EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 13, No. 2, 2020, 287-302 ISSN 1307-5543 – www.ejpam.com Published by New York Business Global Asymptotic solutions of scalar integro-differential equations with partial derivatives and with fast oscillating coefficients Burkhan T. Kalimbetov1,∗, Alisher N. Temirbekov1, Abdimukhan S. Tolep1 1 Institut Natural Sciences, K.A.Yasawi International Kazakh-Turkish University, Turkestan, Kazakhstan Abstract. In the paper, ideas of the Lomov regularization method are generalized to the Cauchy problem for a singularly perturbed partial integro-differential equation in the case when the integral term contains a rapidly varying kernel. Regularization of the problem is carried out, the normal and unique solvability of general iterative problems is proved. 2020 Mathematics Subject Classifications: 35C20, 35F10, 45K05 Key Words and Phrases: Singularly perturbed, partial integro differential equation, regular- ization of an integral, solvability of iterative problems 1. Introduction In the paper, we consider the Cauchy problem for the integro-differential equation with partial derivatives: Lεy(x, t, ε) ≡ ε ∂y∂x = a(x)y + x∫ x0 K(x, t, s)y(s, t, ε)ds+ h(x, t)+ +εg(x)cosβ(x) ε y, y(x0, t, ε) = y0(t) ( (x, t) ∈ [x0, X]× [0, T ] ), (1) where β′(x) > 0, g(x), a(x) is a scalar functions, y0(t) constant, ε > 0 is a small parameter. The problem of constructing a regularized asymptotic solution [1] of the problem (1) is posed. Earlier, in [2], [3], [4], [5], [6], [7], systems for ordinary integro-differential equations were mainly considered. In this paper we consider an partial integro-differential equa- tions. Construction of asymptotic solutions for singularly perturbed integro-differential equations with partial derivatives in the case when integral operators change rapidly was first investigated in the works [8], [9], [10]. Construction of asymptotical solutions for ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v13i2.3664 Email addresses: burkhan.kalimbetov@ayu.edu.kz (B.T. Kalimbetov), alisher.temirbekov@ayu.edu.kz (A.N. Temirbekov), abdimuhan.tolep@ayu.edu.kz (A.S. Tolep) http://www.ejpam.com 287 c© 2020 EJPAM All rights reserved. B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 288 ordinary integro-differential equations with fast oscillating coefficients from the position of the regularization method are considered in [11]. Denote by λ1(x) = −a(x), β′(x) is a frequency of fast oscillating cosine. In the fol- lowing, functions λ2(x) = −iβ′(x), λ3(x) = +iβ′(x) will be called the spectrum of a fast oscillating coefficient. We assume that the conditions are fulfilled: (i) K(x, t, s) ∈ C∞{x0 < x < s < X, 0 < t < T}, h(x, t) ∈ C∞([x0, X]× [0, T ]), a(x), g(x), β(x) ∈ C∞[x0, X], (ii) λ1(x) 