7_hui.dvi EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 5, No. 3, 2012, 365-372 ISSN 1307-5543 – www.ejpam.com A Note on Nearly Quasi-Einstein Manifolds SHYAMAL KUMAR HUI Nikhil Banga Sikshan Mahavidyalya, Bishnupur, Bankura - 722 122, West Bengal, India Abstract. The object of the present paper is to study nearly quasi-Einstein manifold. Also we have studied decomposable Riemannian manifold and it is shown that a decomposable Riemannian mani- fold is nearly quasi-Einstein if and only if both the decompositions are Einstein. 2010 Mathematics Subject Classifications: 53B30, 53B50, 53C15, 53C25 Key Words and Phrases: quasi-Einstein manifold, nearly quasi-Einstein manifold, Ricci-pseudosymmetric, scalar curvature, decomposable Riemannian manifold, Killing vector field, projective Killing vector field 1. Introduction It is well known that a Riemannian manifold (M n, g)(n > 2) is Einstein if its Ricci tensor S of type (0,2) is of the form S = αg, where α is a constant, which reduces to S = r n g, r being the scalar curvature (constant) of the manifold. The notion of quasi-Einstein manifolds arose during the study of exact solutions of the Einstein field equations as well as during considerations of quasi-umbilical hypersurfaces. For instance, the Robertson-Walker spacetimes are quasi-Einstein manifolds. A non-flat Rieman- nian manifold (M n, g)(n > 2) is said to be quasi-Einstein manifold [1, 3, 5, 6, 7, 8, 9, 10, 11, 12, 15, 16] if its Ricci tensor S of type (0,2) is not identically zero and satisfies the following: S(X , Y ) = αg(X , Y ) + βA(X )A(Y ), (1) where α, β are scalars of which β 6= 0 and A is a nowhere vanishing 1-form defined by g(X ,ρ) = A(X ) for all X ; ρ being a unit vector field, called the generator of the manifold. Such an n-dimensional quasi-Einstein manifold is denoted by (QE)n. The scalars α, β are known as the associated scalars of the manifold. Also the 1-form A is called the associated 1-form of the manifold. From the above definition it follows that every Einstein manifold is quasi-Einstein. In particular, every Ricci-flat (e.g. Schwarzschild spacetime) manifold is quasi-Einstein. Recently the notion of quasi-Einstein manifold have been weakened by De and Gaji [2, 14] and they introduced the notion of nearly quasi-Einstein manifold with the existence of such Email address: shyamal_hui�yahoo. o.in http://www.ejpam.com 365 c© 2012 EJPAM All rights reserved. S. HUI / Eur. J. Pure Appl. Math, 5 (2012), 365-372 366 notion. A Riemannian manifold (M n, g)(n> 2) is called nearly quasi-Einstein if its Ricci tensor S is not identically zero and satisfies the condition S(X , Y ) = αg(X , Y ) + βD(X , Y ), (2) where α,β are non-zero scalars and D is a symmetric non-zero (0, 2) tensor. The scalars α, β are known as associated scalars and D is called the associated tensor of the manifold. Such an n-dimensional manifold is denoted by N(QE)n. The present paper deals with a study of N(QE)n(n > 2). The paper is organized as fol- lows. Section 2 is concerned with Ricci-pseudosymmetric N(QE)n and we obtain a N(QE)n is Ricci-pseudosymmetric if and only if it is D-pseudosymmetric. Section 4 deals with de- composable Riemannian manifold. It is proved that a decomposable Riemannian manifold is nearly quasi-Einstein if and only if both the decompositions are Einstein. Section 5 deals with some global properties of N(QE)n and it is proved that under certain condition such a manifold does not admit non-zero Killing vector field, non-zero projective Killing vector field and non-zero conformal Killing vector field. Finally the last section deals with an interesting example of nearly quasi-Einstein manifold with non-vanishing scalar curvature which is not quasi-Einstein. 