequence {unm}∞m=1 as {um}. Then we define vm(x) = η( |x| Rm )um(x), ωm(x) = ηc( |x| Rm )um(x). It implies that lim m→∞ ∫ RN |vm|2dx = b, lim m→∞ ∫ RN |ωm|2dx = 1− b. Next we claim that vm/‖vm‖2 ∈ Oδ,ε. In fact, it follows from (3.15) that lim n→∞ ∫ {x:ε−1(1− δ4 )≤|Px|≤ε−1(1+ δ 4 )}∩{x:|P⊥x|≤R0} |um|2dx ≥ 1− α0. It follows from (un) ⊂ Oδ,ε and 1− b < δ that∫ T 1+σ0 ε \T 1−σ0 ε v2m ‖vm‖22 dx ≥ 1 ‖vm‖22 ∫ T 1+σ0 ε \T 1−σ0 ε |un|2dx ≥ 1− α0 > 1− δ. Hence, the proof of the claim is complete. Consequently, c(Oδ,ε) + om(1) = 1 2 ∫ RN |∇um|2 − 1 p ∫ RN Q(εx)|um|pdx 12 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 ≥ ( 1 2 ∫ RN |∇vm|2 − 1 p ∫ RN Q(εx)|vm|pdx) + (1 2 ∫ RN |∇ωm|2 − 1 p ∫ RN Q(εx)|ωm|pdx ) − C Rm ≥ ‖vm‖ 2 2 2 ∫ RN |∇vm|2 ‖vm‖22 − ‖vm‖ p 2 p ∫ RN Q(εx) vpm ‖vm‖p2 dx + (1 2 ∫ RN |∇ωm|2 − 1 p ∫ RN Q(εx)|ωm|pdx ) − C Rm ≥ ‖vm‖22c(Oδ,ε) + ‖vm‖22 − ‖vm‖ p 2 p ∫ RN Q(εx) vpm ‖vm‖p2 dx+ c(k 2−p 2 , 1− b)− C Rm . Sending m→∞, where C is a constant independent of R, we obtain (1− b)c(Oδ,ε) ≥ c(k 2−p 2 , 1− b). From the choice at the beginning, we derive that 1− b 2 c(k 2−p 2 , 1) ≥ c(k 2−p 2 , 1)(1− b)1+θ. This gives 1/2 ≤ (1− b)θ which yields a contradiction with 1 − b ≤ α0 ≤ 1 2µ0. Thus,1 − b = 0 or b = 1. Therefore, we proved un → u in L2(RN ). Then un → u in Lp(RN ) by interpolation. Using the weakly lower semi-continuity, we deduce c(Oδ,ε) ≤ Jε(u) = lim n→∞ Jε(un) = c(Oδ,ε). By the choice α0 ≤ δ 2 , we have u is in the interior of Oδ,ε. This completes the proof. � Proof of Theorem 1.1. The existence part of non-radial positive solution for each k follows from Lemma 3.4 and the energy asymptotic as ε → 0, limε→0 Jε(uε,k) = c(k 2−p 2 , 1), follows from Lemma 3.2. � 4. Appendix Here we sketch the proof Proposition 2.3. We define a global minimization problem with constraint c(ε) = inf u∈H1 G(R3),‖u‖22=1 Jε(u). (4.1) First using suitable test functions we easily have lim supε→0 c(ε) ≤ c(k 2−p 2 , 1). Under the conditions of Proposition 2.3, using [17, Lemma 4.2] for ε > 0 small enough, c(ε) is achieved at some uε. Now we analyze the asymptotic behavior of uε as ε → 0. Take a sequence εn → 0 and let un := uεn . Applying the concen- tration compactness principle to (un), we can easily rule out the vanishing since c(k 2−p 2 , 1) < 0. Now using the assumption Q(0) > k 2−p 2 and using testing func- tions concentrating at the origin we have lim supε→0 c(ε) ≤ c(Q(0), 1) < c(k 2−p 2 , 1). Now we claim un weakly converges to u 6= 0. Otherwise, by doing a cut-off we obtain a sequence vn ∈ H1 0,G(T cRn) with Rn → ∞. Using Lemma 3.1 we have lim supε→0 c(ε) ≥ c(k 2−p 2 , 1), a contradiction. Now if ‖u‖22 < 1 we may use Brezis- Lieb Lemma to get a contradiction again. Thus compactness holds for the sequence (un). Then it follows that lim supε→0 c(ε) = c(Q(0), 1) and for any α > 0 there EJDE-2023/19 SOLUTIONS FOR A SCHRÖDINGER EQUATION 13 is R > 0 such that lim infn→∞ ∫ RN u 2 ndx ≥ 1 − α. 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Soc., 45 (1982), 169–192. Zhi-Juan Tong College of Mathematics and Statistics, Fujian Normal University, Fuzhou, 350117, China Email address: qsx20200630@student.fjnu.edu.cn Jianqing Chen College of Mathematics and Statistics, Fujian Normal University, Fuzhou, 350117, China Email address: jqchen@fjnu.edu.cn 14 Z.-J. TONG, J. CHEN, Z.-Q. WANG EJDE-2023/19 Zhi-Qiang Wang College of Mathematics and Statistics, Fujian Normal University, Fuzhou, 350117, China. Department of Mathematics and Statistics, Utah State University, Logan, UT 84322, USA Email address: zhi-qiang.wang@usu.edu 1. Introduction 2. Variational formulation and some technical results 3. Asymptotic estimates and the proof of Theorem ?? 4. Appendix Acknowledgments References