Electronic Journal of Differential Equations, Vol. 2020 (2020), No. 118, pp. 1–19. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu STABILITY FOR CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS YUANLIN DING, MICHAL FEČKAN, JINRONG WANG Abstract. In this article, we study impulsive differential equations with con- formable derivatives. Firstly, we derive suitable formulas for solving linear impulsive conformable Cauchy problems. Then, we show that the linear prob- lem has asymptotic stability, and the nonlinear problem has generalized Ulam- Hyers-Rassias stability. Also we illustrate our results with examples. 1. Introduction Among the new mathematical tools, we have the conformable derivative which was introduced in [1, 14]. It has been used in Newton mechanics [9], cobweb models [7], logistic models [2], and other branches of physics [20] and mathematics [4, 18, 22, 24, 25, 26]. Impulsive differential equations have been applied to many problems; see [5, 6, 12, 29, 30]. In particular, [3, 8, 19] consider impulsive differential equations with a conformable derivative of the form Da βy(t) = g(t, y(t)), t ∈ I := [a, b]\{t1, . . . , tm}, 0 < β < 1, ∆y(tk) = Ik(y(t−k )), k = 1, 2, . . . ,m, where Da β is called the conformable derivative with low index a, the function g : [a, b]× R → R is continuous, Ik : R → R is an (instantaneous) impulsive function, a = t0 < t1 < · · · < tm < tm+1 = b, b > 0, y(t−k ) = limε→0− y(tk + ε) and y(t+k ) = limε→0+ y(tk + ε). Motivated by the works [13, 16, 17, 23, 27, 28, 32], we consider the conformable linear non-instantaneous impulsive differential equation Da βy(t) = µy(t), t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m, y(t+k ) = ξy(t−k ), k = 1, 2, . . . ,m, y(t) = ξy(t−k ), t ∈ (tk, sk], k = 1, 2, . . . ,m, y(s+ k ) = y(s−k ), k = 1, 2, . . . ,m. (1.1) 2010 Mathematics Subject Classification. 34A37, 34A08, 34D20. Key words and phrases. Conformable derivative; impulsive differential equation; asymptotic stability; generalized Ulam-Hyers-Rassias stability. c©2020 Texas State University. Submitted October 4, 2020. Published December 8, 2020. 1 2 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 Note that y(t+k ) = ξy(t−k ) is the classical impulsive condition that affects y at the point tk; meanwhile y(t) = ξy(t−k ) for t ∈ (tk, sk] affects y on the interval (tk, sk] and is called non-instantaneous impulsive equation. Next, we consider the conformable non-linear non-instantaneous impulsive dif- ferential equation Da βy(t) = g(t, y(t)), t ∈ (sk, tk+1], k = 0, 1, . . . ,m, y(t+k ) = hk(tk, y(t−k )), k = 1, . . . ,m, y(t) = hk(t, y(t)), t ∈ (tk, sk], k = 1, . . . ,m, y(s+ k ) = y(s−k ), k = 1, 2, . . . ,m, (1.2) where µ and ξ are constants, 0 < β < 1. For k = 1, 2, . . . ,m: the sk are called junction points while the tk are called impulse points, t0 = s0 = a < t1 < s1 < t2 · · · < sm < tm+1 = b, b > 0, g : [a, b]×R→ R is continuous, hk : [tk, sk]×R→ R is continuous and is called a non-instantaneous impulsive function. For details on the non-instantaneous impulsive equations, see [27, eq. (1.6)]. Equations (1.1), (1.2) are used in the dynamics of evolution processes in pharmacotherapy: the first equation denotes the health status of a patient; the second equation denotes the doctor takes some actions to test medicine for the patient practicably; the third equation denotes the testing medicine is valid for this patient and then begin to deal with the effect of patient for some time. The final equation shows the effect of testing medicine disappeared in the health of the patient. The article is organized as follows. In Section 2, we present some basic defini- tions, and derive the solutions for two kinds of non-instantaneous impulsive frac- tional Cauchy problems. In Section 3, we define asymptotic stability and give some conditions for (1.1) to be asymptotically stable. In Section 4, we define generalized Ulam-Hyers-Rassias stability for (1.2), and use a fixed point theorem to study this stability. In Section 5, we illustrates our main results by examples. 