EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 14, No. 1, 2021, 53-64 ISSN 1307-5543 – ejpam.com Published by New York Business Global Coefficient problems in a class of functions with bounded turning associated with Sine function Muhammad Ghaffar Khan1, Bakhtiar Ahmad2, Janusz Sokó l3, Zubair Muhammad1, Wali Khan Mashwani1, Ronnason Chinram 4, Pattarawan Petchkaew5,∗ 1 Institute of Numerical Sciences, Kohat University of Science & Technology, Kohat, Pakistan 2 Government Degree College Mardan, 23200 Mardan, Pakistan 3 University of Rzeszów, College Natural Sciences, ul. Prof. Pigonia 1, 35-310 Rzeszów, Poland 4 Algebra and Applications Research unit, Division of Computational Science, Faculty of Sciences, Prince of Songkla University, Hat Yai, Songkhla 90110 Thailand 5 Program in Mathematics, Faculty of Science and Technology, Songkha Rajabhat University, Songkhla, 90000, Thailand Abstract. The Hankel determinant for a function having power series was first defined by Pom- merenke. The growth of Hankel determinant has been evaluated for different subcollections of univalent functions. Many subclasses with bounded turning have several interesting geometric properties. In this paper, some classes of functions with bounded turning which connect to the sine functions, are studied in the region of the unit disc in order. Our purpose is to obtain some upper bounds for the third and fourth Hankel determinants related to such classes. 2020 Mathematics Subject Classifications: 30C45, 30C50 Key Words and Phrases: Holomorphic functions, Subordinations, Trigonometric function, Hankel determinant 1. Introduction and Preliminaries LetA be the class of all functions f(z) which are holomorphic in the region D = {z ∈ C : |z| < 1} with the normalization f (0) = f ′(0)− 1 = 0. Therefore, for f(z) ∈ A, one has f(z) = z + ∞∑ k=2 akz k (z ∈ D) . (1) ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v14i1.3902 Email addresses: ghaffarkhan020@gmail.com (M. G. Khan), pirbakhtiarbacha@gmail.com (B. Ahmad), jsokol@ur.edu.pl (J. Sokó l), zubair.math1984@gmail.com (Z. Muhammad), walikhan@kust.edu.pk (W. K. Mashwani), ronnason.c@psu.ac.th (R. Chinram), pattarawan.pe@gmail.com (P. Petchkaew) http://www.ejpam.com 53 c© 2021 EJPAM All rights reserved. P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 54 Let S ⊂ A represent all functions that are univalent in D. For a function f ∈ S of the form (1) , Bieberbach conjectured in 1916 that |an| ≤ n, n = 2, 3, . . .. De Branges proved this in 1985, see [7]. During this period, a lot of coefficients results were established for some subfamilies of S. For example, the class S∗ of starlike functions, K of convex functions and R of bounded turning functions: S∗ = { f ∈ S : zf ′(z) f(z) ≺ 1 + z 1− z , z ∈ D } , (2) K = { f ∈ S : (zf ′(z))′ f ′(z) ≺ 1 + z 1− z , z ∈ D } , R = { f ∈ S : f ′(z) ≺ 1 + z 1− z , z ∈ D } , where ” ≺ ” represents the subordination. We write g1 ≺ g2, if there is an analytic function v in D, with limitations v (0) = 0 and |v(z)| < 1, such that g1(z) = g2 (v(z)) , z ∈ D. In case of univalency of g2 in D, the following relation holds; g1(z) ≺ g2(z), z ∈ D ⇐⇒ g1(0) = g2(0) and g1(D) ⊂ g2(D). By varying the function right hand side of subordinations in (2), we can define some subclasses of the set S which have several interesting geometric