EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS Vol. 17, No. 3, 2024, 1937-1947 ISSN 1307-5543 – ejpam.com Published by New York Business Global On Inner Products Derived From the Standard n-Inner Product on an Inner Product Space Adam Adam1∗, Steven Rante2, Hendra Gunawan2 1 Department of Mathematics, Institut Teknologi Kalimantan, Balikpapan 76127, Indonesia 2 Analysis and Geometry Group, Faculty of Mathematics and Natural Sciences, Bandung Institute of Technology, Bandung 40132, Indonesia Abstract. In this paper, we study relations between inner products derived from the standard n-inner product defined on an inner product space. In particular, we are interested in knowing when orthogonality with respect to the original inner product is preserved by the derived inner product. 2020 Mathematics Subject Classifications: 46C50, 46B20, 46C05 Key Words and Phrases: Inner products, n-inner products, orthogonality, orthogonal set, orthonormal basis. 1. Introduction Let X be a real vector space of dimension d ≥ n and let ⟨·, ·|·, . . . , ·⟩ : Xn+1 → R be a function such that for every x0, x1, . . . , xn, xn+1 ∈ X and α ∈ R we have (I1) ⟨x1, x1|x2, . . . , xn⟩ ≥ 0 and ⟨x1, x1|x2, . . . , xn⟩ = 0 if and only if x1, x2, . . . , xn are linearly dependent; (I2) ⟨x1, x1|x2, . . . , xn⟩ = ⟨xi1 , xi1 |xi2 , . . . , xin⟩ for any permutation; {i1, i2, . . . , in} of (1, . . . , n); (I3) ⟨x0, x1|x2, . . . , xn⟩ = ⟨x1, x0|x2, . . . , xn⟩; (I4) ⟨αx0, x1|x2, . . . , xn⟩ = α⟨x0, x1|x2, . . . , xn⟩; (I5) ⟨x0 + xn+1, x1|x2, . . . , xn⟩ = ⟨x0, x1|x2, . . . , xn⟩+ ⟨xn+1, x1|x2, . . . , xn⟩. ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v17i3.5263 Email addresses: adam@lecturer.itk.ac.id (Adam Adam), stevengrante@gmail.com (Steven Rante), hgunawan@math.itb.ac.id (Hendra Gunawan) https://www.ejpam.com 1937 © 2024 EJPAM All rights reserved. A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1938 The function ⟨·, ·|·, . . . , ·⟩ is called an n-inner product introduced by Misiak in 1989 [14]. Here, the pair (X, ⟨·, ·|·, . . . , ·⟩) is called an n-inner product space. If (X, ⟨·, ·⟩) is a real inner product space of dimension d ≥ n, we can define the standard n-inner product by ⟨x0, x1|x2, . . . , xn⟩ = ∣∣∣∣∣∣∣∣∣ ⟨x0, x1⟩ ⟨x0, x2⟩ . . . ⟨x0, xn⟩ ⟨x2, x1⟩ ⟨x2, x2⟩ . . . ⟨x2, xn⟩ ... ... . . . ... ⟨xn, x1⟩ ⟨xn, x2⟩ . . . ⟨xn, xn⟩ ∣∣∣∣∣∣∣∣∣. So, a real inner product space of dimension d ≥ n with the n-inner product defined above is an example of an n-inner product space, which we can call a standard n-inner product space. Next, from n-inner product space we can derive n-norm, defined by ∥x1, x2, . . . , xn∥ = ⟨x1, x1|x2, . . . , xn⟩ 1 2 . Furthermore, an n-norm on X is a function ∥·, . . . , ·∥ : Xn → R such that for every x0, x1, . . . , xn, xn+1 ∈ X and α ∈ R, the function satisfying the following properties: (N1) ∥x1, x2, . . . , xn∥ ≥ 0 and ∥x1, x2, . . . , xn∥ = 0 if and only if x1, x2, . . . , xn