EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 12, No. 2, 2019, 571-576 ISSN 1307-5543 – www.ejpam.com Published by New York Business Global Finite Groups With Certain Permutability Criteria Rola A. Hijazi1, Fatme M. Charaf1,∗ 1 Department of Mathematics, Faculty of Science, King Abdulaziz University, Jeddah, Saudi Arabia Abstract. Let G be a finite group. A subgroup H of G is said to be S-permutable in G if it permutes with all Sylow subgroups of G. In this note we prove that if P , the Sylow p-subgroup of G (p > 2), has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are S-permutable in G, then G′ is p-nilpotent. 2010 Mathematics Subject Classifications: 20D10, 20D20 Key Words and Phrases: S -Permutable Subgroup, p-Nilpotent Group, Solvable Group, Super- solvable Group. 1. Introduction Throughout this note, G denotes a finite group. The relationship between the proper- ties of the Sylow subgroups of a group G and its structure has been investigated by many authors. Starting from Gaschűtz and Itő ([10], Satz 5.7, p.436) who proved that a group G is solvable if all its minimal subgroups are normal. In 1970, Buckely [4] proved that a group of odd order is supersolvable if all its minimal subgroups are normal (a subgroup of prime order is called a minimal subgroup). Recall that a subgroup is said to be S-permutable in G if it permutes with all Sylow subgroup of G. This concept, as a generalization of normality, was introduced by Kegel [11] in 1962 and has been studied extensively in many notes. For example, Srinivasan [15] in 1980 obtained the supersolvability of G under the assumption that the maximal subgroups of all Sylow subgroups are S-permutable in G. In 2000, Ballester-Bolinches et al. [3] introduced the c-supplementation concept of a finite group: A subgroup H of a group G is said to be c-supplemented in G if there exists a subgroup K of G such that G = HK and H ∩K ≤ HG, where HG = CoreG(H) is the largest normal subgroup of G contained in H. By using this concept they were able to prove that a group G is solvable if and only if every Sylow subgroup of G is c-supplemented in G. Moreover, as an application, they got the supersolvability of a group G if all its minimal subgroups and the cyclic subgroups of order 4 are c-supplemented in G. ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v12i2.3399 Email addresses: Rhijazi@kau.edu.sa (R. Hijazi), fa-sharaf@hotmail.com (F. Charaf) http://www.ejpam.com 571 c© 2019 EJPAM All rights reserved. R. Hijazi, F. Charaf / Eur. J. Pure Appl. Math, 12 (2) (2019), 571-576 572 In 2014, Heliel [8] proved that G is solvable if each subgroup of prime odd order of G is c-supplemented in G. Also he proved that G is solvable if and only if every Sylow subgroup of odd order of G is c-supplemented in G. This improved and generalized the results of Hall [6, 7], Ballester-Bolinches and Guo [2], and Ballester-Bolinches et al. [3]. Heliel also posted the following conjecture: Let G be a finite group such that every non-cyclic Sylow subgroup P of odd order of G has a subgroup D such that 1 < |D| ≤ |P | and all subgroups H of P with |H| = |D| are c-supplemented in G. Is G solvable? In the same year, Li et al. [12] presented a counterexample to show that the answer of this conjecture is negative in general and then gave a generalization of Heliel’s theorems. Example 1. Let G = A5 ×H, where A5 is the alternating group of degree 5 and H is an elementary group of order pn with p > 5 and n ≥ 2. Then G satisfies the condition of the