properties, see [9–12, 15– 17, 23, 28, 29, 35]. From among these subfamilies we recall here the families that are associated with trigonometric function as follows; Ksin = { f ∈ A : 1 + zf ′′(z) f ′(z) ≺ 1 + sin(z), z ∈ D } , (3) S∗sin = { f ∈ A : zf ′(z) f(z) ≺ 1 + sin(z), z ∈ D } , (4) Rsin = { f ∈ A : f ′(z) ≺ 1 + sin(z), z ∈ D } . (5) The set defined in (4) was established by Cho et.al [10] and studied the radii problems. Here we investigated only the class (5) . For given parameters q, n ∈ N = {1, 2, . . .}, the Hankel determinant Hq,n (f) was defined by Pommerenke [32, 33] for a function f ∈ S having power series expansion (1) as follows: Hq,n (f) = ∣∣∣∣∣∣∣∣∣ an an+1 . . . an+q−1 an+1 an+2 . . . an+q ... ... . . . ... an+q−1 an+q . . . an+2q−2 ∣∣∣∣∣∣∣∣∣ . (6) The growth of Hq,n (f) has been evaluated for different subcollections of univalent func- tions. Exceptionally, for each of the sets K, S∗ and R the sharp bound of the determinant H2,2 (f) = ∣∣a2a4 − a23∣∣ were found by Janteng et al. [13, 14] while for the family of close- to-convex functions the sharp estimation is still unknown (see, [38]). On the other hand, P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 55 for the set of Bazilevič functions, the best estimate of |H2,2 (f)| was proved by Krishna and RamReddy [21]. For more work on H2,2 (f) , see [5, 26, 27, 30, 31]. The determinant H3,1 (f) = ∣∣∣∣∣∣ 1 a2 a3 a2 a3 a4 a3 a4 a5 ∣∣∣∣∣∣ (7) is known as third order Hankel determinant and the estimation of this determinant |H3,1 (f)| is a challenging task. In 2010, the first article on H3,1 (f) by Babalola [4], in which he obtained the upper bound of |H3,1 (f)| for the groups of S∗, K and R. Later on, a few creators distributed their work regarding |H3,1 (f)| for various subcollections of holo- morphic and univalent functions, see [1, 2, 6, 8, 19, 22, 37, 39]. In 2017, the consequences of Babalola [4] improved by Zaprawa [40], by proving |H3,1 (f)| ≤  1, for f ∈ S∗, 49 540 , for f ∈ K, 41 60 , for f ∈ R. and asserted that these inequalities are as yet not sharp. Additionally for the sharpness, he thought about the subfamilies of S∗, C and R comprising of functions with m-fold symmetry and acquired the sharp bounds. Recently in 2018, Kowalczyk et.al [20] and Lecko et.al [25] evaluated the sharp inequalities |H3,1 (f)| ≤ 4/135, and |H3,1 (f)| ≤ 1/9, for the recognizable sets K and S∗ (1/2) respectively, where the symbol S∗ (1/2) indicates the family of starlike functions of order 1/2. Additionally in 2018, the authors [24] got an improved bound |H3,1 (f)| ≤ 8/9 for f ∈ S∗, yet not best possible. Now in this paper, our main purpose is to study third and fourth order Hankel determinants family defined in (5) . 2. A Set of Lemmas Let P be the family of functions p that are holomorphic in D with Rep(z) > 0 and the power series form as follow; p(z) = 1 + ∞∑ n=1 cn z n (z ∈ D) . (8) Lemma 1. If p ∈ P be expressed in series expansion (8), then |cn| ≤ 2 for n ≥ 1, (9)∣∣∣∣c2 − c21 2 ∣∣∣∣ ≤ 2− |c1| 2 2 , (10) |ci+j − µcicj | ≤ 2, for 0 ≤ µ ≤ 1. (11) P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 56 and for complex number ρ, we have∣∣c2 − ρc21∣∣ ≤ 2 max {1, |2ρ− 1|} . (12) where the inequalities (9) , (10) , (11) are taken from [34] and (12) is obtained in [18]. Lemma 2. If p(z) ∈ P be expressed in series expansion (8), then 2c2 = c21 + x ( 4− c21 ) for some x, |x| ≤ 1 and 4c3 = c31 + 2 ( 4− c21 ) c1x− ( 4− c21 ) c1x 2 + 2 ( 4− c21 ) ( 1− |x|2 ) z for some z, |z| ≤ 1. Lemma 3. ([3]) Let p ∈ P has power series (8), then∣∣Jc31 −Kc1c2 + Lc3 ∣∣ ≤ 2 |J |+ 2 |K − 2J |+ 2 |J −K + L| (13) Corollary 1. ([34]) Let p ∈ P has power series (8), then∣∣c31 − 2c1c2 + c3 ∣∣ ≤ 2, Lemma 4. ([36]) Let m,n, l and a satisfy the inequalities 0 < m < 1, 0 < r < 1, and 8r (1− r) [ (mn− 2l)2 + (m (r +m)− n)2 ] +m (1−m) (n− 2rm)2 ≤ 4m2 (1−m)2 r (1− r) . If p(z) ∈ P and has power series (8) then∣∣∣∣lc41 + rc22 + 2mc1c3 − 3 2 nc21c2 − c4 ∣∣∣∣ ≤ 2. 3. Improved bound of |H3,1 (f)| for the Set Rsin Theorem 1. If f(z) of the form (1) belongs to Rsin, then |ak| ≤ 1 k , k = 2, 3, 4, 5. (14) The results are sharp. Proof. Since f(z) ∈ Rsin, form subordination definition there exists a Schwarz function v(z) with v (0) = 0 and |v(z)| < 1, in such a way that f ′(z) = 1 + sin (v(z)) , (z ∈ D) . Since, f ′(z) = 1 + 2a2z + 3a3z 2 + 4a4z 3 + 5a5z 4 + · · · . (15) P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 57 Define a function h(z) = 1 + v(z) 1− v(z) = 1 + c1z + c2z 2 + · · · . (16) Clearly, we have h(z) ∈ P and v(z) = h(z)− 1 h(z) + 1 = c1z + c2z 2 + c3z 3 + · · · 2 + c1z + c2z2 + c3z3 + · · · . This gives 1 + sin (v(z)) = 1 + 1 2 c1z + ( c2 2 − c21 4 ) z2 + ( 5c31 48 − c1c2 2 + c3 2 ) z3 + ( − 1 32 c41 + 5 16 c21c2 − 1 2 c3c1 − 1 4 c22 + 1 2 c4 ) z4 + · · · . (17) By comparing (15) and (17), we may get a2 = c1 4 , (18) a3 = 1 3 ( c2 2 − c21 4 ) , (19) a4 = 1 4 ( 5 48 c31 + c3 2 − c1c2 2 ) , (20) a5 = 1 5 ( c4 2 + 5 16 c21c2 − c41 32 − c1c3 2 − c22 4 ) . (21) Now implementing (9), in (18), we obtain |a2| ≤ 1 2 . Now using (10), in (19), we get |a3| ≤ 1 6 ( 2− |c1| 2 2 ) The maximum value of above function at c1 = 0. |a3| ≤ 1 3 . Implementation of triangle inequality and Lemma 3, in (20), leads us to |a4| ≤ 1 4 . By applying Lemma 4 in (21), it provides |a5| ≤ 1 5 . P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 58 If for k = 2, 3, 4, 5, we take the functions fk(z) = z + · · · such that f ′k(z) = 1 + sin(zk−1), (z ∈ D), then f ′k(z) ≺ 1 + sin z and so fk ∈ Rsin and fk(z) = z + 1 k zk − 1 3!(3k − 2) z3k−2 + · · · , (z ∈ D) (22) which shows that the bounds are sharp. Conjecture If f(z) of the form (1) belongs to Rsin, then |an| ≤ 1 n , n ≥ 6. (23) Theorem 2. If f(z) of the form (1) belongs to Rsin, then for any complex number ρ∣∣a3 − ρa22∣∣ ≤ 1 3 max { 1, 3|ρ| 4 } . (24) The result is sharp. Proof. Utilizing (18) and (19), we may get∣∣a3 − ρa22∣∣ = ∣∣∣∣c26 − c21 12 − ρ 16 c21 ∣∣∣∣ . This gives ∣∣a3 − ρa22∣∣ = 1 6 ∣∣∣∣{c2 − (4 + 3ρ 8 ) c21 }∣∣∣∣ . Application of (12), leads us to∣∣a3 − ρa22∣∣ ≤ 1 3 max { 1, |3ρ| 4 } . For the sharpness of (24) consider (22), with k = 2: f2(z) = z + 1 2 z2 − 1 4! z4 + · · · , (z ∈ D), which gives equality in (24) when |ρ| ≥ 4/3, namely∣∣a3 − ρa22∣∣ = |ρa22| = |ρ| 4 . For the case |ρ| ≤ 4/3 consider f3(z) = z + 1 3 z3 − 1 42 z7 + · · · , (z ∈ D), which gives ∣∣a3 − ρa22∣∣ = |a3| = 1 3 = 1 3 max { 1, 3|ρ| 4 } . P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 59 Corollary 2. If f ∈ Rsin and |ρ| ≤ 4/3, then∣∣a3 − ρa22∣∣ ≤ 1 3 . (25) Theorem 3. If f of the form (1) belongs to Rsin, then |a2a3 − a4| ≤ 1 4 . (26) The result is sharp. Proof. From (18),(19) and (20), we have |a2a3 − a4| = ∣∣∣∣− 3 64 c31 + 1 6 c2c1 − 1 8 c3 ∣∣∣∣ = ∣∣∣∣ 3 64 c31 − c1c2 6 + c3 8 ∣∣∣∣ . Implementation of triangle inequality and Lemma 3, in (20), leads us to |a2a3 − a4| ≤ 1 4 . The sharpness of (26) shows f4(z) = z + z4/4− z10/60 + · · · which was defined in (22). Theorem 4. If f(z) of the form (1) belongs to Rsin, then∣∣a2a4 − a23∣∣ ≤ 1 9 . (27) The result is sharp. Proof. Now since from (18), (19), and (20), we have ∣∣a2a4 − a23∣∣ = ∣∣∣∣c1c332 − c21c2 288 − c41 2304 − c22 36 ∣∣∣∣ . Now in terms of Lemma 2, we obtain ∣∣a2a4 − a23∣∣ = ∣∣∣∣c1c332 − c21c2 288 − c41 2304 − c22 36 ∣∣∣∣ = ∣∣∣∣∣∣− c41 768 − c21x 2 ( 4− c21 ) 128 − x2 ( 4− c21 )2 144 + c1 ( 4− c21 ) ( 1− |x|2 ) z 64 ∣∣∣∣∣∣ . Let |z| = 1 , |x| = t, t ∈ [0, 1], |c1| = c ∈ [0, 2] . Then, using the triangle inequality, we get ∣∣a2a4 − a23∣∣ ≤ c4 768 + t2c2 ( 4− c2 ) 128 + t2 ( 4− c2 )2 144 + ( 1− t2 ) c ( 4− c2 ) 64 . P. Petchkaew et al. / Eur. J. Pure Appl. Math, 14 (1) (2021), 53-64 60 Putting H (c, t) = c4 768 + t2c2 ( 4− c2 ) 128 + t2 ( 4− c2 )2 144 + ( 1− t2 ) c ( 4− c2 ) 64 , then, ∂H (c, t) ∂t = t ( c2 − 18c+ 32 ) ( 4− c2 ) 576 > 0, which shows that H (c, t) increases on [0, 1] with respect t. That is H (c, t) have maximum value at t = 1, which is maxH (c, t) = H (c, 1) = c4 768 + c2 ( 4− c2 ) 128 + ( 4− c2 )2 144 . Setting G (c) = c4 768 + c2 ( 4− c2 ) 128 + ( 4− c2 )2 144 , then we have G ′ (c) = c3 192 + c ( 4− c2 ) 64 − c3 64 − c ( 4− c2 ) 36 . If G ′ (c) = 0, then the root is c = 0. Further, since G ′′ (c) = − 7 144 < 0, so the function G (c) can attain the maximum value at c = 0, which is∣∣a2a4 − a23∣∣ ≤ 1 9 . The sharpness of (27) shows f3(z) = z + z3/3− z7/42 + · · · which was defined in (22). Theorem 5. If f(z) = z + a2z 2 + a3z 3 + · · · belongs to Rsin, then |H3,1 (f)| ≤ 359 2160 = 0.16620 . . . . (28) Proof. Third order Hankel determinant form equation (7) one may written as; H3,1 (f) = a3 ( a2a4 − a23 ) − a4 (a4 − a2a3) + a5 ( a3 − a22 ) . where a1 = 1. This provides that |H3,1 (f)| ≤ |a3| ∣∣a2a4 − a23∣∣+ |a4| |a4 − a2a3|+ |a5| ∣∣a3 − a22∣∣ . By implementing (14), (25), (26) and (27 ), we obtain our desired result. REFERENCES 61 4. Bound of |H4,1 (f)| for the Set Rsin First we can write H4,1 (f) in the form H4,1 (f) = a7H3,1 (f)− 2a4a6 ( a2a4 − a23 ) − 2a5a6 (a2a3 − a4)− a26 ( a3 − a22 ) +a25 ( a2a4 − a23 ) + a25 ( a2a4 + 2a23 ) − a35 + a44 − 3a3a 2 4a5. (29) Also ∣∣a2a4 + 2a23 ∣∣ ≤ ∣∣a2a4 − a23∣∣+ 3 |a3|2 , using (14) and (27) , we get ∣∣a2a4 + 2a23 ∣∣ ≤ 1 9 + 1 3 = 4 9 . (30) Theorem 6. If f(z) = z + a2z 2 + a3z 3 + · · · belongs to Rsin, then |H4,1 (f)| ≤ 0.10556. Proof. Using triangle inequality in (29) , we obtain |H4,1 (f)| ≤ |a7| |H3,1 (f)|+ 2 |a4| |a6| ∣∣a2a4 − a23∣∣+ 2 |a5| |a6| |a2a3 − a4|+ |a6|2 ∣∣a3 − a22∣∣ + |a5|2 ∣∣a2a4 − a23∣∣+ |a5|2 ∣∣a2a4 + 2a23 ∣∣+ |a5|3 + |a4|4 + 3 |a3| |a4|2 |a5| . By using(14), (23) , (25), (26) , (27 ) , (28) and (30) , we get the required result. Acknowledgements The authors would like to express our appreciation to the anonymous referees for the comprehensive reading of this paper and their valuable comments and suggestions. References [1] S Altinkaya and S Yalçin. Third hankel determinant for bazilevič functions. Advances in Mathematics, 5:91–96, 2016. [2] M Arif, K M Noor, and M Raza. Hankel determinant problem of a subclass of analytic functions. 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