EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS 2025, Vol. 18, Issue 3, Article Number 6173 ISSN 1307-5543 – ejpam.com Published by New York Business Global Inertial Iterative Method for Generalized Mixed Equilibrium Problem and Fixed Point Problem Vahid Darvish1, Grace Nnennaya Ogwo2,∗, Olawale Kazeem Oyewole3,4, Hammed Anuoluwapo Abass5,6, Amirbek Aminovich Ikramov6 1 Department of Mathematics and Statistics, Nanjing University of Information Science and Technology, Nanjing China 2 School of Mathematical Sciences, Zhejiang Normal University, Jinhua 321004, China 3 Department of Mathematics and Statistics, Tshwane University of Technology, PMB 007, Arcadia, Pretoria, South Africa 4 Department of Mathematics, Saveetha School of Engineering, Saveetha Institute of Medical and Technical Sciences, Saveetha University, Chennai 602 105, Tamil Nadu, India 5 Department of Mathematics and Applied Mathematics, Sefako Makgato Health Science University, P.O. Box 94, Pretoria 0204, South Africa 6Center of Research and Innovation, Asia International University, Yangiobod MFY, G‘ijduvon Street, House 74, Bukhara, Uzbekistan Abstract. In this paper, we study the generalized mixed equilibrium problem and the fixed point problem. We propose an inertial iterative method for approximating the common solution of a generalized mixed equilibrium problem of a monotone mapping and a fixed point problem for a Bregman strongly nonexpansive mapping in the framework of real reflexive Banach spaces. Under certain mild conditions, we obtain a strong convergence result of the proposed method. Finally, we present numerical examples to illustrate the applicability of our method. 2020 Mathematics Subject Classifications: 47H05, 47H09, 47J05, 49J25 Key Words and Phrases: Generalized mixed equilibrium problem, fixed point problem, inertial technique, Bregman strongly nonexpansive mapping 1. Introduction Let E be a real reflexive Banach space and E∗ be its dual space. Let C be a nonempty, closed and convex subset of E, Θ : C × C → R a bifunction, Ψ : C → E∗ a nonlinear ∗Corresponding author. DOI: https://doi.org/10.29020/nybg.ejpam.v18i3.6173 Email addresses: vahid.darvish@mail.com, vdarvish@nuist.edu.cn (V. Darvish), graceogwo@zjnu.edu.cn (G. N. Ogwo), oyewoleolawalekazeem@gmail.com (O. K. Oyewole), hammedabass548@gmail.com,hammed.abass@smu.ac.za (H. A. Abass), amirbekikramov@oxu.uz (A. A. Ikramov) https://www.ejpam.com 1 Copyright: © 2025 The Author(s). (CC BY-NC 4.0) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 2 of 32 mapping and φ : C → R a real valued function. The generalized mixed equilibrium problem (GMEP) is defined as follows: Find x ∈ C such that Θ(x, y) + ⟨Ψx, y − x⟩+ φ(y) ≥ φ(x), for all y ∈ C. (1.1) The set of solutions of (1.1) is denoted by GMEP(Θ,Ψ, φ), that is GMEP(Θ,Ψ, φ) = {x ∈ C : Θ(x, y) + ⟨Ψx, y − x⟩+ φ(y) ≥ φ(x), for all y ∈ C}. In particular, if Ψ ≡ 0, the problem (1.1) is reduced to the mixed equilibrium problem (MEP) [1] defined as follows: Find x ∈ C such that Θ(x, y) + φ(y) ≥ φ(x), for all y ∈ C. (1.2) The set of solutions of (1.2) is denoted by MEP (Θ, φ). If φ ≡ 0, the problem (1.1) is reduced to the generalized equilibrium problem (GEP) [2] defined as follows: Find x ∈ C such that Θ(x, y) + ⟨Ψx, y − x⟩ ≥ 0, for all y ∈ C. (1.3) The set of solution (1.3) is denoted by GEP (Θ,Ψ). If Θ ≡ 0, the problem (1.1) is reduced to the mixed variational inequality of Browder type (MVI) [3] defined as follows: Find x ∈ C such that ⟨Ψx, y − x⟩+ φ(y) ≥ φ(x), for all y ∈ C. (1.4) The set of solution of (1.4) is denoted by MV I(φ,Ψ). If Ψ ≡ 0 and φ ≡ 0, the problem (1.1) is reduced to the equilibrium problem (EP) [4] for finding x ∈ C such that Θ(x, y) ≥ 0, for all y ∈ C. (1.5) The set of solutions of (1.5) is denoted by EP (Θ). We observe that (1.1) generalizes (1.2)-(1.5). The equilibrium problem was introduced by Blum and Oettli [4] and Noor and Oettli [5] in 1994, and has had a great impact and influence in the development of several branches of pure and applied sciences. It has been shown that equilibrium problem theory provides a novel and unified treatment of a wide class of problems that arise in economics, finance, image reconstruction, ecology, transportation, networks, elasticity, and optimization. The EP was shown in [4] to cover monotone inclusion problems, saddle point problems, vari- ational inequality problems, minimization problems, optimization problems, variational inequality problems, vector equilibrium problems, Nash equilibrium problems in noncoop- erative games. Some methods have been proposed to solve the equilibrium problem. These methods include the penalty and gap functions, regularization, extragradient methods and splitting methods (see [6–10] and other references therein). For solving the generalized mixed equilibrium problem, let us assume that the bifunction Θ : C × C → R satisfies the following conditions: V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 3 of 32 (Q1) Θ(x, x) = 0 for all x ∈ C; (Q2) Θ is monotone, i.e., Θ(x, y) + Θ(y, x) ≤ 0 for any x, y ∈ C; (Q3) for each y ∈ C, x 7→ Θ(x, y) is upper-hemicontinuous, i.e., for each x, y, z ∈ C, lim sup t↘0 Θ(tz + (1− t)x, y) ≤ Θ(x, y); (Q4) for each x ∈ C, y 7→ Θ(x, y) is convex and lower semicontinuous (see [11]). Several authors have studied and proposed various iterative methods for studying (1.1). Tuyen [12] introduced a hybrid projection method for solving systems of GMEP in a reflexive Banach space and defined it as follows: yin = ResfΘi,Ψi,φi xn, i = 1, 2, · · · , N in := argmaxi=1,2··· ,N{Df (y i n, xn)}, ȳn = yinn Cn := {z ∈ E : Df (z, ȳn ≤ Df (z, xn))} Qn := {z ∈ E : ⟨∇f(x0)−∇f(xn), z − xn⟩ ≤ 0} xn+1 = ProjCn∩Qn (x0), n ≥ 0. The author obtained a strong convergence result of the proposed method. The limitation OF this method is the fact that it requires the computation of subsets of Cn and Qn which can be computationally expensive. On the other hand, another problem of interest is the fixed point problem (FPP). Let T : C → C be a nonlinear mapping. A point x ∈ C is a fixed point of T if Tx = x. Let F (T ) denote the set of fixed points, that is F (T ) = {x ∈ C : Tx = x}. Many problems in sciences and engineering can be transformed into a problem of finding the solution of a fixed point problem (FPP) of a nonlinear mapping. For more information on fixed point see [13–17]. Moudafi [18] introduced the viscosity approximation method for a nonexpansive mapping T and defined it as follows: xn+1 = αnf(xn) + (1− αn)Txn, n ≥ 1, where {αn} ⊂ (0, 1) and f is a contraction mapping. Recently, several authors have studied iterative algorithms for finding a common solution of the FFP and GMEP. In particular, several authors have considered the following problem (see [19–21] and other references therein): Find x ∈ C such that x ∈ F (T ) ∩GMEP(Θ,Ψ, φ). The motivation for studying a common solution problem lies in its application to problems whose constraints can be reformulated as FPPs and GMEPs. For instance, in signal processing, network resource allocation, among others. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 4 of 32 Recently, Takahashi and Takahashi [22] introduced the following iterative scheme for solv- ing GEP and FPP of a nonexpansive mapping T in a Hilbert space. They defined the proposed method as follows: Find x1, z ∈ C and zn ∈ C such that Θ(zn, y) + ⟨Bxn, y − zn⟩+ 1 rn ⟨y − zn, zn − xn⟩ ≥ 0, y ∈ C xn+1 = βnxn + (1− βn)T [ αnz + (1− αn)zn ] , n ≥ 1 {αn} ⊂ (0, 1), {βn} ⊂ (0, 1), {rn} ⊂ (0,+∞) and B is an α-inverse strongly monotone mapping. The authors obtained a strong convergent result under certain conditions. Es- kandari and Raeisi [23] introduced an iterative method for approximating a common so- lution of FPP of Bregman quasi-nonexpansive mappings and zeros of maximal monotone operators. They defined the algorithm as follows: x1 ∈ E, zn = Resf λN n Bn ◦ . . . ◦Resf λ1 nB1 xn, yn = βn∇f(zn) + (1− βn)∇f(Tn(zn)), xn+1 = ∇f∗(αn∇f(qn) + (1− αn)yn), where {αn} ⊂ (0, 1). Under certain standard conditions, the authors obtained a strong convergence result. The ultimate aim of every researcher is to construct effective iterative methods with high convergence rates to the solutions of the optimization problem under consideration. To achieve this high rate of convergence, authors employ the inertial technique. Polyak [24] introduced the inertial extrapolation as an acceleration process to solve smooth convex minimization problems. It has been shown by several authors that the inertial term improves the performance of iterative algorithms numerically in terms of the number of iterations and CPU time. Several authors have studied and proposed iterative algorithms with the inertial technique for solving optimization problems (see to [25–27] and other references therein). Motivated by the above mentioned methods in the literature and the ongoing research in this area, we introduce a new inertial iterative method for approximating the solutions of a generalized mixed equilibrium problem with a maximal monotone mapping and fixed point of a Bregman strongly nonexpansive mapping in the framework of a reflexive Banach space. Our method does not require us to compute subsets of Cn and Qn. Under mild condition, we establish a strong convergence result for the proposed method. Finally, we present numerical examples to illustrate the applicability of our proposed method. The rest of the paper is organized as follows: In Section 2, we present some basic def- initions, concepts, lemmas, and results which will be required to obtain the convergence analysis of the proposed method. In Section 3, we present some required assumptions and introduce our proposed method. In Section 4, we present our convergence analysis. In Section 5, we present numerical experiments in comparisons with other related methods to illustrate the effectiveness of our proposed method. In Section 6, we present a brief summary of our result. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 5 of 32 2. Preliminaries Let f : E → (−∞,+∞] be a proper, lower semi-continuous and convex function. We denote by domf , the domain of f , that is the set {x ∈ E : f(x) < +∞}. For a sequence {xn} in E, we denote the strong and weak convergence of {xn} to x ∈ E by xn → x and xn ⇀ x, respectively. Let x ∈ int(domf), the subdifferential of f at x is the convex set defined by ∂f(x) = {x∗ ∈ E∗ : f(x) + ⟨x∗, y − x⟩ ≤ f(y), for all y ∈ E}, where the Fenchel conjugate of f is the function f∗ : E∗ → (−∞,+∞] defined by f∗(x∗) = sup{⟨x∗, x⟩ − f(x) : x ∈ E, x∗ ∈ E∗}. For any x ∈ int(domf), the right-hand derivative of f at x in the derivation y ∈ E is defined by f ′ (x, y) := lim t↘0 f(x+ ty)− f(x) t . The function f is called Gâteaux differentiable at x if limt↘0 f(x+ty)−f(x) t exists for all y ∈ E. In this case, f ′ (x, y) coincides with ∇f(x), the value of the gradient (∇f) of f at x. The function f is called Gâteaux differentiable if it is Gâteaux differentiable for any x ∈ int(domf) and f is called Fréchet differentiable at x if this limit is attain uniformly for all y which satisfies ∥y∥ = 1. The function f is uniformly Fréchet differentiable on a subset C of E