preceding conjecture, but G is not solvable. In 2015, Hijazi [9] continued the above mentioned investigations and proved the follow- ing: Suppose that each Sylow subgroup P of G has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are S-permutable in G. Then G is solvable. The main goal of this note is to prove the following main theorem: Main Theorem 1. Let P be a Sylow p-subgroup of G (p > 2). Suppose that P has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are S-permutable in G. Then G′ is p-nilpotent. As immediate consequences of the main theorem we have: Corollary 1. Let P be a Sylow p-subgroup of G (p > 2). Suppose that P has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are permutable in G. Then G′ is p-nilpotent. Corollary 2 ([9], Theorem 3.1). Suppose that each Sylow subgroup P of G has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are S-permutable in G. Then G is solvable. Corollary 3 (Gaschűtz and Itő [10], Satz 5.7, p.436 ). A group G is solvable if all its minimal subgroups are normal. 2. Proofs We first prove the following theorems: Theorem 2. Let P be a Sylow p-subgroup of a group G, where p is an odd prime. If each subgroup of P of order p is S-permutable in G, then G′is p-nilpotent. Proof. We prove the theorem by induction on |G| . Hence if each subgroup of P of order p is normal in G, then each subgroup of G ′ of order p is normal in G′. Let L be a R. Hijazi, F. Charaf / Eur. J. Pure Appl. Math, 12 (2) (2019), 571-576 573 subgroup of G′ such that |L| = p. Then G/CG(L) ⊆ Aut(L) and, since Aut(L) is cyclic of order p− 1, we have G/CG(L) is abelian. Thus G′ ≤ CG(L) and so L ≤ Z(G′). By ([10], Satz 5.5(a), p. 435), G′is p-nilpotent. Thus we may assume that there exists a subgroup H of P of order p such that H is not normal in G. By the hypothesis, H is S-permutable in G and hence by ([13], Lemma A), Op(G) ≤ NG(H) < G. Let M be a maximal subgroup of G such that NG(H) ≤M < G. Then M CG and | G/M |= p. By induction on |G| , M ′ is p-nilpotent. Hence if Op′(G) 6= 1, G/ Op′(G) satisfies the hypothesis of the theorem and so (G/ Op′(G))′ = G′Op′(G)/Op′(G) ∼= G′/(G8 ∩Op′(G)) is p-nilpotent which implies that G′is p-nilpotent. Thus assume that Op′(G) = 1. Since M ′ char M and M CG, we have M ′ C G. As M ′ is p-nilpotent and Op′(G) = 1, we have M ′ is a p-group. Then P1 CM where P1 is a Sylow p-subgroup of M . By Schur-Zassenhaus Theorem [5, Theorem 6.2.1, p. 221], M = P1K , where K is a p′-Hall subgroup of M . Hence if CG(P1) ≤ P1, K is a p′-group of automorphisms of P1, and since K leaves each subgroup of P1 invariant because every subgroup of P of prime order is S-permutable, then by ([14], Lemma 2.20), K is cyclic. Let Q be a Sylow q-subgroup of K, where q is a prime divisor of the order of K. Hence if p < q, then P1Q = P1×Q and this means that Q ≤ CG(P1), a contradiction. Thus p is the largest prime dividing |G| and since K is cyclic, it follows, by Burnside′s p-Nilpotent Theorem ([10], Satz 2.8, p.420), that P C G. But G/P ∼= K, therefore G/P is cyclic and so abelian, then G′ ≤ P . This completes the proof of the theorem. As a corollary of Theorem 2.1: Corollary 4. If each subgroup of prime order of G is S-permutable in G, then G is solvable, S CG′and G′/S is nilpotent,where S is a Sylow 2-subgroup of G′. Proof. By Theorem 2.1, G′ is p-nilpotent for each odd prime p dividing |G|. So G′ /S is nilpotent, S is a Sylow 2-subgroup of G′and hence G is solvable. Theorem 3. Let p be an odd prime and let P be a Sylow p-subgroup of G. Suppose that P