6= λj(x), j = 2, 3, λi(x) 6= 0, (∀x ∈ [x0, X]), i = 1, 2, 3; (iii) Reλ1(x) ≤ 0, (∀x ∈ [x0, X]); (iv) for ∀x ∈ [x0, X] and n2 6= n3 inequalities n2λ2(x) + n3λ3(x) 6= λ1(x), λ1(x) + n2λ2(x) + n3λ3(x) 6= λ1(x), (∀x ∈ [x0, X]) for all multi-indices n = (n2, n3) with |n| ≡ n2 + n3 ≥ 1 (n2 and n3 are non-negative integers) are holds. We will develop an algorithm for constructing a regularized [1] asymptotic solution of problem (1). 2. Regularization of the problem Denote by σj = σj(ε) independent of magnitude σ1 = e− i ε β(t0), σ2 = e+ i ε β(t0), and rewrite system (1) as ε ∂y∂x = a(x)y + εg(x) 2 e− i ε t∫ t0 β′(θ)dθ σ1+ +e + i ε t∫ t0 β′(θ)dθ σ2  y+ + x∫ x0 K(x, t, s)y(s, t, ε)ds+ h(x, t), y(x0, t, ε) = y0. (2) Introduce the regularized variables: τj = 1 ε x∫ x0 λj(θ)dθ ≡ ψj(x) ε , j = 1, 3 and instead of problem (2), consider the problem ε ∂ỹ∂x + 3∑ j=1 λj(x) ∂ỹ∂τj − a(x)ỹ − x∫ x0 K(x, t, s)ỹ(s, t, ψ(s) ε , ε)ds− −εg(x) 2 (eτ2σ1 + eτ3σ2)ỹ = h(x, t), ỹ(x0, t, 0, ε) = y0, (3) for the function ỹ = ỹ(x, t, τ, ε) where is indicated: ψ = (ψ1, ψ2, ψ3). It is clear that if ỹ = ỹ(x, t, τ, ε) is a solution of the problem (3), then the function is ỹ = ỹ(x, t, ψ(x) ε , ε) an B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 289 exact solution to problem (2), therefore, problem (3) is extended with respect to problem (2). However, it cannot be considered fully regularized, since it does not regularize the integral Jỹ = x∫ x0 K(x, t, s)ỹ(s, t, ψ(s, ε), ε)ds. Definition. A class Mε is said to be asymptotically invariant (with ε → +0) with respect to an operator P0 if the following conditions are fulfilled: 1) Mε ⊂ D(P0) for each fixed ε > 0; 2) the image P0µ(x, t, ε) of any element µ(x, t, ε) ∈Mε decomposes in a power series P0µ(x, t, ε) = ∞∑ n=0 εnµn(x, t, ε)(ε→ +0, µn(x, t, ε) ∈Mε, n = 0, 1, ...), convergent asymptotically for ε→ +0) (uniformly with ∈ [t0, T ]). From this definition it can be seen that the class Mε depends on the space U, in which the operator P0 is defined. In our case P0 = J. For the space U we take the space of vector functions y (x, t, τ) , represented by sums y(x, t, τ, σ) = 3∑ i=1 yi(x, t, σ)eτi + ∗∑ 2≤|m|≤Ny ym(x, t, σ)e(m,τ)+ +y0(x, t, σ) + ∗∑ 1≤|m|≤Ny ye1+m(x, t, σ)e(e1+m,τ), yi(x, t, σ), ym(x, t, σ), ye1+m(x, t, σ) ∈ C∞ ([x0, X]× [0, T ]) , 1 ≤ |m| ≡ m2 +m3 ≤ Ny, i = 0, 3, m = (0,m2,m3). (4) where is denoted: (m,λ(x)) ≡ m2λ2(x) +m3λ3(x), (e1 +m,λ(x)) ≡ λ1(x) +m2λ2(x) + m3λ3(x); an asterisk ∗ above the sum sign indicates that the summation for |m| ≥ 1 it occurs only over multi-indices m = (0,m2,m3) with m2 6= m3, e1 = (1, 0, 0) , σ = (σ1, σ2) . Note that here the degree Ny of the polynomial y (x, t, τ) , relative to the exponentials eτj depends on the element y. In addition, the elements of space U depend on bounded in ε > 