EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS 2025, Vol. 18, Issue 2, Article Number 5826 ISSN 1307-5543 – ejpam.com Published by New York Business Global Common Fixed Points of Asymptotically Regular Mappings in Convex Metric Spaces with Application Abdul Rahim Khan1, Godwin Chidi Ugwunnadi2,3,∗, Maggie Aphane3, Faizan Yousaf1, Amir Abbas1 1 Department of Mathematics and Statistics, University of Southern Punjab, Multan, Pakistan 2 Department of Mathematics, Faculty of Science and Engineering, University of Eswatini, Private Bag 4, Kwaluseni M201, Eswatini 3 Department of Mathematics and Applied Mathematics, Sefako Makgatho Health Sciences University, Medunsa, P.O. Box 94, Pretoria 0204, South Africa Abstract. In this paper, based upon Górnicki’s work on fixed points of a continuous asymptoti- cally regular self-mapping on a metric space, we establish common fixed point results for similar self-mappings and their average mappings on a convex metric space by using various types of con- tractive conditions. The closedness and convexity of the set of fixed points of a non- self- mapping is obtained here in the context of a uniformly convex hyperbolic space. We also apply our findings to solve Volterra type integral equations, demonstrating practical use of our work in mathematical analysis and its related fields. 2020 Mathematics Subject Classifications: 47H05, 47J20, 47J25, 65K15 Key Words and Phrases: Górnicki Type Contraction Mapping; Common Fixed Point; Convex Metric Space, Uniformly Convex Hyperbolic Space; Asymptotically Regular Mapping; Nonlinear Integral Equations 1. Introduction Fixed point theory is an integral part of modern mathematics, offering essential tools and techniques for resolving various problems in nonlinear analysis, optimization, economics, and engineering. Over the past two decades, the development of this theory in metric- type spaces has garnered significant attention from researchers, especially its usefulness for solving many existence problems in nonlinear differential and integral equations with applications in engineering and applied sciences [1]. The relevance and applicability of ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v18i2.5826 Email addresses: abdulrahimkhan@isp.edu.pk (A. R. Khan), gcugwunnadi@uniswa.sz (G. C. Ugwunnadi), maggie.aphane@smu.ac.za (M. Aphane), faizanyousef967@gmil.com ( F. Yousaf), aamirbuzdar112@gmail.com (A. Abbas) https://www.ejpam.com 1 Copyright: © 2025 The Author(s). (CC BY-NC 4.0) A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 2 of 23 fixed point theory continues to expand as new results and methodologies emerge. Recently, Górnicki [2] generalized a well-known result of Reich [3] related to contractions on a complete metric space. This new result has been further extended by Bisht [4], Karapinar et al. [5], and Panja et al. [6] for discontinuous mappings and by Khan and Oyetunbi [7] for two discontinuous mappings satisfying a Lipschitz-Kannan type condition considered in [8]. These advancements highlight the dynamic nature of fixed point theory. Applications of fixed point theory have been widely explored in various settings. Specif- ically, the theory has been instrumental in developing iterative methods for solving exis- tence and uniqueness problems in differential and integral equations, as well as systems of linear equations. These applications demonstrate the versatility of fixed point theory in addressing complex mathematical challenges. The theory’s ability to ensure the existence and uniqueness of solutions makes it a valuable tool for tackling a wide range of real-world problems in mathematics, engineering and applied sciences [1, 9, 10]. In this paper, we aim to contribute to this growing body of knowledge by proving fixed point and common fixed point results for asymptotically regular mappings in hyperbolic spaces and convex metric spaces. Our work is built on a basic concept introduced by Browder and Petryshyn [11], namely, asymptotically regular mapping and explores its implications in more general spaces. 2. Preliminaries Let (Q, d) be a metric space and E : Q → Q be a mapping. A point q0 ∈ Q is called fixed point of E if Eq0 = q0. The set of fixed points of E is denoted and defined as Fix(E) := {q0 ∈ Q : Eq0 = q0}. The concept of asymptotically regular mappings was introduced by Browder and Petryshyn [11]. A mapping E : Q → Q is called asymptotically regular at x0 ∈ Q, if limn→∞ d(Enx0, E n+1x0) = 0. If E is asymptotically regular at each point of Q, then E is said to be asymptotically regular on Q. E is non-expansive if d(Ex,Ey) ≤ d(x, y) for all x, y ∈ Q. Consider Q = R , the set of real numbers with its usual metric d(q, p) = |q − p|. Suppose E : Q → Q is given by Eq = q 2 . This function is both asymptotically regu- lar