EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 17, No. 2, 2024, 931-944 ISSN 1307-5543 – ejpam.com Published by New York Business Global Volterra-Composition Operators Acting on Sp Spaces and Weighted Zygmund Spaces Waleed Al-Rawashdeh Department of Mathematics, Zarqa University, 2000 Zarqa, 13110 Jordan Abstract. Let φ be an analytic selfmap of the open unit disk D and g be an analytic function on D. The Volterra-type composition operators induced by the maps g and φ are defined as ( Iφg f ) (z) = ∫ z 0 f ′(φ(ζ))g(ζ)dζ and ( Tφ g f ) (z) = ∫ z 0 f(φ(ζ))g′(ζ)dζ. For 1 ≤ p < ∞, Sp(D) is the space of all analytic functions on D whose first derivative f ′ lies in the Hardy space Hp(D), endowed with the norm ∥f∥Sp = |f(0)|+ ∥f ′∥Hp . Let µ : (0, 1] → (0,∞) be a positive continuous function on D such that for z ∈ D we define µ(z) = µ(|z|). The weighted Zygmund space Zµ(D) is the space of all analytic functions f on D such that supz∈D µ(z)|f ′′(z)| is finite. In this paper, we characterize the boundedness and compactness of the Volterra-type composition operators that act between Sp spaces and weighted Zygmund spaces. 2020 Mathematics Subject Classifications: 47B33, 47B38, 30H10, 30H20, 47B37, 30H05, 32C15 Key Words and Phrases: Weighted Zygmund Spaces, Sp spaces, Volterra operators, composi- tion operators, bounded operators, compact operators 1. Introduction Let D be the open unit disk {z ∈ D : |z| < 1} in the complex plane C. Let H(D) be the space of all analytic functions on the open unit disk D. For 1 ≤ p < ∞, the analytic Hardy space Hp(D on the unit disk D is the Banach space of all analytic functions f ∈ H(D) such that ∥f∥pHp = sup 0 0. Let g be an analytic function on D, the Volterra type operator (see [18]) is defined as (Tgf) (z) = ∫ z 0 f(ζ)g′(ζ)dζ, where f ∈ H(D) and z ∈ D. Note that Tg can be viewed as a generalization of the cesâro operator whose first studied by Aleman and Siskkis [4]. It is natural to define another Volterra type operator Ig as follows (Igf) (z) = ∫ z 0 f ′(ζ)g(ζ)dζ. W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 933 Recently, many researchers considered these operators and characterized their bound- edness and compactness between various spaces of analytic functions, for example see ([3], [8], [10], [11], [12], [13], [14], [16], [20]) and the references therein. Let φ be an analytic function maps D into itself, the composition operator induced by φ is defined on the space H(D) of all analytic functions on D by Cφf(z) = f(φ(z)), for all f ∈ H(D) and z ∈ D. It is well known that the composition operator Cφf = f ◦ φ defines a linear operator Cφ which acts boundedly on various spaces of analytic or har- monic functions on D. These operators have been studied on many spaces of analytic functions. During the past few decades much effort has been devoted to the study of these operators with the goal of explaining the operator-theoretic properties of Cφ in terms of the function-theoretic properties of the induced map φ. We