are linearly dependent; (N2) ∥x1, x2, . . . , xn∥ is invariant under permutation; (N3) ∥αx1, x2, . . . , xn∥ = |α| ∥x1, x2, . . . , xn∥; (N4) ∥x0 + x1, x2, . . . , xn∥ ≤ ∥x0, x2, . . . , xn∥+ ∥x1, x2, . . . , xn∥. Geometrically, ∥x1, x2, . . . , xn∥ represents the generalized volume of an n-dimensional parallelepiped spanned by x1, x2, . . . , xn. Then, ⟨x0, x1|x2, . . . , xn⟩ ∥x0, x2, . . . , xn∥ ∥x1, x2, . . . , xn∥ is the cosine of the angle between two parallelepipeds spanned by x0, x2, . . . , xn and x1, x2, . . . , xn. See [9, 10, 15] for more properties of n-inner products. The related results may also be found in [3–6, 13, 16, 17]. Historically, numerous authors have introduced and developed several concepts of or- thogonality in 2-normed spaces and 2-inner product spaces [1, 2, 7, 11, 12, 15]. Just as the concepts of orthogonality in normed spaces draw inspiration from those in inner product spaces, the notions of orthogonality in 2-normed spaces are similarly linked to those in 2-inner product spaces. In [11], it is shown that the standard definition of orthogonality in a 2-inner product space (X, ⟨·, ·|·⟩) with dim(X) ≥ 3, is as follows: A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1939 Definition 1 (G-orthogonality in 2-inner product spaces). Let (X, ⟨·, ·|·⟩) be a 2-inner product spaces. x1 is G-orthogonal to x2 if and only if there exists a subspace V of X with codim(V ) = 1 such that ⟨x1, x2|x⟩ = 0 for all x ∈ V (Denoted by x1⊥Gx2). We can say this definition is standard because when X is a standard 2-inner product space, we have x1⊥x2 if and only if x1⊥Gx2. The definition of G-orthogonality provided above represents an enhancement over the definition proposed by Cho and Kim [2] and Godini [7] as demonstrated in [11]. On the other hand, Cho and Kim’s concept of or- thogonality and Godini can be seen as a development of Khan and Siddiqui’s concept of orthogonality [12]. Furthermore, one can define the notion of G-orthogonality in n-inner product spaces as follows: Definition 2 (G-orthogonality in n-inner product spaces). Let (X, ⟨·, ·|·, . . . , ·⟩) be an n- inner product spaces with dim(X) ≥ n + 1. x1 is G-orthogonal to x2 if and only if there exists a subspace V of X with codim(V ) = 1 such that ⟨x1, x2|x3, . . . , xn+1⟩ = 0 for all x3, . . . , xn+1 ∈ V (Denoted by x1⊥Gx2). With this definition, in a standard n-inner product space, G-orthogonality is also equivalent to the usual orthogonality (with respect to the inner product). In other words, x1⊥x2 if and only if x1⊥Gx2. We can see that the definition requires the assumption that the dimension of X is greater than n. In [11], it is shown that if we define G-orthogonality in the standard 2-inner product space X of dimension 2, any pair of linearly independent vectors becomes G-orthogonal. Similarly, if we define G-orthogonality for a standard n-inner product space X of dimension n, any pair of