2. Preliminaries Let PC(I,R) = {y : I → R : y ∈ C((tk, tk+1],R), k = 0, 1, . . . , y(t−k ) = y(tk)}, where C((tk, tk+1],R). This is the space of piecewise continuous functions endowed with the norm ‖y‖ = supt∈I |y(t)|. Definition 2.1 ([15, Definition 2.1]). The conformable derivative with lower index a of a function y : [a, b]→ R is defined as Da βy(t) = lim ε→0 y(t+ ε(t− a)1−β)− y(t) ε , a < t, 0 < β < 1, Da βy(a) = lim t→a+ Da βy(t). A function y is called β-differentiable at t0 if Da βy(t0) exists and is finite. If y ∈ C1([a, b],R), then Da βy(t) = (t − a)1−βy′(t). For t > a the conformable derivative Da βy(t) exists if and only if y is differentiable at t and Da βy(t) = (t − a)1−βy′(t); see [1] Definition 2.2 (see [15, Definition 2.3]). The conformable integral with lower index a of a function y : [a, b]→ R is defined as Iaβy(t) = ∫ t a y(s)dβ(s, a) = ∫ t a (s− a)β−1y(s)ds, a ≤ t; 0 < β < 1. EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 3 When a = 0, we write dβ(s) = dβ(s, 0). Lemma 2.3 (see [15, Definition 3.3]). Let y : I → R be a continuous function. A solution y ∈ C(I,R) of the linear problem Da βy(t) = µy(t) + g(t), t ∈ I, 0 < β < 1, y(a) = ya has the form y(t) = yae µ(t−a)β/β + ∫ t a eµ(t−a)β/βe−µ(s−a)β/βg(s)(s− a)β−1ds. The result in Lemma 2.3 is also valid when continuous function is replaced by integrable functions with finitely many points of discontinuity. Remark 2.4. Consider the multi-dimensional case Da βy(t) = f(y(t), t), t ≥ a y(a) = ya, (2.1) where f ∈ C(Rn × [a,∞),Rn). Then we consider the associate ODE Y ′(z) = f ( Y (z), β √ βz + a ) , z ≥ 0 Y (0) = ya. (2.2) For a solution Y (z) of (2.2), by defining y(t) = Y ( (t− a)β β ) , (2.3) for t > a, we obtain Da βy(t) = (t− a)1−βy′(t) = (t− a)1−βY ′ ( (t− a)β β ) (t− a)β−1 = f ( Y ( (t− a)β β ) , β √ β (t− a)β β + a ) , = f(y(t), t), y(a) = Y (0) = ya. Note that Da βy(a) = lim t→a+ Da βy(t) = f(y(a), a) = f(ya, a). So all solutions of (2.1) are determined by (2.2) and viceversa. For instance, when f(y, t) = Ay + g(t), for a matrix A. Then (2.1) becomes y′(z) = Ay(t) + g(t), t ≥ a y(t) = ya, (2.4) and (2.2) becomes Y ′(z) = AY (z) + g( β √ βz + a), z ≥ 0 Y (0) = ya, 4 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 with solution Y (z) = eAzya + ∫ z 0 eA(z−u)g( β √ βu+ a)du. Thus by (2.3), a solution of (2.4) is y(t) = eA (t−a)β β ya + ∫ (t−a)β β 0 eA( (t−a)β β −u)g( β √ βu+ a)du ( u = (s− a)β β ) = eA (t−a)β β ya + ∫ t a eA( (t−a)β β − (s−a)β β )g ( β √ β (s− a)β β + a ) (s− a)β−1ds, = e 1 βA(t−a)βya + ∫ t a e 1 βA((t−a)β−(s−a)β)g(s)(s− a)β−1ds. This is a generalization of Lemma 2.3 to higher dimensions. Next, we establish two standard frameworks and derive appropriate formulas for solving the impulsive Cauchy problem (1.1), and the problem Da βy(t) = g(t), t ∈ (sk, tk+1], k = 0, 1, . . . ,m, 0 < β < 1, y(t) = hk(t), t ∈ (tk, sk], k = 1, . . . ,m, y(a) = ya. (2.5) Lemma 2.5. Let y(t, s, ys) be the solution of (1.1) with initial value y(s) = ys. Then y(t) := y(t, s, ys) = W (t, s)ys, 0 ≤ s ≤ t, where W (t, s) = ξn(a,t)−n(a,s) exp (µ β [( ((t− a)β − (sn(a,t) − a)β)+ − ( (s− a)β − (sn(a,s) − a)β )+) + n(a,t)−1∑ k=n(a,s) ((tk+1 − a)β − (sk − a)β) ]) , where n(a, t) denotes the number of the impulse points that belong to (a, t) and z+ := max{0, z}, z ∈ R. Note that when n(a, t) = n(a, s), we have ∑n(a,t)−1 k=n(a,s) = 0. In particular, y(t) = ξn(a,t)e µ β [ ((t−a)β−(sn(a,t)−a)β)++ ∑n(a,t)−1 k=n(a,s) ((tk+1−a)β−(sk−a)β) ] ya. Proof. Depending on the number of pulse and junction points between times t and s, we have the following 8 cases. Case 1: There are no pulse or junction points between t and s, i.e. n(a, t) = n(a, s). (i) Let t, s ∈ (sk, tk+1] for k = 0, 1, 2, . . . , n(a, t). When t ∈ (a, t1], we have y(t) = yae µ(t−a)β/β . When t ∈ (t1, s1], we have y(t) = ξy(t−1 ) = ξeµ(t1−a)β/βya. When t ∈ (s1,2 ], according to y(s1) = ξy(t−1 ) = ξeµ(t1−a)β/βya = eµ(s1−a)β/βya1 , EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 5 we have y(t) = eµ(t−a)β/βya1 = eµ(t−a)β/β ξe µ(t1−a)β/βya eµ(s1−a)β/β , y(s) = e µ β (s−a)βya1 = eµ(t−a)β/β ξe µ(t1−a)β/βya eµ(s1−a)β/β , so W (t, s) = eµ ( (t−a)β−(s−a)β ) /β . (ii) Let us set t, s ∈ (tk, sk], k = 1, 2, . . . , n(a, t). From y(t) = ξy(t−k ), k = 1, 2, . . . , n(a, t), we obtain y(t) = y(s), so W (t, s) = 1, a constant. Case 2: There is only one junction point between t and s, i.e. n(a, t) = n(a, s). For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (sn(a,t), tn(a,t)+1), we have y(t) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s+ n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s), so W (t, s) = e µ β ( (t−a)β−((sn(a,t)−a)β ) . Case 3: There is only one pulse point between time t and s, i.e. n(a, t) = n(a, s)+1. Let us select every s ∈ (sn(a,s), tn(a,s)+1] and t ∈ (tn(a,t), sn(a,t)]. When y(t) = ξy(t−n(a,t)), we have y(t) = ξy(t−n(a,t)) = ξeµ ( (tn(a,t)−a)β−(s−a)β ) /βy(s), so W (t, s) = ξeµ ( (tn(a,t)−a)β−(s−a)β ) /β . Case 4: There are one pulse and one junction points between t and s, i.e. n(a, t) = n(a, s) + 1. (i) By selecting every s ∈ (sn(a,s), tn(a,s)+1] and t ∈ (sn(a,t), tn(a,t)+1], we have y(t) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s+ n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξy(t−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(s−a)β ) /βy(s), so W (t, s) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(s−a)β ) /β . (ii) For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (tn(a,t), sn(a,t)], we have y(t) = ξy(t−n(a,t)) 6 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 = ξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /βy(s+ n(a,s)) = ξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /βy(s−n(a,s)) = ξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /βy(s), so W (t, s) = ξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /β . Case 5: There are two pulse and one junction points between t and s, i.e. n(a, t) = n(a, s) + 2. For every t ∈ (tn(a,t), sn(a,t)] and s ∈ (sn(a,s), tn(a,s)+1], we have y(t) = ξy(t−n(a,t)) = ξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βy(s+ n(a,s)+1) = ξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βy(s−n(a,s)+1) = ξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βξy(t−n(a,s)+1) = ξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βξe µ β ( (tn(a,s)+1−a)β−(s−a)β ) y(s) = ξ2 exp (µ β β ( (tn(a,t) − a)β − (sn(a,t)−1 − a)β ) + ( (tn(a,s)+1 − a)β − (sn(a,s) − a)β ) − ( (s− a)β − (sn(a,s) − a)β )) y(s), so W (t, s) = ξ2 exp (µ β ( (tn(a,t) − a)β − (sn(a,t)−1 − a)β ) + ( (tn(a,s)+1 − a)β − (sn(a,s) − a)β ) − ( (s− a)β − (sn(a,s) − a)β )) . Case 6: There are one pulse and two junction points between t and s, i.e. n(a, t) = n(a, s) + 1. For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (sn(a,t), tn(a,t)+1), we have y(t) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s+ n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξy(t−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /βy(s+ (a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,s)−a)β ) /βy(s), so W (t, s) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /β . Case 7: There are two pulse and two junction points between t and s, i.e. n(a, t) = n(a, s) + 2. EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 7 (i) For every s ∈ (sn(a,s), tn(a,s)+1] and t ∈ (sn(a,t), tn(a,t)+1), we have y(t) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s+ n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βy(s−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξy(t−n(a,t)) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βy(s+ n(a,t)−1) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βy(s−n(a,s)+1) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /βξy(t−n(a,s)+1) = eµ ( (t−a)β−(sn(a,t)−a)β ) /βξeµ ( (tn(a,t)−a)β−(sn(a,t)−1−a)β ) /β × ξe µ β ( (tn(a,t)−1−a)β−(s−a)β ) y(s) = ξ2 exp (µ β ( (t− a)β − (sn(a,t) − a)β ) + ( (tn(a,t) − a)β − (sn(a,t)−1 − a)β ) + ( (tn(a,t)−1 − a)β − (s− a)β )) y(s), so W (t, s) = ξ2 exp (µ β ( (t− a)β − (sn(a,t) − a)β ) + ( (tn(a,t) − a)β − (sn(a,t)−1 − a)β ) + ( (tn(a,t)−1 − a)β − (s− a)β )) . (ii) For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (tn(a,t), sn(a,t)], we have y(t) = ξy(t−n(a,t)) = ξe µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) y(s+ n(a,s)+1) = ξe µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) y(s−n(a,s)+1) = ξe µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) ξy(t−n(a,s)+1) = ξe µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) ξe µ β ( (tn(a,s)+1−a)β−(sn(a,s)−a)β ) y(s) = ξ2e µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) + ( (tn(a,s)+1−a)β−(sn(a,s)−a)β ) y(s), so W (t, s) = ξ2e µ β ( (tn(a,t)−a)β−(sn(a,s)+1−a)β ) + ( (tn(a,s)+1−a)β−(sn(a,s)−a)β ) . Case 8: There are several pulse and several junction points between t and s. (i) For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (sn(a,t), tn(a,t)+1) we have W (t, s) = ξn(a,t)−n(a,s)e µ β [( (t−a)β−(sn(a,t)−a)β ) + ∑n(a,t)−1 k=n(a,s) ( (tk+1−a)β−(sk−a)β )] . (ii) For every s ∈ (sn(a,s), tn(a,s)+1] and t ∈ (tn(a,t), sn(a,t)], we have W (t, s) = ξn(a,t)−n(a,s)e µ β [∑n(a,t)−1 k=n(a,s) ( (tk+1−a)β−(sk−a)β ) − ( (s−a)β−(sn(a,s)−a)β )] . 8 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 (iii) For every s ∈ (sn(a,s), tn(a,s)+1] and t ∈ (sn(a,t), tn(a,t)+1], we have W (t, s) = ξn(a,t)−n(a,s) exp (µ β [( ((t− a)β − (sn(a,t) − a)β) − ((s− a)β − (sn(a,s) − a)β) ) + n(a,t)−1∑ k=n(a,s) ((tk+1 − a)β − (sk − a)β) ]) . (iv) For every s ∈ (tn(a,s), sn(a,s)] and t ∈ (tn(a,t), sn(a,t)], we have W (t, s) = ξn(a,t)−n(a,s)e µ β ∑n(a,t)−1 k=n(a,s) ( (tk+1−a)β−(sk−a)β ) . Summarizing the 8 cases above, we can write W (t, s) = ξn(a,t)−n(a,s) exp (µ β [( ((t− a)β − (sn(a,t) − a)β)+ − ((s− a)β − (sn(a,s) − a)β)+ ) + n(a,t)−1∑ k=n(a,s) ((tk+1 − a)β − (sk − a)β) ]) . (2.6) In particular when s = a, W (t, a) = ξn(a,t)e µ β [ ( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=n(a,s) ((tk+1−a)β−(sk−a)β)] . The proof is complete. � Lemma 2.6. A function y ∈ PC(I,R), is a solution of the fractional integral equations y(t) = ∫ t a (s− a)β−1g(s)ds+ ya, t ∈ (a, t1]; y(t) = ∫ t sk (s− a)β−1g(s)ds+ hk(sk), t ∈ (sk, tk+1], k = 1, . . . ,m; y(t) = hk(t), t ∈ (tk, sk], k = 1, . . . ,m, if and only if y is a solution of (2.5). Proof. Assume y is the solution of (2.5). When t ∈ [a, t1], we have Da βy(t) = g(t), t ∈ (a, t1] with y(a) = ya. (2.7) By Definition 2.2 and integrating (2.7), we obtain y(t) = ∫ t a (s− a)β−1g(s)ds+ c. Obviously, y(a) = ya so c = ya. Therefore y(t) = ∫ t a (s− a)β−1g(s)ds+ ya, t ∈ [a, t1]. Note that when t ∈ (t1, s1], we have y(t) = h1(t). Also when t ∈ (s1,2 ], we have Da βy(t) = g(t), t ∈ (s1,2 ] with y(s1) = h1(s1). Similarly, we have y(t) = ∫ t s1 (s− a)β−1g(s)ds+ h1(s1), for t ∈ (s1,2 ]. EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 9 When t ∈ (2, s2], we have y(t) = h2(t). Also when t ∈ (s2, t3], we have Da βy(t) = g(t), t ∈ (s2, t3] with y(s2) = h2(s2). So, we obtain y(t) = ∫ t s2 (s− a)β−1g(s)ds+ h2(s2), t ∈ (s2, t3]. Summarizing, Da βy(t) = g(t), t ∈ (sk, tk+1] with y(sk) = hk(sk). Then y(t) = ∫ t sk (s− a)β−1g(s)ds+ hk(sk), t ∈ (tk, sk]. The remaining proofs can be done by continuing the standard steps and then verify the conclusions. � Lemma 2.7 (see [10]). Suppose that (Y, d) is a complete metric space, and that W : Y → Y is a strictly contractive operator with constant L < 1. If there exists a nonnegative integer k such that d(W k+1y,W ky) <∞ for some y ∈ Y , then: (i) The sequence {Wny} converges to a fixed point y∗ in W ; (ii) y∗ is the unique fixed point of W in Y ∗ = {x ∈ Y : d(W ky, x) <∞}; (iii) If x ∈ Y ∗, then d(x, y∗) ≤ 1 1−Ld(Wx, x). 