2. Ricci-pseudosymmetry N(QE)n An n-dimensional Riemannian manifold (M n, g) is called Ricci-pseudosymmetric [4] if the tensor R · S and Q(g,S) are linearly dependent, where (R(X , Y ) · S)(Z , U) = −S(R(X , Y )Z , U)− S(Z ,R(X , Y )U), (3) Q(g,S)(Z , U; X , Y ) = −S((X ∧g Y )Z , U)− S(Z , (X ∧g Y )U). (4) Thus the condition of Ricci-pseudosymmetry is (R(X , Y ) · S)(Z , U) = LSQ(g,S)(Z , U; X , Y ) (5) holding on the set US = {x ∈ M : S 6= r n g at x}, where LS is some function on US. If R · S = 0 then M is called Ricci-semisymmetric. Every Ricci-semisymmetric manifold is Ricci-pseudosymmetric but the converse is not true [4]. In [2] De and Gaji studied Ricci- semisymmetric N(QE)n. Now we prove the following: Theorem 1. A nearly quasi-Einstein manifold is Ricci-pseudosymmetric if and only if it is D- pseudosymmetric. Proof. We now consider a Ricci-pseudosymmetric N(QE)n. Then from (3)–(5), we can write S(R(X , Y )Z , U) + S(Z ,R(X , Y )U) = LS{S(X , U)g(Y, Z) (6) −S(Y, U)g(X , Z)+ S(X , Z)g(Y, U)− S(Y, Z)g(X , U)}. S. HUI / Eur. J. Pure Appl. Math, 5 (2012), 365-372 367 Using (2) in (6), we get D(R(X , Y )Z , U) + D(Z ,R(X , Y )U) = LS{D(X , U)g(Y, Z) (7) −D(Y, U)g(X , Z)+ D(X , Z)g(Y, U)− D(Y, Z)g(X , U)}, which implies that the manifold is D-pseudosymmetric. Conversely, if the manifold is D-pseudosymmetric, then (7) holds. By virue of (2), it fol- lows from (7), we get the relation(6) and consequently, the manifold is Ricci-pseudosymmetric. Corollary 1. A nearly quasi-Einstein manifold is Ricci-semisymmetric if and only if it is D- semisymmetric [2]. 3. Decomposable Riemannian manifold A non-flat Riemannian manifold (M n, g) is said to be decomposable [19] if it can be expressed as M p 1 ×M n−p 2 for 2≤ p ≤ n− 2, that is, in some coordinate neighbourhood of the Riemannian manifold (M n, g), the metric can be expressed as ds2 = gi jd x id x j = g̃abd x ad x b+ ∗ g αβ d xαd xβ , (8) where g̃ab are functions of x1, x2, · · · , x p(p < n) denoted by x̃ and ∗ g αβ are functions of x p+1, x p+2, · · · , xn denoted by ∗ x ; a, b, c, · · · run from 1 to p and α,β ,γ, · · · run from p+ 1 to n. The two parts of (8) are the metrics of M p 1 (p ≥ 2) and M n−p 2 (n− p ≥ 2) which are called the decomposition of the manifold M n = M p 1 ×M n−p 2 (2≤ p ≤ n− 2). Let (M n, g) be a Riemannian manifold such that M p 1 × M n−p 2 for 2 ≤ p ≤ n − 2. Here throughout this section each object denoted by a “tilde” is assumed to be from M1 and each object denoted by a “star” is assumed to be from M2. Let X̃ , Ỹ , Z̃ , Ũ , Ṽ ∈ χ(M1) and ∗ X , ∗ Y , ∗ Z , ∗ U , ∗ V∈ χ(M2), then we have the following relations: R( ∗ X , Ỹ , Z̃ , Ũ) = 0= R(X̃ , ∗ Y , Z̃ , ∗ U) = R(X̃ , ∗ Y , ∗ Z , ∗ U), (∇ ∗ X R)(Ỹ , Z̃ , Ũ , Ṽ ) = 0= (∇X̃ R)(Ỹ , ∗ Z , Ũ , ∗ V ) = (∇ ∗ X R)(Ỹ , ∗ Z , Ũ , ∗ V ), R(X̃ , Ỹ , Z̃ , Ũ) = R̃(X̃ , Ỹ , Z̃ , Ũ); R( ∗ X , ∗ Y , ∗ Z , ∗ U) = ∗ R ( ∗ X , ∗ Y , ∗ Z , ∗ U), S(X̃ , Ỹ ) = S̃(X̃ , Ỹ ); S( ∗ X , ∗ Y ) = ∗ S ( ∗ X , ∗ Y ), (∇X̃ S)(Ỹ , Z̃) = (∇̃X̃ S)(Ỹ , Z̃); (∇ ∗ X S)( ∗ Y , ∗ Z) = ( ∗ ∇ ∗ X S)( ∗ Y , ∗ Z), and r = r̃+ ∗ r, where r, r̃, and ∗ r are the scalar curvature of M , M1, M2 respectively. In [19] Yano and Kon find a necessary and sufficient condition that both the decomposi- tions of a decomposable Riemannian manifold are Einstein and they obtained that S. HUI / Eur. J. Pure Appl. Math, 5 (2012), 365-372 368 Theorem 2. In a decomposable Riemannian manifold M n = M p 1 × M n−p 2 (2 ≤ p ≤ n− 2), a necessary and sufficient condition that the two decompositions are both Einstein is that the Ricci tensor of the manifold has the form S(X , Y ) = ag(X , Y ) + bF(X , Y ), (9) a and b being necessarily constant and F is a (0, 2) type metric tensor such that F(X , Y ) = g̃(X̃ , Ỹ )+ ∗ g ( ∗ X , ∗ Y ). (10) By virtue of Theorem 2, we can state the following: Theorem 3. A decomposable Riemannian manifold M n = M p 1 ×M n−p 2 (2≤ p ≤ n− 2) is nearly quasi-Einstein if and only if both the decompositions are Einstein. 