and non-expansive. If E is a function on a metric space Q into itself, then the set O(E, e) := {Ene : n = 0, 1, 2, 3, · · · } is called the orbit of E at the point e ∈ Q. E is called orbitally continuous at p ∈ Q if for any sequence {qk} ⊂ O(E, q) for some q ∈ Q, limk→∞ qk = p entails that limk→∞Eqk = Ep. We say that E is orbitally continuous on Q if E is orbitally continuous at each point p ∈ Q. Clearly, continuity implies orbital continuity, but the converse is not true [4, 12, 13]. A self-mapping E on a metric space Q, is called k-continuous, k = 1, 2, · · · if lim n→∞ Ek−1qn = z implies that lim n→∞ Ekqn = Ez. Note that 1-continuity is equivalent to continuity, and for any k = 1, 2, ..., k-continuity implies (k + 1)-continuity, while the converse is not true. Moreover, continuity of E and k-continuity of E are independent conditions when k > 1([13], Examples 1.2-1.5). Górnicki [2] has obtained the following result. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 3 of 23 Theorem 1. ([2], Theorem 2.6) Suppose that (Q, d) is a complete metric space and E is a continuous asymptotically regular self-mapping on Q satisfying the following condition: d(Eq,Ep) ≤ µd(q, p) + ν{d(q, Eq) + d(p,Ep)},∀q, p ∈ Q (1) where 0 ≤ µ < 1, 0 ≤ ν < ∞. Then E has a unique fixed point x ∈ Q and Enq → x for each q ∈ Q . Khan and Oyetunbi [7] have obtained the following generalization of Theorem 1. Theorem 2. ([7],Theorem 2.2) Suppose that (Q, d) is a complete metric space, E and F are asymptotically regular self-mappings on Q satisfying the following condition: d(Eq, Fp) ≤ µd(q, p) + ν{d(q, Eq) + d(p, Fp)}, ∀q, p ∈ Q (2) where 0 ≤ µ < 1, 0 ≤ ν < ∞. Suppose further that E and F are either k-continuous for some k ≥ 1 or orbitally continuous. Then E and F have a unique common fixed point b. Furthermore, limn→∞Enq = b = limn→∞ Fnq for any q ∈ Q. Here is a result of Khan and Oyetunbi [7] without asymptotically regularity of the mappings. Theorem 3. [7, Theorem 2.6] Suppose that (Q, d) is a complete metric space and E,F : Q → Q are continuous mappings satisfying (2). Suppose that E and F have a com- mon approximate fixed point sequence (i.e. there exists a sequence {qn} ⊂ Q such that d(qn, Eqn) → 0 and d(qn, F qn) → 0 as n → ∞). Then E and F have a unique common fixed point q. In particular, qn → q, as n → ∞. Lemma 1 ([14],Lemma 2.1). Let {τn} , {ϕn} and {χn} be three real sequences with τn ≥ 0 and ϕn ∈ (0, 1). Suppose that (i)τn+1 ≤ (1− ϕn)τn + ϕnχn (ii) ∑∞ n=1 ϕn = ∞ (iii) lim supn→∞χn ≤ 0 or ∑∞ n=1 ϕnχn is convergent. Then limn→∞ τn = 0. Definition 1. [14] Let R+ := {f ∈ R | f ≥ 0}. Define a function κ : R+ → [0, 1] satisfying the following properties: (i) 0 ≤ κ(f) < 1 for all f > 0. (ii) limn→∞ κ(fn) = 1 implies limn→∞ fn = 0. The collection of all functions κ(f) is denoted by S. Kohlenbouch [10] proposed the concept of a hyperbolic metric space as follows. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 4 of 23 Definition 2. A hyperbolic space is a triplet (Q, d, η) where (Q, d) is a metric space and η : Q×Q×[0, 1] → Q satisfies the following conditions, for all ω, ξ, κ, ι ∈ Q and µ, x ∈ [0, 1] (η1) : d(ι, η(ω, ξ, µ)) ≤ (1− µ)d(ι, ω) + µd(ι, ξ), (η2) : d(η(ω, ξ, µ), η(ω, ξ, x)) = |µ− x|d(ω, ξ), (η3) : η(ω, ξ, µ) = η(ξ, ω, 1− µ), (η4) : d(η(ω, ι, µ), η(ξ, κ, µ)) ≤ (1− µ)d(ω, ξ) + µd(ι, κ). In case only (η1) is satisfied, then the Definition 2 of hyperbolic space coincides with the convex metric space introduced by Takahashi [15]. Clearly, a hyperbolic space is a convex metric space. In the case of a convex metric space, we shall replace η by W (a convex structure on Q) and denote it by (Q, d,W ). A nonempty subset J of a convex metric space Q is convex if W (p, q, λ) ∈ J for all p, q ∈ J and λ ∈ [0, 1]. In the context of a normed space Q, the natural convex structure on Q is given by W (p, q;λ) = λp+ (1− λ)q, p, q ∈ Q and λ ∈ [0, 1]. If J is a convex subset of a normed space and E : J → J, then the average mapping Eµ : J → J is given by Eµp = (1− µ)p+ µEp, where µ ∈ (0, 1]. A hyperbolic space (Q, d, η) is said to be uniformly convex if for all x, y, z ∈ Q, r > 0 and ε ∈ (0, 2], there exists δ ∈ (0, 1] such that d (η (x, y, 1/2) , z) ≤ (1 − δ)r whenever d(x, z) ≤ r and d(y, z) ≤ r and d(x, y) ≥ εr. A map h : (0,∞) × (0, 2] → (0, 1] which provides in the above definition, a δ = h(r, ε) for r > 0 and for a fixed ε ∈ (0, 2] , is called modulus of uniform convexity. We call h monotone if it decreases with r ( for a fixed ε). Let {qn} be a bounded sequence in a hyperbolic space Q. For q ∈ Q, we define a continuous functional r(., {qn}) : Q → [0,∞) by r(q, {qn}) = lim n→∞ sup d(qn, q). The aymptotic radius ρ = r({qn}) of {qn} is given by ρ = inf{r(q, {qn}) : q ∈ Q}. The asymptotic center of a bounded sequence {qn} with respect to a subset U of Q is defined as: AU ({qn}) = {q ∈ Q : r(q, {qn}) ≤ r(p, {qn}) for any p ∈ U}. If the asymptotic center is taken with respect to Q, then it is simply denoted by A({qn}). It is known that uniformly convex Banach spaces and even CAT(0) spaces enjoy the property that ”bounded sequences have unique asymptotic centers with respect to closed convex subsets”. The following lemma ensures that this property also holds in complete uniformly convex hyperbolic spaces. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 5 of 23 Lemma 2. ([16, Lemma 2.2]). Let (Q, d, η) be a complete uniformly convex hyperbolic space with monotone modulus of uniform convexity. Then every bounded sequence {qn} in Q has a unique asymptotic center with respect to any nonempty closed convex subset U of Q. Recall that a bounded sequence {qn} in Q is known as ∆ − convergent to q ∈ Q if q is the unique asymptotic center of {un} for every subsequence {un}of {qn}. In this case, we write ∆− lim n→∞ {qn} = q. We include the following lemmas of Berinde and Pacurar [17, 18] for a ready reference. Lemma 3. Let (Q,d,W) be a convex metric space. For all x, y ∈ Q and any λ ∈ [0, 1], we have d(x, y) = d(x,W (x, y;λ)) + d(W (x, y;λ), y). Proof. By the triangular inequality and (η1), we get d(x, y) ≤ d(x,W (x, y;λ)) + d(W (x, y;λ), y) ≤ λd(x, x) + (1− λ)d(x, y) + λd(x, y) + (1− λ)d(y, y) = d(x, y). Lemma 4. Let (Q, d,W ) be a convex metric space. For all x, y ∈ Q and any λ ∈ [0, 1], we have d(x,W (x, y;λ)) = (1− λ)d(x, y) and d(W (x, y;λ), y) = λd(x, y). Proof. By (η1), we get d(x,W (x, y;λ)) ≤ (1− λ)d(x, y), and d(W (x, y;λ), y) ≤ λd(x, y). If we had strict inequality in either of the above two inequalities, then, by Lemma 3, we would reach the contradiction d(x, y) = d(x,W (x, y;λ)) + d(W (x, y;λ), y) < d(x, y). Lemma 5. Let (Q, d,W ) be a convex metric space and E : Q → Q be a mapping. Define the mapping Eλ : Q → Q by Eλx = W (x,Ex;λ), x ∈ Q. Then for any λ ∈ [0, 1), Fix(E) = Fix(Eλ). A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 6 of 23 Proof. For λ = 0, Eλ = E and the assertion is trivial. Assume λ ∈ (0, 1) and let a ∈ Fix(E). This means a = Ea and therefore it follows that d(a,Eλa) = d(a,W (a,Ea;λ)) ≤ d(a, a) + (1− λ)d(a,Ea) = 0, i.e., a ∈ Fix(Eλ). Conversely, assume that a ∈ Fix(Eλ). This means that d(a,Ea) = 0, which implies d(a,W (a,Ea;λ)) = 0. By Lemma 4, d(a,W (a,Ea;λ)) = (1− λ)d(a,Ea), so it follows that (1− λ).d(a,Ea) = 0, which, in view of the fact that (1− λ) ̸= 0, implies d(a,Ea) = 0. Hence a ∈ Fix(E). 3. Common fixed points results Following the notion introduced in Definition 1 by Huang and Qian [14], we extended Theorem 3 by replacing µ with a function κ ∈ S and weakening the continuity hypothesis. Theorem 4. Suppose that (Q, d) is a complete metric space and E and F are asymptoti- cally regular self-mappings on Q. Suppose that there exist a function κ ∈ S and a constant K ∈ [0,+∞) satisfying the following condition: d(Eq, Fp) ≤ κ(d(q, p))d(q, p) +K{d(q, Eq) + d(p, Fp)} (3) for all q, p ∈ Q. Suppose that E and F have a common approximate fixed point sequence (i.e., there is a sequence {qh} ⊂ Q, such that d(qh, Eqh) → 0 and d(qh, F qh) → 0 as h → ∞). Then E and F have a unique common fixed point p provided E and F are either k-continuous or orbitally continuous. In particular, {qh} → p as h → ∞. Proof. Take q ∈ Q. Define qh = Ehq and ph = F hq for all h ∈ N. By (3), we have d(Eh+1q, F h+1q) = d(E(Ehq), F (F hq)) (4) d(Eh+1q, F h+1q) ≤ κ(d(Ehq, F hq))d(Ehq, F hq) +K[d(Ehq, Eh+1q) + d(F hq, F h+1q)]. (5) In view of the condition, 0 ≤ κ(d(Ehq, F hq)) ≤ 1, we consider two cases for lim suph→∞ κ(d(Ehq), F hq). Case 1: lim sup h→∞ κ(d(Ehq, F hq)) = 1. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 7 of 23 In this case, there exists a subsequence {κ(d(Ehkq, F hkq))} of {κ(d(Ehq, F hq))} such that lim k→∞ κ(d(Ehkq, F hkq)) = 1. (6) Now (6) implies on the basis of Definition 1 , lim k→∞ d(Ehkq, F hkq) = 0. (7) We prove that {Ehkq} is a Cauchy sequence. Suppose on the contrary that {Ehkq} is not a Cauchy sequence. Then there exists ϵ0 > 0 and two integer sequences {hk̃(i)}, {hk(i)} of {hk} with hk̃(i) > hk(i) > i such that d(E hk̃(i)q, Ehk(i)q) ≥ ϵ0, i = 1, 2, 3, · · · (8) Consequently, we have ϵ0 ≤ d(E hk̃(i)q, Ehk(i)q), ϵ0 ≤ d(E hk̃(i)q, Ehk(i−1)q) + d(E hk̃(i−1)q, Ehk(i−1)q) + d(E hk̃(i−1)q, Ehk(i)q). (9) If i → ∞ in (9), then by asymptotic regularity of E, we obtain lim inf i→∞ d(E hk̃(i−1)q, Ehk(i−1)q) ≥ ϵ0. (10) Now by (3), we have d(E hk̃(i)q, Ehk(i)q) ≤ d(E hk̃(i)q, F hk(i)q) + d(F hk(i)q, Ehk(i)q) (11) d(E hk̃(i)q, Ehk(i)q) ≤ κ(d(E hk̃(i−1)q, F hk(i−1)q))d(E hk̃(i−1)q, F hk(i−1)q) +K[d(E hk̃(i−1)q, F hk̃(i)q) + d(F hk(i−1)q, F hk(i)q)] +d(F hk(i)q, Ehk(i)q). and d(E hk̃(i)q, Ehk(i)q) ≤ κ(d(E hk̃(i−1)q, F hk(i−1)q))d(E hk̃(i−1)q, Ehkĩq) +d(E