EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 17, No. 2, 2024, 1283-1293 ISSN 1307-5543 – ejpam.com Published by New York Business Global 2-Distance Zero Forcing Sets in Graphs Javier A. Hassan∗, Lestlene T. Udtohan, Ladznar S. Laja Mathematics and Sciences Department, College of Arts and Sciences, MSU Tawi-Tawi College of Technology and Oceanography, Bongao, Tawi-Tawi, Philippines Abstract. In this paper, we introduce new concept in graph theory called 2-distance zero forc- ing. We give some properties of this new parameter and investigate its connections with other parameters such as zero forcing and hop domination. We show that 2-distance zero forcing and hop domination(respectively, zero forcing parameter) are incomparable. Moreover, we characterize 2-distance zero forcing sets in some special graphs, and finally derive the exact values or bounds of the parameter using these results. 2020 Mathematics Subject Classifications: 05C69 Key Words and Phrases: Zero forcing, 2-distance zero forcing, 2-distance zero forcing number 1. Introduction Zero forcing is a propagation process in a graph that increases the number of blue vertices given on initial set of blue vertices, with all other vertices white, and a color- change rule. The color-change rule states that a blue vertex adjacent to a single white neighbor can force its neighbor to blue. Formally, if u is a blue vertex and w is the only white vertex in N(u), then u−→w will be used to denote that u forces w to blue. Given a graph G, a zero forcing set B of G is a subset of vertices of V (G) such that B is initially colored blue, and the remaining vertices in G are white, then iteratively applying applying the color-change rule given B results in every vertex in G becoming blue. Zero forcing sets have applications in control theory, network coding, and determining structural properties of graphs. Some studies related to zero forcing sets and its variants can be found in [1–6]. Recently, J. Manditong et al.[16], introduced new variant of zero forcing in a graph called zero forcing hop domination. They have established some properties of this param- eter and determined its connections with other known parameters in graph theory. More- over, they have obtained some exact values or bounds of the parameter on the generalized graph, some families of graphs, and graphs under some operations via characterizations. Some interesting studies related to zero forcing hop domination can be found in [7–15]. DOI: https://doi.org/10.29020/nybg.ejpam.v17i2.5046 Email addresses: javierhassan@msutawi-tawi.edu.ph (J. A. Hassan) lestleneudtohan@msutawi-tawi.edu.ph (L. T.Udtohan) ladznarlaja@msutawi-tawi.edu.ph (L.S. Laja) https://www.ejpam.com 1283 © 2024 EJPAM All rights reserved. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1284 In this paper, we introduce the concept of 2-distance zero forcing sets in a graph. Let G be a graph and let x, y ∈ V (G). Then the 2-distance color change rule is if x is colored (active) vertex and exactly one hop neighbor y of x is uncolored (inactive) , then y will become colored (active). A 2-distance zero forcing set N of G is a subset of vertices of G such that when the vertices in N are colored (active) and the remaining vertices are uncolored(inactive) initially, repeated application of the 2-distance color change rule all vertices of G will become colored (active). The minimum cardinality of a 2-distance zero forcing set of G, denoted by Z2(G), is called the 2-distance zero forcing number of G. We study its connections with the standard zero forcing and hop domination parameter, respectively. Moreover, we investigate this parameter on some families of graphs such as complete, path, cycle, star, and complete bipartite graph. We believe, this new parameter and its results would serve as reference to future researchers who will study on variants of zero forcing, and would lead to an interesting topics of research in the future. 