4. Some global properties of N(QE)n This section is concerned with a compact, orientable N(QE)n(n > 2) without boundary with α, β as associated scalars and D as the structure tensor. Then we prove the following: Theorem 4. If in a compact, orientable N(QE)n(n> 2) without boundary, the associated scalars and the structure tensor are such that α < 0 and βD(X , X ) < 0, then there exists no non-zero Killing vector field in this manifold. Proof. It is known that [17] for a vector field X in a Riemannian manifold M , the following relation holds ∫ M h S(X , X )− |∇X |2− (div X )2 i dv ≤ 0, (11) where “dv” denotes the volume element of M . If X is a Killing vector field, then div X = 0 [18]. Hence (11) takes the following form ∫ M h S(X , X )− |∇X |2 i dv = 0. (12) Let us consider α < 0 and βD(X , X )< 0. Hence by virtue of (2) we have ∫ M=N(QE)n h α|X |2+ βD(X , X )− |∇X |2 i dv ≥ ∫ M h S(X , X )− |∇X |2 i dv, which yields by virtue of (12) that ∫ M h α|X |2+ βD(X , X )− |∇X |2 i dv ≥ 0. S. HUI / Eur. J. Pure Appl. Math, 5 (2012), 365-372 369 If α < 0 and βD(X , X )< 0, then the last relation reduces to ∫ M h α|X |2+ βD(X , X )− |∇X |2 i dv = 0. Hence X = 0. This proves the theorem. Definition 1. [18] A vector field X in a Riemannian manifold (M n, g) (n > 2) is said to be projective Killing vector field if it satisfies ($X g)(Y, Z) =ω(Y )Z +ω(Z)Y for any vector fields Y and Z,ω being a certain 1-form and $ is the operator of Lie differentiation. Theorem 5. If in a compact, orientable N(QE)n(n> 2) without boundary, the associated scalars and the structure tensor are such that α ≤ 0 and βD(X , X ) ≤ 0, then a projective Killing vector field has vanishing covariant derivative, and if α < 0 and βD(X , X ) < 0, then there exists no non-zero projective Killing vector field in this manifold. Proof. We know that [17] for a vector field X in a Riemannian manifold M , the following relation holds ∫ M h S(X , X )− 1 4 |dξ|2− n− 1 2(n+ 1) (div X )2 i dv = 0, (13) where ξ is an 1-form corresponding to the vector field X . We now assume α ≤ 0 and βD(X , X ) ≤ 0. Therefore (13) yields S(X , X ) ≤ 0 and hence from (13) we obtain dξ = 0 and div X = 0. This implies that X is harmonic as well as a Killing vector field. Consequently its covariant derivative vanishes. This proves the theorem. Definition 2. [18] A vector field X in a Riemannian manifold (M n, g) (n > 2) is said to be conformal Killing vector field if it satisfies $X g = 2ρg for any vector field X , where ρ is given by ρ = − 1 n (div X ) and $ is the operator of Lie differenti- ation. Theorem 6. If in a compact, orientable N(QE)n(n> 2) without boundary, the associated scalars and the structure tensor are such that α < 0 and βD(X , X ) < 0, then there exists no non-zero conformal Killing vector field in this manifold. Proof. It is known from [17] that for a vector field X in a Riemannian manifold M , the following relation holds ∫ M h S(X , X )− |∇X |2− n− 2 n (div X )2 i dv = 0, (14) where dv denotes the volume element of M . Now we assume that the associated scalars and the structure tensor are such that α < 0 and βD(X , X ) < 0. Then proceeding similarly as before we obtain ∇X = 0, div X = 0. This proves the theorem. REFERENCES 370 5. Example of N(QE)n We define a Riemannian metric g on the n-dimensional real number space Rn by the formula ds2 = ekx1 [(d x1)2 + sin2 x3(d x2)2 + (d x3)2] + f (x4)(d x4)2 + n ∑ l=5 (d x l)2, (15) where x1 is non-zero finite, 0 < x3 < π 2 , k is a non-zero finite real number excepting ±2 and f is a positive smooth function of x4 only. Then the only non-vanishing components of the Christoffel symbols, the curvature tensor, the Ricci tensors are given by Γ1 11 = k 2 = Γ2 12 = Γ 3 13 = −Γ 1 33,Γ1 22 = − k 2 sin2 x3, Γ3 22 = − sin x3 cos x3,Γ2 23 = cot x3,Γ4 44 = 1 2 f ′(x4) f (x4) , R2332 = �k2 4 − 1 � ekx1 sin2 x3,S22 = �k2 4 − 1 � sin2 x3,S33 = �k2 4 − 1 � . Here the scalar curvature of the manifold is r = 2( k2 4 − 1)e−kx1 6= 0. Therefore Rn with the considered metric is a Rimennian manifold (M n, g) of non-vanishing scalar curvature. 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