Electronic Journal of Differential Equations, Vol. 2020 (2020), No. 129, pp. 1–25. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu POINTWISE ESTIMATES OF SOLUTIONS TO CONSERVATION LAWS WITH NONLOCAL DISSIPATION-TYPE TERMS FENGBAI LI, WEIKE WANG, YUTONG WANG Abstract. This article concerns the Cauchy problem of conservation laws with nonlocal dissipation-type terms in R3. By using Green’s function and the time-frequency decomposition method, we study global classical solutions and their long time behavior including pointwise estimates for large initial data, for solutions near the nontrivial equilibrium state. 1. Introduction In this article, we study the existence of global solutions and their decay estimates to conservation laws with nonlocal dissipation-type terms in R3. We consider the solution, near the equilibrium state u∗ 6= 0, of the equation ∂tu− γ14ut − γ24u = div h(u), (1.1) subject to the initial value u(x, 0) = u0(x), (t, x) ∈ R+ × R3. (1.2) Here, γ1, γ2 > 0, and h(u) = (h1(u), h2(u), h3(u)) satisfies the condition hk(u) = O(u2), k = 1, 2, 3. This model is motivated by physical considerations from fluid dynamics. It describes a variety of important physical processes, such as the aggregation of pop- ulations in which u describes the population density [12]. It can also be used in the analysis of a seepage of homogeneous fluids through a fissured rock and the unidirectional propagation of nonlinear dispersive long waves [1, 14]. There are many equations similar to problem (1.1). For instance, the equation ∂tu− k4ut −4u = div h(u), which is (1.1) with γ2 = 1, can be used to describe the nonstationary processes in semiconductors in the presence of sources [9, 10]. Here k∆ut − ut indicates the rate of change in free charge’s density, ∆u indicates the electric current of linear dissipative free charge and div h(u) describes a source of free electron current [9]. Ting, Showalter and Golpala Rao studied the initial-boundary value problem and the Cauchy problem for the linear equation when γ2 = 1 and proved the existence and uniqueness of the solution [6, 13, 15]. Afterwards, considerable attention has 2010 Mathematics Subject Classification. 35A01, 35A22, 35A25. Key words and phrases. Conservation law; dissipation; Cauchy problem; equilibrium state; Green’s function; time-frequency decomposition method; pointwise estimate. c©2020 Texas State University. Submitted February 12, 2020. Published December 22, 2020. 1 2 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 been paid to the study of the nonlinear equation, and the large time behavior of the solutions [7, 8, 21]. Cao, Yin and Wang [2] studied the equation ∂tu− k4ut −4u = up. They focused on the parameter p and sufficiently small initial data. They obtained two critical indices about p and then considered the global existence or the blow up of the solutions. In [16], the authors considered the following equation under the condition 0 ≤ s ≤ 1/2: ut − ∆u (1−∆)s = div h(u). (1.3) They got the global classical solution and long-time behavior for arbitrary large initial data. In [17], Wang proved that in the case s = 1, the solution is global with sufficiently small initial data, but will blow up with some large initial data. Wang and Zhang [20] investigated the problem ∂tu− γ14ut − γ24u+ γ3∆2u = n∑ j=1 hj(u)xj , (1.4) which is what we call the Benjamin-Bona-Mahony (BBM) equation. They obtained ta global solution and the optimal decay estimates with large initial data when γ3 6= 0. In our case, i.e. γ3 = 0, there are some new difficulties. First of all, the condition γ3 6= 0 in (1.4) gives a dissipation term ∆2u, which allows using the energy method to get the L∞ estimate, and it also gives a better decay. Without this term, we need to use some new methods such as the time-frequency decomposition. Moreover, there is no maximum principle like for the viscous Burgers equation, which increases the difficulty. Another motivation for us to consider the solution near the nontrivial equilibrium state is that the equation in our paper actually has some hyperbolic properties which however will vanish if we just consider the trivial equilibrium state. From the main results, we will see from the solution that the phenomenon of a propagating wave appears, and the propagation direction and speed of the wave are decided by the initial data. Obviously, if we only consider the solution near zero, the speed and direction will both be zero and will not be observed. So here, to get the optimal decay estimate and the hyperbolic property of the solution, we first do the pointwise estimate of the Green’s function, then combining it with the variable substitution and Green’s method to obtain the L1 and L∞ bounded estimate. Based on this, we obtain the pointwise estimate of the solution. Since we