3. Asymptotic stability for the linear problem Definition 3.1. The solution y(t) of (1.1) is locally asymptotically stable if there exists δ > 0 such that for any xa ∈ R with |ya − xa| < δ, it holds lim t→∞ |y(t, a, ya)− y(t, a, xa)| = 0. If δ is arbitrary, then y(t) is globally asymptotically stable. For the next theorem we assume that sk and tk+1 satisfy η1 ≤ (tk+1 − a)β β − (sk − a)β β ≤ η2, k = 0, 1, 2, . . . ,m (3.1) and define η = { η1, µ < 0, η2, µ ≥ 0. Theorem 3.2. Assume that (3.1) holds. If Θ := µ+ 1 η ln ξ < 0, (3.2) then (1.1) is asymptotically stable. Proof. From (2.6) and (3.1), we have |W (t, a)| ≤ eµ [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] ξn(a,t) ≤ eµ [ ( (t−a)β β − (sn(a,t)−a)β β )++n(a,t)η ] ξn(a,t) ≤ eµη ( eµηξ )n(a,t) . 10 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 By (3.2), we have eµηξ ≤ e ηΘ 2 < 1, so when t→∞, we have n(a, t)→∞, and then |W (t, a)| ≤ eµηe ηΘ 2 n(a,t) → 0, as t→∞. The proof is complete. � Theorem 3.3. Assume that λ = µ + ρ ln ξ < 0 and one of the following two conditions holds: ξ ≥ 1, and lim sup t→∞ n(a, t) ( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) := ρ <∞, (3.3) or ξ < 1 and lim inf t→∞ n(a, t) ( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) := ρ <∞, (3.4) then (1.1) is asymptotically stable. Proof. By (2.6), we have |W (t, a)| ≤ eµ [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] ξn(a,t). When ξ ≥ 1, by (3.3), we obtain n(a, t) < ρ [ ( (t− a)β β − (sn(a,t) − a)β β )+ + n(a,t)−1∑ k=0 ( (tk+1 − a)β β − (sk − a)β β ) ] , for any t large enough. Then |W (t, a)| ≤ e(µ+ρ ln ξ) [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] . Because µ+ ρ ln ξ < λ/2 < 0 we have |W (t, a)| ≤ e λ 2 [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] → 0, as t→∞. Similarly, when ξ < 1, by (3.4), we obtain n(a, t) > ρ [ ( (t− a)β β − (sn(a,t) − a)β β )+ + n(a,t)−1∑ k=0 ( (tk+1 − a)β β − (sk − a)β β ) ] , for any t large enough. When ξ < 1, we have |W (t, a)| ≤ e(µ+ρ ln ξ) [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] , and satisfy µ+ ρ ln ξ < λ/2 < 0, so |W (t, a)| ≤ e λ 2 [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] → 0, as t→∞. The proof is complete. � EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 11 Note that W (t, a) = e µ β [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ] ξn(a,t) = e λ β [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ] × eln ξ ( n(a,t)− ρβ [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ]) . (3.5) Next we discuss the condition on λ = µ+ ρ ln ξ directly. Theorem 3.4. Assume that lim t→∞ n(a, t) ( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) := ρ <∞. (3.6) Then: (i) If λ < 0, then (1.1) is asymptotically stable. (ii) If λ > 0, then (1.1) is unstable. Proof. (i) Since λ < 0, there exists ζ1 such that |eλt| ≤ e−ζ1t, t ≥ 0, (3.7) in which ζ1 = −λ/2. By (3.6), there exist ω1 > 0 such that for any t ≥ ω1, we have∣∣∣ n(a, t) ( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) − ρ ∣∣∣ ≤ ζ1 2| ln ξ| . Then∣∣∣eln ξ ( n(a,t)−ρ [( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β )])∣∣∣ ≤ e| ln ξ| ∣∣n(a,t)−ρ [( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β )])∣∣ ≤ e ζ1 2 [( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β )] . (3.8) Substituting (3.7) and (3.8) into (3.5), we obtain |W (t, a)| ≤ e− ζ1 2 [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] → 0, as t→∞. Thus (i) is proved. (ii) We rewrite (3.5) as W (t, a)e− ln ξ ( n(a,t)− ρβ [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ]) = e λ β [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ] . (3.9) Since λ > 0, there exists ζ2 and y0 ∈ Rn such that |eλtya| ≥ eζ2t, t ≥ 0, (3.10) in which ζ2 = λ/2. 12 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 By (3.6), there exist ω2 > 0 such that for any t > ω2, we obtain∣∣∣e− ln ξ ( n(a,t)− ρβ [( (t−a)β−(sn(a,t)−a)β )+ + ∑n(a,t)−1 k=0 ((tk+1−a)β−(sk−a)β) ])∣∣∣ ≤ e ζ2 2 [( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β )] . (3.11) Substituting (3.10) and (3.11) into (3.9), we obtain eζ2 [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] ≤ ∣∣∣eλ[( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] y0 ∣∣∣ ≤ |W (t, a)ya| ∣∣∣ exp ( − ln ξ ( n(a, t)− ρ β [( (t− a)β − (sn(a,t) − a)β )+ + n(a,t)−1∑ k=0 ((tk+1 − a)β − (sk − a)β) ]))∣∣∣ ≤ |W (t, a)ya|e ζ2 2 [( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β )] , so |W (t, a)ya| ≥ e ζ2 2 [ ( (t−a)β β − (sn(a,t)−a)β β )++ ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ] →∞, as t→∞. The proof is complete. � 4. Generalized Ulam-Hyers-Rassias stability for the nonlinear problem We introduce the concept of generalized Ulam-Hyers-Rassias stability through the concept of stability in [21, 31]. Let ε > 0, ψ ≥ 0 and φ ∈ PC(I,R+) be nondecreasing, in the conditions |Da βx(t)− g(t, x(t))| ≤ φ(t), t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m, 0 < β < 1, |x(t)− hk(t, x(t))| ≤ ϕ, t ∈ (tk, sk], k = 1, 2, . . . ,m. (4.1) Definition 4.1. Equation (1.2) has generalized Ulam-Hyers-Rassias stability if there exists cg,β,hk,φ > 0 such that for each solution x ∈ PC(I,R) of inequality (4.1), there exists a solution y ∈ PC(I,R) of (1.2) with |x(t)− y(t)| ≤ cg,β,hk,φ(φ(t) + ϕ), t ∈ I. When ε = 1, the generalized Ulam-Hyers-Rassias stability reduces to the classical Ulam-Hyers-Rassias stability, see [27, Remark 3.5]. Remark 4.2. A function x ∈ PC(I,R) is a solution of (4.1) if and only if there exists H ∈ PC(I,R) and a sequence Hk, k = 1, 2, . . . ,m which depends on x such that (i) |H(t)| ≤ φ(t) for t ∈ I, and |Hk| ≤ ϕ for k = 1, 2, . . . ,m; (ii) Da βx(t) = g(t, x(t)) +H(t) for t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m; (iii) x(t) = hk(t, x(t)) +Hk, t ∈ (sk−1, tk], k = 1, 2, . . . ,m. EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 13 Remark 4.3. If x ∈ PC(I,R) is the solution of (4.1) then x satisfies the following integral inequalities: |x(t)− hk(t, x(t))| ≤ ϕ, t ∈ (tk, sk], k = 1, 2, . . . ,m, |x(t)− x(a)− ∫ t a (s− a)β−1g(s, x(s)ds| ≤ ∫ t a (s− a)β−1φ(s)ds, t ∈ (a, t1], |x(t)− ∫ t sk (s− a)β−1g(s, x(s))ds− hk(sk, x(sk))| ≤ ∫ t (s− a)β−1φ(s)ds+ ϕ, t ∈ (sk, tk+1], k = 1, 2, . . . ,m. (4.2) By Remark 4.2 (i), we have Da βx(t) = g(t, x(t)) +H(t), t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m, x(t) = hk(t, x(t)) +Hk, t ∈ (tk, sk], k = 1, 2, . . . ,m. (4.3) Obviously, x(t) = hk(t, x(t)) +Hk, t ∈ (tk, sk], k = 1, 2, . . . ,m, x(t) = ∫ t a (s− a)β−1 ( g(s, x(s)) +H(s) ) ds+ ya, t ∈ (a, t1], x(t) = ∫ t sk (s− a)β−1 ( g(s, x(s)) +H(s) ) ds+ hk(sk, x(sk)) +Hk, t ∈ (tk, sk], k = 1, 2, . . . ,m is the solution of (4.3). For t ∈ (sk, tk+1], k = 1, 2, . . . ,m, we have∣∣∣x(t)− ∫ t sk (s− a)β−1g(s, x(s))ds− hk(sk, x(sk)) ∣∣∣ ≤ ∣∣∣ ∫ t sk (s− a)β−1H(s)ds ∣∣∣+ |Hk| ≤ ∫ t sk (s− a)β−1φ(s)ds+ ϕ. As mentioned above, we can obtain |x(t)− hk(t, x(t))| ≤ |Hk| ≤ ϕ, t ∈ (tk, sk], k = 1, 2, . . . ,m, and∣∣∣x(t)− x(a)− ∫ t a (s− a)β−1g(s, x(s))ds ∣∣∣ ≤ ∣∣∣ ∫ t a (s− a)β−1H(s)ds ∣∣∣ ≤ ∫ t a (s− a)β−1φ(s)ds, t ∈ (a, t1]. For using a fixed point theorem of the alternative and for deriving our main result, which is about contractions on a complete metric space, we consider the following assumptions: (H1) g ∈ C(I × R,R). (H2) There exists a positive constant Lg such that |g(t, v1)− g(t, v2)| ≤ Lg|v1 − v2|, for each t ∈ I and all v1, v2 ∈ R. 14 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 (H3) hk ∈ C([tk, sk]×R,R) and there are positive constants Lhk , k = 1, 2, . . . ,m such that |gk(t, v1)− gk(t, v2)| ≤ Lhk |v1 − v2|, for each t ∈ [tk, sk] and all v1, v2 ∈ R. (H4) φ ∈ C(I,R+) is a nondecreasing function, and there exists cφ > 0 such that(∫ t a ( φ(s) )1/p ds )p ≤ cφφ(t), p ∈ (0, 1), for each t ∈ I. We use the concept of generalized Ulam-Hyers-Rassias to show stability of (1.2) in the following section. Theorem 4.4. Assume that (H1)–(H4) are satisfied and a function x ∈ PC(I,R) that satisfies (4.1). Then there exists a unique solution x0 of (1.2) such that x0(t) = ∫ t a (s− a)β−1g(s, x0(s))ds+ ya, t ∈ [a, t1], x0(t) = hk(t, x0(t)), t ∈ (tk, sk], k = 1, 2, . . . ,m, x0(t) = ∫ t sk (s− a)β−1g(s, x0(s))ds+ hk(sk, x0(sk)), t ∈ (sk, tk+1], k = 1, 2, . . . ,m, (4.4) and |x(t)− x0(t)| ≤ ( 2cφ ( 1−p β−p )1−p bβ−p + 1 ) (φ(t) + ϕ) 1−M , (4.5) for all t ∈ I provided that 0 < p < β < 1 and M = M1 < 1, (4.6) where M1 = max{Lgcφ ( 1− p β − p )1−p tβ−pk+1 + Lhk : k = 0, 1, 2, . . . ,m}. Proof. Consider the space of piecewise continuous functions Y = {f : I → R : f ∈ PC(I,R)}, and the generalized metric d(f, h) = inf { A1+A2 ∈ [0,+∞] : |f(t)−h(t)| ≤ (A1+A2)(φ(t)+ϕ) ∀t ∈ I } , (4.7) where A1 ∈ {A ∈ [0,+∞] ∣∣|f(t)− h(t)| ≤ Aφ(t) for all t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m}, A2 ∈ {A ∈ [0,+∞] ∣∣|f(t)− h(t)| ≤ Aϕ for all t ∈ (tk, sk], k = 1, 2, . . . ,m}. This is a generalized metric in the sense that it can have value +∞. For the necessity of introducing such a generalized metric and applications, we refer to [10]. One can easily show that (Y, d) is a complete generalized metric space. We define an operator Υ : Y → Y by (Υy)(t) =  ∫ t a (s− a)β−1g(s, y(s))ds+ ya if t ∈ [a, t1], hk(t, y(t)) if t ∈ (tk, sk], k = 1, 2, . . . ,m,∫ t sk (s− a)β−1g(s, y(s))ds+ hk(sk, y(sk)) if t ∈ (sk, tk+1], k = 1, 2, . . . ,m, (4.8) for all y ∈ Y and t ∈ [a, b]. Obviously, Υ is a well defined operator by (H1). EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 15 Next, we verify that Υ is strictly contractive. We considering the definition of (Y, d), for any f, h ∈ Y , we find a A1, A2 ∈ [0,∞] such that |f(t)− h(t)| ≤ { A1φ(t), t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m, A2ϕ, t ∈ (tk, sk], k = 1, 2, . . . ,m. (4.9) By the definition of Υ in (4.8), (H2), (H3) and (4.9), we obtain the following three cases: Case 1: For t ∈ [a, t1] we have |(Υf)(t)− (Υh)(t)| = ∣∣∣ ∫ t a (s− a)β−1g(s, f(s))ds− ∫ t a (s− a)β−1g(s, h(s))ds ∣∣∣ ≤ ∫ t a (s− a)β−1|g(s, f(s))− g(s, h(s))|ds ≤ Lg ∫ t a (s− a)β−1|f(s)− h(s)|ds ≤ LgA1 ∫ t a (s− a)β−1|φ(s)|ds ≤ LgA1 (∫ t a (s− a) β−1 1−p ds )1−p(∫ t a ( φ(s) )1/p ds )p ≤ LgA1cφφ(t) ( 1− p β − p )1−p tβ−p ≤ Lgcφ ( 1− p β − p )1−p tβ−p1 A1φ(t). Case 2: For t ∈ (tk, sk] we have |(Υf)(t)− (Υh)(t)| = |hk(t, f(t))− hk(t, h(t))| ≤ Lhk |f(t)− h(t)| ≤ LhkA2ϕ. Case 3: For t ∈ (sk, tk+1] we have |(Υf)(t)− (Υh)(t)| = ∣∣∣ ∫ t sk (s− a)β−1g(s, f(s))ds+ hk(sk, f(sk)) − ∫ t sk (s− a)β−1g(s, h(s))ds− hk(sk, h(sk)) ∣∣∣ ≤ ∣∣∣ ∫ t sk (s− a)β−1g(s, f(s))ds− ∫ t sk (s− a)β−1g(s, h(s))ds ∣∣∣ + ∣∣hk(sk, f(sk))− hk(sk, h(sk)) ∣∣ ≤ Lgcφ ( 1− p β − p )1−p tβ−pk+1A1φ(t) + LhkA2ϕ ≤ ( Lgcφ ( 1− p β − p )1−p tβ−pk+1 + Lhk ) (A1 +A2)(φ(t) + ϕ). 16 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 In this case we have |(Υf)(t)− (Υh)(t)| ≤M(A1 +A2)(φ(t) + ψ), t ∈ I. Then d(Υf,Υh) ≤M(A1 +A2). Therefore, d(Υf,Υh) ≤Md(f, h), for any f, h ∈ Y , and because of (4.6), we verify the strictly continuous property. Let us take f0 ∈ Y . By the piecewise continuous property of f0 and Υf0, there exists a constant 0 < F1 <∞ such that |(Υf0)(t)− f0(t)| = ∣∣∣ ∫ t a (s− a)β−1g(s, f0(s))ds+ ya − f0(t) ∣∣∣ ≤ F1φ(t) ≤ F1(φ(t) + ϕ), t ∈ [a, t1]. Then there exists a constant 0 < F2 <∞ such that |(Υf0)(t)− f0(t)| = ∣∣hk(t, f0(t))− f0(t)| ≤ F2ϕ ≤ F2(φ(t) + ϕ), for t ∈ (tk, sk] and k = 1, 2, . . . ,m. Also there exists a constant 0 < F3 < ∞ such that |(Υf0)(t)− f0(t)| = ∣∣∣ ∫ t sk (s− a)β−1g(s, f0)ds+ hk(sk, f0(sk))− f0(t) ∣∣∣ ≤ F3(φ(t) + ϕ), t ∈ (sk, tk+1], k = 1, 2, . . . ,m. because g, hk, f0 <∞ are bounded on I and φ(·) + ϕ > 0. So (4.7) implies that d(Υf0, f0) <∞. Using the Banach fixed point theorem, we obtain a continuous function x0 : I → R such that Υn(f0)→ x0 in (Y, d) as n→∞ and Υx0 → x0, and for every t ∈ I, x0 satisfies (4.4). Next, we verify that {f ∈ Y |d(f0, f) < ∞} = Y . For any f ∈ Y , because f0, f are bounded on I and mint∈I(φ(t) + ϕ) > 0, there is a constant 0 < Af < ∞ such that |f0(t)− f(t)| ≤ Af (φ(t) + ϕ), for any t ∈ I. So we have d(f0, f) <∞ for any f ∈ Y ; that is, {f ∈ Y |d(f0, f) <∞} = Y . Therefore, we know that x0 is the unique continuous function and it has the property (4.4). From (4.2) and (H4), we have d(x,Υx) ≤ 2cφ ( 1− p β − p )1−p bβ−p + 1, In summary, we have d(x, x0) ≤ d(Υy, y) 1−M ≤ 2cφ ( 1−p β−p )1−p bβ−p + 1 1−M , so (4.5) holds for t ∈ I. The proof is