if the limit is attained uniformly for any x ∈ C and ∥y∥ = 1. It is known that if f is Gâteaux differentiable (resp. Fréchet differentiable) on int(domf), then f is continuous and its Gâteaux derivative ∇f is norm-to-weak∗ continuous (resp. continuous) on int(domf) (see [28]). Let f : E → (−∞,+∞] be a Gâteaux differentiable function. The function Df : domf × int(domf) → [0,+∞) defined as follows: Df (x, y) := f(x)− f(y)− ⟨∇f(y), x− y⟩, for all x ∈ dom(f), y ∈ int(dom(f)) (2.1) is called the Bregman distance with respect to f , [29]. Remark 1. The Bregman distance has the following properties: (i) the three-point identity, for any x ∈ domf and y, z ∈ int(domf), Df (x, y) +Df (y, z)−Df (x, z) = ⟨∇f(z)−∇f(y), x− y⟩; (2.2) [30] (ii) the four-point identity, for any y, w ∈ domf and x, z ∈ int(domf), Df (y, x)−Df (y, z)−Df (w, x) +Df (w, z) = ⟨∇f(z)−∇f(x), y − w⟩. (2.3) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 6 of 32 Definition 1. A Gâteaux differentiable function f is said to be γ-strongly convex if there exists a constant γ > 0 such that f(x) ≥ f(y) + ⟨x− y,∇f(y)⟩+ γ 2 ∥x− y∥2, for all x ∈ dom(f), y ∈ int(dom(f)). Lemma 1. [31] Let f be a strongly convex function with constant γ > 0. Then for all y ∈ dom(f) and x ∈ int(dom(f)), we have: Df (x, y) ≥ γ 2 ∥x− y∥2, (2.4) where Df (x, y) is the Bregman distance with respect to f. The Legendre function f : E → (−∞,+∞] is defined in [32]. It is well known that in reflexive spaces, f is Legendre function if and only if it satisfies the following conditions: (L1) The interior of the domain of f , int(domf), is nonempty, f is Gâteaux differentiable on int(domf) and domf = int(domf); (L2) The interior of the domain of f∗, int(domf∗), is nonempty, f∗ is Gâteaux differentiable on int(domf∗) and domf∗ = int(domf∗). Since E is reflexive, we know that (∂f)−1 = ∂f∗ (see [28]). This , with (L1) and (L2), imply the following equalities: ∇f = (∇f∗)−1, ran∇f = dom∇f∗ = int(domf∗) and ran∇f∗ = dom(∇f) = int(domf), where ran∇f denotes the range of ∇f . When the subdifferential of f is single-valued, it coincides with the gradient ∂f = ∇f , [33]. By Bauschke et al. [32] the conditions (L1) and (L2) also yields that the function f and f∗ are strictly convex on the interior of their respective domains. If E is a smooth and strictly convex Banach space, then an important and interesting Legendre function is f(x) := 1 p∥x∥ p(1 < p < +∞). In this case the gradient ∇f of f coincides with the generalized duality mapping of E, i.e., ∇f = Jp(1 < p < +∞). In particular, ∇f = I, the identity mapping in Hilbert spaces. From now on we assume that the convex function f : E → (−∞,+∞] is Legendre. In connection with Legendre functions, see also the recent paper [34]. Definition 2. Let f : E → (−∞,+∞] be a convex and Gâteaux differentiable function. The Bregman projection of x ∈ int(domf) onto the nonempty, closed and convex subset C ⊂ domf is the necessary unique vector projfC(x) ∈ C satisfying Df (proj f C(x), x) = inf{Df (y, x) : y ∈ C}. Remark 2. If E is a smooth and strictly convex Banach space and f(x) = ∥x∥2 for all x ∈ E, then we have that ∇f(x) = 2Jx for all x ∈ E, where J is the normalized duality V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 7 of 32 mapping from E in to 2E ∗ , and hence Df (x, y) reduced to ϕ(x, y) = ∥x∥2−2⟨x, Jy⟩+∥y∥2, for all x, y ∈ E, which is the Lyapunov function introduced by Alber [35] and Bregman projection P f C(x) reduces to the generalized projection ΠC(x) which is defined by ϕ(ΠC(x), x) = min y∈C ϕ(y, x). If E = H, a Hilbert space, J is the identity mapping and hence Bregman projection P f C(x) reduced to the metric projection of H onto C, PC(x). Definition 3. [36, 37] Let f : E → (−∞,+∞] be a convex