0 terms of constants σ1 = σ1 (ε) and σ2 = σ2 (ε) and which do not affect the development of the algorithm described below, therefore, in the record of element (4) of this space U , we omit the dependence on σ = (σ1, σ2) for brevity. We show that the class Mε = U |τ=ψ(t)/ε is asymptotically invariant with respect to the operator J . The image of the integral operator J on an arbitrary element y (x, t, τ) , of the space U has the form Jy(x, t, τ) = x∫ x0 K(x, t, s)y0(s, t)ds+ 3∑ i=1 x∫ x0 K(x, t, s)yi(s, t)e 1 ε s∫ x0 λi(θ)dθ ds+ + ∗∑ 2≤|m|≤Ny x∫ x0 K(x, t, s)ym(s, t)e 1 ε s∫ x0 (m,λ(θ))dθ ds+ B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 290 + ∗∑ 1≤|m|≤Ny x∫ x0 K(x, t, s)ye1+m(s, t)e 1 ε s∫ x0 (e1+m,λ(θ))dθ ds. Apply the operation of integration by parts to the first term. Ji(x, t, ε) = x∫ x0 K(x, t, s)yi(s, t)e 1 ε s∫ x0 λi(θ)dθ ds = ε x∫ x0 K(x, t, s)yi(s, t) λi(s) de 1 ε s∫ x0 λi(θ)dθ = = ε K(x, t, s)yi(s, t) λi(s) e 1 ε s∫ x0 λi(θ)dθ ∣∣∣∣∣∣ s=x s=x0 − x∫ x0 ( ∂ ∂s K(x, t, s)yi(s, t) λi(θ) ) e 1 ε s∫ x0 λi(θ)dθ ds  = = ε K(x, t, x)yi(x, t) λi(x) e 1 ε x∫ x0 λi(θ)dθ − K(x, t, x0)yi(x0, t) λi(x0) − −ε x∫ x0 ( ∂ ∂s K(x, t, s)yi(s, t) λi(s) ) e 1 ε s∫ x0 λi(θ)dθ ds . Continuing this process, we obtain the series Ji(x, t, ε) = ∞∑ ν=0 (−1)νεν+1 (Iνi (K(x, t, s)yi(s, t)))s=x e 1 ε x∫ x0 λi(θ))dθ − − (Iνi (K(x, t, s)yi(s, t)))s=x0 ] , where I0 i = 1 λi(s) · , Iνi = 1 λi(s) Iν−1 i (ν ≥ 1, i = 1, 3). Applying the integration operation in parts to integrals Jm(x, t, ε) = x∫ x0 K(x, t, s)ym(s, t)e 1 ε s∫ x0 (m,λ(θ))dθ ds, Je1+m(x, t, ε) = x∫ x0 K(x, t, s)ye1+m(s, t)e 1 ε s∫ x0 (e1+m,λ(θ))dθ ds, we note that for all multi-indices m = (0,m2,m3) , m2 6= m3, inequalities (m,λ(x)) ≡ m2λ2(x) +m3λ3(x) 6= 0 ∀x ∈ [x0, X] , m2 +m3 ≥ 2 are satisfied. In addition, for the same multi-indices we have (e1 +m,λ(x)) 6= 0∀x ∈ [x0, X] , m2 6= m3, |m| = m2 +m3 ≥ 1. B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 291 Indeed, if (e1 +m,λ(x)) = 0 for some x ∈ [x0, X] and m2 6= m3, m2 + m3 ≥ 1, then m2λ2(x) +m3λ3(x) = −λ1(x)), m2 +m3 ≥ 1, which contradicts condition (iv). Therefore, integration by parts in integrals Jm (t, ε) , Je1+m (t, ε) is possible. Performing it, we will have: Jm(x, t, ε) = x∫ t0 K(x, t, s)ym(s, t)e 1 ε s∫ x0 (m,λ(θ))dθ ds = ε x∫ x0 K(x, t, s)ym(s, t) (m,λ(s)) de 1 ε s∫ x0 (m,λ(θ))dθ = = ε K(x, t, x)ym(x, t) (m,λ(x)) e 1 ε x∫ x0 (m,λ(θ))dθ − K(x, t, x0)ym(x0, t) (m,λ(x0)) − −ε x∫ x0 ( ∂ ∂s K(x, t, s)ym(s, t) (m,λ(s)) ) e 1 ε s∫ x0 (m,λ(θ))dθ ds = = ∞∑ ν=0 (−1)νεν+1 (Iνm (K(x, t, s)ym(s, t)))s=t e 1 ε x∫ x0 (m,λ(θ))dθ − − (Iνm (K(x, t, s)ym(s, t)))s=t0 ] , where I0 m = 1 (m,λ(s)) · , I ν m = 1 (m,λ(s)) ∂ ∂s I ν−1 m (ν ≥ 1, |m| ≥ 2), Je1+m(x, t, ε) = x∫ x0 K(x, t, s)ye1+m(s, t)e 1 ε s∫ x0 (e1+m,λ(θ))dθ ds = = ε s∫ x0 K(x, t, s)ye1+m(s, t) (e1 +m,λ(s)) de 1 ε s∫ x0 (e1+m,λ(θ))dθ = = ε K(x, t, x)ye1+m (x, t) (e1 +m,λ(x)) e 1 ε x∫ x0 (e1+m,λ(θ))dθ − K(x, t, x0)ye1+m (x0, t) (e1 +m,λ(x0)) − −ε x∫ x0 ( ∂ ∂s K (t, s) ye1+m(s, t) (e1 +m,λ (s)) ) e 1 ε s∫ x0 (e1+m,λ(θ))dθ ds = = ∞∑ ν=0 (−1)νεν+1 (Iνe1+m ( K(x, t, s)ye1+m(s, t) )) s=t e 1 ε x∫ x0 (e1+m,λ(θ))dθ − − ( Iνe1+m ( K(x, t, s)ye1+m(s, t) )) s=t0 ] , where I0 e1+m = 1 (e1+m,λ(s)) · , I ν e1+m = 1 (e1+m,λ(s)) ∂ ∂s I ν−1 e1+m (ν ≥ 1, |m| ≥ 1, B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 292 Therefore, the image of the operator J on the element (5) of the space U is represented as a series Jy(x, t, τ) = x∫ x0 K(x, t, s)y0(s, t)ds+ + 3∑ i=1 ∞∑ ν=0 (−1)νεν+1 (Iνi (K(x, t, s)yi(s, t)))s=t e 1 ε x∫ x0 λi(θ))dθ − − (Iνi (K(x, t, s)yi(s, t)))s=t0 ] + + ∗∑ 2≤|m|≤NY ∞∑ ν=0 (−1)νεν+1 (Iνm (K(x, t, s)ym(s, t)))s=t e 1 ε x∫ x0 (m,λ(θ))dθ − − (Iνm (K(x, t, s)ym(s, t)))s=t0 ] + + ∑ 1≤|m|≤NY ∞∑ ν=0 (−1)νεν+1[ ( Iνe1+m ( K(x, t, s)ye1+m(s, t) )) s=t × ×e 1 ε x∫ x0 (e1+m,λ(θ))dθ − ( Iνe1+m ( K(x, t, s)ye1+m(s, t) )) s=t0 ] . It is easy to show (see, for example, [12], pp. 291-294) that this series converges asymptotically for ε → +0 (uniformly in (x, t) ∈ [x0, X] × [0, T ]). This means that the class Mε is asymptotically invariant (for ε→ +0) with respect to the operator J . We introduce operators Rν : U → U, acting on each element y(x, t, τ) ∈ U of the form (5) according to the law: R0y(x, t, τ) = x∫ x0 K(x, t, s)y0(s, t)ds, (60) R1y(x, t, τ) = 3∑ i=1 [( I0 i (K(x, t, s)yi(s, t)) ) s=x eτi − ( ( I0 i (K(x, t, s)yi(s, t)) ) s=x0 ]+ + ∗∑ 1≤|m|≤Ny [ ( I0 m (K(x, t, s)ym(s, t)) ) s=x e(m,τ) − ( I0 m (K(x, t, s)ym(s, t)) ) s=x0 ]+ + ∗∑ 1≤|m|≤Ny [( I0 e1+m ( K(x, t, s)y e1+m (s, t) )) s=x e(e1+m,τ)− (61) − ( I0 e1+m ( K(x, t, s)y e1+m (s, t) )) s=x0 ] , B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 293 Now let ỹ(x, t, τ, ε) be an arbitrary continuous function on (x, t, τ) ∈ [x0, X]× [0, T ]× {τ : Re τj , j = 1, 3}, with asymptotic expansion ỹ(x, t, τ, ε) = ∞∑ k=0 εkyk(x, t, τ), yk(x, t, τ) ∈ U, (7) converging as ε→ +0 (uniformly in (x, t, τ) ∈ [x0, X]× [0, T ]×{τ : Re τj , j = 1, 3}). Then the image Jỹ (x, t, τ, ε) of this function is decomposed into an asymptotic series Jỹ(x, t, τ, ε) = ∞∑ k=0 εkJyk(x, t, τ) = ∞∑ r=0 εr r∑ s=0 Rr−sys(x, t, τ)|τ=ψ(t)/ε. This equality is the basis for introducing an extension of an operator J on series of the form (7): J̃ ỹ ≡ J̃ ( ∞∑ k=0 εkyk(x, t, τ) ) = ∞∑ r=0 εr ( r∑ k=0 Rr−kyk(x, t, τ) ) . Although the operator J̃ is formally defined, its utility is obvious, since in practice it is usual to construct the N -th approximation of the asymptotic solution of the problem (2), in which impose only N -th partial sums of the series (7), which have not a formal, but a true meaning. Now you can