refer the reader to the mono- graphs ([5], [7], [9], [15], [17], [22], [23]) and the references therein. Let g be a fixed analytic function on D, f an analytic function of D and z ∈ D. The Volterra type composition operators are defined as ( Tφ g f ) (z) = ∫ z 0 f(φ(ζ))g′(ζ)dζ, ( Iφg f ) (z) = ∫ z 0 f ′(φ(ζ))g(ζ)dζ. The classical Volterra operators are obtained in the case when φ(z) = z. These operators have been studied by many researchers, for example see ([3], [11], [12], [19], [21], [24], [25]) and the references therein. In this paper, we are investigating the boundedness and compactness of the Volterra type composition operators Tφ g and Iφg acting between Sp(D) spaces and weighted Zyg- mund spaces Zµ. 2. Preliminaries In this section we present some well known, but useful, information that are curial for the main results of this paper. The following lemma is a well known fact that can be proven by using Cauchy estimates, so we omit the proof. Lemma 1. If {fn} is a sequence converges to zero on compact subsets of D, then {f ′ n} also converges to zero on compact subsets of D as n → ∞. In particular if K is a compact subset of D, then lim n→∞ sup w∈K |f ′(w)| = 0. The following lemma is a know fact, for the readers who are interested in its proof we refer them to (Theorem 1, [16]). W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 934 Lemma 2. If 1 ≤ p < ∞, the following are true: (i) Sp(D) ⊂ S1(D) ⊂ H∞; (ii) ∥f∥∞ ≤ π∥f∥S1(D) ≤ π∥f∥Sp(D); (iii) Sp(D) is a Banach algebra; (iv) polynomials are dense in Sp(D). 3. Boundedness and Compactness of Iφg In this section, we characterize the boundedness and compactness of the operator Iφg acting between Sp spaces and weighted Zygmund spaces Zµ. The results will be written in terms of K1(z) = µ(z)|g′(z)| (1− |φ(z)|2)1/p , and K2(z) = µ(z)|g(z)||φ′(z)| (1− |φ(z)|2)(1+p)/p , where z ∈ D, g ∈ H(D), and φ is the analytic selfmap of D. In the following Theorem 1, we characterize the boundedness of Iφg that acts between Sp spaces and weighted Zygmund spaces. Theorem 1. Let g be an analytic function on D and φ be an analytic selfmap of D. Then Iφg : Sp → Zµ is bounded if and only if M1 = sup z∈D K1(z) < ∞ and M2 = sup z∈D K2(z) < ∞. Proof. Suppose that Iφg : Sp → Zµ is bounded. First, for a fixed w ∈ D we consider the test function f1,w(z) = ( 1− |φ(w)|2 )(2p−1)/p φ(w)(1− φ(w)z) . By direct calculations, we get ∥f1,w∥Sp = ∥f ′ 1,w∥Hp ≤ 2(2p−2)/p, (1) f ′ 1,w(φ(w)) = 1 (1− |φ(w)|2)1/p , (2) W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 935 and f ′′ 1,w(φ(w)) = 2φ(w) (1− |φ(w)|2)(p+1)/p . (3) Therefore, we obtain the following( Iφg f1,w )′′ (w) = ( f ′ 1,w(φ(w))g(w) )′ = f ′′ 1,w(φ(w))g(w)φ ′(w) + f ′ 1,w(φ(w))g ′(w) = 2φ(w)φ′(w)g(w) (1− |φ(w)|2)(p+1)/p + g′(w) (1− |φ(w)|2)1/p (4) Moreover, we consider another test function f2,w(z) = ( 1− |φ(w)|2 )(3p−1)/p 2φ(w)(1− φ(w)z)2 . By direct calculations, we get ∥f2,w∥Sp = ∥f ′ 2,w∥Hp ≤ 2(3p−2)/p, f ′ 2,w(φ(w)) = 1 (1− |φ(w)|2)1/p , and f ′′ 2,w(φ(w)) = 3φ(w) (1− |φ(w)|2)(p+1)/p . Similarly, we obtain the following ( Iφg f2,w )′′ (w) = 3φ(w)φ′(w)g(w) (1− |φ(w)|2)(p+1)/p + g′(w) (1− |φ(w)|2)1/p (5) Now, using equations (4) and (5), we get ( Iφg f2,w )′′ (w)− ( Iφg f1,w )′′ (w) = φ(w)φ′(w)g(w) (1− |φ(w)|2)(p+1)/p . Hence, by the boundedness of Iφg : Sp → Zµ we have µ(w) ∣∣∣φ(w)φ′(w)g(w) ∣∣∣ (1− |φ(w)|2)(p+1)/p ≤ ∥Iφg ∥∥f2,w∥Sp + ∥Iφg ∥∥f1,w∥Sp ≤ ∥Iφg ∥ ( 2(3p−2)/p + 2(2p−2)/p ) ≤ C1 (6) W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 936 On the other hand, Lemma 2 tells us that polynomials are dense in Sp spaces. Thus Pn(z) = zn in Sp and we get the following ( Iφg P1 )′′ (z) = (∫ z 0 P ′ 1(φ(w))g(w)dw )′′ = (∫ z 0 g(w)dw )′′ = g′(z). Similarly, we obtain the following ( Iφg P2 )′′ (z) = (∫ z 0 P ′ 2(φ(w))g(w)dw )′′ = (∫ z 0 2φ(w)g(w)dw )′′ = 2φ(z)g′(z) + 2φ′(z)g(z). Hence, using the previous equations, we get 2 ( φ′g ) (z) = ( Iφg P2 )′′ (z)− 2φ(z) ( Iφg P1 )′′ (z). (7) Therefore, using equation (7) we get sup w∈D µ(w)|φ′(w)g(w)| ≤ 1 2 ∥Iφg P2∥Zµ + sup w∈D ( ∥Iφg P1∥Zµ sup w∈D |φ(w)| ) ≤ ∥Iφg ∥∥P2∥SP + ∥Iφg ∥∥P1∥SP ≤ C2 Now, for a fixed 0 < r < 1, consider w ∈ D such that 0 ≤ |φ(w)| ≤ r < 1. Then we get µ(w)|φ(w)φ′(w)g(w)| (1− |φ(w)|2)(p+1)/p ≤ µ(w)|φ′(w)g(w)| (1− |φ(w)|2)(p+1)/p ≤ C2 (1− r2)1+1/p (8) Moreover, consider w ∈ D such that r < |φ(w)| < 1. Then we get µ(w)|rφ′(w)g(w)| (1− |φ(w)|2)(p+1)/p ≤ µ(w)|φ(w)φ′(w)g(w)| (1− |φ(w)|2)(p+1)/p ≤ ∥Iφg ∥ ( 2(3p−2)/p + 2(2p−2)/p ) . W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 937 Hence, using equation (6), we get µ(w)|φ′(w)g(w)| (1− |φ(w)|2)(p+1)/p ≤ C1 r . (9) Therefore, using inequalities (8) and (9), we get M2 = sup z∈D µ(z)|φ′(z)g(z)| (1− |φ(z)|2)(p+1)/p ≤ max { C1 r + C2 (1− r2)1+1/p } < ∞. Second, for a fixed w ∈ D, using equations (2), (3) and (4) we get µ(w)|g′(w)| (1− |φ(w)|2)1/p = µ(w) ∣∣g′(w)f ′ 1,w(φ(w)) + f ′′ 1,w(φ(w))g(w)φ ′(w)− f ′′ 1,w(φ(w))g(w)φ ′(w) ∣∣ = µ(w) ∣∣∣∣∣(Iφg f1,w)′′ (w)− 2φ(w)g(w)φ′(w) (1− |φ(w)|2)(p+1)/p ∣∣∣∣∣ ≤ ∥Iφg f1,w∥Zµ + 2µ(w)|φ(w)g(w)φ′(w)| (1− |φ(w)|2)(p+1)/p ≤ ∥Iφg ∥∥f1,w∥SP + 2M2. Taking the supremum over all w ∈ D, we get that M1 < ∞. Conversely, Suppose that conditions M1 and M2 are finite. Let f ∈ Sp, then it is well known, see [6] or [23], that for all z ∈ D we have |f ′(z)| ≤ ∥f ′∥Hp (1− |z|2)1/p , and |f ′′(z)| ≤ ∥f ′∥Hp (1− |z|2)1+1/p . Therefore, for z ∈ D, we have µ(z) ∣∣∣(Iφg f)′′ (z)∣∣∣ = µ(z) ∣∣∣∣(∫ z 0 f ′(φ(w))g(w)dw )′′∣∣∣∣ = ( f ′(φ(z))g(z) )′ = µ(z) ∣∣f ′′(φ(z))φ′(z)g(z) + f ′(φ(z))g′(z) ∣∣ ≤ µ(z)|φ′(z)g(z)| (1− |φ(z)|2)(p+1)/p ∥f ′∥Hp + µ(z)|g′(z)| (1− |φ(z)|2)1/p ∥f ′∥Hp W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 938 ≤ (M1 +M2) (∥f∥Sp − |f(0)|) ≤ (M1 +M2) ∥f∥Sp . Taking the supremum over all z ∈ D, we get ∥ ( Iφg f ) (z)∥Zµ ≤ (M1 +M2) ∥f∥Sp . Hence, Iφg is bounded, as desired. In the following Theorem 2, we characterize the compactness of Iφg that acts between Sp spaces and weighted Zygmund spaces. Theorem 2. Let g be an analytic function on D, φ be an analytic selfmap of D and Iφg : Sp → Zµ be