consider the solution near the equilibrium state u∗, using u−u∗ as the new u, we can rewrite equation (1.1) as ∂tu− γ14ut − γ24u+ 3∑ j=1 bjuxj = div f(u), (1.5) with initial condition u(x, 0) = u0(x)− u∗. (1.6) EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 3 Here, γ1, γ2 > 0, b = (C1u ∗, C2u ∗, C3u ∗) and f(u) = (f1(u), f2(u), f3(u)) satisfies the condition fk(u) = O(u2), (k = 1, 2, 3. The main results of this article read as follows. Theorem 1.1. Suppose that the initial data v0 = u0−u∗ ∈ L1(R3)∩Hs(R3), with s > 1 + [ 3 2 ]. Then, the Cauchy problem (1.1)-(1.2) has a global solution (u− u∗) ∈ L∞(0,∞;Hs(R3)). Theorem 1.2. Assume that the initial data u0 satisfies the conditions in Theorem 1.1, and u is a solution of (1.1)-(1.2) in L∞([1,∞), Hs(R3)) with initial data u0. Then ‖(u− u∗)‖Ḣs(R3) ≤ C(1 + t)− 3 4− s 2 , for any t ≥ 1, where C only depends on the initial data. Theorem 1.3. Assume that the initial data u0 satisfies the conditions in Theorem 1.1, and v0 satisfies |Dβ xv0| = |Dβ x(u0 − u∗)| ≤ C(1 + |x|2)−r, r > 3 2 , with |β| ≤ s− 1. Then the solution satisfies the pointwise estimate |Dα x (u− u∗)| ≤ C(1 + t)− 3+|α| 2 Br(|x− bt|, t). Where Br(|x|, t) is defined by (2.1), t ≥ 1, and |α| ≤ s− 1. From the above results, we see that the solution mainly follows the decay of heat equation and, near the equilibrium state u∗ 6= 0, the equation has some hyperbolic properties with speed b. This article is organized as follows. In Section 2, we first recall some important lemmas that will be used in this paper. In Section 3, we introduce the properties of the Green’s function, mainly focusing on the pointwise estimate and the Lp estimate of the Green’s function. Then in Section 4, using Green’s function and the variable substitution, we obtain the Lp boundedness of the solution u to equation (1.5) with initial value (1.6). In Section 5, we obtain the optimal decay estimates of the solution in Ḣs by using the time-frequency decomposition method. And, as a corollary of Theorem 1.2, the optimal L∞ convergence rate can be obtained easily. Finally, in Section 6, based on the Lp boundedness and the decay of the solution, the pointwise estimate of the solution is established. 2. Preliminaries In this section, we first introduce some notation, and then give some lemmas which will be used later. For a multi-index α = (α1, · · · , αn), we write Dα x = ∂αnxn · · · ∂ α2 x2 ∂α1 x1 and |α| =∑n i=1 |αi|. As usual, the Fourier transform of f(t, x) with respect to the variable x ∈ Rn is f̂(t, ξ) = (F(f))(t, ξ) = ∫ Rn f(t, x)e−ix·ξdx, and the inverse Fourier transform is f(t, x) = (F−1f̂)(t, x) = (2π)−n ∫ Rn f̂(t, ξ)eix·ξdξ. 4 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Here, n denotes the space dimension. The space W s,p(Rn), with s a positive integer and p ∈ [1,+∞], is the usual Sobolev space with the norm ‖f‖W s,p(Rn) = s∑ |α|=0 ‖Dα xf‖Lp(Rn). In particular, when p = 2, W s,2(Rn) = Hs(Rn). We denote by Ẇ s,p(Rn) the Sobolev space equipped with the norm ‖ · ‖Ẇ s,p(Rn) = ‖Λs · ‖Lp(Rn), where Λs is defined by Λ̂sf(ξ) = |ξ|sf̂(ξ). When p = 2, Ẇ s,2(Rn) = Ḣs(Rn) is the homogeneous Sobolev space. Next, we recall some useful lemmas. The first lemma gives some estimate of f(u), its proof can be found in [11]. Lemma 2.1. Assume that f(u) is smooth enough and f(u) = O(|u|1+α0) when |u| ≤ ν0, where α0 ≥ 1 is an integer. For each integer s ≥ 0, if u satisfies ‖u‖L∞(Rn) ≤ ν0, then ‖f(u)‖Ẇ s,r(Rn) ≤ C‖u‖Ẇ s,q(Rn)‖u‖Lp(Rn)‖u‖α0−1 L∞(Rn), ‖f(u)‖L1(Rn) ≤ C‖u‖2L2(Rn)‖u‖ α0−1 L∞(Rn), where C is a constant and only depends on s and ν0, and 1 r = 1 p + 1 q , with 1 ≤ p, q, r ≤ ∞. The following two lemmas are very useful for obtaining the pointwise estimate of the solutions. Their proofs can be found in [19]. Lemma 2.2. If f̂(ξ, t) has a compact support about ξ, and there exists b > 0 such that |Dβ ξ ξ αf̂(ξ, t)| ≤ C(|ξ|(|α|+k−|β|)+ + |ξ|(|α|+k)t |β| 2 )(1 + t|ξ|2) m e−b|ξ| 2t, for all |β| ≤ 2N , with N a positive integer, then |Dα xf(x, t)| ≤ CN (1 + t)−(|α|+k+n)/2BN (t, |x|), where k and m are positive integers, and BN (t, |x|) = ( 1 + |x|2 1 + t )−N , (a)+ = { a, a ≥ 0, 0, a < 0. (2.1) Lemma 2.3. If supp f̂(ξ) ⊂ OR =: {ξ, |ξ| > R}, and f̂(ξ) satisfies |Dβ ξ f̂(ξ)| ≤ C|ξ|−1−|β|, then there exist distributions f1(x), f2(x) and a constant C0 such that f(x) = f1(x) + f2(x) + C0δ(x), where δ(x) is the Dirac function. Furthermore, for positive integers N with 2N > 3+ |α|, we have |Dα xf1(x)| ≤ C(1+ |x|2)−N , ‖f2‖L1 ≤ C and supp f2(x) ⊂ {x; |x| < 2ε0}, with ε0 sufficiently small. EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 5 Lemma 2.4 ([18]). For |y| ≤ M , t ≥ 4M2 and N > 0, there exists CN > 0 such that ( 1 + |y − x|2 1 + t )−N ≤ CN ( 1 + |x|2 1 + t )−N . Finally, note that for any g(u) ∈ Lp(Rn) and p ≥ 1, we have (1− γ1∆)−1g(u) = Kγ1(·) ∗ g(u(·, t)), where