complete. � 5. Examples To illustrate our results we present the following examples. EJDE-2020/118 CONFORMABLE IMPULSIVE DIFFERENTIAL EQUATIONS 17 Example 5.1. Consider the conformable linear non-instantaneous impulsive dif- ferential equations Da βy(t) = υy(t), t ∈ (sk, tk+1], k = 0, 1, 2, . . . ,m, y(t+k ) = νy(t−k ) on (tk, sk], k = 1, 2, . . . ,m, y(t) = νy(t−k ), t ∈ (tk, sk], k = 1, 2, . . . ,m, y(s+ k ) = y(s−k ), k = 1, 2, . . . ,m. (5.1) Let ta = sa = 1 and (tk+1−a)β β − (sk−a)β β = 1 for k = 0, 1, 2, 3, . . . ,m. Then η = 1. Note that n(a, t) n(a, t) + 1 = n(a, t)∑n(a,t) k=0 ( (tk+1−a)β β − (sk−a)β β ) ≤ n(a, t)( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) ≤ n(a, t)∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) = 1, because n(a, t) > 1. Then ρ = lim t→∞ n(a, t) ( (t−a)β β − (sn(a,t)−a)β β )+ + ∑n(a,t)−1 k=0 ( (tk+1−a)β β − (sk−a)β β ) = 1. Next, λ = υ+ ln ν. By Theorem 3.4, we know that if υ < − ln ν, (5.1) is asymptot- ically stable. Also if υ > − ln ν, (5.1) is unstable. Example 5.2. Consider D0 βy(t) = |y(t)| 10 + 4t2 + 10et , t ∈ (0, 1] ∪ (2, 3], y(t) = t 6 e−y(t), t ∈ (1, 2], and ∣∣D0 βx(t)− |x(t)| 10 + 4t2 + 10et ∣∣ ≤ et, t ∈ [0, 1] ∪ (2, 3],∣∣x(t)− t 6 e−x(t) ∣∣ ≤ 1, t ∈ (1, 2]. Let I = [0, 3], β = 1/2, p = 1/3 and 0 = t0 = s0 < 1 = t1 < 2 = s1 <2= 3. Denote g(t, y(t)) = |y(t)| 10+4t2+10et with Lg = 1 20 , for t ∈ (0, 1]∪ (2, 3] and h1(t, y(t)) = t 6e −y(t) with Lh1 = 1 3 for t ∈ (1, 2]. Putting φ(t) = et, ϕ = 1 and cφ = 1, we have( ∫ t 0 (et)3ds )1/3 ≤ et. Let M1 = { 1 2042/331/6 + 1 3} = 0.4846, so M = 0.4846 < 1. By Theorem 4.4, there exists a unique solution x0 : [0, 3]→ R such that x0(t) =  ∫ t 0 s−1/2 |x0(s)| 10+4s2+10es ds+ y0, t ∈ [0, 1], t 6e −x0(t), t ∈ (1, 2], ∈t2 s−1/2 |x0(s)| 10+4s2+10es ds+ 2 6e −x0(2), t ∈ (2, 3], and |x(t)− x0(t)| ≤ 2× 42/3 × 31/6 + 1 1− 0.5 (et + 1) ≈ 14.1047(et + 1), 18 Y. DING, M. FEČKAN, J. WANG EJDE-2020/118 for all t ∈ [0, 3]. Conclusion. This article gives elementary results for linear and nonlinear non- instantaneous conformable impulsive differential equations keeping the lower limit at a fixed point a. Representation of solutions and asymptotical stability for linear problems are established. The generalized Ulam-Hyers-Rassias stability for nonlin- ear problems are also derived. In a forthcoming paper, we can extend the current results to higher dimension case based on Remark 2.4. Note there is no nonconstant periodic solution for (2.5). We can consider (2.5) replacing a by sk, i.e., in each impulse starting at impulsive time. 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Wang, M. Fečkan, Y. Zhou; Fractional order differential switched systems with coupled nonlocal initial and impulsive conditions, Bull. Sci. Math., 141 (2017), 727-746. [31] J. Wang, M. Fečkan, Y. Zhou; Ulam’s type stability of impulsive ordinary differential equa- tions, J. Math. Anal. Appl., 395 (2012), 258-264. [32] D. Yang, J. Wang, D. O’Regan; On the orbital Hausdorff dependence of differential equations with non-instantaneous impulses, Comptes Rendus Mathematique, 356 (2018), 150-171. Yuanlin Ding Department of Mathematics, Guizhou University, Guiyang, Guizhou 550025, China Email address: yldingmath@126.com Michal Fečkan Department of Mathematical Analysis and Numerical Mathematics, Faculty of Math- ematics, Physics and Informatics, Comenius University in Bratislava, Mlynská dolina, 842 48 Bratislava, Slovakia. Mathematical Institute, Slovak Academy of Sciences, Štefánikova 49, 814 73 Bratislava, Slovakia Email address: Michal.Feckan@fmph.uniba.sk Jinrong Wang (corresponding author) Department of Mathematics, Guizhou University, Guiyang, Guizhou 550025, China. School of Mathematical Sciences, Qufu Normal University, Qufu, Shandong 273165, China Email address: wjr9668@126.com 1. Introduction 2. Preliminaries 3. Asymptotic stability for the linear problem 4. Generalized Ulam-Hyers-Rassias stability for the nonlinear problem 5. Examples Conclusion Acknowledgments References