and Gâteaux differentiable function. f is called: (i) totally convex at x ∈ int(domf) if its modulus of total convexity at x, that is, the function νf : int(domf)× [0,+∞) → [0,+∞) defined by νf (x, t) := inf{Df (y, x) : y ∈ domf, ∥y − x∥ = t}, is positive whenever t > 0; (ii) totally convex if it is totally convex at every point x ∈ int(domf); (iii) totally convex on bounded sets if νf (B, t) is positive for any nonempty bounded subset B of E and t > 0, where the modulus of total convexity of the function f on the set B is the function νf : int(domf)× [0,+∞) → [0,+∞) defined by νf (B, t) := inf{νf (x, t) : x ∈ B ∩ domf}. The set levf≤(r) = {x ∈ E : f(x) ≤ r} for some r ∈ R is called a sublevel of f . Definition 4. [37, 38] The function f : E → (−∞,+∞] is called; (i) cofinite if domf∗ = E∗; (ii) coercive [39] if the sublevel set of f is bounded; equivalently, lim ∥x∥→+∞ f(x) = +∞; (iii) strongly coercive if lim∥x∥→+∞ f(x) ∥x∥ = +∞; (iv) sequentially consistent if for any two sequences {xn} and {yn} in E such that {xn} is bounded, lim n→+∞ Df (yn, xn) = 0 ⇒ lim n→+∞ ∥yn − xn∥ = 0. Lemma 2. [40] The function f is totally convex on bounded subsets if and only if it is sequentially consistent. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 8 of 32 Lemma 3. [38, Proposition 2.3] If f : E → (−∞,+∞] is Fréchet differentiable and totally convex, then f is cofinite. Lemma 4. [40] Let f : E → (−∞,+∞] be a convex function whose domain contains at least two points.Then the following statements hold: (i) f is sequentially consistent if and only if it is totally convex on bounded sets; (ii) If f is lower semicontinuous, then f is sequentially consistent if and only if it is uniformly convex on bounded sets; (iii) If f is uniformly strictly convex on bounded sets, then it is sequentially consistent and the converse implication holds when f is lower semicontinuous, Fréchet differentiable on its domain and Fréchet derivative ∇f is uniformly continuous on bounded sets. Lemma 5. [41, Proposition 2.1] Let f : E → R be uniformly Fréchet differentiable and bounded on bounded subsets of E. Then ∇f is uniformly continuous on bounded subsets of E from the strong topology of E to the strong topology of E∗. Lemma 6. [38, Lemma 3.1] Let f : E → R be a Gâteaux differentiable and totally convex function. If x0 ∈ E and the sequence {Df (xn, x0)} is bounded, then the sequence {xn} is also bounded. A mapping T is said to be nonexpansive if ∥Tx − Ty∥ ≤ ∥x − y∥ for all x, y ∈ C. T is said to be quasi-nonexpansive if F (T ) ̸= ∅ and ∥Tx − p∥ ≤ ∥x − p∥, for all x ∈ C and p ∈ F (T ). A point p ∈ C is called an asymptotic fixed point of T (see [42]) if C contains a sequence {xn} which converges weakly to p such that limn→+∞ ∥xn − Txn∥ = 0. We denote by F̂ (T ) the set of asymptotic fixed points of T . A mapping T : C → int(domf) with F (T ) ̸= ∅ is called: (i) quasi-Bregman nonexpansive [38] with respect to f if Df (p, Tx) ≤ Df (p, x), for all x ∈ C, p ∈ F (T ). (ii) Bregman relatively nonexpansive [38, 43] with respect to f if, Df (p, Tx) ≤ Df (p, x), for all x ∈ C, p ∈ F (T ), and F̂ (T ) = F (T ). (iii) Bregman strongly nonexpansive (see [38, 44]) with respect to f and F̂ (T ) if, Df (p, Tx) ≤ Df (p, x), for all x ∈ C, p ∈ F̂ (T ) and, if whenever {xn} ⊂ C is bounded, p ∈ F̂ (T ), and lim z→+∞ (Df (p, xn)−Df (p, Txn)) = 0, it follows that lim n→+∞ Df (xn, Txn) = 0. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 9 of 32 (iv) Bregman firmly nonexpansive (for short BFNE [45]) with respect to f if, for all x, y ∈ C, ⟨∇f(Tx)−∇f(Ty), Tx− Ty⟩ ≤ ⟨∇f(x)−∇f(y), Tx− Ty⟩ equivalently, Df (Tx, Ty)+Df (Ty, Tx)+Df (Tx, x)+Df (Ty, y) ≤ Df (Tx, y)+Df (Ty, x). (2.5) The existence and approximation of Bregman firmly nonexpansive mappings was studied in [42]. It is also known that if T is Bregman firmly nonexpansive and f is Legendre function which is bounded, uniformly Fréchet differentiable and totally convex on bounded subset of E, then F (T ) = F̂ (T ) and F (T ) is closed and convex. It also follows that every Bregman firmly nonexpansive mapping is Bregman strongly nonexpansive with respect to F (T ) = F̂ (T ). Lemma 7. [40] Let C be a nonempty, closed and convex subset of E. Let f : E → R be a Gâteaux differentiable and totally convex function. Let x ∈ E, then 1) z = projfC(x) if and only if ⟨∇f(x)−∇f(z), y − z⟩ ≤ 0, for all y ∈ C. 2) Df (y, proj f C(x)) +Df (proj f C(x), x) ≤ Df (y, x), for all x ∈ E, y ∈ C. Let f : E → R be a convex, Legendre and Gâteaux differentiable function. Following [35] and [29], we make use of the function Vf : E × E∗ → [0,+∞) associated with f , which is defined by Vf (x, x ∗) = f(x)− ⟨x∗, x⟩+ f∗(x∗), for all x ∈ E, x∗ ∈ E∗. (2.6) Then Vf is nonexpansive and Vf (x, x ∗) = Df (x,∇f∗(x∗)) for all x ∈ E and x∗ ∈ E∗. Moreover, by the subdifferential inequality, Vf (x, x ∗) + ⟨y∗,∇f∗(x∗)− x⟩ ≤ Vf (x, x ∗ + y∗) (2.7) for all x ∈ E and x∗, y∗ ∈ E∗ [46]. In addition, if f : E → (−∞,+∞] is a proper lower semicontinuous function, then f∗ : E∗ → (−∞,+∞] is a proper weak∗ lower semicontinu- ous and convex function (see [47]). Hence, Vf is convex in the second variable. Thus, for all z ∈ E, Df ( z,∇f∗ ( N∑ i=1 ti∇f(xi) )) ≤ N∑ i=1 tiDf (z, xi), (2.8) where {xi}Ni=1 ⊂ E and {ti}Ni=1 ⊂ (0, 1) with ∑N i=1 ti = 1. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 10 of 32 Definition 5. Let Br = {x ∈ E : ∥x∥ ≤ r} for all r > 0. Then a function g : E −→ R is said to be uniformly convex on bounded sets of E [48] if ρr(t) > 0 for all r, t > 0 where ρr : [0,+∞) −→ [0,+∞] is defined by ρr(t) = inf x,y∈Br,∥x−y∥=t,α∈(0,1) αg(x) + (1− α)g(y)− g[αx+ (1− α)y] α(1− α) for all t > 0. The function ρr is called the gauge of uniform convexity of g. The function g is said to be uniformly convex if the function δg : [0,+∞) −→ [0,+∞], defined by δg(t) = sup ∥x−y∥=t { 1 2 g(x) + 1 2 g(y)− g ( x+ y 2 )} satisfies that limt↓0 δg(t) t = 0. Lemma 8. [49] Let C be a nonempty, closed and convex subset of int(domf) and T : C → C be a quasi-Bregman nonexpansive mappings with respect to f . Then F (T ) is closed and convex. Definition 6. Let C be a nonempty, closed and convex subsets of a real reflexive Banach space and let φ be a lower semicontinuous and convex functional from C to R and Ψ : C → E∗ be a continuous monotone mapping. Let Θ : C × C → R be a bifunctional satisfying (A1)-(A4). The mixed resolvent of Θ is the operator ResfΘ,φ,Ψ : E → 2C ResfΘ,φ,Ψ(x) = {z ∈ C : Θ(z, y) + φ(y) + ⟨Ψz, y − z⟩+ ⟨∇f(z)−∇f(x), y − z⟩ ≥ φ(z), for all y ∈ C}. (2.9) Lemma 9. [50] Let f : E → (−∞,+∞] be a coercive and Gâteaux differentiable function. Let C be a closed and convex subset of E. Assume that φ : C → R be a lower semicon- tinuous and convex functional, Ψ : C → E∗ be a continuous monotone mapping and the bifunctional Θ : C × C → R satisfies conditions (A1)-(A4), then dom(ResfΘ,φ,Ψ) = E. Lemma 10. [50] Let f : E → (−∞,+∞] be a Legendre function. Let C be a closed and convex subset of E. If the bifunction Θ : C × C → R satisfies conditions (A1)-(A4), then (i) ResfΘ,φ,Ψ is single-valued; (ii) ResfΘ,φ,Ψ is a BFNE operator; (iii) F ( ResfΘ,φ,Ψ ) = GMEP(Θ, φ,Ψ); (iv) GMEP(Θ, φ,Ψ) is closed and convex; (v) Df ( p,ResfΘ,φ,Ψ(x) ) +Df ( ResfΘ,φ,Ψ(x), x ) ≤ Df (p, x), for all p ∈ F ( ResfΘ,φ,Ψ ) , x ∈ E. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 11 of 32 Let Θ : C × C → R be a bifunction and define the mapping BΘ : E → 2E ∗ in the following way: BΘ(x) :=  {x∗ ∈ E∗ : Θ(x, y) + φ(y) + ⟨Ψx, y − x⟩ ≥ ⟨x∗, y − x⟩+ φ(x) for all y ∈ C}, x ∈ C, ∅ x /∈ C. (2.10) Lemma 11. [51] Let E be a Banach space and f : ER be a Gâteaux differentiable function which is uniformly convex on bounded subsets of E. Suppose that {xn} and {yn} are two sequenecs in E. Then, lim n→+∞ Df (xn, yn) = 0 if and only if lim n→+∞ ∥xn − yn∥ = 0. Lemma 12. [52] Let {an} be a sequence of nonnegative real numbers, {αn} be a sequence in (0, 1) with +∞∑ n=1 αn = +∞ and {bn} be a sequence of real numbers. Assume that an+1 ≤ (1− αn)an + αnbn, for all n ≥ 1. If lim sup k→+∞ bnk ≤ 0 for every subsequence {ank } of {an} satisfying lim inf k→+∞ (ank+1 − ank ) ≥ 0, then lim n→+∞ an = 0. 3. Main result In this section, we present the assumptions under which our convergence analysis will be obtained. Furthermore, we present our proposed algorithm. Assumption 3.1. Assumption A: (A1) E is a reflexive Banach space with dual E∗ and C is a nonempty, closed and convex subset of int(dom(f)). (A2) T : C → C is a Bregman strongly nonexpansive mapping such that F (T ) = F̂ (T ) and T is uniformly continuous. (A3) f : E → R is a super coercive Legendre function that is bounded, uniformly Fréchet differentiable and totally convex on bounded subsets of E. (A4) Bθj : E → 2E ∗ , j = 1, 2, . . . N is a maximal monotone mapping with dom(Bθj ) ⊂ C. (A5) The solution set Ω = F (T ) ∩ (⋂N j=1B −1 θj (0∗) ) ̸= ∅. Assumption B: (B1) Let {αn} and {βn} be sequences in [0, 1] satisfying the following lim n→+∞ βn = 0 and +∞∑ n=1 βn = +∞. 0 < lim inf n→+∞ αn ≤ lim sup n→+∞ αn < 1. (B2) Let θ > 0 and {ξn} be a positive sequence such that lim n→+∞ ξn βn = 0. (B3) Let {qn} ⊂ E such that lim n→+∞ qn = q ∈ E. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 12 of 32 Algorithm 3.2. Common solution of generalized mixed equilibrium problem and fixed point problem Step 0 : Let x0, x1 ∈ E be arbitrary initial points and set n = 1. Step 1: Given the (n − 1)th and nth iterates, choose θn such that 0 ≤ θn ≤ θ̂n with θ̂n defined by θ̂n = { min{θ, ξn ∥xn−xn−1∥}, If xn ̸= xn−1, θ, Otherwise. (3.1) Step 2: Compute wn = ∇f∗ (∇f(xn) + θn (∇f(xn−1)−∇f(xn))) zn = ResfBθN ◦ · · · ◦ ResfBθ1 (wn) yn = ∇f∗ (βn∇f (qn) + (1− βn)∇f (T (zn))) xn+1 = ∇f∗ (αn∇f (wn) + (1− αn)∇f (T (yn))) . Set n := n+ 1 and return to Step 1. Remark 3. The inertial technique used in step 1 of Algorithm 1 can be easily imple- mented since the value of ∥xn − xn−1∥ is known before choosing θn. We also note that the restrictive summability condition +∞∑ n=1 ∥xn − xn−1∥ < +∞ often used by several authors when constructing initial algorithms is dispensed with in our proposed algorithm. 4. Convergence Analysis First, we present some lemmas which will be needed in obtaining our convergence result. In the following lemma, we obtain some results for the maximal operator BΘ from the bifunction Θ. The main idea of the following lemma is from [53]. Lemma 13. Let f : E → (−∞,+∞] be a supercoercive, Legendre, Fréchet differentiable and totally convex function. Let C be a closed and convex subset of E and assume that the bifunction Θ : C × C → R satisfies conditions (A1)-(A4) and Ψ is monotone. Then (1) GMEP(Θ, φ,Ψ) = B−1 Θ (0∗); (2) BΘ is a maximal monotone mapping; (3) ResfΘ,φ,Ψ = ResfBΘ . Proof. (1) If x ∈ C then from the definition of the mapping BΘ (2.10) we have x ∈ B−1 Θ (0∗) ⇔ Θ(x, y)+φ(y)+ ⟨Ψx, y−x⟩ ≥ φ(x) for all y ∈ C ⇔ x ∈ GMEP(Θ, φ,Ψ). (2) We show that BΘ is monotone mapping. Let (x1, x ∗ 1) and (x2, x ∗ 2) belong to the graph of BΘ. By the definition of the mapping BΘ, we have Θ(x1, z) + φ(z) + ⟨Ψx1, z − x1⟩ ≥ ⟨x∗1, z − x1⟩+ φ(x1) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 13 of 32 and Θ(x2, z) + φ(z) + ⟨Ψx2, z − x2⟩ ≥ ⟨x∗2, z − x2⟩+ φ(x2) for any z ∈ C. In