write a problem that is completely regularized with respect to the original problem (2): Lεỹ(x, t, τ, ε) ≡ ε ∂ỹ∂x + 3∑ j=1 λj(x) ∂ỹ∂τj − a(x)ỹ − J̃ ỹ − εg(x) 2 (eτ2σ1 + eτ3σ2)ỹ = = h(x, t), ỹ(x0, t, 0, ε) = y0, ((x, t) ∈ [x0, X]× [0, T ]) . (8) 3. Solvability of iterative problems Substituting the series (7) into (8) and equating the coefficients of the same powers of ε, we obtain the following iterative problems: Ly0 ≡ 3∑ j=1 λj(x)∂y0∂τj − a(x)y0 −R0y0 = h(x, t), y0(x0, t, 0) = y0; (90) Ly1 = −∂y0 ∂x + g(x) 2 (eτ2σ1 + eτ3σ2)y0 +R1y0, y1(x0, t, 0) = 0; (91) Ly2 = −∂y1 ∂x + g(x) 2 (eτ2σ1 + eτ3σ2)y1 +R1y1 +R2y0, y2(x0, t, 0) = 0; (92) ............................................................ Lyk = −∂yk−1 ∂x + g(x) 2 (eτ2σ1 + eτ3σ2)yk−1 +Rky0 +R1yk−1, yk(x0, t, 0) = 0, k ≥ 1. (9k) B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 294 Each iterative problem (9k) has the form Ly ≡ 3∑ j=1 λj(x) ∂y ∂τj − a(x)y −R0y = H(x, t, τ), y(x0, t, 0) = y∗, (10) where H(x, t, τ) ∈ U, is the known vector function of space U, y∗ is the known constant vector of the complex space C, and the operator R0 has the form (see (60)) R0y(x, t, τ) ≡ R0 y0(x, t) + 3∑ i=1 yi(x, t)e τi+ ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ + ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ)  ∆ = x∫ x0 K(x, t, s)y0(s, t)ds. We introduce scalar (for each x ∈ [x0, X]) product in space U : < u,w >≡< u0(x, t) + 3∑ i=1 ui(x, t)e τi + ∗∑ 2≤|m|≤Ny um(x, t)e(m,τ)+ + ∗∑ 1≤|m|≤Ny ue1+m(x, t)e(e1+m,τ), w0(x, t) + 3∑ i=1 wi(x, t)e τi+ + ∗∑ 2≤|m|≤Nw wm(x, t)e(m,τ) + ∗∑ 1≤|m|≤Nw we1+m(x, t)e(e1+m,τ) > ∆ = ∆ = (u0(x, t), w0(x, t)) + 3∑ i=1 (ui(x, t), wi(x, t)) + ∗∑ 2≤|m|≤min(Ny ,Nw) (um(x, t), wm(x, t)) + + ∗∑ 1≤|m|≤min(Ny ,Nw) ( ue1+m(x, t), we1+m(x, t) ) , where we denote by (∗ , ∗) the usual scalar product in the complex space C. Let us prove the following statement. Theorem 1. Let conditions (i)-(ii), (iv) be fulfilled and the right-hand side H(x, t, τ) of system (10) belongs to the space U . Then the system (10) is solvable in U, if and only if H1(x, t, τ) ≡ 0, ∀x ∈ [x0, X] . (11) Proof. We will determine the solution of system (10) as an element (5) of the space U : y(x, t, τ) = y0(x, t) + 3∑ i=1 yi(x, t)e τi + ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 295 + ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ) ≡ y0(x, t) + 3∑ i=1 yi(x, t)e τi+ (12) + ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ) + ∗∑ 2≤|m1|≤Ny ym 1 (x, t)e(mk,τ), where for convenience introduced multi-indices m1 = e1 + m ≡ (1,m2,m3) , m2 and m3 are non-negative integer numbers. Substituting (12) into system (10), we will have 3∑ i=1 [λi(x)− a(x)] yi(x, t)e τi + ∗∑ 2≤|m|≤Ny [(m,λ(x))− a(x)] ym(x, t)e(m,τ)+ + ∗∑ 2≤|m1|≤Ny [( m1, λ(x) ) − a(x) ] ym 1 (x, t)e(m1,τ)− −a(x)y0(x, t)− x∫ x0 K(x, t, s)y0(s, t)ds = H0(x, t)+ + 3∑ i=1 Hi(x, t)e τi + ∗∑ 2≤|m|≤Ny Hm(x, t)e(m,τ) + ∗∑ 2≤|m1|≤Ny Hm1 (x, t)e(m1,τ). Equating here the free terms and coefficients separately for identical exponents, we obtain the following systems of equations: −a(x)y0(x, t)− x∫ x0 K(x, t, s)y0(s, t)ds =H0(x, t), (13) [λi(x)− a(x)] yi(x, t) = Hi(x, t), i = 1, 4, (13i) [(m,λ(x))− a(x)] ym(x, t) = Hm(x, t), m2 6= m3, 2 ≤ |m| ≤ Ny, (13m)[( m1, λ(x) ) − a(x) ] zm 1 (x, t) = Hm1 (x, t),m2 6= m3,2 ≤ ∣∣m1 ∣∣ ≤ Ny. (14) The equation (13) can be written as y0(x, t) = x∫ x0 ( −a−1(x)K(x, t, s) ) y0(s, t)ds− a−1(x)H0(x, t). (130) Due to the smoothness of the kernel −a−1(x)K(x, t, s) and heterogeneity −a−1(x)H0(x, t), this Volterra integral equation has a unique solution z0(x, t) ∈ C∞ ([x0, X]× [0, T ]) . The equations (132) and (133) also have unique solutions zi(x, t) = [λ1(x)− a(x)]−1Hi(x, t) ∈ C∞ ([x0, X]× [0, T ]) , i = 2, 3. B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 296 Equation (131) are solvable in space C∞ ([x0, X]× [0, T ]) if and only if there are identities H1(x, t) ≡ 0 ∀x ∈ [x0, X] , It is not difficult to see that these identities coincide with identities (11). Further, since (m,λ(x)) ≡ m2λ2(x) + m3λ3(x) 6= λ1(x), |m| = m2 + m3 ≥ 2 (see condition (iv)) the absence of resonance), the equation system (13m) has a unique solution zm(x, t) = [(m,λ(x))− a(x)]−1Hm(x, t), 2 ≤ |m| ≤ Ny ∈ C∞ ([x0, X]× [0, T ]) . We now consider equation (14). Let ( m1, λ(x) ) = λ1(x), ∣∣m1 ∣∣ ≥ 2. Then λ1(x) +m2λ2(x) +m3λ3(x) = λ1(x)⇔ ⇔ m2λ2(x) +m3λ3(x) = 0⇔ m2 6= m3, m2 +m3 ≥ 1, which cannot be (see definition of class U). Unique solution of equation (18) for ∣∣m1 ∣∣ ≥ 2 in the class C∞ ([x0, X]× [0, T ]) : zm 1 (x, t) = [( m1, λ(x) ) − a(x) ]−1 Hm1 (x, t), 2 ≤ ∣∣m1 ∣∣ ≤ Ny. Thus, condition (11) is necessary and sufficient for the solvability of equation (10) in the space U . The theorem is proved. Remark. If identity (11) holds, then under conditions (i)-(ii) and (iv), equation (10) has the following solution in the space U : y(x, t, τ) = y0(x, t) + α1(x, t)eτ1 + 3∑ i=2 [λi(x)− a(x)]−1Hi(x, t)e τi+ + ∗∑ 2≤|m|≤Ny [(m,λ(x))− a(x)]−1Hm(x, t)e(m,τ)+ (14) + ∗∑ 1≤|m|≤Ny [(e1 +m,λ(x))− a(x)]−1He1+m(x, t)e(e1+m,τ), where α1(x, t) ∈ C∞ ([x0, X]× [0, T ]) are arbitrary function, y0(x, t) is the solution of an integral equation (130), m ≡ (0,m2,m3) ,m2 6= m3, |m| = m2 +m3 ≥ 1. 