has a subgroup D such that 1 < |D| < |P | and all subgroups H of P with |H| = |D| are normal in G. Then G′is p-nilpotent. Proof. We prove the theorem by induction on |G|. Clearly, P∩G′ is a Sylow p-subgroup of G′. Set P1 = P ∩G′. We deal with the following two cases: Case 1. |P1| ≤ |D|. Hence if |D| = p, |P1| = p , and P1 C G. Then G′ ≤ CG(P1) and so P1 ≤ Z(G′). Hence, by Schur-Zassenhaus Theorem, G′ = P1 ×K, where K is a p′-Hall subgroup of G′. In particular, G′ is p-nilpotent. Thus we may assume that |D| = pn (n ≥ 2). Let H be a subgroup of P with |H| = |D| such that P1 ≤ H < P . By the hypothesis, H CG. Assume that Φ(H) 6= 1 and consider the factor group G/Φ(H). Obviously, G/Φ(H) satisfies the theorem hypothesis and so (G/Φ(H))′ = G′Φ(H)/Φ(H) is p-nilpotent by the induction on |G|. But G′Φ(H)/Φ(H) ∼= G′/G′ ∩ Φ(H) and Φ(H) ≤ Φ(G), then we have G′ ∩ Φ(H) ≤ G′ ∩ Φ(G) and therefore R. Hijazi, F. Charaf / Eur. J. Pure Appl. Math, 12 (2) (2019), 571-576 574 G′/G′ ∩ Φ(G) is p-nilpotent. Now G′Φ(G)/Φ(G) ∼= G′/G′ ∩ Φ(G) is p-nilpotent implies that G′Φ(G) is p-nilpotent and consequently G′ is p-nilpotent. Thus we may assume that Φ(H) = 1 and so H is elementary abelian p-group of order pn (n ≥ 2). Let L be a subgroup of P contains H such that H is maximal in L. Clearly, L is not cyclic because H is elementary abelian group of order pn (n ≥ 2). Then L contains a subgroup H1 such that |H1| = |D| and H1 6= H. By the hypothesis, H1CG and since HCG, we have L = H1H C G and so Φ(L) ≤ Φ(G). Hence if Φ(L) 6= 1, Φ(L) ≤ H1 < L ≤ P . Since L is not cyclic, we have Φ(L) is contained properly in H1. Now it is easy to notice that the factor group G/Φ(L) satisfies the hypothesis of the theorem, so by induction on |G|, G′ is p-nilpotent. Thus we may assume that Φ(L) = 1 and so P1 is elementary abelian p-group. Since P1 ≤ H < L ≤ P and H is maximal in L, it follows that |L| = pn+1. Let L1 =< x1 > be a subgroup of P1 of order p. Then L =< x1 > × < x2 > × . . .× < xn+1 >. By the hypothesis, each maximal subgroup of L is normal in G. Applying ([1], Lemma 2.9) implies that each subgroup of L of order p is normal in G; in particular each subgroup L1 of P1 of order p is normal in G. So, G8 ≤ CG(L1) and consequently P1 ≤ Z(G′). By Schur-Zassenhaus Theorem, G′ = P1 × K1, where K1 is a p′-Hall subgroup of G; in particular G′ is p-nilpotent. Case 2. |P1| > |D|. Hence if |D| = p, then every subgroup of P1 of order p is normal in G, so Ω1(P1) ≤ Z(G′) which implies that G′ is p-nilpotent by ([10], Satz 5.5(a), p 435). Thus assume that |D| = pn (n ≥ 2). Hence if Φ(D) 6= 1, G/Φ(D) satisfies the hypothesis of the theorem and so (G/Φ(D))′ = G′Φ(D)/Φ(D) is p-nilpotent by induction on |G| which implies that G′/G′ ∩ Φ(G) is p-nilpotent; in particular G′ is p-nilpotent. Thus we may assume that Φ(D) = 1. Let L ≤ P1 such that D is maximal in L. Then |L| = pn+1(n > 2). Clearly L is not cyclic. Then there exists a maximal subgroup L1 6= D in L. By the hypothesis L1 C G and D C G which implies that L = L1D C G. Hence if Φ(L) 6= 1, Φ(L) ≤ D < L ≤ P1 and since L is not cyclic, it follows that Φ(L) < D. By induction on |G|, G′Φ(L)/Φ(L) ∼= G′/G′ ∩ Φ(L) is p-nilpotent. In particular, G′Φ(G)/Φ(G) is p- nilpotent and it follows easily that G′ is p-nilpotent. So we may assume that Φ(L) = 1 and so L is elementary abelian. Let L1 < P such that |L1| = p. Then L1 < L ≤ P1 and so L1 CG by ([1], Lemma 2.9). In particular, Ω1(P1) ≤ Z(G′). Again by ([10], Satz 5.5(a), p 435), G′ is p-nilpotent. This completes the proof of the theorem. Now