linearly independent vectors also becomes G-orthogonal. Indeed, this fact is undesirable. It is necessary to adopt a different approach to establish orthogonality in n-inner product spaces of dimension n in a general sense. Meanwhile, note that if (X, ⟨·, ·|·, . . . , ·⟩) is an arbitrary n-inner product space and A = {a1, a2, . . . , an} is a set of n linearly independent vectors in X, then one may observe that ⟨x, y⟩A := ∑ {i2,...in}⊂{1,2,...,n} ⟨x, y|ai2 , . . . , ain⟩ defines an inner product on X. There are n terms in the above sum, as there are n subsets of {1, 2, . . . , n} consisting of n− 1 elements. If dimX = d < ∞, we can also define an inner product by the above formula using a set of d linearly independent vectors in X (see [8]). Thus, starting from an inner product, we can define the standard n-inner product, and then from the n-inner product, we can derive a new inner product. It is then interesting to investigate how the new inner product derived from standard n-inner product relates to the original inner product on (X, ⟨·, ·⟩). In particular, we would like to know whether A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1940 or not the new inner product preserves orthogonality. This generally depends on the set A that we choose in the definition of the new inner product. In the next sections, we present necessary and sufficient conditions for the set A to give the positive answer. With this approach, we have an alternative way to establish the orthogonality of two vectors in arbitrary n-inner product spaces because we can define the inner product on n-inner product spaces. 2. The n-dimensional case Let (X, ⟨·, ·|·, . . . , ·⟩) be a standard n-inner product space. As indicated in [10] and [11], the n-dimensional case is special. So we shall first pay attention to the case where dimX = n. Our results are the following theorems. Theorem 1. Let A = {a1, a2, . . . , an} ⊂ X be an orthogonal set with ∥ai∥ = α > 0 for all i = 1, 2, . . . , n. Then ⟨x, y⟩A = 0 if and only if ⟨x, y⟩ = 0 for all x, y ∈ X. Proof. For any subset {i2, . . . , in} ⊂ {1, 2, . . . , n}, we have ⟨x, y|ai2 , ai3 , . . . , ain⟩ = ∣∣∣∣∣∣∣∣∣∣∣ ⟨x, y⟩ ⟨x, ai2⟩ . . . ⟨x, ain⟩ ⟨ai2 , y⟩ ⟨ai2 , ai2⟩ . . . ⟨ai2 , ain⟩ ... ... . . . ... ⟨ain , y⟩ ⟨ain , ai2⟩ . . . ⟨ain , ain⟩ ∣∣∣∣∣∣∣∣∣∣∣ n×n = ⟨x, y⟩ ∣∣∣∣∣∣∣∣∣ ∥ai2∥ 2 0 . . . 0 0 ∥ai3∥ 2 . . . 0 ... ... . . . ... 0 0 . . . ∥ain∥ 2 ∣∣∣∣∣∣∣∣∣ (n−1)×(n−1) − ⟨x, ai2⟩ ∣∣∣∣∣∣∣∣∣ ⟨ai2 , y⟩ 0 . . . 0 ⟨ai3 , y⟩ ∥ai3∥ 2 . . . 0 ... ... . . . ... ⟨ain , y⟩ 0 . . . ∥ain∥ 2 ∣∣∣∣∣∣∣∣∣ (n−1)×(n−1) + · · ·+ (−1)n−1⟨x, ain⟩ ∣∣∣∣∣∣∣∣∣ ⟨ai2 , y⟩ ∥ai2∥ 2 . . . 0 ... ... . . . ... ⟨ain−1 , y⟩ 0 . . . ∥∥ain−1 ∥∥2 ⟨ain , y⟩ 0 . . . 