hk̃(i)q, Ehk(i−)q) + d(Ehk(i)q, F hk(i)q)d(F hk(i)q, F hk(i−1)q) +K[d(E hk̃(i−1)q, Ehkĩq) + d(F hk(i−1)q, F hk(i)q) +d(F hk(i)q, Ehk(i)q)]. (12) Dividing both sides of the inequality (12) by d(E hk̃(i)q, Ehk(i)q) and comparing the new inequality with (8), we conclude that A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 8 of 23 1 ≤ κ(d(E hk̃(i−1)q, F hk(i−1)q))( d(E hk̃(i−1)q, Ehk̃(i)q) d(E hk̃(i)q, Ehk(i)q) ) +1 + d(Ehk(i)q, F hk(i)q) d(E hk̃(i)q, Ehk(i)q) + d(F hk(i)q, F hk(i−1)q) d(E hk̃(i)q, Ehk(i)q) +K d(E hk̃(i−1)q, F hk̃(i)q) + d(F hk(i−1)q, F hk(i)q) d(E hk̃(i)q, Ehk(i)q) + d(F hk(i)q, Ehk(i)q) d(E hk̃(i)q, Ehk(i)q) . (13) Let i → ∞ in (13), using (7), (8), asymptotically regularity of E and F and the fact 0 ≤ κ(.) ≤ 1, we deduce that lim i→∞ κ(d(E hk̃(i)−1 q, F hk(i)−1q)) = 1. Using Definition 1, we obtain lim i→∞ (d(E hk̃(i)−1 q, F hk(i)−1q)) = 0. (14) In view of d(E hk̃(i)−1 q, Ehk(i)−1q) ≤ d(E hk̃(i)−1 q, F hk(i)−1q) + d(F hk(i)−1q, Ehk(i)−1q), a combination of (7) and (14), gives lim i→∞ d(E hk̃(i)−1 q, F hk(i)−1q) = 0. It contradicts (10). Hence {qhk } = {Ehkq} is a Cauchy sequence. Since Q is complete, {qhk } converges to u in Q. Since d(F hkq, u) ≤ d(Ehkq, F hkq) + d(Ehkq, u), therefore by (7), we conclude that {F hkq} converges to u. Suppose that E is orbitally continuous. Let {Eqh} be a sequence in the orbit of E at the point q. The orbital continuity of E implies that {Eqhk } converges to Eu. By asymptoti- cally regularity of E, we have lim k→∞ d(qhk+1 , qhk ) = lim k→∞ d(Ehk+1q, Ehkq) = 0, which gives lim k→∞ d(qhk+1 , qhk ) ≤ lim k→∞ ( d(qhk+1 , Eqhk+1 ) + d(Eqhk+1 , Eqhk ) + d(Eqhk , qhk ) ) . A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 9 of 23 Since d(qhk+1 , Eqhk+1 ) → 0, d(Eqhk , qhk ) → 0, therefore, lim k→∞ d(qhk+1 , qhk ) = 0. Hence lim k→∞ Eqhk = lim k→∞ qhk+1 = lim k→∞ qhk = u implies that Eu = u by the uniqueness of limit. Now suppose that E is k-continuous. In view of d(qhk+j , qhk ) ≤ d(qhk+j , qhk+j−1 ) + · · ·+ d(qhk+1 , qhk ) and d(Ehk+jqhk+j , Ehkqhk ) = d(Ehk+jq, Ehk+j−1q) + · · ·+ d(Ehk+1q, Ehkq), for all j = 1, 2, 3, · · · , k by asymptotic regularity of E, we get lim k→∞ qhk+j = lim k→∞ qhk = u, j = 1, 2, 3, · · · , k. (15) In particular, lim k→∞ Ek−1qhk = lim k→∞ qhk+j−1 = u. (16) As E is k-continuous, (16) gives lim k→∞ Ekqhk = Eu. (17) By (15), we have lim k→∞ Ekqhk = lim k→∞ qhk+j = u. (18) A combination of (17) and (18), gives Eu = u. Similarly, we can prove that Fu = u. So u is a common fixed point of E and F . Next, assume that v is another common fixed point of E and F with u ̸= v. Definition 1 (i) applied to (3) gives d(u, v) = d(Eu,Fv) ≤ κ(d(u, v))d(u, v) +K[d(u,Eu) + d(v, Fv)]. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 10 of 23 d(u, v) ≤ κ(d(u, v))d(u, v). d(u, v) < d(u, v), which is a contradiction. Therefore common fixed point of E and F is unique. Case 2: lim sup h→∞ κ(d(Ehq, F hq)) < 1. In this case, there exists σ ∈ (0, 1) such that 0 < κ(d(Ehq, F hq)) < σ. By (5) we have (d(Eh+1q, F h+1q)) ≤ σd(Ehq, F hq) +K(d(Ehq, Eh+1q) + d(F hq, F h+1q)). (19) Let uh = d(Ehq, F hq), vh = 1− σ, wh = K(d(Ehq, Eh+1q) + d(F hq, F h+1q)) 1− σ . By (19), we have uh+1 ≤ (1− vh)uh + vhwh,∀h ∈ N. Since E and F are asymptotically regular on Q, we conclude lim h→∞ wh = 0. Moreover, ∞∑ h=1 vh = ∞∑ h=1 (1− σ) = ∞. By Lemma 1, lim h→∞ (Ehq, F hq) = 0. Hence for any subsequence {hk(i)} of {hk}, we have lim i→∞ (Ehk(i)q, F h(i)q) = 0. Thus (7) holds. The rest of proof is the same as in Case I. Next, we present a numerical example to illustrate Theorem 4. Example 1. Consider Q = [0, 1], equipped with the metric d defined by d(q, p) = |q − p|. Define self-mappings on Q: Eq = q 2 and Fq = q 3 for all q ∈ Q. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 11 of 23 For q = 1 2 ∈ Q, lim k→∞ d ( Ek (1 2 ) , Ek+1 (1 2 )) = lim k→∞ ∣∣∣ 1 2k+1 − 1 2k+2 ∣∣∣ = 0 implies that E is asymptotically regular. Similarly, it can be demonstrated that F is asymp- totically regular. Furthermore, the mappings E and F are orbitally continuous. Next, we establish that E and F satisfy condition (3) with the parameter K = 1. Now define κ : R+ → [0, 1] by κ(t) = { 1 2 + 1 2 t if t ∈ [0, 1], 1 if t ∈ (1,+∞). Then κ ∈ S, for any q, p ∈ Q, since |q − p| ≤ 1. Consider (3) in the form κ(d(q, p))d(q, p) + d(q, Eq) + d(p, Fp)− d(Eq, Fp) = 1 2 (1 + |q − p|)|q − p|+ ∣∣∣q − q 2 ∣∣∣+ ∣∣∣p− p 3 ∣∣∣− ∣∣∣q 2 − p 3 ∣∣∣ = 1 2 (1 + |q − p|)|q − p|+ q 2 + 2p 3 − ∣∣∣q 2 − p 3 ∣∣∣. (20) Now, there are two cases to consider for (20): Case i. If q ≥ p, then we have: 1 2 (1 + (q − p))(q − p) + q 2 + 2p 3 − (q 2 − p 3 ) = 1 2 (q − p) + 1 2 (q − p)2 + q 2 + 2p 3 − q 2 + p 3 = 1 2 (q + p) + 1 2 (q − p)2 ≥ 0; thus d(Eq, Fp) ≤ κ(d(q, p))d(q, p) + d(q, Eq) + d(p, Fp). Case ii. if q < p, then we have: 1 2 (1 + (p− q))(p− q) + q 2 + 2p 3 − ∣∣∣q 