we can move forward to prove our main theorem: Proof. We prove the theorem by induction on |G|. Hence if Op′(G) 6= 1, G/Op′(G) satisfies the hypothesis of the theorem and so (G/Op′(G))′ is p-nilpotent by induction on |G|; in particular, G′ is p-nilpotent. Thus we may assume that Op′(G) = 1. If each subgroup H of P with |H| = |D| is normal in G, then G′ is p-nilpotent by Theorem 2.2. So we may assume that there exists a subgroup H of P with |H| = |D| and H is not normal in G. By hypothesis, H is S-permutable in G. Since H 6 G and H is S-permutable in G, we have by ([13], Lemma A) that Op(G) ≤ NG(H) < G. Let M be a maximal subgroup of G contains NG(H) properly. Then M CG and |G/M | = p. Let P1 = P ∩M be a Sylow p-subgroup of M . By the hypothesis, |D| ≤ |P1|. If |D| = |P1|, then |H| = |P1| and so REFERENCES 575 P ≤ NG(H), and since Op(G) ≤ NG(H), we have POp(G) = G ≤ NG(H) < M which is impossible. Thus we may assume that |D| < |P1|. Now M ′ is p-nilpotent, by the inductive hypothesis, implies that M ′ is a p-group because Op′(G) = 1. Then P1 is characteristic in M and since MCG, we have P1CG. If PCG, then G/P is abelian and since all subgroups H of P with |H| = |D| are S-permutable in G, we have that G is supersolvable by ([14], Theorem 1.3) and so G′ is nilpotent; in particular G′ is p-nilpotent. Thus we may assume that P 6 G and P1 = F (G) the Fitting subgroup of G (recall that Op′(G) = 1 and that F (G) =< Op(G) for all p divides |G| >). Consider the subgroup Φ(P1) and assume that Φ(P1) 6= 1. Hence if |Φ(P1)| < |D|, then (G/Φ(P1)) ′ is p-nilpotent by induction on |G|; in particular G′ is p-nilpotent. So assume that |Φ(P1)| ≥ |D|. If |Φ(P1)| = |D|, then P/Φ(P1) is not cyclic. Let L/Φ(P1) be a proper subgroup of P/Φ(P1) such that |L/Φ(P1)| = p (L is not cyclic; otherwise Φ(P1) is cyclic and this implies that there exists L1 ≤ Φ(P1) such that L1CG; in particular G/CG(L1) is isomorphic to a subgroup of Aut(L1) and so G′ ≤ CG(L1) and we conclude then that G′ is p-nilpotent). As |L/Φ(P1)| = p, then there exists a maximal subgroup L1 of L such that |L1| = |Φ(P1)| = |D| and L1 6= Φ(P1). But L1Φ(P1) is S-permutable in G, then L1Φ(P1)/Φ(P1) = L/Φ(P1) is S-permutable in G/Φ(P1). By Theorem 2.1, (G/Φ(P1)) ′ = G′Φ(P1)/Φ(P1) is p-nilpotent and so G′ is p-nilpotent. Thus we may assume that Φ(P1) = 1 and P1 is elementary abelian. Since all subgroups H of P1 with |H| = |D| are normal in M , we have by ([1], Lemma 2.9) that all subgroups of P1 of order p are normal in M . So P1 ∩ Z(P ) 6= 1. Let L ≤ P1 ∩ Z(P ) such that |L| = p. Then L C G and since G/CG(L) is isomorphic to a subgroup of Aut(L), we have that G′ ≤ CG(L), in particular G′L/L is p-nilpotent and so G′ is p-nilpotent. This completes the proof of the theorem. References [1] M. Asaad and A. A. Heliel, On S-quasinormally embedded subgroups of finite groups, JPAA 165(2001) 129-135. [2] A. Ballester-Bolinches and X. Guo, On complemented subgroups of finite groups, Arch. Math. 72(1999) 161-166. [3] A. Ballester-Bolinches, Y. Wang and X. Guo (2000), C-supplemented subgroups of finite groups, Glasgow Math. J. 42(2000) 383-389. [4] J. Buckely, Finite groups whose minimal subgroups are normal, Math. Z. 116(1970) 15-17. [5] D. Gorenstein, Finite Groups, American Mathematical Society, 1980. [6] P. Hall, A characteristic property of solvable groups, J. London Math. Soc. 12(1937) 198-200. [7] P. Hall, Complemented Groups, J. London Math. Soc. 12(1937) 201-204. REFERENCES 576 [8] A. A. 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