4. The unique solvability of the general iterative problem in the space U . Residual term theorem Let us proceed to the description of the conditions for the unique solvability of equation (10) in space U . Along with problem (10), we consider the equatiom Ly(x.t, τ) = −∂y ∂x + g(x) 2 (eτ2σ1 + eτ3σ2) y +Q(x, t, τ), (15) B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 297 where y = y(x, t, τ) is the solution (14) of the equation (10), Q(x, t, τ) ∈ U is the well- known function of the space U. The right part of this equation: G(x, t, τ) ≡ −∂y ∂x + g(x) 2 (eτ2σ1 + eτ3σ2) y +Q(x, t, τ) = = − ∂ ∂x y0(x, t) + 3∑ i=1 yi(x, t)e τi + ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ + ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ) + + g(x) 2 (eτ2σ1 + eτ3σ2) y0(x, t) + 3∑ i=1 yi(x, t)e τi + ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ + ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ) +Q(x, t, τ), may not belong to space U , if y = y(x, t, τ) ∈ U. Indeed, taking into account the form (14) of the function y = y(x, t, τ) ∈ U, we will have Z(x, t, τ) ≡ G(x, t, τ) + ∂y ∂x − g(x) 2 (eτ2σ1 + eτ3σ2) [ y0(x, t) + 3∑ i=1 yi(x, t)e τi+ + ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ) + ∗∑ 1≤|m|≤Ny ze1+m(x, t)e(e1+m,τ)  = = g(x) 2 y0(x, t) (eτ2σ1 + eτ3σ2) + 3∑ i=2 g(x) 2 yi(x, t) ( eτi+τ2σ1 + eτi+τ3σ2 ) + + g(x) 2 y1(x, t) ( eτ1+τ2σ1 + eτ1+τ3σ2 ) + g(x) 2 (eτ2σ1 + eτ3σ2)  ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ + ∗∑ 1≤|m|≤Ny ze1+m(x, t)e(e1+m,τ) +Q(x, t, τ). Here are terms with exponents eτ3+τ2 = e(m,τ)|m=(0,1,1), eτ2+(m,τ) (if m2 + 1 = m3) , eτ3+(m,τ) (if m3 + 1 = m2) , (∗) B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 298 eτ2+(e1+m,τ) (if m2 + 1 = m3)m3 + 1 = m2, do not belong to space U, since in multi-index m = (0,m2,m3) of the space U must be m2 6= m3, m2 +m3 ≥ 1. Then, according to the well-known theory (see, [1] , p. 234), we embed these terms in the space U according to the following rule (see (∗)): êτ2+τ3 = e0 = 1, ̂eτ2+(m,τ) = e0 = 1 (m2 + 1 = m3,m2 6= m3) , ̂eτ3+(m,τ) = e0 = 1 (m3 + 1 = m2,m2 6= m3) , ̂eτ2+(e1+m,τ) = eτ1 (m2 + 1 = m3,m2 6= m3) . (∗∗) In Z(x, t, τ) need of embedding only the terms M(x, t, τ) ≡ 3∑ i=2 g(x) 2 yi(x, t) ( eτi+τ2σ1 + eτi+τ3σ2 ) + g(x) 2 y1(x, t) ( eτ1+τ2σ1 + eτ1+τ3σ2 ) , S(x, t, τ) ≡ g(x) 2 (eτ2σ1 + eτ3σ2) [ ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ)]. We describe this embedding in more detail, taking into account formulas (∗∗) : M(x, t, τ) ≡ g(x) 2 y1(x, t) ( eτ1+τ2σ1 + eτ1+τ3σ2 ) + 3∑ i=2 g(x) 2 yi(x, t) ( eτi+τ2σ1 + eτi+τ3σ2 ) = = g(x) 2 [ y1(x, t)eτ1+τ2σ1 + y1(x, t)eτ1+τ3σ2 + y2(x, t)e2τ2σ1 + y2(x, t)σ2+ +y3(x, t)σ1 + y3(x, t)e2τ3σ2 ] ⇒ ⇒ M̂(x, t, τ) = g(x) 2 [ y1(x, t)eτ1+τ2σ1 + y1(x, t)eτ1+τ3σ2 + y2(x, t)e2τ2σ1+ +y2(x, t)σ2 + y3(x, t)σ1 + y3(x, t)e2τ3σ2 ] , (note that in M̂(x, t, τ) there are no members containing eτ1 , measurement exponents |m| = 1) : S(x, t, τ) ≡ g(x) 2 (eτ2σ1 + eτ3σ2)  ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ)+ ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ)  = = g(x) 2  ∗∑ 2≤|m|≤Ny ym(x, t) ( eτ2+(m,τ)σ1 + eτ3+(m,τ)σ2 ) + + ∗∑ 1≤|m|≤Ny ye1+m(x, t) ( e(e1+m,τ)+τ2σ1 + e(e1+m,τ)+τ3σ2 ) ⇒ B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 299 ⇒ Ŝ(x, t, τ) = g(x) 2 [ ∑ 2 ≤ |m| ≤ Ny, m2 + 1 = m3 ym(x, t)σ1 + ∑ 2 ≤ |m| ≤ Ny, m3 + 1 = m2 ym(x, t)σ2+ + ∗∑ 2 ≤ |m| ≤ Ny, m2 + 1 6= m3,m3 + 1 6= m2 ym(x, t)e(m,τ)+ +  ∑ 1 ≤ |m| ≤ Ny, m2 + 1 = m3 ye1+m(x, t)σ1 + ∑ 1 ≤ |m| ≤ Ny, m3 + 1 = m2 ye1+m(x, t)σ2  e τ1+ + ∗∑ 1 ≤ |m| ≤ Ny, m2 + 1 6= m3,m3 + 1 6= m2 ye1+m(x, t)e(e1+m,τ), After embedding, the right-hand side of system (15) will look like Ĝ(x, t, τ) = − ∂ ∂x y0(x, t) + 3∑ i=1 yi(x, t)e τi+ ∗∑ 2≤|m|≤Ny ym(x, t)e(m,τ) − − ∂ ∂x  ∗∑ 1≤|m|≤Ny ye1+m(x, t)e(e1+m,τ) + M̂(x, t, τ) + Ŝ(x, t, τ) +Q(x, t, τ), moreover, in Ŝ(x, t, τ) the coefficients at eτ1 do not depend on z1(x, t). As indicated in [1], the embedding G(x, t, τ) → Ĝ(x, t, τ) will not affect the accuracy of the construction of asymptotic solutions of problem (2), since G(x, t, τ)→ Ĝ(x, t, τ). Theorem 2. Let conditions (i)-(ii), (iv) be fulfilled and the right-hand side H(x, t, τ) ∈ U of equation (10) satisfy condition (11). Then problem (10) under additional conditions Ĝ(x, t, τ) ≡ 0 ∀t ∈ [x0, X] , (16) where Q(x, t, τ) is the known vector function of space U , is uniquely solvable in U . Proof. Since the right-hand side of equation (10) satisfies condition (11), this equation has a solution in space U in the form (14), where α1(x, t) ∈ C∞ ([x0, X]× [0, T ]) are arbitrary function so far. Submit (14) to the initial condition y (x0, t, 0) = y∗. We get α1(x0, t) = y∗, where denoted y∗ = y∗ + a−1(x0)H0(x0, t)− 3∑ i=2 [λi(x0)− a(x0)]−1Hi(x0, t)− B.T. Kalimbetov, A.N. Temirbekov, A.S. Tolep / Eur. J. Pure Appl. Math, 13 (2) (2020), 287-302 300 − ∗∑ 2≤|m|≤Ny [(m,λ(x0))− a(x0)]−1Hm(x0, t)− − ∗∑ 1≤|mk|≤Ny [( mk, λ(x0) ) − a(x0) ]−1 Hmk (x0, t). where do we find the values α1(x0, t) = y∗. Then condition (16) takes the form − ∂ ∂x α1(x, t)eτ1+ +  ∑ 1 ≤ |m| ≤ Ny, m2 + 1 = m3 ye1+m(x, t)σ1 + ∑ 1 ≤ |m| ≤ Ny, m3 + 1 = m2 ye1+m(x, t)σ2  e τ1+ +Q1(x, t)eτ1 ≡ 0 ∀(x, t) ∈ [x0, X]× [0, T ], . We obtain linear ordinary differential equations with respect to the function α1(x, t), involved in the solution (14) of equation (10). Attaching to them the initial conditions α1 (t0) = y∗ computed earlier, we find uniquely the function α1(x0, t) = y∗ and, therefore, we construct solution (14) in the space in a unique way. The theorem 2 is proved. Applying Theorems 1 and 2 to iterative problems (9k) (in this case, the right-hand sides H(k)(x, t, τ) of these problems are embedded in the space U , i.e. H(k)(x, t, τ) we replace with Ĥ(k)(x, t, τ) ∈ U), we find uniquely their solutions in space U and construct series (7). Justasin [1], we prove the following statement. Theorem 3. Suppose that conditions (i)-(ii), (iv) are satisfied for problem (2). 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