Kγ1(x) = (4π)−n/2 ∫ t 0 e−γ1s− |x|2 4s s−n/2ds, ‖Kγ1‖L1(Rn) = γ1. Thus, we have ‖(1− γ1∆)−1g(u)‖Lp(Rn) ≤ C‖Kγ1‖L1(Rn)‖g(u(·))‖Lp(Rn) ≤ C‖g(u(·))‖Lp(Rn). (2.2) 3. Existence of a local solution In this section, we construct a convergent Cauchy sequence to obtain the local solution. Let vm(x, t) be the solution of the Cauchy problem ∂tv m − γ14vmt − γ24vm = div h(vm−1), vm(x, 0) = v0(x), (3.1) where m ≥ 1, v0(x, t) = 0 and v0(x) ∈ Hs(R3). For any given integer s ≥ 1 + [3/2], define the function space X = {v(x, t) : ‖v‖X < E}, where ‖v‖X = sup0≤t≤T0 ‖v‖Hs , T0 is an undetermined constant and E = C0v0‖v‖Hs , with C0 > 2. One readily checks that X is a complete metric space. Next we prove that the function sequence vm(x, t) converges in the space X. Lemma 3.1. For any m ≥ 1, there exists a sufficiently small constant T0, such that vm(x, t) ∈ X. Proof. We use induction. For m = 1, we know that ∂tv 1 − γ1∆v1 t − γ2∆v1 = div h(v0). Taking derivatives with respect to x, α times, on both sides of the above equation, where |α| ≤ s− 1, we have Dα xv 1 t − γ1D α x∆v1 t − γ2D α x∆v1 = 0. Multiplying Dα xv 1 on both sides, and integrating with respect to x and t on R3 × [0, t], we have ‖v1‖2Hs−1 + γ1‖∇v1‖2Hs−1 + 2γ2 ∫ t 0 ‖∇v1‖2Hs−1dτ = ‖v0‖2Hs−1 + γ1‖∇v0‖2Hs−1 . Since γ1 > 0 is a constant, it implies that sup 0≤t≤T0 ‖v1‖Hs−1 ≤ ‖v0‖Hs . Thus for T0 > 0, we have v1(x, t) ∈ X. 6 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Assume that there is a sufficiently small T0 such that for each j ≤ m, vj(x, t) ∈ X. We shall show that vm+1(x, t) ∈ X. In fact, from (3.1) we have 1 2 d dt ‖Dα xv m+1‖2L2 + γ1 2 d dt ‖∇(Dα xv m+1)‖2L2 + γ2‖∇(Dα xv m+1)‖2L2 = ∫ (Dα xv m+1)Ḋα x div h(vm)dx ≤ C‖∇(Dα xv m+1)‖2L2‖vm‖L∞‖Dα xv m‖2L2 ≤ C‖∇(Dα xv m+1)‖2L2‖vm‖Hs‖Dα xv m‖2L2 ≤ C‖vm|2Hs‖Dα xv m‖2L2 + ε‖∇(Dα xv m+1)‖2L2 . (3.2) Here, we have used the inequalities ‖vm‖L∞ ≤ C‖vm‖Hs and s ≥ 1 + [ 2 3 ]. In- tegrating with respect to t and taking the summation of |α| from 0 to s − 1, we have ‖vm+1‖2Hs−1 + γ1‖∇vm+1‖2Hs−1 + γ2 ∫ t 0 ‖∇vm+1‖2Hs−1dτ ≤ ∫ t 0 ‖vm|2Hs‖vm‖2Hs−1dτ + ‖v0‖2Hs−1 + γ1‖∇v0‖2Hs−1 . (3.3) By (3.3), we have ‖vm+1‖2Hs−1 + γ1‖∇vm+1‖2Hs−1 ≤ CE4T0 + ‖v0‖2Hs−1 + γ1‖∇v0‖2Hs−1 . Since γ1 > 0 is an arbitrary constant, ‖vm+1‖2Hs ≤ CE4T0 + ‖v0‖2Hs . Thus for T0 small enough, we obtain vm+1(x, t) ∈ X. � Lemma 3.2. There is a sufficiently small constant T0, such that vm(x, t) is a Cauchy sequence in the complete metric space X. Proof. We are going to show that for some 0 < κ < 1, ‖vm+1 − vm‖X ≤ κ‖vm − vm+1‖X. Similar to the proof of (3.2), we have ‖vm+1 − vm‖X + γ1‖∇(vm+1 − vm)‖2Hs + γ2 ∫ t 0 ‖∇(vm+1 − vm)‖2Hsdτ ≤ ∫ t 0 ‖vm+1 − vm‖2Hs(‖vm‖2Hs−1 + ‖vm‖2Hs)dτ Since vm(x, t) ∈ X, we have sup0≤t≤T0 ‖vm‖Hs ≤ E. Thus, sup 0≤t≤T0 ‖vm+1 − vm‖Hs ≤ (CE2T0)1/2 sup 0≤t≤T0 ‖vm − vm−1‖Hs . Choosing sufficiently small T0 such that CE2T0 ≤ 1 4 , we obtain sup 0≤t≤T0 ‖vm+1 − vm‖Hs ≤ 1 2 sup 0≤t≤T0 ‖vm − vm−1‖Hs . Thus vm(x, t) is a Cauchy sequence in X. � Since X is a complete metric space, combining Lemmas 3.1 and 3.2, the limit function v(x, t) ∈ X satisfies the Cauchy problem (3.1). Hence we obtain the existence of a local solution. EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 7 4. Lp decay estimate of Green’s function In this section, we consider the behavior of the solution to the linear form of (1.5). Consider the following Cauchy problem ∂tG− γ14Gt − γ24G+ 2 3∑ j=1 bj ·Gxj = 0, x ∈ R3, t > 0, G ∣∣ t=0 = δ(x). (4.1) Here, b = (b1, b2, b3), bi = ciu ∗, δ(x) is the Dirac function. G is called Green’s function. Let G(t, x) be the inverse Fourier transform corresponding to Ĝ(t, ξ). Taking the Fourier transform with respect to x and solving the ordinary differential equation directly, we obtain Ĝ(t, ξ) = eµ(ξ)t+η(ξ)t, with µ(ξ) = − γ2|ξ|2 1 + γ1|ξ|2 , η(ξ) = − √ −1b · ξ 1 + γ1|ξ|2 . Note that the solution of the Cauchy problem (1.5) with initial data (1.6) has the integral representation u = G ∗ u0 + ∫ t 0 G(t− τ, ·) ∗ div 1− γ1∆ f(u)(τ, ·)dτ. Next, we use the frequency decomposition to get an estimate for the Green’s func- tion G. We divide the solution into the low frequency part and the high frequency part and discuss them separately to obtain the decay property of the solution. Let χ1(ξ) = { 1, |ξ| ≤ ε, 0, |ξ| > 2ε, χ3(ξ) = { 1, |ξ| ≥ R, 0, |ξ| < R− 1, χ2(ξ) = 1− χ1(ξ)− χ3(ξ) be smooth cut-off functions in C∞(R3), where ε and R are positive constants satis- fying 2ε < R−1. We define three pseudo-differential operators χ1(D), χ2(D), χ3(D) with the symbols χ1(ξ), χ2(ξ), χ3(ξ) respectively and set Ĝi(t, ξ) = χi(ξ)Ĝ(t, ξ), i = 1, 2, 3. Now we estimate the three parts separately. Using Lemma 2.2, we have the following estimate on G1(t, x). Proposition 4.1. For sufficiently small ε, there exists a constant CN > 0 such that |Dα xG1(t, x)| ≤ CN t− 3+|α| 2 BN (t, |x− bt|). Proof. For ξ sufficiently small, the Taylor expansion gives µ(ξ) + η(ξ) = −(γ2|ξ|2 + √ −1b · ξ) 1 1 + γ1|ξ|2 = −(γ2|ξ|2 + √ −1b · ξ) +O(|ξ|3). Therefore, Ĝ(t, ξ) = e−γ2|ξ| 2t · e− √ −1b·ξt(1 +O(|ξ|3)t). 