0 ∣∣∣∣∣∣∣∣∣ (n−1)×(n−1) = ⟨x, y⟩ n∏ j=2 ∥∥aij∥∥2 − ⟨x, ai2⟩⟨ai2 , y⟩ n∏ j=3 ∥∥aij∥∥2 − · · · − ⟨x, ain⟩⟨ain , y⟩ n−1∏ j=2 ∥∥aij∥∥2 = [ ⟨x, y⟩ − ⟨x, ai2⟩⟨ai2 , y⟩ ∥ai2∥ 2 − ⟨x, ai3⟩⟨ai3 , y⟩ ∥ai3∥ 2 − · · · − ⟨x, ain⟩⟨ain , y⟩ ∥ain∥ 2 ] n∏ j=2 ∥∥aij∥∥2 . A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1941 Let {1, 2, . . . n}\{i2, . . . in} = {i1}. By Parseval’s identity, we have ⟨x, y⟩ = n∑ j=1 ⟨x, aij ⟩⟨aij , y⟩∥∥aij∥∥2 (since {i1, i2, . . . , in} = {1, 2, . . . , n} as sets). Hence it follows that ⟨x, y|ai2 , ai3 , . . . , ain⟩ = ⟨x, ai1⟩⟨ai1 , y⟩ ∥ai1∥ 2 n∏ j=2 ∥∥aij∥∥2 = ⟨x, ai1⟩⟨ai1 , y⟩ ∥ai1∥ 4 n∏ i=1 ∥ai∥2 . Summing the above expressions for i1 = 1, 2, . . . , n, we get ⟨x, y⟩A = ∑ {i2,...in}⊂{1,2,...,n} ⟨x, y|ai2 , . . . , ain⟩ = [ ⟨x, a1⟩⟨a1, y⟩ ∥a1∥4 + ⟨x, a2⟩⟨a2, y⟩ ∥a2∥4 + · · ·+ ⟨x, an⟩⟨an, y⟩ ∥an∥4 ] n∏ i=1 ∥ai∥2 . However, we are assuming that ∥ai∥ = α for all i = 1, 2, . . . , n and so we obtain ⟨x, y⟩A = [ ⟨x, a1⟩⟨a1, y⟩ α4 + ⟨x, a2⟩⟨a2, y⟩ α4 + · · ·+ ⟨x, an⟩⟨an, y⟩ α4 ] n∏ i=1 α2 = ⟨x, y⟩ α2 α2n = α2(n−1)⟨x, y⟩. Since α ̸= 0, we conclude that ⟨x, y⟩A = 0 if and only if ⟨x, y⟩ = 0, which proves the theorem. Theorem 2. Let A = {b1, b2, . . . , bn} be a set of n linearly independent vectors in X. Then ⟨x, y⟩A = ⟨x, y⟩ if and only if A is an orthonormal basis for X. Proof. The sufficient part follows immediately from the previous theorem. For the necessary part, suppose that ⟨x, y⟩A = ⟨x, y⟩ for all x, y ∈ X. To prove that A is an orthonormal basis for X, let us first compute (bi, bj) for i ̸= j. We have ⟨bi, bj⟩ = ⟨bi, bj⟩A = ∑ {i2,...in}⊂{1,2,...,n} ⟨bi, bj |bi2 , . . . , bin⟩. For any {i2, . . . , in} ⊂ {1, 2, . . . , n}, observe that bi ∈ {bi2 , . . . , bin} or bj ∈ {bi2 , . . . , bin}, because {bi2 , . . . , bin} consists of n−1 elements of A. Consequently , ⟨bi, bj |bi2 , . . . , bin⟩ = 0, because two rows or two columns in the determinant will be identical. Since this is true for any {i2, . . . , in} ⊂ {1, 2, . . . , n}, we conclude that ⟨bi, bj⟩ = ∑ {i2,...in}⊂{1,2,...,n} ⟨bi, bj |bi2 , . . . , bin⟩ = 0. Let us now compute ⟨bi, bi⟩ for i = 1, 2, . . . , n. Notice that if bi ∈ {bi2 , . . . , bin}, then we have ⟨bi, bi|bi2 , . . . , bin⟩ = 0. Meanwhile, if bi ̸∈ {bi2 , . . . , bin} then —by the properties of the standard n−product— we have A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1942 ⟨bi, bi|bi2 , . . . , bin⟩ = ⟨b1, b1|b2, . . . , bn⟩ = ∣∣∣∣∣∣∣∣∣ ⟨b1, b1⟩ ⟨b1, b2⟩ . . . ⟨b1, bn⟩ ⟨b2, b1⟩ ⟨b2, b2⟩ . . . ⟨b2, bn⟩ ... ... . . . ... ⟨bn, b1⟩ ⟨bn, b2⟩ . . . ⟨bn, bn⟩ ∣∣∣∣∣∣∣∣∣ = n∏ j=1 ∥bj∥2 . Hence, we obtain ⟨bi, bi⟩A = ∑ {i2,...in}⊂{1,2,...,n} ⟨bi, bi|bi2 , . . . , bin⟩ = n∏ j=1 ∥bj∥2 . By our hypothesis, ∥bi∥2 = ∥bi∥2A = n∏ j=1 ∥bj∥2. This holds only if ∥bi∥ = 1 for all i = 1, 2, . . . , n. To sum up, we have proved that ⟨x, y⟩A = ⟨x, y⟩ if and only if A is an orthonormal basis for X. 3. The higher dimensional case Let us now consider the case where n+1 ≤ d = dim X < ∞. Let A := {a1, a2, . . . , ad} be a set of linearly independent vectors in X. (What happens if we use only n vectors will be discussed later, together with the case where d = ∞.) We define the following inner product on