2. Terminology and Notation A path graph is a non-empty graph with vertex-set {x1, x2, . . . , xn} and edge-set {x1x2, x2x3, . . . , xn−1xn}, where the x ′ is are all distinct. The path of order n is denoted by Pn. If G is a graph and u and v are vertices of G, then a path from vertex u to vertex v is sometimes called a u-v path. The cycle graph Cn is the graph of order n ≥ 3 with vertex-set {x1, x2, . . . , xn} and edge-set {x1x2, x2x3, . . . , xn−1xn, xnx1}. Let G = (V (G), E(G)) be a simple and undirected graph. The distance dG(u, v) in G of two vertices u, v is the length of a shortest u-v path in G. The greatest distance between any two vertices in G, denoted by diam(G), is called the diameter of G. Two vertices x, y of G are adjacent, or neighbors, if xy is an edge of G. The open neighborhood of x in G is the set NG(x) = {y ∈ V (G) : xy ∈ E(G)}. The closed neighborhood of x inG is the setNG[x] = NG(x)∪{x}. IfX ⊆ V (G), the open neighborhood of X in G is the set NG(X) = ⋃ x∈X NG(x). The closed neighborhood of X in G is the set NG[X] = NG(X) ∪X. A vertex of a in G is a hop neighbor of a vertex b in G if dG(a, b) = 2. The set N2 G(a) = {b ∈ V (G) : dG(a, b) = 2} is called the open hop neighborhood of a. The closed hop neighborhood of a in G is given by N2 G[a] = N2 G(a) ∪ {a}. The open hop neighborhood of S ⊆ V (G) is the set N2 G(S) = ⋃ a∈S N2 G(a). The closed hop neighborhood of S in G is the set N2 G[S] = N2 G(S) ∪ S. A subset S of V (G) is a hop dominating of G if for every a ∈ V (G)\S, there exists b ∈ S such that dG(a, b) = 2. The minimum cardinality among all hop dominating sets of G, denoted by γh(G), is called the hop domination number of G. Let G and H be any two graphs. The join of G and H, denoted by G+H is the graph with vertex set V (G+H) = V (G) ∪ V (H) and edge set E(G+H) = E(G) ∪ E(H) ∪ {uv : u ∈ V (G), v ∈ V (H)}. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1285 The color change rule states that a blue vertex adjacent to a single white neighbor can force its neighbor to blue. Formally, if u is a blue vertex and w is the only white vertex in NG(u), then u−→w will be used to denote that u forces w blue. A zero forcing set for a graph G is a subset of vertices in Z such that if initially the vertices in Z are colored blue and the remaining vertices are colored white, the entire graph G May be colored blue by repeatedly applying the color-change rule. Furthermore, the zero forcing number, Z(G), of a graph G is the minimum cardinality of a set of blue vertices(whereas vertices in V (G)\S are colored white) such that V (G) is turned blue after finitely many applications of ”the color change rule”: a white vertex is converted to a blue vertices if it is the only white neighbor of a blue vertex. 3. Results We begin this section by introducing the concepts of 2-distance zero forcing set and 2-distance zero forcing number of a graph. Definition 1. LetG be a graph and let x, y ∈ V (G). Then the 2-distance color change rule is if x is colored (active) vertex and exactly one hop neighbor y of x is uncolored (inactive), then y will become colored (active). Formally, if x is a colored(active) vertex and y is the only uncolored (inactive) vertex in N2 G(x), then x−→y will be used to denote that x 2- forces y to be colored (active). A 2-distance zero forcing set N of G is a subset of vertices of G such that when the vertices in N are colored (active) and the remaining vertices are uncolored(inactive) initially, repeated application of the 2-distance color change rule all vertices of G will become colored (active). The minimum cardinality of a 2-distance zero forcing set of G, denoted by Z2(G), is called the 2-distance zero forcing number of G. Example 1. Consider the graph G in Figure 1 and let N = {a, b, d}. Then vertex c is 