8 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Now we take the Fourier transform and set Ĝ1(t, ξ) = χ1(ξ)e−γ2|ξ| 2t(1 +O(|ξ|3)t)e− √ −1b·ξ =: Ĥ(t, ξ)e− √ −1b·ξ. By properties of the Fourier transform, we have G1(t, ξ) = H(t, x) ∗ F−1(e− √ −1b·ξ) = H(t, x− bt), Dα xG1(t, ξ) = H(t, x) ∗Dα xF−1(e− √ −1b·ξ) = Dα xH(t, x− bt). Thus it suffices to show that |Dα xH(t, x)| ≤ CN t− 3+|α| 2 BN (t, |x|). Since Ĥ(t, ξ) is smooth in the variable ξ near |ξ| = 0, for |β| ≤ 2N , we obtain |Dβ ξ (ξαĤ(t, ξ))| ≤ C(|ξ|(|α|−|β|)+ + |ξ||α|t |β| 2 )(1 + t|ξ|2) |β| 2 +1 e−γ2|ξ| 2t. Thus, by Lemma 2.2, we have |Dα xH(t, x)| ≤ CN (1 + t)− 3+|α| 2 BN (t, |x|). This completes the proof. � Next, we consider G2(t, x). Proposition 4.2. For fixed ε and R, there exist positive numbers m0 and C such that |Dα xG2(t, x)| ≤ Ce− t 2m0BN (t, |x|). Proof. Choose m > 1/(2ε). When ε ≤ |ξ| ≤ R, we have Re(µ(ξ) + η(ξ)) ≤ − 1 2m . This implies |Ĝ2| = |χ2(ξ)eµ(ξ)t| ≤ Ce− t 2m . (4.2) Thus, |G2(t, x)| ≤ C ∣∣ ∫ R3 eix·ξĜ2(t, ξ)dξ ∣∣ ≤ Ce− t 2m . (4.3) Next, we give an estimate for xβG2(t, x) using induction on β. Assume that for any |β| ≤ l − 1, it holds |Dβ ξ Ĝ2(t, ξ)| ≤ Ct|β|e− t 2m , (4.4) for |β| = 0 by (4.2). Taking the Fourier transform of (4.1) with respect to x and then multiplying by χ2(ξ) we have ∂tĜ2(t, ξ)− (µ(ξ) + η(ξ))Ĝ2(t, ξ) = 0, Ĝ2(0, ξ) = χ2(ξ). (4.5) Applying the operator Dβ ξ on (4.5), we obtain ∂tD β ξ Ĝ2(t, ξ)− (µ(ξ) + η(ξ))Dβ ξ Ĝ2(t, ξ) = F (ξ), Ĝ2(0, ξ) = a0, EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 9 where a0 is a polynomial of |ξ|, and F (ξ) = ∑ β1+β2=β,|β1|6=0 β! β1!β2! (Dβ1 ξ (µ(ξ) + η(ξ)))Dβ2 ξ Ĝ2(t, ξ). Then for |β| = l, by the ODE theory, we have Dβ ξ Ĝ2(t, ξ) = a0Ĝ(t, ξ) + ∫ t 0 Ĝ(t− s, ξ)F (ξ)ds. Using the induction hypothesis, we obtain |Dβ ξ Ĝ2(t, ξ)|ε≤|ξ|≤R ≤ Ce− t 2m + C ∫ t 0 e− t−s 2m t|β|−1e− s 2m ds ≤ Ct|β|e− t 2m , which implies that (4.4) is also valid for |β| = l. Then for 1 ≤ |β| ≤ l, we have |xβDα xG2(t, x)| ≤ C| ∫ R3 e √ −1xξDβ ξ (ξαĜ2(t, ξ))dξ| ≤ Ce− t 2m ∫ ε≤|ξ|≤R (|ξ||α| + |ξ|(|α|−|β|)+)t|β|dξ ≤ Ct|β|e− t 2m ≤ Ct |β| 2 e− t 2m0 , m0 < m. (4.6) Using (4.3) when |x|2 ≤ t and using (4.6) when |x|2 > t, we obtain (|β| = 2N) |Dα xG2(t, x)| ≤ Ce− t 2m0 min{1, tN |x|2N }. Since 1 + |x|2 t ≤ { 2, |x|2 ≤ t, 2 |x| 2 t , |x| 2 ≥ t, we have |Dα xG2(t, x)| ≤ Ce− t 2m0BN (t, |x|), which completes the proof. � Finally, we consider G3(t, x) by using Lemma 2.3. Proposition 4.3. For sufficiently large R, there exist positive numbers C0 and C such that |Dα x (G3(t, x)−Gfα)| ≤ Ce−C0tBN (t, |x|). Here Gfα is the distribution of the form Gfα = χ3(D) [ e−γ2t/γ1 ( δ(x) + [ |α|+3 2 ]∑ j=1 pj(t)∆ −j+ |α|2 )] , (4.7) where pj(t)s are polynomials of degree j. Proof. Since R is large enough, |Dα xG3| ≤ Ce−C1teµ(ξ)t. We set ρ = 1 |ξ|2 , h(ρ) = e − γ2t |ρ|+γ1 . 10 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Then, it is easy to see that h(ρ) = e−γ2t/γ1(1 +O(|ρ|)), |ρ| → 0. Thus, eµ(ξ)t = χ3(ξ)e−γ2t/γ1 ( 1 + [ |α|+3 2 ]∑ j=1 pj(t)(|ξ|−2)j ) + R̂(t, ξ). Using Lemma 2.3, we obtain | |ξ|αR̂(t, ξ)| ≤ Ce−γ2T/γ1 +∞∑ j=[ |α|+3 2 ]+1 pj(t)(|ξ|−2j), |Dα xR(t, x)| ≤ Ce−γ2t/γ1(1 + |x|2)−N , which implies |xβDα xR(t, x)| ≤ Ce−γ2t/γ1 ∫ |ξ|>R |ξ|−2( |α|+3 2 )−|β|dξ ≤ Ce−γ2t/γ1 . Hence, |Dα x (G3 −Gfα)| ≤ Ce−γ2t/γ1BN (t, |x|). � In conclusion, we obtain the following estimate for the regular part of G. Theorem 4.4. Assume that G is the solution of the linear form of equation (1.5). Then |Dα x (G−Gfα)| ≤ Ct− 3+|α| 2 BN (t, |x− bt|), with Gfα defined by (4.7). Proof. Since |Dα x (G−Gfα)(t, x)| ≤ |Dα xG1(t, x)|+ |Dα xG2(t, x)|+ |Dα x (G3 −Gfα)(t, x)|, the desired estimate follows from Propositions 4.1, 4.2 and 4.3. � Noting that ∫ Rn BN (t, |x|)dx ≤ C(1 + t)3/2, we can use the Hausdorff-Young’s inequality to obtain the following theorems about the Green’s function, which are essential for the proof of the existence and the decay estimate of the Cauchy problem (1.5)-(1.6). Theorem 4.5. For any multi-index α and p ∈ [1,∞], we have ‖Dα x (G−Gfα)‖Lp(R3) ≤ Ct− 3 2 (1− 1 p )− |α|2 . Theorem 4.6. For all ϕ and N ≥ 0 integer, we have ‖(G−Gfα) ∗ ϕ‖WN,∞(R3) ≤ C0(1 + t)−3/2‖ϕ‖WN+4,1(R3), ‖(G−Gfα) ∗ ϕ‖WN,1(R3) ≤ ‖ϕ‖WN,1(R3). Theorem 4.7. For f ∈ Lp(R3) with p ∈ [1,∞], we have ‖G ∗ f‖Lp(R3) ≤ Cp‖f‖Lp(R3). Here Cp depends only on p. EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 11 5. Lp bound estimate of solutions Now we prove an Lp (p ∈ [0,∞]) estimate of the solution u of (1.5)-(1.6). First, by the fundamental energy estimate, we have d dt (‖u‖2L2 + γ1‖∇u‖2L2) + 2γ2‖∇u‖2L2 = 0. (5.1) Integrating with respect to t, we obtain (‖u‖2L2 + γ1‖∇u‖2L2) + 2γ2 ∫ t 0 ‖∇u‖2L2dτ = ‖u0‖2L2 + γ1‖∇u0‖2L2 . Therefore, we have the following basic bounds for u: ‖u‖L2 ≤ C, ‖∇u‖L2 ≤ C, ∫ t 0 ‖∇u(τ, ·)‖2L2dτ ≤ C. 5.1. L1 bounds. Let χ0(η) = { 1, |η| ≤ 1, 0, |η| > 2, be a smooth cut-off function in C∞(R3). Define the time-frequency cut-off oper- ator χ(t,D) with symbol χ(t, ξ) = χ0 ( 1+t µ |ξ| 2 ) , where µ is a constant and µ > max{ 3 2γ1 , 3 2γ2 }. A solution u of (1.5) can be decomposed it into two parts: the low frequency part uL and the high frequency part uH , where uL(t, x) = χ(t,D)u(t, x) and uH(t, x) = (1− χ(t,D))u(t, x). Lemma 5.1. Assume that u0 ∈ L1(R3). Then ‖uL‖L2 ≤ C(1 + t)−3/4, where C is a positive constant depending only on u0. Proof. Using Green’s function, we have uL = χ(t,D)(G ∗ u0) + ∫ t 0 χ(t,D) (G(t− τ, ·) 1− γ1∆ ∗ div f(u) ) dτ. Using Minkowski’s inequality, we obtain ‖uL‖L2 = ‖χ(t,D)(G ∗ u0)‖L2 + (∫ t 0 ∥∥χ(t,D) (G(t− τ, ·) 1− γ1∆ ∗ div f(u) ) ) ∥∥2 L2dτ )1/2 = S1 + S2. (5.2) For S1, by Hausdorff-Young’s inequality and Theorem 4.4, we have S1 ≤ ‖χ(t,D)G‖L2 · ‖u0‖L1 ≤ C(1 + t)−3/4. (5.3) 12 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 For S2, by Plancherel’s theorem, we obtain |S2|2 = ∫ t 0 ∥∥χ(t,D) (G(t− τ, ·) 1− γ1∆ ∗ div f(u) )∥∥2 L2dτ = ∫ t 0 ∥∥χ(t, ξ) Ĝ 1 + γ1|ξ|2 |ξ|f̂(u) ∥∥2 L2dτ ≤ C ∫ t 0 ∫ R3 ξ χ2(t, ξ)|ξ|2 |f̂(u)|2 (1 + γ1|ξ|2) dξdτ ≤ C ∫ t 0 ∥∥ f̂(u) 1 + γ1|ξ|2 ∥∥2 L∞ ∫ R3 ξ χ2(t, ξ)|ξ|2dξdτ ≤ C ∫ t 0 ∥∥ f(u) 1− γ1∆ ∥∥2 L1(1 + t)− 3 2−1dτ ≤ C ∫ t 0 ‖f(u)‖2L1(1 + t)− 3 2−1dτ ≤ C(1 + t)−3/2. (5.4) Hence, by (5.2), (5.3) and (5.4), we obtain the desired estimate. � From the decay estimate of ‖uL‖L2 , we have the following interesting relation between the decay rates of uL and u. Lemma 5.2. If u0 ∈ H1(R3) and ‖uL‖L2 ≤ C(1 + t)−σ, then ‖u‖2L2 + γ1‖∇u‖2L2 ≤ C(1 + t)−2σ, where C is a positive constant depending only on u0. Proof. We already have the basic energy estimate (5.1), that is d dt (‖u‖2L2 + γ1‖∇u‖2L2) + 2γ2‖∇u‖2L2 = 0. Set ε2(t) = µ/(1 + t). Then ‖∇u‖L2 ≥ ∫ |ξ|>ε(t) |ξ|2|û|2dξ ≥ ε2(t) ∫ |ξ|>ε(t) |û|2dξ ≥ ε2(t) ( ‖u‖2L2 − ∫ |ξ|≤ε(t) |û|2dξ ) . From the above inequality, we deduce that d dt (‖u‖2L2 + γ1‖∇u‖2L2) + γ2µ 1 + t ‖u‖2L2 + γ2‖∇u‖2L2 ≤ ε2(t) ∫ |ξ|≤ε(t) γ2|û|2dξ ≤ Cε2(t)‖uL‖2L2 . (5.5) By the assumption, (5.5) becomes d dt (‖u‖2L2 + γ1‖∇u‖2L2) + C0 µ 1 + t (‖u‖2L2 + γ1‖∇u‖2L2) ≤ d dt (‖u‖2L2 + γ1‖∇u‖2L2) + γ2µ 1 + t ‖u‖2L2 + γ2‖∇u‖2L2 EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 13 ≤ C(1 + t)−2σ−1. Multiplying the above inequality by e ∫ t 0 C0µ 1+τ dτ = (1 + t)C0µ and integrating from 0 to t, we obtain (1 + t)C0µ(‖u‖2L2 + γ1‖∇u‖2L2) ≤ ‖u0‖2L2 + γ1‖∇u0‖2L2 + C(1 + t)C0µ−2σ. Thus ‖u‖2L2 + γ1‖∇u‖2L2 ≤ (‖u0‖L2 + γ1‖∇u0‖2L2)(1 + t)−C0µ + C(1 + t)−2σ. Since C0µ > 2σ, we have ‖u‖2L2 + γ1‖∇u‖2L2 ≤ C(1 + t)−2σ. � Remark 5.3. Combining Lemmas 5.2 with 5.1, we obtain ‖u‖2L2 + γ1‖∇u‖2L2 ≤ C(1 + t)−3/2. Proposition 5.4. If u0 ∈ L1(R3) ∩H1(R3), then we have ‖u‖L1 ≤ C, where C is a positive constant depending only on u0. Proof. Using Green’s function, we have ‖u‖L1 ≤ ‖G ∗ u0‖L1 + ∥∥∫ t 0 G(t− τ, ·) 1− γ1∆ ∗ div f(u)dτ ∥∥ L1 ≤ ‖G ∗ u0‖L1 + ∫ t 0 ‖G(t− τ, ·) ∗ div f(u)‖L1dτ = Q1 +Q2. (5.6) For Q1, by Theorem 4.7, we have Q1 ≤ C‖u0‖L1 ≤ C. (5.7) For Q2, notice that ‖f(u)‖L1 ≤ C‖u‖2L2 ≤ C(1 + t)−3/2. Again, by Theorem 4.7, we have Q2 = ∫ t 0 ‖G(t− τ, ·) ∗ div f(u)‖L1dτ = ∫ t 0 ‖(G−Gf1 +Gf1) ∗ div f(u)‖L1dτ ≤ ∫ t 0 ‖(G−Gf1) ∗ div f(u)‖L1dτ + ∫ t 0 ‖Gf1 ∗ div f(u)‖L1dτ = Q2,1 +Q2,2. (5.8) 14 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 For Q2,1, by Young’s inequality, we have Q2,1 = ∫ t 0 ‖(G−Gf1) ∗ div f(u)‖L1dτ = ∫ t 0 ‖∇(G−Gf1) ∗ f(u)‖L1dτ ≤ C ∫ t 0 ‖∇(G−Gf1)‖L1‖f(u)‖L1dτ ≤ C ∫ t 0 (1 + t− τ)− 1 2 (1 + τ)−3/2dτ ≤ C. (5.9) For Q2,2, we have Q2,2 = ∫ t 0 ‖Gf1 ∗ div f(u)‖L1dτ ≤ ∫ t 0 e− γ2 γ1 (t−τ)‖∇u‖L2‖∇u‖L2dτ ≤ ∫ t 0 e− γ2 γ1 (t−τ)(1 + τ)−3/2dτ ≤ C. (5.10) Now (5.6), (5.7), (5.8), (5.9) and (5.10) imply ‖u‖L1 ≤ C, as desired. � 5.2. L∞ bounds. We now estimate ‖u‖L∞ . Unlike the method in [20], the energy method is not enough. However, using the variable substitution and Green’s func- tion method, we can first obtain the bounded estimate of ‖u‖H2 and then apply the embedding theorem to get the L∞ bounded estimate. Set w = (1− γ1∆)u, w0 = (1− γ1∆)u0. Then (1.5) can be rewritten as ∂tw − γ2∆ 1− γ1∆ w + b γ2∇ 1− γ1∆ w = div f(u). By Duhamel Principle, we know that the solution will be of the form w = G ∗ w0 + ∫ t 0 G(t− τ, ·) ∗ div f(u)(τ, ·)dτ. (5.11) Now we use Green’s function to estimate w. Proposition 5.5. Suppose that u0 ∈ L1(R3) ∩Hs(R3), s ≥ 2. Then we have ‖w‖L2 ≤ C, where C is a positive constant depending only on u0. EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 15 Proof. Applying Theorem 4.7 to (5.11) and using the Hölder inequality, we obtain ‖w‖L3/2 = ‖G ∗ w0‖L3/2 + ‖ ∫ t 0 G(t− τ, ·) ∗ div f(u)(τ, ·)dτ‖L3/2 ≤ ‖G ∗ w0‖L3/2 + ∫ t 0 ‖G(t− τ, ·) ∗ div