X: ⟨x, y⟩A := ∑ {i2,...in}⊂{1,2,...,n} ⟨x, y|ai2 , . . . , ain⟩. Note that there are ( d n− 1 ) terms in the above sum. Analogous to Theorem 2.1, we have the following theorem. Theorem 3. Let A = {a1, a2, . . . , ad} ⊂ X be an orthogonal set with ∥ai∥ = α > 0 for all i = 1, 2, . . . , d. Then ⟨x, y⟩A = 0 if and only if ⟨x, y⟩ = 0 for all x, y ∈ X. Proof. Let Id := {1, 2, . . . , d}. For any I0 := {i2, . . . , in} ⊂ Id, let I1 := Id \ I0. Then, we have ⟨x, y|ai2 , . . . ain⟩ = ∑ i∈I1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ∏ i∈I0 ∥ai∥2 = [ ⟨x, y⟩ − ∑ i∈I0 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] ∏ i∈I0 ∥ai∥2 . A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1943 Summing over all subsets I0 ⊂ Id and using the assumption that ∥ai∥ = α for all i = 1, 2, . . . n, we obtain ⟨x, y⟩A = ∑ I0⊂Id [ ⟨x, y⟩ − ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] α2(n−1) = ∑ I0⊂Id α2(n−1)⟨x, y⟩ − ∑ I0⊂Id ∑ i∈I0 α2(n−1) ⟨x, ai⟩⟨ai, y⟩ α2 . The first sum on the right hand side is equal to ( d n− 1 ) α2(n−1)⟨x, y⟩. For the second sum, we observe that each expression ⟨x, ai⟩⟨ai, y⟩ occurs precisely ( d− 1 n− 2 ) times for all i ∈ Id. Hence, by Parseval’s identity, the second sum is equal ( d− 1 n− 2 ) α2(n−1)⟨x, y⟩. Therefore we get ⟨x, y⟩A = [( d n− 1 ) − ( d− 1 n− 2 )] α2(n−1)⟨x, y⟩ = ( d− 1 n− 1 ) α2(n−1)⟨x, y⟩, which gives us the desired conclusion. Corollary 1. If A = {a1, a2, . . . , ad} is an orthonormal basis for X, then ⟨x, y⟩A =( d− 1 n− 1 ) ⟨x, y⟩ for all x, y ∈ X. Remark 1. The converse of the above corollary does not hold. To give an example, let d = dimX = 3 and n = 2. Let A = {a1, a2, a3} be linearly independent set in X. Suppose that ⟨x, y⟩A = 2⟨x, y⟩ for all x, y ∈ X. We would like to check whether we have ∥ai∥ = 1 for i = 1, 2, 3 and ⟨ai, aj⟩ = 0 for i ̸= j. Notice that ⟨x, y⟩A = 3∑ i=1 ⟨x, y|ai⟩ = 3∑ i=1 ∣∣∣∣ ⟨x, y⟩ ⟨x, ai⟩ ⟨ai, y⟩ ⟨ai, ai⟩ ∣∣∣∣ for all x, y ∈ X. From the hypothesis, we have ⟨ai, aj⟩A = 2⟨ai, aj⟩ for i, j = 1, 2, 3, which may be rewritten as ∥a1∥2 ∥a2∥2 − ⟨a1, a2⟩2 + ∥a1∥2 ∥a3∥2 − ⟨a1, a3⟩2 = 2 ∥a1∥2 , ∥a1∥2 ∥a2∥2 − ⟨a1, a2⟩2 + ∥a2∥2 ∥a3∥2 − ⟨a2, a3⟩2 = 2 ∥a2∥2 , ∥a1∥2 ∥a3∥2 − ⟨a1, a3⟩2 + ∥a2∥2 ∥a3∥2 − ⟨a2, a3⟩2 = 2 ∥a3∥2 , ⟨a1, a2⟩ ∥a3∥2 − ⟨a1, a3⟩⟨a2, a3⟩ = 2⟨a1, a2⟩, ⟨a1, a3⟩ ∥a2∥2 − ⟨a1, a2⟩⟨a2, a3⟩ = 2⟨a1, a3⟩, ⟨a2, a3⟩ ∥a1∥2 − ⟨a1, a2⟩⟨a1, a3⟩ = 2⟨a2, a3⟩. A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1944 Let A := ∥a1∥ , B := ∥a2∥ , C := ∥a3∥ , D := ⟨a1, a2⟩, E := ⟨a1, a3⟩, F := ⟨a2, a3⟩. Then A2B2 −D2 +A2C2 − E2 = 2A2, A2B2 −D2 +B2C2 − F 2 = 2B2, A2C2 − E2 +B2C2 − F 2 = 2C2, DC2 − EF = 2D, EB2 −DF = 2E, FA2 −DE = 2F. Observe that A = B = C = 1, D = E = F = 0 satisfy the above equations simultaneously. We shall see that there are other possible solutions with D,E, F ̸= 0. Multiplying both sides in the last three equations by D,E, and F (respectively) and rearranging the terms, we obtain D2 + E2 = A2B2 +A2C2 − 