2 − p 3 ∣∣∣ = { 1 2(p− q) + 1 2(p− q)2 + p if q 3 ≥ p 3 , 1 2(p− q) + 1 2(p− q)2 + q + p 3 if q 2 < p 3 ≥ 0; hence d(Eq, Fp) ≤ κ(d(q, p))d(q, p) + d(q, Eq) + d(p, Fp). Therefore E and F satisfy (3) with K = 1. Next, we show that E and F have a common approximate fixed point sequence. Consider the sequence {qk} ⊂ Q where qk = 1 k . d(qk, Eqk) = ∣∣∣∣1k − 1 2k ∣∣∣∣ = 1 2k → 0 as k → ∞, A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 12 of 23 and d(qk, F qk) = ∣∣∣∣1k − 1 3k ∣∣∣∣ = 1 3k → 0 as k → ∞. Hence, E and F have a common approximate fixed point sequence. Since E and F are both continuous (and thus k-continuous), therefore by Theorem 4, they have a unique common fixed point q = 0. In particular, {qk} → 0 as k → ∞. We now present a partial extension of Theorem 2 for a function which is not asymptotically regular and is defined on a closed and convex subset of a uniformly convex hyperbolic space. Theorem 5. Let J be a nonempty closed and convex subset of complete uniformly convex hyperbolic space Q with monotone modulus of convexity η. Let E : J → Q be a mapping satisfying d(Eq,Ep) ≤ µd(q, p) + ν{d(q, Eq) + d(p,Ep)}, for all q, p ∈ J, (21) where 0 ≤ µ < 1, 0 ≤ ν < ∞ with µ+2νblue<1. Let {qk} be a bounded sequence in J such that limk→∞ d(qk, Eqk) = 0 and ∆− limk→∞ qk = q∗. Then E has a unique fixed point q∗. Proof. Let {qk} be any bounded sequence in J . Since J is a subset of Q which is complete convex hyperbolic space with monotone uniform convexity, therefore by Lemma 2, {qk} has a unique asymptotic center in J . But ∆− limk→∞ qk = q∗. So A({qk}) = q∗. Using (21), we get d(qk, Eq∗) ≤ d(qk, Eqk) + d(Eqk, Eq∗). ≤ d(qk, Eqk) + µd(qk, q ∗) + ν[d(qk, Eqk) + d(q∗, Eq∗)]. ≤ (1 + ν)d(qk, Eqk) + (µ+ ν)d(qk, q ∗) + νd(qk, Eq∗). Thus d(qk, Eq∗) ≤ 1 + ν 1− ν d(qk, Eqk) + µ+ ν 1− ν d(qk, q ∗) = 1 + ν 1− ν d(qk, Eqk) + µ+ 2ν − ν 1− ν d(qk, q ∗) ≤ 1 + ν 1− ν d(qk, Eqk) + d(qk, q ∗). (22) Since limk→∞ d(qk, Eqk) = 0, taking lim sup on both sides of inequality (22), we obtain r(Eq∗, qk) = lim sup k→∞ d(qk, Eq∗) ≤ lim sup k→∞ d(qk, q ∗) = r(q∗, {qk}). We know that asymptotic center of sequence {qk} is unique, so Eq∗ = q∗; thus q∗ ∈ Fix(E). The uniqueness of fixed point follows by (21). A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 13 of 23 Example 2. Let Q = R2 and d∗ : R2 × R2 → [0,∞) be defined by d∗(q̄, p̄) = √ (q1 − p1)2 + (q21 − q2 − p21 + p2)2, (23) where q̄ = (q1, q2), p̄ = (p1, p2) ∈ R2. Then (R2, d∗) is not a metric space in the classical sense but is a Hardamard space (see [19]). Hence (R2, d∗) is a complete uniformly convex hyperbolic space (for details, see Example 2.1 in [20]). Let J = [0, 1]× [0, 1]. Define E : J → Q as Eq̄ = (q1, q 2 1 + q2), where q̄ = (q1, q2). For any µ ∈ [ 2 5 , 1 ) and 0 ≤ ν < ∞ with µ + 2ν < 1, we need to verify the following, for any q̄, p̄ ∈ J , Γ := µd∗(q̄, p̄) + ν[d∗(q̄, Eq̄) + d∗(p̄, Ep̄)]− d∗(Eq̄,Ep̄) ≥ 0. (24) Thus, for any q̄ = (q1, q2), p̄ = (p1, p2) ∈ J , by using (23) in (24), we get Γ = d∗((q1, q2), (p1, p2)) + d∗((q1, q2), (q1, q 2 1 + q2)) + d∗((p1, p2), (p1, p 2 1 + p2)) −d∗((q1, q 2 1 + q2), (p1, p 2 1 + p2)) = µ √ (q1 − p1)2 + (q21 − q1 − p22 + p2)2 + ν (√ (q1 − q1)2 + (q21 − q2 − q21 + (q21 + q2))2 + √ (p1 − p1)2 + (p21 − p2 − p21 + (p21 + p2))2 ) − √ (q1 − p1)2 + (q21 − (q21 + q2)− p21 + (p21 + p2))2 = µ √ (q1 − p1)2 + ((q2 − p2) + (q21 − p21)) 2 + ν(q21 + p21)− √ (q1 − p1)2 + (q2 − p2)2 ≥ 0 Hence (24) holds. Therefore E satisfies (21) with µ ∈ [ 2 5 , 1 ) and 0 ≤ ν < ∞ where µ+ 2ν < 1. For any qk ∈ J , define qk = ( 1 k , 1 k ) . Then Eqk = ( 1 k , 1 k2 + 1 k ) , so from (23), we get that d∗(qk, Eqk) = d∗( 1 k , 1 k2 + 1 k ) = √(1 k − 1 k )2 + ( 1 k2 − 1 k − 1 k2 + ( 1 k2 + 1 k ))2 = 1 k2 . It follows that d∗(qk, Eqk) → 0 as k → ∞. All the assumptions of Theorem 5 hold and hence, the mapping E has a unique fixed point at (0, 0). Khan [21] has studied some properties of the set of fixed points of a ∗-nonexpansive mapping in the context of strictly convex Banach spaces. In the following result, we establish the closedness and convexity of the set of fixed points of a contractive-type mapping on a convex metric space. Theorem 6. Let J be a closed and convex subset of a convex metric space Q and E : J → Q be a mapping satisfying (21). Then Fix(E) is closed and convex. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 14 of 23 Proof. If Fix(E) = ∅, then nothing to show, since empty set is closed and convex. Now assume that Fix(E) ̸= ∅. We first show that Fix(E) is closed. Let {qk} be a sequence in Fix(E) such that {qk} converges to a point u in J . We show that u ∈ Fix(E). By (21) , we obtain d(qk, Eu) = d(Eqk, Eu) ≤ µd(qk, u) + ν[d(qk, Eqk) + d(u,Eu)]. Implies d(qk, Eu) ≤ µd(qk, u) + ν[d(u, qk) + d(qk, Eu)]. Thus d(u,Eu) ≤ d(u, qk) + d(qk, Eu) ≤ d(u, qk) + µd(qk, u) + ν[d(qk, Eqk) + d(u,Eu)] = (1 + µ)d(qk, u) + νd(u,Eu); hence d(u,Eu) ≤ 1 + µ 1− ν d(qk, u) (25) As µ ∈ [0, 1) and µ + 2ν < 1, that is, ν < 1 and since {qk} → u as k → ∞, therefore limk→∞ d(qk, u) = 0. From (25), we get u ∈ Fix(E) as desired. Next, we show that Fix(E) is convex. Let q, p ∈ Fix(E) and α ∈ [0, 1]. For any z ∈ J , assume that z = η(q, p, α). Now we show that z ∈ Fix(E), that is, z = Ez or E(η(q, p, α)) = η(q, p, α). Thus d(q, Ez) = d(Eq,Ez) ≤ µd(q, z) + ν[d(q, Eq) + d(z, Ez)]. ≤ µd(q, z) + ν[d(z, q) + d(q, Ez)]. ≤ (µ+ ν)d(q, z) + νd(q, Ez). Hence d(q, Ez) ≤ (µ+ ν) 1− ν d(q, z) ≤ d(q, z). (26) Similarly, d(p,Ez) ≤ d(p, z). (27) Using (26), (27) and (η1), we get d(q, p) ≤ d(q, Ez) + d(Ez, p). ≤ d(q, z) + d(z, p). ≤ d(q, η(q, p, α)) + d(η(q, p, α), p) ≤ (1− α)d(q, q) + αd(q, p) + (1− α)d(q, p) + d(p, p) A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 15 of 23 = d(p, q) Thus, we conclude by (26)) and (27) that d(q, Ez) = d(q, z) and d(p,Ez) = d(p, z) because if d(q, Ez) < d(q, z) or d(p,Ez) < d(p, z), then we will obtain a contradiction d(p, q) < d(p, q). Hence Ez = z, that is, Eη((q, p, α)) = η(q, p, α) for all q, p ∈ Fix(E) and α ∈ [0, 1]. Therefore Fix(E) is convex. Based on Lemma 5, we introduce the contractive condition for self-mappings Tλ and Sλ on Q as follows: d(Tλx, Sλy) ≤ M(d(x, y)) +K{d(x, Tλx) + d(y, Sλy)} (28) where 0 ≤ M < 1, 1 < K < ∞ and M + 2K ≤ 1. An extension of Theorem 2, is obtained by replacing the maps E and F on a metric space with their, respective, average mappings, in the context of a convex metric space, as follows. Theorem 7. Let (Q, d,W ) be a complete convex metric space. Assume that Tλ and Sλ are asymptotically regular self-mappings on Q satisfying (28). If Tλ and Sλ are orbitally continuous or k-continuous for some k ≥ 1, then Tλ and Sλ have a unique common fixed point p. Furthermore, limn→∞ Tn λ x = p = limn→∞ Sn λx for any x ∈ Q. Proof. Step 1: We note that the Picard iterations of Tλ and Sλ form the Krasnoselskij iterative sequence {xn}∞n=0 defined by xn+1 = Tλxn = (1− µ)xn + µTλxn and xn = Sλxn−1 n = 0, 1, 2, · · · (29) Using (28), we get d(xn+1, xn) ≤ Md(xn, xn−1) +K{d(xn, xn+1) + d(xn−1, xn)}; thus d(xn+1, xn) ≤ (M +K) 1−K d(xn, xn−1) d(xn+1, xn) ≤ αd(xn, xn−1), ( α := M +K 1−K ) , (30) which inductively implies that d(Tn+1 λ x, Sn λx) = d(xn+1, xn) ≤ αnd(x1, x0). (31) This implies d(Tn+1 λ x, Sn λx) → 0 as n → ∞. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 16 of 23 Step 2: We now prove that {xn}∞n=0 is a Cauchy sequence. Suppose on contrary that {xn}∞n=0 is not a Cauchy sequence. Then there exisst ϵ > 0 and sequences of numbers {m(k)} and {n(k)} with m(k) > n(k) > k for k = 1, 2, 3, · · · such that d(T m(k) λ , T n(k) λ ) ≥ ϵ. (32) Assume that m(k) ≥ n(k). So by (31), we have d(T m(k)−1 λ x, T n(k) λ x) < ϵ. Hence ϵ ≤ d(T m(k) λ x, T n(k) λ x) ≤ d(T n(k) λ x, T n(k)−1 λ x) + d(T m(k)−1 λ x, T n(k) λ x) < d(T m(k) λ x, T m(k)−1 λ x) + ϵ. (33) Letting k → ∞ and using asymptotically regularity of Tλ, we get lim k→∞ d(T m(k) λ x, T n(k) λ x) = ϵ. Now the following inequality and asymptotic regularity of Tλ d(T m(k)−1 λ x, T n(k)−1 λ x) ≤ d(T m(k)−1 λ x, T m(k) λ x) + d(T m(k) λ x, T m(k) λ x) +d(T n(k) λ x, T n(k)−1 λ x) imply lim k→∞ d(T m(k)−1 λ x, T n(k)−1 λ x) = ϵ. From (29), we get d(T m(k) λ x, T n(k) λ x) ≤ d(T m(k) λ x, S n(k) λ x) + d(S n(k) λ x, T n(k) λ x) and d(T m(k) λ x, T n(k) λ x) ≤ d(S n(k) λ x, T n(k) λ x) +Md(T m(k)−1 λ x, T n(k)−1 λ x) +K[d(T m(k)−1 λ x, T m(k) λ x) + d(S n(k)−1 λ x, S n(k) λ x)] +Md(T n(k)−1 λ x, S n(k)−1 λ x). Letting k → ∞, it follows by (30) (32) and (33) that ϵ ≤ Mϵ. This is a contradiction. Therefore {xn} is a Cauchy sequence. Given that Q is complete, {xn} converges to p ∈ Q. Moreover, d(Sn λx, p) ≤ d(Sn λx, T n λ x) + d(Tn λ x, p), so it follows from Step 1 that Tn λ x and Sn λx converge to p ∈ Q. A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 17 of 23 Step 3: Tλ and Sλ have a unique common fixed point p. Let Tλ be k-continuous. Since limn→∞ Tn−1 λ x = p. So by k-continuity of Tλ, limn→∞ Tn λ x = Tλp. By uniqueness of limit , Tλp = p. Analogically, suppose that Tλ is orbital continuous . Since limn→∞ xn = p, orbital conti- nuity of Tλ implies that lim n→∞ Tλxn = Tλp. This yield Tλp = p. Similarly, limn→∞ Sn λx = p, we have that Sp = p. Hence p ∈ Fix(Tλ) ∩ Fix(Sλ). Uniqueness: Assume that p, q ∈ Fix(Tλ) ⋂ Fix(Sλ) and q1 ̸= p. Let x = p and y = q1. Then (28) becomes d(p, q1) ≤ Md(p, q1). It is a contradiction. Hence p is a unique common fixed point of Tλ and Sλ. In the light of Lemma 5, we define Zemfirescue mapping in terms of Tλ: Definition 3. Let (Q, d,W ) be a complete convex metric space and Tλ : Q → Q satisfies the following conditions. (i) d(Tλx, Tλy) ≤ ad(x, y), 0 < a < 1, (ii) d(Tλx, Tλy) ≤ b ( (d(x, Tλx) + d(y, Tλy) ) , 