f(u)‖L3/2dτ ≤ C‖w0‖L3/2 + C ∫ t 0 ‖u · ∇u‖L3/2dτ ≤ C + C ∫ t 0 ‖u‖L6‖∇u‖L2dτ ≤ C + C ∫ t 0 ‖∇u‖2L2dτ ≤ C. (5.12) Note that we have used the Sobolev inequality ‖u‖L6(R3) ≤ C‖∇u‖L2(R3) above. Combining (5.12) with (2.2), we obtain ‖u‖L3/2 = ‖(1− γ1∆)−1w‖L3/2 ≤ C. Thus ‖∆u‖L3/2 = ‖u+ w‖L3/2 ≤ ‖u‖L3/2 + ‖w‖L3/2 ≤ C. Combining these with the Green’s function again, we obtain ‖w‖L2 = ‖G ∗ w0‖L2 + ‖ ∫ t 0 G(t− τ, ·) ∗ div f(u)(τ, ·)dτ‖L2 ≤ C‖w0‖L2 + ∫ t 0 ‖(G−Gf1 +Gf1) ∗ div f(u)(τ, ·)‖L2dτ ≤ C + ∫ t 0 (‖(G−Gf1) ∗ div f(u)‖L2 + ‖Gf1 ∗ div f(u)‖L2)dτ ≤ C + I1 + I2. (5.13) For I1, we have I1 = ∫ t 0 ‖(G−Gf1) ∗ div f(u)‖L2dτ ≤ ∫ t 0 ‖div(G−Gf1)‖L2‖f(u)‖L1dτ ≤ C ∫ t 0 (1 + t− τ)− 3 2 (1− 1 2 )− 1 2 ‖u‖2L2dτ ≤ C. (5.14) For I2, we have I2 = ∫ t 0 ‖Gf1 ∗ div f(u)‖L2dτ ≤ ∫ t 0 e− γ2 γ1 (t−τ)‖u‖L6‖∇u‖L3dτ ≤ ∫ t 0 e− γ2 γ1 (t−τ)‖∇u‖L2‖∆u‖ L 3 2 dτ ≤ C. (5.15) In the last inequality we used that ‖∇u‖L3(R3) ≤ C‖∆u‖L3/2(R3). From (5.13), (5.14) and (5.15), we obtain ‖w‖L2 ≤ C + I1 + I2 ≤ C. � 16 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Remark 5.6. By Proposition 5.5, we can easily obtain ‖u‖H2(R)3 ≤ C. Then by the Sobolev embedding theorem H2(R3) ↪→ L∞(R3), we can get the L∞ boundedness of u, ‖u‖L∞(R3) ≤ C. 5.3. Lp bounds. Since we already have L1 and L∞ bounds, by the interpolation inequality we easily get ‖u‖Lp(R3) ≤ C, p ∈ [1,∞]. Here C is a positive constant depending only on the initial data u0. 5.4. Hs bounds. With the L∞ boundedness, we can improve the regularity of u as follows. Lemma 5.7. If u0 ∈ Hs(R3), 3 ≤ s ∈ Z, then ‖u‖Hs ≤ C, where C is a positive constant depending only on u0. Proof. Multiplying Λ2ju to both sides of (1.5) and integrating with respect to x, we obtain d dt (‖u‖2 Ḣj + γ1‖u‖2Ḣj+1) + 2γ2‖u‖2Ḣj = −2 ∫ R3 Λ2judiv f(u)dx. By Hölder’s inequality, we have∣∣2 ∫ R3 Λ2judiv f(u)dx ∣∣ ≤ γ2‖u‖2Ḣj + C‖f(u)‖2 Ḣj ≤ γ2‖u‖2Ḣj + Cjγ2‖u‖2Ḣj . Thus, for any j ≥ 1, we obtain d dt (‖u‖2 Ḣj + γ1‖u‖2Ḣj+1) + γ2‖u‖2Ḣj ≤ Cjγ2‖u‖2Ḣj . By summation, we have d dt s∑ j=0 Cs−j(‖u‖2 Ḣj +γ1‖u‖2Ḣj+1)+ s∑ j=0 Cs−jγ2‖u‖2Ḣj ≤ s∑ j=0 (j+1)Cs−j+1Cjγ2‖u‖2Ḣj . One readily checks that this implies d dt s∑ j=0 Cs−j(‖u‖2 Ḣj + γ1‖u‖2Ḣj+1) ≤ 0. Integrating the above inequality with respect to t, we obtain s∑ j=0 Cs−j(‖u‖2 Ḣj + γ1‖u‖2Ḣj+1) ≤ s∑ j=0 Cs−j(‖u0‖2Ḣj + γ1‖u0‖2Ḣj+1). Then, it follows that ‖u‖Hs ≤ C. � From the Hs boundedness and the existence of local solutions, we obtain the existence of global solutions to (1.5), by the continuity method. Moreover, (u− u∗) ∈ L∞(0,∞;Hs(R3)), s ≥ 1 + [3 2 ] . EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 17 6. Decay estimate in Ḣs and L∞ In this section, we establish the optimal decay rates of the solution u in the homogeneous Sobolev spaces. 6.1. Decay rate of the low frequency part in Ḣs. Based on the boundedness of ‖u‖L1 , Plancherel’s theorem, and Hausdorff-Young’s inequality, we can directly obtain the following estimate for the low frequency part, ‖ΛsuL‖L2 = ‖χ(t,D)Λsu‖L2 = ‖χ(t, ξ)|ξ|sû‖L2 ≤ C ∥∥χ0 (1 + t µ |ξ|2 ) |ξ|s ∥∥ L2‖û‖L∞ ≤ C‖u‖L1 ∥∥χ0 (1 + t µ |ξ|2 ) |ξ|s ∥∥ L2 ≤ C(1 + t)− 3 4− s 2 . (6.1) Here, the constant C depends on the choice of µ, which is the same as in the last section. 6.2. Decay rate of the high frequency part in Ḣs. According to the definition of uH , uH satisfies the equation (uH)t − γ1∆(uH)t − γ2∆uH + 2b · ∇uH = div(f(u))H − χt(t,D)u+ γ1χt(t,D)∆u. (6.2) Lemma 6.1. If u0 ∈ H1(R3), then we have the estimate∫ t 0 (1 + t)C0µ‖u‖Ḣ1dτ ≤ C(1 + t)C0µ− 3 2 . Proof. As in Lemma 5.2, using (5.1), we obtain d dt (‖u‖2L2 + γ1‖∇u‖2L2) + γ2‖∇u‖2L2 = −γ2‖∇u‖2L2 ≤ −ε2(t)γ2 ( ‖u‖2L2 − ∫ |ξ|≤ε(t) |û|2dξ ) . This leads to d dt (‖u‖2L2 + γ1‖∇u‖2L2) + γ2µ 1 + t ‖u‖2L2 + γ2‖∇u‖2L2 ≤ ε2(t) ∫ |ξ|≤ε(t) γ1û 2dξ ≤ Cε2(t)‖uL‖2L2 ≤ C(1 + t)− 3 2−1. The last inequality uses (6.1). Therefore, d dt (‖u‖2L2 + γ1‖∇u‖2L2) + C0µ 1 + t (‖u‖2L2 + γ1‖∇u‖2L2) + C1‖∇u‖2L2 ≤ d dt (‖u‖2L2 + γ1‖∇u‖2L2) + γ2µ 1 + t ‖u‖2L2 + γ2‖∇u‖2L2 ≤ C(1 + t)− 3 2−1. 18 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Multiplying the inequality above by e ∫ t 0 C0µ 1+τ dτ = (1 + t)C0µ and integrating from 0 to t, we obtain (1 + t)C0µ(‖u‖2L2 + γ1‖∇u‖2L2) + C1 ∫ t 0 (1 + t)C0µ‖∇u‖2L2dτ ≤ ‖u0‖2L2 + γ1‖∇u0‖2L2 + C ∫ t 0 (1 + τ)C0µ− 3 2−1dτ ≤ C(1 + t)C0µ− 3 2 . This completes the proof. � The next result gives the optimal decay estimate for ‖uH‖Ḣs . Theorem 6.2. If u0 ∈ L1(R3)∩Hs(R3) with s ≥ 1 + [ 3 2 ] a given integer, and u is a solution of (1.5) in L∞(0,∞;Hs(R3)) with initial data u0, then ‖uH‖Ḣs ≤ C(1 + t)− 3 4− s 2 , for any t ≥ 1, where C only depends on the initial data u0. Proof. Multiplying (6.2) by Λ2suH and integrating it in x, we obtain 1 2 d dt (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) + γ2‖uH‖2Ḣs+1 − 2 ∫ R3 Λ2sb · uH∇uHdx = ∫ R3 Λ2suH div(f(u))Hdx− ∫ R3 ûûH |ξ|2s∂tχ(t, ξ)dξ + γ1 ∫ R3 ûûH |ξ|2s+2∂tχ(t, ξ)dξ = R1 +R2 +R3. (6.3) For R1, by Hölder’s inequality and Lemma 2.1, we have |R1| = ∣∣ ∫ R3 D(u2)HD 2suHdx ∣∣ = ∣∣ ∫ R3 (iξ)(û2)H |ξ|2sûHdξ ∣∣ ≤ ∥∥|ξ|s∣∣f̂(u)H ∣∣ · |ξ|s+1û ∥∥ L1 ≤ C‖f(u)H‖Ḣs‖u‖Ḣs+1 ≤ C(‖u‖L∞‖u‖Ḣs)‖u‖Ḣs+1 ≤ C‖u‖Ḣs‖u‖Ḣs+1 . By the Galgliardo-Nirenberg-Sobolev inequality, we have ‖u‖Ḣs ≤ C‖u‖ s−1 s Ḣs+1 ‖u‖1/s Ḣ1 . Then, using the Young’s inequality, we obtain |R1| ≤ C‖u‖ s−1 s +1 Ḣs+1 ‖u‖1/s Ḣ1 ≤ γ2 4 ‖u‖2 Ḣs+1 + C 2 ‖u‖2 Ḣ1 ≤ γ2 4 ‖uL‖2Ḣs+1 + γ2 4 ‖uH‖2Ḣs+1 + C 2 ‖u‖2 Ḣ1 . (6.4) EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 19 The same calculation can be done to ∫ R3 Λ2suH∇uHdx.∣∣2 ∫ R3 Λ2sb · uH∇uHdx ∣∣ = 2b ∣∣ ∫ R3 (iξ)(û)H |ξ|2sûHdξ ∣∣ ≤ C‖|ξ|s|ûH | · |ξ|s+1û‖L1 ≤ C‖uH‖Ḣs‖u‖Ḣs+1 ≤ γ2 4 ‖uL‖2Ḣs+1 + γ2 4 ‖uH‖2Ḣs+1 + C 2 ‖u‖2 Ḣ1 . (6.5) For R2, by Proposition 5.4, we have |R2| = ∫ R3 ûûH |ξ|2s∂tχ(t, ξ)dξ ≤ ∫ R3 |ûû||ξ|2s+2 1 µ χ′0 (1 + t µ |ξ|2 )∣∣1− χ0 (1 + t µ |ξ|2 )∣∣dξ ≤ C‖û2‖L∞ ∫ R3 (1 + t)−(s+1)|η|2s+2χ′0(|η|2)|1− χ0(|η|2)|(1 + t)−3/2dη ≤ C‖u2‖L1(1 + t)− 3 2−s−1 ≤ C(1 + t)− 3 2−s−1. (6.6) For R3, similar to R2, we obtain |R3| ≤ C(1 + t)− 3 2−s−2. (6.7) Combining (6.3)-(6.7), we obtain d dt (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) + γ2‖uH‖2Ḣs+1 ≤ γ2 2 ‖uL‖2Ḣs+1 + C‖u‖2 Ḣ1 + C(1 + t)− 3 2−s−1 + C(1 + t)− 3 2−s−2 ≤ C‖u‖2 Ḣ1 + C(1 + t)− 3 2−s−1. We used (6.1) in the last inequality above. Also, according to the definition of the cut-off operator, we find that ‖uH‖2Ḣs+1 ≥ µ 1 + t ‖uH‖2Ḣs . Therefore, d dt (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) + C0 µ 1 + t (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) ≤ d dt (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) + γ2 2 ‖uH‖2Ḣs+1 ≤ C‖u‖2 Ḣ1 + C(1 + t)− 3 2−s−1. Using Lemma 6.1 and multiplying the inequality above by e ∫ t 0 C0µ 1+τ dτ = (1 + t)C0µ and integrating from 0 to t, we have (1 + t)C0µ(‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) ≤ ‖u0H‖2Ḣs + γ1‖u0H‖2Ḣs+1 + C ∫ t 0 (1 + τ)C0µ‖u‖2 Ḣ1dτ + C ∫ t 0 (1 + τ)C0µ− 3 2−s−1dτ 20 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 ≤ ‖u0H‖2Ḣs + γ1‖u0H‖2Ḣs+1 + C(1 + t)C0µ− 3 2 + C(1 + t)C0µ− 3 2−s. Since C0µ > 3/2, we have ‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1 ≤ C(1 + t)−3/2. Combining the above with (6.1) and setting s = 3, we obtain ‖u‖2 Ḣ3 ≤ C(1 + t)−3/4. Therefore, by the Gagliardo-Nirenberg-Sobolev inequality, we have ‖u‖L∞ ≤ C‖u‖1/2Ḣ3 ‖u‖1/2L2 ≤ C(1 + t)−3/4. Hence, we can use the estimate of ‖u‖L∞ to get a better decay as follows. |R1| ≤ C(‖u‖L∞‖u‖Ḣs)‖u‖Ḣs+1 ≤ γ2 2 ‖u‖2 Ḣs+1 + C‖u‖2 Ḣs ‖u‖2L∞ ≤ γ2 2 ‖u‖2 Ḣs+1 + C(1 + t)−3/2(‖uL‖2Ḣs + ‖uH‖2Ḣs). (6.8) By (6.3) and (6.6)-(6.8), we have d dt (‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) + γ2‖uH‖2Ḣs+1 ≤ C(1 + t)−3/2(‖uH‖2Ḣs) + C(1 + t)− 3 2−s−1. Similar to the proof above and note that C0µ > 3 2 , we have (1 + t)C0µ(‖uH‖2Ḣs + γ1‖uH‖2Ḣs+1) ≤ ‖u0H‖2Ḣs + γ1‖u0H‖2Ḣs+1 + C ∫ t 0 (1 + τ)C0µ− 3 2 (‖uH‖2Ḣs)dτ + C ∫ t 0 (1 + τ)C0µ− 3 2−s−1dτ ≤ ‖u0H‖2Ḣs + γ1‖u0H‖2Ḣs+1 + C(1 + t)C0µ− 3 2−s + C ∫ t 0 (1 + τ)C0µ− 3 2 (‖uH‖2Ḣs)dτ. By Gronwall’s inequality [3], we have (1 + t)C0µ‖uH‖2Ḣs ≤ C(1 + (1 + t)C0µ− 3 2−s)e ∫ t 0 (1+τ)−3/2dτ ≤ C + C(1 + t)C0µ− 3 2−s. Since C0µ > 3/2, we obtain ‖uH‖Ḣs ≤ C(1 + t)− 3 4− s 2 , which is the optimal decay estimates of uH . This completes the proof. � Corollary 6.3. Suppose that u0 satisfies the same assumptions as in Theorem 6.1 and u is a solution of (1.5) in L∞([1,∞), Hs(R3)). Then ‖u‖L∞ ≤ C(1 + t)−3/2, for t ≥ 1, where C only depends on ‖u0‖L1 . EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 21 Proof. By Theorem 1.2, we have ‖u‖Ḣs ≤ C(1 + t)− 3 4− s 2 . In particular, for s = 3, we have ‖u‖Ḣ3 ≤ C(1+ t)− 9 4 . Therefore, by the Gagliardo- Nirenberg-Sobolev inequality, we immediately obtain ‖u‖L∞ ≤ C‖u‖1/2Ḣ3 ‖u‖1/2L2 ≤ C(1 + t)−3/2, which completes the proof. � 7. Pointwise estimate of the solution Finally, we come to the pointwise estimate of the solution u. Our goal is to prove the following theorem. Theorem 7.1. For Cauchy problem (1.1), if the initial data v0 = u0 − u∗ ∈ L1(R3) ∩Hs(R3), and satisfies |Dβ xv0| = |Dβ x(u0 − u∗)| ≤ C(1 + |x|2)−r, r > 3 2 , then the solution has the pointwise estimate |Dα̃ x (u− u∗)| ≤ C(1 + t)− 3+|α̃| 2 Br(t, |x− bt|), where |β| ≤ s− 1, |α̃| ≤ s− 1, t ≥ 1 and Br(t, |x|) is given in (2.1). Proof. From (5.11), we have Dα̃ xu = Dα̃ xG ∗ u0 + ∫ t 0 Dα̃ xG(t− τ, ·) ∗ div 1− γ1∆ f(u)dτ = Π1 + Π2. (7.1) Obviously Π1 means the initial term while Π2 represents the nonlinear term. 7.1. Estimate of the initial term. For Π1 = Dα̃ xG∗u0, since G has a distribution Gfα̃, we need to separate it into two parts: |Π1| = |Dα̃ xG ∗ u0| ≤ |Dα̃ x (G−Gfα̃) ∗ u0|+ |Gfα̃ ∗Dα xu0| = Π1,1 + Π1,2. For Π1,1, since |u0| ≤ (1 + |y|2)−N and supp u0 ⊂ {|y| ≤ M}, if t is large enough, then applying Lemma 2.4 we obtain |Dα̃ x (G−Gfα̃) ∗ u0| ≤ Ct− 3 2− |α̃| 2 ∫ Rn Br(t, |x− bt− y|)(1 + |y|2)−rdy ≤ Ct− 3 2− |α̃| 2 Br(t, |x− bt|). (7.2) For Π1,2, by the assumption of the initial data and [18], we have |Gfα̃ ∗Dα̃ xu0| ≤ C ∫ Rn e− γ2 γ1 t(1 + |y|2)−rdy ≤ Ct− 3 2− |α̃| 2 Br(t, |x− bt|). (7.3) Combining (7.2) and (7.3), we obtain |Dα̃ xG ∗ u0| ≤ Ct− 3 2− |α̃| 2 Br(t, |x− bt|). (7.4) 22 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 7.2. The estimate of the nonlinear term. Set Φ = (1 + t)−3/2Br(t, |x− bt|), Φα̃ = (1 + t)− 3 2− |α̃| 2 Br(t, |x− bt|), M(t) = sup 0≤s≤t,x∈R |Dα̃ xu(x, s)|Φ−1 α̃ (x, s). Then |u| ≤M · Φ, |Dα̃ xu| ≤M · Φα̃. For the nonlinear term, we again separate it into two parts: Π2 = ∫ t 0 Dα̃ xG(t− τ, ·) ∗ div f(u)dτ. ≤ ∫ t 0 Dα̃+1 x (G−Gfα̃) ∗ f(u)dτ + ∫ t 0 Gfα̃ ∗Dα̃ x div f(u)dτ = Π2,1 + Π2,2. For Π2,1, let Ω = [0, t]× Rn, Ω1 = Ω ∩ { t2 < τ ≤ t}, Ω2 = Ω ∩ {0 ≤ τ ≤ t 2}. Then Π2,1 = ∫ t 0 Dα̃ x (G−Gfα̃) ∗ div f(u)dτ ≤ C ∫ Ω1 (G−Gfα̃) ∗Dα̃ x div f(u)dτ + C ∫ Ω2 Dα̃+1 x (G−Gfα̃) ∗ f(u)dτ. There are two cases: Case 1: |x− bt|2 < t. Then Π2,1 = C ∫ Ω1 (t− τ)− 3 2Br(t− τ, |x− y − b(t− τ)|)|Dα̃+1u2|dydτ + C ∫ Ω2 (t− τ)− 3 2− |α̃|+1 2 Br(t− τ, |x− y − b(t− τ)|)‖u‖L∞ |u|dydτ ≤ CM(t)(1 + t)− 3+|α̃| 2 − 1 8 ∫ t t 2 (t− τ)− 3 2 (1 + τ)− 3 2− 3 8 (t− τ) 3 2 dτ + CM(t)t− 4+|α̃| 2 ∫ t/2 0 (1 + τ)−3τ 3 2 dτ ≤ CM(t)t− 3+|α̃| 2 − 1 8 . When |x− bt|2 < t, we have 1 ≤ 2r ( 1 + |x− bt|2 t )−r = 2rBr(t, |x− bt|). Thus, we obtain Π2,1 ≤ CM(t)t− 3+|α̃| 2 − 1 8Br(t, |x− bt|). (7.5) Case 2: |x− bt|2 ≥ t. We set P = ( 1 + |x− y − b(t− τ)|2 t− τ )−r( 1 + |y − bτ |2 τ )−r . EJDE-2020/129 POINTWISE ESTIMATES FOR CONSERVATION LAWS 23 Then P ≤ C ( 1 + |x−bt|2 t−τ )−r( 1 + |y−bτ |2 τ )−r , |x− bt| ≥ |y−bτ |2 , C ( 1 + |x−y−b(t−τ)|2 t−τ )−r( 1 + |x−bτ |2 τ )−r , |x− bt| ≤ |y−bτ |2 . We separate the region into {y : |x− bt| ≥ |y−bτ |2 } and {y : |x− bt| ≤ |y−bτ |2 }. Then Π2,1 = C ∫ Ω1 (t− τ)−3/2Br(t− τ, |x− y − b(t− τ)|)(1 + τ)−3− |α̃|+1 2 Br(τ, |y − bτ |)dydτ + C ∫ Ω2 (t− τ)− 3 2− |α̃|+1 2 Br(t− τ, |x− y − b(t− τ)|)(1 + τ)−3Br(τ, |y − bτ |)dydτ ≤ CM(t)Br(t, |x− bt|) ∫ Ω1 (t− τ)− 4+|α̃| 2 (1 + τ)−3 τ 3/2 t3/2 Br(t− τ, |x− y − bτ |)dydτ + CM(t)Br(t, |x− bt|) ∫ Ω1 (t− τ)−3/2(1 + τ)−3− |α̃|+1 2 τ3/2 t3/2 Br(t− τ, |x− y − bτ |)dydτ + CM(t)Br(t, |x− bt|) ∫ Ω2 (t− τ)− 3+|α̃|+1 2 (1 + τ)−3 (t− τ)3/2 t3/2 Br(τ, |y − bτ |)dydτ + CM(t)Br(t, |x− bt|) ∫ Ω2 (t− τ)−3/2(1 + τ)−3− |α̃|+1 2 (t− τ)3/2 t3/2 Br(τ, |y − bτ |)dydτ ≤ CM(t)Br(t, |x− bt|) ∫ t t 2 (t− τ)− 4+|α̃| 2 (1 + τ)−3 τ 3/2 t3/2 (t− τ)3/2dτ + CM(t)Br(t, |x− bt|) ∫ t t 2 (t− τ)−3/2(1 + τ)−3− |α̃|+1 2 τ3/2 t3/2 (t− τ)3/2dτ + CM(t)Br(t, |x− bt|) ∫ t 2 0 (t− τ)− 3+|α̃|+1 2 (1 + τ)−3 (t− τ)3/2 t3/2 τ3/2dτ + CM(t)Br(t, |x− bt|) ∫ t 2 0 (t− τ)−3/2(1 + τ)−3− |α̃|+1 2 (t− τ)3/2 t3/2 τ3/2dτ ≤ CM(t)Br(t, |x− bt|)t− 4+|α̃| 2 ∫ t t 2 (1 + τ)−3/2dτ + CM(t)Br(t, |x− bt|)t− 4+|α̃| 2 ∫ t 2 0 (1 + τ)−3/2dτ ≤ CM(t)t− 3+|α̃| 2 − 1 8Br(t, |x− bt|). (7.6) Then, by (7.5) and (7.6), we obtain Π2,1 ≤ CM(t)t− 3+|α̃| 2 − 1 8Br(t, |x− bt|) = CM(t)Φα̃(1 + t)−1/8. (7.7) 24 F. B. LI, W. K. WANG, Y. T. WANG EJDE-2020/129 Next, we consider Π2,2. From [19], we have Π2,2 = ∫ t 0 Gfα̃ ∗Dα̃ x div f(u)dτ ≤ C ∫ t 0 ∫ Rn Gfα̃(x− y, τ)Φα̃(y, τ)Φα̃+1dydτ ≤ C ∫ t 0 e− γ2 γ1 (t−τ)Φα̃Φα̃+1dτ ≤ CΦα̃. (7.8) Combining (7.1), (7.4), (7.7) and (7.8), and noticing that t ≥ 1, we have |Dα̃ xu| ≤ CΦα̃ + CM(t)Φα̃(1 + t)−1/8. Thus we obtain M(t) ≤ C + CM(t)(1 + t)−1/8. Since there exists T > 0 such that when t > T , C(1 + t)−1/8 ≤ 1 2 , we conclude that M(t) ≤ 2C, t > T , which implies that ‖Dβu‖L∞ ≤ C, |β| = |α|+ 2. Then, by the structure of the equation, we have ‖∂tDβu‖L∞ ≤ C. By the continuity of M(t) on [1, T ], M(1) ≤ C0 and M(t) ≤ C0 for t > T , we have M(t) ≤ C0 for t ≥ 1. By the definition of M(t), this gives us |Dα̃ xu| ≤ C(1 + t)− 3+|α̃| 2 Br(|x− bt|, t). This completes the proof. � Acknowledgments. F. 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Fengbai Li School of Mathematics, Shanghai University of Finance and Economics, 777 Guo Ding Road, Shanghai 200433, China Email address: li.fengbai@mail.shufe.edu.cn Weike Wang School of Mathematical Sciences and Institute of Natural Sciences, Shanghai Jiao Tong University, 800 Dong Chuan Road, Shanghai 200240, China Email address: wkwang@sjtu.edu.cn Yutong Wang School of Mathematical Sciences, Shanghai Jiao Tong University, 800 Dong Chuan Road, Shanghai 200240, China Email address: wyt0521@sjtu.edu.cn 1. Introduction 2. Preliminaries 3. Existence of a local solution 4. Lp decay estimate of Green's function 5. Lp bound estimate of solutions 5.1. L1 bounds 5.2. L bounds 5.3. Lp bounds 5.4. Hs bounds 6. Decay estimate in s and L 6.1. Decay rate of the low frequency part in s 6.2. Decay rate of the high frequency part in s 7. Pointwise estimate of the solution 7.1. Estimate of the initial term 7.2. The estimate of the nonlinear term Acknowledgments References