2A2, (1) D2 + F 2 = A2B2 +B2C2 − 2B2, (2) E2 + F 2 = A2C2 +B2C2 − 2C2, (3) C2D2 − 2D2 = DEF, (4) B2E2 − 2E2 = DEF, (5) A2F 2 − 2F 2 = DEF. (6) From (1), (2), and (3), we get D2 = A2B2 −A2 −B2 + C2, (7) E2 = A2C2 −A2 +B2 − C2, (8) F 2 = B2C2 +A2 −B2 − C2. (9) From (4), (5), and (6), we get (C2 − 2)D2 = (B2 − 2)E2 = (A2 − 2)F 2 = DEF. (10) Substituting (7), (8), and (9) into (10), we obtain (B2 − C2)(A2 +B2 + C2 − 4) = 0, (A2 − C2)(A2 +B2 + C2 − 4) = 0, (A2 −B2)(A2 +B2 + C2 − 4) = 0. Now one may check that A = B = C = 4 3 , D + E + F = −2 3 satisfy the above equations simultaneously. This tells us that A is not necessarily an orthonormal basis. A. Adam, S. Rante, H. Gunawan / Eur. J. Pure Appl. Math, 17 (3) (2024), 1937-1947 1945 We now come to the case where d = dim X = ∞. We assume that X is separable and B := {ai : i = 1, 2, 3, . . . } is an orthogonal basis for X. Thus for all x, y ∈ X, we have Parseval’s identity that ∞∑ i=1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 will converge to ⟨x, y⟩. Next, let A := {a1, a2, . . . , an}, where the vectors ai’s are the first n vectors in B. We define ⟨x, y⟩A := ∑ {i2,...,in}⊂{1,2,...,n} ⟨x, y|ai2 , . . . , ain⟩ for all x, y ∈ X. Then we have the following theorem. Theorem 4. For all x, y ∈ X, we have ⟨x, y⟩A = [ n∑ i=1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥4 + n ∞∑ i=n+1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] n∏ j=1 ∥aj∥2 . In particular, if ∥ai∥ = α for i = 1, 2, . . . , n then ⟨x, y⟩A = α2(n−1) [ n∑ i=1 ⟨x, ai⟩⟨ai, y⟩ α2 + n ∞∑ i=n+1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] . Proof. The proof is similar to the proof of Theorem 2.1 but this time we have ⟨x, y|ai2 , . . . , ain⟩ = [ ⟨x, ai1⟩⟨ai1 , y⟩ ∥ai1∥ 4 + 1 ∥ai1∥ 2 ∞∑ i=n+1 ⟨x, ai1⟩⟨ai1 , y⟩ ∥ai∥2 ] n∏ j=1 ∥aj∥2 , where {i1} = {1, 2, . . . , n} \ {i2, . . . , in}. Summing all these expression for all subsets {i2, . . . , in} ⊂ {1, 2, . . . , n}, we obtain ⟨x, y⟩A = [ n∑ i=1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥4 + n∑ i=1 1 ∥ai∥2 ∞∑ i=n+1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] n∏ j=1 ∥aj∥2 . In particular, if ∥ai∥ = α for i = 1, 2, . . . , n, then we have ⟨x, y⟩A = α2(n−1) [ n∑ i=1 ⟨x, ai⟩⟨ai, y⟩ α2 + n ∞∑ i=n+1 ⟨x, ai⟩⟨ai, y⟩ ∥ai∥2 ] as claimed. Remark 2. Note that if ∥ai∥ = 1 for i = 1, 2, 3, . . . (that is, B is an orthonormal basis for X), then the conclusion in the above theorem tells us that ⟨x, y⟩A = n∑ i=1 ⟨x, ai⟩⟨ai, y⟩+ n ∞∑ i=n+1 ⟨x, ai⟩⟨ai, y⟩ for all x, y ∈ X. REFERENCES 1946 Corollary 2. Suppose that ∥ai∥ = α for i = 1, 2, . . . , n. For every x, y ∈ X, let x := xA+x⊥A and y := yA+y⊥A where xA and yA are the orthogonal projections of x and y on span A (respectively), and x⊥A and y⊥A are their complements (respectively). If ⟨xA, yA⟩A = 0 and ⟨x⊥A, y⊥A⟩ = 0, then ⟨x, y⟩ = 0. Conversely, if ⟨xA, yA⟩ = 0 and ⟨x⊥A, y⊥A⟩ = 0, then ⟨x, y⟩A = 0. 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