2-forced by vertex a and vertex e is 2-forced by either vertex d or b. Thus, N is a 2-distance zero forcing set of G. Moreover, Z2(G) = 3. a b d c e G : Figure 1: Graph G with Z2(G) = 3 Proposition 1. Let n be a positive integer. Then S is a 2-distance zero forcing set of Kn if and only if S = V (Kn). Proof. Let S be a 2-distance zero forcing set of Kn. Suppose that S ̸= V (Kn). Then there exists x ∈ V (Kn) such that x /∈ S. However, dKn(x, y) = 1 for all y ∈ S. It follows J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1286 that S cannot 2-forced x, a contradiction. Therefore, S = V (Kn). The converse is clear. Corollary 1. Let n be a positive integer. Then Z2(Kn) = n. Theorem 1. Z2(G) = |V (G)| if and only if diam(H) ≤ 1 for each component H of G. Proof. Suppose that Z2(G) = |V (G)|. Suppose further that diam(H) ≥ 2 for some component H of G. Then there exist a, b ∈ V (H) such that dH(a, b) = 2 = dG(a, b). Let N = V (G) \ {b}. Then N is a 2-distance zero forcing set of G. Thus, Z2(G) ≤ |V (G)|− 1, a contradiction. Therefore, diam(H) ≤ 1 for each component H of G. Conversely, suppose that diam(H) ≤ 1 for each component H of G. If G is connected, then G = Kn. Thus, Z 2(G) = |V (G)| = n by Corollary 1. Suppose that G is disconnected. Let H1, . . . ,Hk, k ≥ 2 be components of G. Since diam(Hi) ≤ 1, Z2(Hi) = |V (Hi)| for each i ∈ {1, . . . , k}. Thus, Z2(G) = Z2(H1) + · · ·+ Z2(Hk) = |V (H1)|+ · · ·+ |V (Hk)| = |V (G)|. Corollary 2. Let n be a positive integer. Then, Z2(Kn) = n. Proposition 2. Let G be a graph and let N be a 2-distance zero forcing set of G. Then every dominating vertex v ∈ V (G), v ∈ N . Proof. Let v ∈ V (G) be a dominating vertex of G. Then NG[v] = V (G), that is, v is adjacent to every vertex u ∈ V (G) \ {v}. Suppose that v /∈ N . Then dG(v, w) = 2 for some w ∈ N , a contradiction. Therefore, v ∈ N . Proposition 3. Let n be a positive integer. Then, Z2(Pn) = { 1 , n = 1 2 , n ≥ 2 Proof. By Theorem 1, Z2(P1) = 1 and Z2(P2) = 2. Clearly, Z2(Pn) = 2 for n = 3, 4, 5 Suppose that n ≥ 6 Let V (Pn) = {v1, v2, ..., vn} and N = {v1, v2}. If n is odd, then vertices v3, v5, . . . , vn are 2-forced by vertices v1, v3, . . . , vn−2, respectively, and vertices v4, v6, . . . , vn−1 are 2-forced by vertices v2, v4, . . . , vn−3, respectively. If n is even, then vertices v3, v5, . . . , vn−1 are 2-forced by vertices v1, v3, . . . , vn−3, respectively, and vertices v4, v6, . . . , vn are 2-forced by vertices v2, v4, . . . , vn−2, respectively. Therefore, N is a 2- distance zero forcing set of Pn. Since any singleton subset of V (Pn) is not a 2-distance zero forcing set of Pn, it follows that N is a minimum 2-distance zero forcing set of Pn. Consequently, Z2(Pn) = 2 for all n ≥ 2. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1287 Proposition 4. Let n be a positive integer. Then, (i) Z2(Cn) =  3 , n = 3 2 , n = 4 or n ≥ 5 and odd 4 , n ≥ 6 and even (ii) Z2(Sn) = { 2 , n = 1 n , n ≥ 2 Proof. (i) By Theorem 1, Z2(C3) = 3. Clearly, Z2(C4) = 2. Suppose n ≥ 5 and odd. Let V (Cn) = {v1, v2, ..., vn} and let N = {v1, v3}. Then N is a minimum 2-distance zero forcing set of Cn. Thus, Z2(Cn) = 2 for all n ≥ 5 and odd. Next, suppose that n ≥ 6 and even. Let N ′ = {v1, v2, v3, v4}. Then N ′ is a minimum 2-distance zero forcing set Cn. Thus, Z2(Cn) = 4 for all n ≥ 6 and even. (ii) By Theorem 1, Z2(S1) = 2. Suppose that n ≥ 2. Let V (Sn) = {d, v1, ..., vn}, where d is the dominating vertex of Sn. Consider M = {d, v1, ..., vn−1}. Then M is a minimum 2-distance zero forcing set of Sn. Therefore, Z 2(Sn) = n for all n ≥ 2. Theorem 2. Let G be a graph. If H is a subgraph of G, then Z2(H) ≤ Z2(G) is not true in general. Proof. Consider the graph K2 + P3 below. a b c d e K2 + P3 : Let S1 = {a, b, d, e}. Then S1 is a minimum 2-distance zero forcing set of K2+P3. Hence, Z2(K2 + P3) = 4. Now, consider the graph P3 + P4 below. u1 u2 u3 