0 < b < 1 2 (iii) d(Tλx, Tλy) ≤ c ( d(x, Tλy) + d(y, Tλx) ) , 0 < c < 1 2 . An analogue of Theorem 1 by Zamfiresuc [22] for the mapping Tλ is presented below. Theorem 8. Let (Q, d,W ) be a complete convex metric space and Tλ : Q → Q be Zam- firescue asymptotically regular map. Then, (i) Fix(Tλ) = {p}, and (ii) the sequence {xn}∞n=0 obtained from the iterative process xn+1 = W (xn, Tλxn;λ), n ≥ 0 converges to p, for x0 ∈ Q. Proof. We note that the Picard iterations of Tλ actually form the Kranoselskij iterative process {xn}∞n=0. Now, choose x0 ∈ Q arbitrarily and fix integer n ≥ 0. Consider x = Tn λ x0 and y = Tn+1 λ x0, we obtain by Definition 3(i), with δ < 1 d(Tn+1 λ x0, T n+2 λ x0) ≤ δd(Tn λ x0, T n+1 λ x0) and by Definition 3(ii) d(Tn+1 λ x0, T n+2 λ x0) ≤ b ( d(Tn λ x0, T n+1 λ x0) + d(Tn+1 λ x0, T n+2 λ x0) ) which implies d(Tn+1 λ x0, T n+2 λ x0) ≤ b 1− b d(Tn λ x0, T n+1 λ x0). A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 18 of 23 Thus d(Tn+1 λ x0, T n+2 λ x0) ≤ δd(Tn λ x0, T n+1 λ x0) where δ := b 1− b . Similarly, with condition (iii) of Definition 3, we obtain d(Tn+1 λ x0, T n+2 λ x0) ≤ c ( d(Tn λ x0, T n+2 λ x0) + d(Tn+1 λ x0, T n+1 λ x0) ) . Hence d(Tn+1 λ x0, T n+2 λ x0) ≤ δd(Tn λ x0, T n+1 λ x0). This inequality is true for every n. So that {Tn λ (x0)}∞n=0 is a Cauchy sequence and therefore converges to some point p ∈ Q. (i) We now prove that p is a fixed point of Tλ. Suppose Tλp ̸= p. We consider the ball B = {p ∈ Q : d(p, x) ≤ 1 4 d(p, Tλp)}. Observe that d(x, Tλp) ≥ 3 4d(p, Tλp) for every point p ∈ B. So there exists a number N such that Tn λ x0 ∈ B for each n ≥ N . Now taking x = TN λ x0 and y = p. We must have one of the following situations: (a) d(Tn+1 λ x0, Tλp) ≤ ad(TN λ x0, p), which sets a contradiction as follows d(Tn λ x0, p) ≤ 1 4 d(p, Tλp) < d(Tn+1 λ x0, Tλp), (b) d(Tn λ x0, Tλp) ≤ b ( d(Tn λ x0, T n+1 λ x0) + d(p, Tλp) ) , contradicting b ( d(Tn λ x0, T n+1 λ x0) + d(p, Tλp) ) < 1 2 (d(Tn λ x, p) + d(p, Tn+1 λ x0) + d(p, Tλp)) ≤ 3 4 d(p, Tλp) ≤ d(Tn+1 λ x0, Tλp) (c) d(Tn+1 λ x0, Tλp) ≤ c ( d(Tn λ x0, Tλ(p)) + d(Tn+1 λ x0, p) ) contradicting c ( d(Tn λ x0, Tλ(p)) + d(Tn+1 λ x0, p) ) < 1 2 (d(Tn λ x0, p) + d(p, Tλp) + d(Tn+1 λ x0, p)) ≤ 3 4 d(p, Tλ, p) ≤ d(Tn+1 λ x0, Tλp) Thus Tλp = p. Now we show that this fixed point p is unique. Suppose that this is not true . Let Tλp ′ = p ′ for some point p ′ ̸= p ∈ Q. Then d(Tλp, Tλp ′ ) = d(p, p ′ ) A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 19 of 23 d(Tλp, Tλp ′ ) > d(p, Tλp) + d(p ′ , Tλp ′ ) d(Tλp, Tλp ′ ) = 1 2 (d(p, Tλp ′ ) + d(p ′ , Tλ(p))) So that none of the three conditions of Zamfirescue map is satisfied by the points p and p ′ . This is a contradiction. Hence Tλ has a unique fixed point. (ii) Obvious. It is natural to ask, when the assumption that Tλ is asymptotically regular in Theorem 7, is satisfied. For an affirmative answer to this question, we need the following useful result. Theorem 9. [9, Theorem 5.2.7] Let J be a nonempty convex subset of a normed space Q and T be non-expansive map on J . If for x0 ∈ J, {Tn λ x0} is bounded, then the average map Tλ is asymptotically regular at x0. For the existence of fixed points, apart from the other conditions, Huang and Qian ([14, Theorem 2.5]) have imposed continuity condition on the mappings already satisfying con- tractive condition similar to (1). In the result to follow, we employ weak requirement of nonexpansiveness to get nonexpansive version of Górnicki result for the average mapping. Theorem 10. Let J be a nonempty convex subset of a normed space Q and T : J → J be non-expansive map satisfying (1). If for x0 ∈ J, {Tn λ x0} is bounded, then Tλ has a unique fixed point p ∈ Q. Moreover, {xn}∞n=0, the Krasnoselskij iterative sequence converges to p. Proof. The map Tλ is asymptotically regular at x0 by Theorem 9. Now the rest of the proof is similar to that of Theorem 1. Remark 1. (1) Theorem 2.5 of Khan and Oyetuabi [7], holds in a convex metric space with the same proof. (2) Theorem 10 provides a non-expansive version of Theorem 1 with a very simple proof. 4. Application: Volterra-Type Integral Equations In this section, we investigate the existence and uniqueness of the common solution of Volterra-type integral equations, utilizing the common fixed point result established in Theorem 4. Volterra-type integral equations play a significant role in various fields, including physics, biology, and engineering, in view of their capability to model systems with memory effects. These equations are crucial for capturing the dynamics of processes where the future state A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 20 of 23 depends on the entire history of the system, such as in viscoelastic materials, population dynamics, and heat conduction. The importance of Volterra-type