bounded. Then Iφg is compact if and only if lim |φ(z)|→1 K1(z) = 0 and lim |φ(z)|→1 K2(z) = 0. (10) Proof. Suppose Iφg is compact. Let {zn}n∈N be a sequence in the open unit disk D such that |φ(zn)| → 1 as n → ∞. For each n ∈ N, consider the test functions f1,w and f2,w we used in the proof of Theorem 1 with w = zn. Then, we get f1,zn(φ(zn)) = φ(zn) ( 1− |φ(zn)|2 )1−1/p , and f2,zn(φ(zn)) = φ(zn) 2 ( 1− |φ(zn)|2 )1−1/p ( 2− |φ(zn)|2 ) . Hence, the sequences {f1,zn} and {f2,zn} converge to zero uniformly on D. Then, by the compactness of Iφg , we get lim n→∞ ∥Iφg f1,zn∥Zµ = 0 and lim n→∞ ∥Iφg f2,zn∥Zµ = 0. (11) Now, following similar argument as in the proof of Theorem 1, we get µ(zn) ∣∣∣φ(zn)φ′(zn)g(zn) ∣∣∣ (1− |φ(zn)|2)(p+1)/p ≤ ∥Iφg f1,w∥Zµ + ∥Iφg f2,w∥Zµ . (12) Hence, using equations (11) and (12), we get lim n→∞ µ(zn) |φ′(zn)g(zn)| (1− |φ(zn)|2)(p+1)/p = 0. (13) Moreover, following similar argument as in the proof of Theorem 1, we get µ(zn) |g′(zn)| (1− |φ(zn)|2)1/p ≤ ∥Iφg f1,w∥Zµ∥+ 2µ(zn) |φ′(zn)g(zn)| (1− |φ(zn)|2)(p+1)/p . (14) W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 939 Hence, using equations (11) and (14), we get lim n→∞ µ(zn) |g′(zn)| (1− |φ(zn)|2)1/p = 0. (15) Therefore, equations (13) and (15) give us the desired conditions lim |φ(z)|→1 K1(z) = 0 and lim |φ(z)|→1 K2(z) = 0. Conversely, suppose conditions (10) hold. Then for ϵ > 0, there is δ ∈ (0, 1) such that K1(z) < ϵ and K2(z) < ϵ whenever δ < |φ(z)| < 1. Let {fn} be a bounded sequence in Sp such that sup n∈N ∥fn∥Sp < L and {fn} converges to zero uniformly on compact subsets of D. Let U = {z ∈ D : |φ(z)| ≤ δ}. Now, it is clear that sup z∈D µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣ ≤ sup z∈D\U µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣+ sup z∈U µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣ First, we consider the case |φ(z)| > δ then we have µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣ = µ(z) ∣∣f ′′ n(φ(z))φ ′(z)g(z) + f ′ n(φ(z))g ′(z) ∣∣ ≤ µ(z)|φ′(z)g(z)| (1− |φ(z)|2)(p+1)/p ∥f ′ n∥Hp + µ(z)|g′(z)| (1− |φ(z)|2)1/p ∥f ′ n∥Hp ≤ (K2(z) +K1(z)) ∥fn∥Sp < 2Lϵ. (16) Second, we consider the case |φ(z)| ≤ δ. Since Iφg is bounded and polynomials are dense in Sp(D), by taking f(z) = z we get sup z∈D µ(z) ∣∣∣(Iφg f)′′ (z)∣∣∣ = sup z∈D µ(z)|g′(z)| < ∞, (17) and by taking f(z) = z2 we get sup z∈D µ(z) ∣∣∣(Iφg f)′′ (z)∣∣∣ = 2 sup z∈D µ(z)|φ(z)g′(z) + φ′(z)g(z)| < ∞. (18) Using equations (17) and (18), and the boundedness of φ(z) we get W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 940 C1 = sup z∈D µ(z)|g′(z)| < ∞, and C2 = sup z∈D µ(z)|φ′(z)g(z)| < ∞ Hence, for |φ(z)| ≤ δ, using these facts we get µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣ ≤ C2 ∣∣f ′′ n(φ(z)) ∣∣+ C1 ∣∣f ′ n(φ(z)) ∣∣ . (19) Since {fn} is bounded in Sp and converges to zero on {w ∈ D : |w| ≤ δ}, so do the sequences {f ′ n} and {f ′′ n} by Cauchy’s estimate. Thus, there exists N ∈ D such that for all n ≥ N and w ∈ D with |w| ≤ δ we have |f ′ n(w)| < ϵ and |f ′′ n(w)| < ϵ Hence, using inequality (19), we get sup z∈D µ(z) ∣∣∣(Iφg fn)′′ (z)∣∣∣ ≤ C2 sup |w|<δ |f ′′ n(w)|+ C1 sup |w|<δ |f ′ n(w)|. < (C1 + C2)ϵ. (20) Now, using inequalities (16) and (20), we get ∥Iφg fn∥Zµ = |f ′ n(φ(0))g(0)|+ sup z∈D µ ∣∣∣(Iφg fn)′′ (z)∣∣∣ ≤ |f ′ n(φ(0))g(0)|+ 2Lϵ+ (C1 + C2)ϵ Since {f ′ n} converges to zero uniformly on compact subsets of D, it converges point- wise. Thus, |f ′ n(φ(0))g(0)| → 0 as n → 0. Hence, for arbitrary ϵ > 0, we get ∥Iφg fn∥Zµ → 0 as n → 0. Therefore, Iφg is compact, which completes the proof. 4. Boundedness and Compactness of Tφ g In this section, we characterize the boundedness and compactness of the operator Tφ g acting between Sp spaces and weighted Zygmund spaces Zµ. In the following Theorem 3, we characterize the boundedness of Tφ g that acts between Sp spaces and weighted Zygmund spaces. Theorem 3. Let g be an analytic function on D and φ be an analytic selfmap of D. Then Tφ g : Sp → Zµ is bounded if and only if g ∈ Zµ and M3 = sup z∈D µ(z)|g′(z)||φ′(z)| (1− |φ(z)|2)1/p < ∞. W. Al-Rawashdeh / Eur. J. Pure Appl. Math, 17 (2) (2024), 931-944 941 Proof. Suppose Tφ g : Sp → Zµ is bounded. Since polynomials are dense in Sp, P1(z) = 1 ∈ Sp. By the boundedness of Tφ g , we get ∥Tφ g P1∥Zµ < ∞. Therefore, sup z∈D µ|g′′(z)| = sup z∈D µ ∣∣∣(Tφ g P1 )′′∣∣∣ ≤ ∥Tφ g P1∥Zµ < ∞, which gives us that g ∈ Zµ. Second, consider the test function f1,w we defined in the proof of Theorem 1. Then,( Tφ g f1,w )′′ (w) = ( f1,w(φ(w))g ′(w) )′ = f1,w(φ(w))g ′′(w) + f ′ 1,w(φ(w))φ ′(w)g′(w) = f1,w(φ(w))g ′′(w) + φ′(w)g′(w) (1− |φ(w)|2)1/p . Therefore, by the boundedness of Tφ g and equation (1), we get µ(w)|φ′(w)g′(w)| (1− |φ(w)|2)1/p ≤ µ(w) ∣∣∣(Tφ g f1,w )′′ (w) ∣∣∣+ µ(w)|g′′(w)||f1,w(φ(w))| ≤ ∥Tφ g f1,w∥Zµ + ∥g∥Zµ∥f1,w∥Sp ≤ ∥Tφ g ∥∥f1,w∥Sp + ∥g∥Zµ∥f1,w∥Sp ≤ ( ∥Tφ g ∥+ ∥g∥Zµ ) 2(2p−2)/p. Taking the supremum over all w ∈ D, we get sup w∈D µ(w)|φ′(w)g′(w)| (1− |φ(w)|2)1/p < ∞. Conversely, suppose g ∈ Zµ and condition M3 is finite. Let f ∈ Sp and z ∈ D. Then, by using Lemma 2, we get µ(z) ∣∣∣(Tφ g f )′′ (z) ∣∣∣ = µ(z) ∣∣∣(f(φ(z))g′(z))′∣∣∣ = µ(z) ∣∣f(φ(z))g′′(z) + f ′(φ(z))φ′(z)g′(z) ∣∣ ≤ ∥g∥Zµ∥f∥∞ + µ(z) |φ′(z)g′(z)| (1− |φ(z)|2)1/p ∥f ′∥Hp ≤ π∥g∥Zµ∥f∥Sp +M3∥f∥Sp . REFERENCES 942 Since g ∈ Zµ and f ∈ Sp, by taking supremum over all z ∈ D, we get sup z∈D µ(z) ∣∣∣(Tφ g f )′′ (z) ∣∣∣ < C∥f∥Sp , (21) for some constant C. Finally, using equation (21), we get ∥Tφ g f∥Zµ = ∣∣(Tφ g f ) (0) ∣∣+ ∣∣∣(Tφ g f )′ (0) ∣∣∣+ sup z∈D µ(z) ∣∣∣(Tφ g f )′′ (z) ∣∣∣ ≤ ∣∣∣(Tφ g f )′ (0) ∣∣∣+ C∥f∥Sp < (C∗ + C)∥f∥Sp , for some constant C∗. Hence, Tφ g is bounded, as desired. The following Theorem 4 characterizes the compactness of Tφ g : Sp → Zµ whose proof is similar to that of Theorem 2 and Theorem 3. So the details are omitted. Theorem 4. Let g be an analytic function on D and φ be an analytic selfmap of D. Then Tφ g : Sp → Zµ is compact if and only if g ∈ Zµ and lim |φ(z)|→1 µ(z)|g′(z)||φ′(z)| (1− |φ(z)|2)1/p = 0. 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