u4 u5 u6 u7 P3 + P4 : J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1288 Let S2 = {u1, u2, u6}. Then u3, u4, u7 and u5 are 2-forced by u1, u6, u4 and u7, respectively. Thus, S2 is a 2-distance zero forcing set of P3+P4. It can be verified that Z2(P3+P4) = 3. Consequently, the assertion follows. Theorem 3. Let H be a graph. If K is a subgraph of H, then Z2(K) ≥ Z2(H) is not true in general. Proof. Consider the graph H below. a b c d e f gH : Let Q1 = {a, b, c, e, f}. Then Q1 is a minimum 2-distance zero forcing set of H. Thus, Z2(H) = 5. Now, consider the subgraph K of H below. a b c d g K : Let Q2 = {a, b, c}. Then Q2 is a minimum 2-distance zero forcing set of K. Thus, Z2(K) = 3. Therefore, the assertion follows. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1289 Proposition 5. Let G be a graph. Then the 2-distance zero forcing Z2(G) and hop domination parameters γh(G) of G are incomparable. Proof. Consider the graph G below. a1 a2 a3 a4 a5 a6 a7 a8 G : Let Q = {a5, a6}. Then Q is a hop dominating set of G since N2 G[Q] = V (G). Since N2 G[ai] ̸= V (G) for every i ∈ {1, 2, · · · , 8}, it follows that Q is a minimum hop dominating set of G. Thus, γh(G) = 2. Now, let S = {a1, a2, a3, a6, a8}. Then S is a minimum 2-distance zero forcing set of G. Therefore, Z2(G) = 5. On the other hand, consider the graph H below. H : a1 a2 a3 a4 a5 a6 a7 a8 a9 Let D = {a1, a2, a8}. Then vertices a3, a5 and a7 are 2-forced by the vertices a1, a3 and a5, respectively, and vertices a4, a6 and a9 are 2-forced by the vertices a2, a4 and a6, respectively. This follows that D is a 2-distance zero forcing set of H. Moreover, Z2(H) = 3. Next, let D′ = {a3, a4, a5, a6}. Then D′ is a minimum hop dominating set of H. Consequently, γh(H) = 4. Theorem 4. Let G be a graph. Then Z2(G) = γh(G) = |V (G)| if and only if every component of G is complete. Proof. Suppose that Z2(G) = |V (G)| = γh(G). Then V (G) is both the minimum 2- distance zero forcing and minimum hop dominating set of G. Suppose there is a component of G which is non-complete. Then there exist a, b ∈ V (Q) such that dG(a, b) = 2. Let S = V (G) \ {a}. Then S is both a 2-distance zero forcing and a hop dominating set of G. a contradiction. Therefore, every component of G is complete. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1290 Conversely, suppose that every component of G is complete. Then by Theorem 1, Z2(G) = |V (G)|. Moreover, γh(G) = |V (G)|. Consequently, Z2(G) = γh(G) = |V (G)|. Proposition 6. Let G be a graph. Then zero forcing Z(G) and 2-distance zero forcing Z2(G) parameter of G are incomparable. Proof. Consider the graph P4 + P4 below. a b c d e f g h P4 + P4 : Let S1 = {b, f} and S2 = {a, b, c, d, e}. Then S1 and S2 are minimum 2-distance zero forcing and zero forcing sets of P4 + P4, respectively. Thus, Z 2(P4 + P4) = 2 and Z(P4 + P4) = 5. Next, consider the graph G below. u1 u2 u3 u4 u5 u6 u7 u8 u9 u10 u11 u12 u13 G : Let D1 = {u1, u11, u12, u13} and D2 = {u1, u3, u11, u12, u13}. Then D1 and D2 are mini- mum zero forcing and 2-distance zero forcing set of G, respectively. Therefore, Z(G) = 4 and Z2(G) = 5. J. A. Hassan, L. T. Udtohan, L. S. Laja / Eur. J. Pure Appl. Math, 17 (2) (2024), 1283-1293 1291 Theorem 5. There exists a graph G such that Z2(G) = Z(G). Proof. Consider the graph K2 + P4 below. v1 v2 v3 v4 v5 v6 K2 + P4 : LetD′ = {v1, v5, v6} andD′′ = {v3, v5, v6}. ThenD′ andD′′ are minimum zero forcing and 2-distance zero forcing sets of K2+P4, respectively. Hence, Z(K2+P4) = 3 = Z2(K2+P4). Let G = K2 + P4. Then the assertion follows. Theorem 6. Let G be a graph. Then Z2(G) = Z(G) = |V (G)| if and only if every component of G is trivial. Proof. Suppose that Z2(G) = Z(G) = |V (G)|. Suppose there is component K of G which is non-trivial. Let V (K) = {k1, ..., kn}, k ≥ 2. Consider Q = V (G) \ {k1}. 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