integral equations lies in their ability to provide insights into the existence and uniqueness of solutions to com- plex mathematical problems. By applying fixed point theorems, researchers can establish stability and convergence of these solutions; thereby addressing fundamental challenges in both theoretical and applied mathematics. The reader interested in this matter, is referred to the recent literature developed in [23–25]. Let Q be the space of continuous functions on [0, T ] equipped with the supremum norm. That is, Q := {u : [0, T ] → R : u is continuous}. Define a metric d : Q×Q → R+ by d(u, v) = ||u− v||∞ = sup t∈[0,T ] |u(t)− v(t)|, u, v ∈ Q. Then (Q, d) is a complete metric space. We consider the following Volterra-type integral equations formulated as a common fixed point problem of the following nonlinear mappings: u(t) = ∫ t 0 K1(t, s, u(s))ds (34) v(t) = ∫ t 0 K2(t, s, v(s))ds (35) for all t, s ∈ [0, T ], where the kernels K1(t, s, u(s)) and K2(t, s, v(s)) are known function. We will find the solution of (34) and (35). Now, we prove the following theorem to ensure the existence of common solution of the integral equations (34) and (35). Theorem 11. Assume that the following conditions are satisfied: (a) K1,K2 : [0, T ]× [0, T ]×Q → R+, (b) define the mappings E and F as follows: (Eu)(t) = ∫ t 0 K1(t, s, u(s))ds (36) (Fv)(t) = ∫ t 0 K2(t, s, v(s))ds. (37) Assume further that A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 21 of 23 (i) there exists a continuous functions τ : [0, T ] × [0, T ] → R+ and a continuous and nondecreasing function α : R+ → R+ such that α(0) = 0 and α(t) < t for t > 0 satisfying ∣∣∣K1(t, s, u(s))−K2(t, s, v(s)) ∣∣∣ ≤ τ(t, s)α(|u− v|) for t, s ∈ [0, T ] and u(s), v(s) ∈ Q. (ii) sup t∈[0,T ] ∫ t 0 τ(t, s)ds ≤ ω, for some ω ∈ (0, 1). Then E and F have a unique common solution. Proof. Let u, v ∈ Q. By assumptions (i) and (ii), we have d(Eu,Fv) = ||Eu− Fv||∞ = sup t∈[0,T ] |(Eu)(t)− (Fv)(t)| = sup t∈[0,T ] ∣∣∣ ∫ t 0 K1(t, s, u(s))ds− ∫ t 0 K2(t, s, v(s))ds ∣∣∣ = sup t∈[0,T ] ∣∣∣ ∫ t 0 ( K1(t, s, u(s))−K2(t, s, v(s)) ) ds ∣∣∣ ≤ sup t∈[0,T ] ∫ t 0 ∣∣∣K1(t, s, u(s))−K2(t, s, v(s)) ∣∣∣ds ≤ sup t∈[0,T ] ∫ t 0 τ(t, s)α(|u− v|)ds ≤ sup t∈[0,T ] ∫ t 0 τ(t, s)|u− v|ds ≤ ||u− v||∞ sup t∈[0,T ] ∫ t 0 τ(t, s)ds ≤ ω||u− v||∞ = ω ( ||u− v + (E(u)− u)− (E(u)− u) + (v − F (v))− (v − F (v))||∞ ) ≤ ω ( 2||u− v||∞|+ ||u− E(u)||∞ + ||v − F (v)||∞ + ||E(u)− F (v)||∞ ) ; thus d(Eu,Fv) ≤ 2ω 1− ω d(u, v) + ω 1− ω ( d(u,Eu) + d(v, Fv) ) Letting κ(d(u, v)) := 2ω 1−ω , it follows that the mappings E and F satisfy (3). Hence by Theorem 4, there exists a unique common fixed point of E and F which is the common solution of the Voterra-type integral equations (34) and (35). A. R. Khan et al. / Eur. J. Pure Appl. Math, 18 (2) (2025), 5826 22 of 23 5. Conclusions We have extended the existing body of knowledge on fixed point theory for asymptotically regular mappings on a metric space by proving new common fixed point results on convex metric spaces. Our work verifies that under certain contractive conditions, asymptotically regular self-mappings not only possess unique fixed points but also exhibit properties of closedness and convexity for their fixed point sets. We have also demonstrated that replacing standard mappings with their average mappings in a convex metric space context retains their fixed point properties. Furthermore, we have applied our theoretical findings to solve integral equations, showcasing the practical utility of our theorems in real-world problems. These results are pivotal in advancing the understanding of fixed point theory in more general and complex spaces, offering new avenues for future research and applications in various mathematical and practical fields. Looking ahead, several interesting directions arise for future exploration: (i) Establishing an analogue of Theorem 5 in a convex metric space. (ii) Finding an analogue of Theorem 6 for a quasi-nonexpansive map. (iii) Addressing the question posed before Theorem 9 in the context of a convex metric space. Acknowledgements The authors G. C. Ugwunnadi and M. Aphane are grateful to Department of Math- ematics and Applied Mathematics, Sefako Makgato Health Science University, Pretoria 0204, South Africa for supporting this research work. References [1] N. Hussain, S M Alsulami, and H Alamri. Solving fractional diffenerential equations via fixed points of chatterjea maps. Computer Modeling Engr. Sc., 135:2617–2648, 2023. [2] J Górnicki. Remarks on asymptotic regularity and fixed points. J. Fixed Point Theory Appl., 21:29, 2019. [3] S Reich. Some remarks concerning contration mappings. Canada. Math. Bull., 14:121– 165, 1971. [4] R K Bisht. A note on fixed point theorem of górnicki. J. 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