particular we have that Θ(x1, x2) + φ(x2) + ⟨Ψx1, x2 − x1⟩ ≥ ⟨x∗1, x2 − x1⟩+ φ(x1) (4.1) and Θ(x2, x1) + φ(x1) + ⟨Ψx2, x1 − x2⟩ ≥ ⟨x∗2, x1 − x2⟩+ φ(x2). (4.2) Adding equations (4.1) and (4.2) together, we obtain Θ(x1, x2) + Θ(x2, x1) + φ(x2) + φ(x1) + ⟨Ψx1, x2 − x1⟩+ ⟨Ψx2, x1 − x2⟩ ≥ ⟨x∗1, x2 − x1⟩+ ⟨x∗2, x1 − x2⟩+ φ(x1) + φ(x2). By (A2), it is equivalent to write 0 ≥ Θ(x1, x2) + Θ(x2, x1) + ⟨Ψx1 −Ψx2, x2 − x1⟩ ≥ ⟨x∗1 − x∗2, x2 − x1⟩. It means that ⟨x∗1 − x∗2, x1 − x2⟩ ≥ 0 which follows that BΘ is a monotone mapping. To show that BΘ is maximal monotone mapping, it is enough to show that ran(BΘ + ∇f) = E∗ ([54, Corollary 2.3]). Let x∗ ∈ E∗ from [55, Proposition 2.3] and [48, Theorem 3.5.10], we have that f is cofinite and therefore ran∇f = intdomf∗ = E∗ which follows that ∇f is surjective. So, there exists x ∈ E such that ∇f(x) = x∗. From Lemma 9 we know that dom(ResfΘ,φ,Ψ) = E and from the definition of ResfΘ,φ,Ψ we obtain Θ ( ResfΘ,φ,Ψ(x1), x2 ) + φ(x2) + ⟨Ψ(ResfΘ,φ,Ψ(x1)), x2 −ResfΘ,φ,Ψ(x1)⟩ +⟨∇f(ResfΘ,φ,Ψ(x1))−∇f(x1), x2 −ResfΘ,φ,Ψ(x1)⟩ ≥ φ(ResfΘ,φ,Ψ(x1)) for any x2 ∈ C. It follows that Θ ( ResfΘ,φ,Ψ(x1), x2 ) + φ(x2) + ⟨Ψ(ResfΘ,φ,Ψ(x1)), x2 −ResfΘ,φ,Ψ(x1)⟩ ≥ ⟨∇f(x1)−∇f(ResfΘ,φ,Ψ(x1)), x2 −ResfΘ,φ,Ψ(x1)⟩ +φ(ResfΘ,φ,Ψ(x1)) for any x2 ∈ C. This shows that ∇f(x1)−∇f(ResfΘ,φ,Ψ(x1)) ∈ BΘ(ResfΘ,φ,Ψ(x1)). Hence x∗ = ∇f(x1) ∈ (∇f +BΘ) ( ResfΘ,φ,Ψ(x1) ) . (4.3) It follows that x∗ ∈ ran(BΘ +∇f). (3) It is easy to show that ResfBΘ is single valued. From Lemma 9 we know that ResfΘ,φ,Ψ is single valued too. From (4.3) we have ResfBΘ = (BΘ +∇f)−1 ◦ ∇f = ResfΘ,φ,Ψ. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 14 of 32 Lemma 14. Let {xn} be a sequence generated by Algorithm 3.2 satisfying Assumption 3.1 (A and B). Then, {xn} is bounded. Proof. Let p ∈ Ω. Then, from Lemma 8 we have that F (T ) is closed and convex. From Lemma 10 and the definition of zn we have Df (p, zn) = Df ( p,ResfBθN ◦ · · · ◦ResfBθ2 ◦ResfBθ1 (wn) ) ≤ Df ( p,ResfBθ1 (wn) ) ≤ Df (p, wn) . (4.4) Also, from the definition of wn and (2.8), we obtain Df (p, wn) ≤ Df (p,∇f∗ (∇f (xn) + θn (∇f (xn−1)−∇f (xn))) = Df (p,∇f∗ ((1− θn)∇f (xn) + θn∇f (xn−1))) ≤ (1− θn)Df (p, xn) + θnDf (p, xn−1) . (4.5) Also, Df (p, yn) = Df (p,∇f∗ (βn∇f (qn) + (1− βn)∇f (T (zn))) ≤ βnDf (p, qn) + (1− βn)Df (p, T (zn)) ≤ βnDf (p, qn) + (1− βn)Df (p, zn) ≤ βnDf (p, qn) + (1− βn)Df (p, wn) (4.6) From the definition of xn+1 and (2.8), we obtain Df (p, xn+1) = Df (p,∇f∗ (αn∇f (wn) + (1− αn)∇f (T (yn))) ≤ αnDf (p, wn) + (1− αn)Df (p, T (yn)) ≤ αnDf (p, wn) + (1− αn)Df (p, yn) ≤ αnDf (p, wn) + (1− αn) [βnDf (p, qn) + (1− βn)Df (p, wn)] = βn (1− αn)Df (p, qn) + [αn + (1− αn) (1− βn)]Df (p, wn) ≤ βn (1− αn)Df (p, qn) + [1− βn (1− αn)] [(1− θn)Df (p, xn) + θnDf (p, xn−1)] ≤ max {Df (p, qn) , Df (p, xn) , Df (p, xn−1)} . (4.7) Since {qn} is bounded and ∇f is bounded on bounded subset of E, there exists a real number d > 0 such that Df (p, qn) ≤ d, for all n ∈ N. Thus, by induction, we have Df (p, xn+1) ≤ max {d,Df (p, xn) , Df (p, xn−1)} ... ≤ max { d,Df (p, xN0) , Df ( p, xN0−1 )} . This implies that {Df (p, xn)} is bounded. Hence, from Lemma 6 we have that {xn} is bounded. Consequently, {wn} , {zn} and {yn} are all bounded. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 15 of 32 Lemma 15. Let {xn} be a sequence generated by Algorithm 3.2 satisfying Assumption 3.1 (A and B). Suppose that p ∈ Ω. Then, the following holds: (i) lim n→+∞ θn [Df (p, xn−1)−Df (p, xn)) = 0. (ii) lim n→+∞ θn βn [Df (p, xn−1)−Df (p, xn)] = 0. Proof. (i) Let p ∈ Ω. From (3.1), we have θn ∥xn − xn−1∥ ≤ ξn, for each n ≥ 1. (4.8) From Assumption 3.1(B2), we have that lim n→+∞ ξn βn = 0 and lim n→+∞ βn = 0. It follows that lim n→+∞ ξn = 0. Hence, we have that lim n→+∞ θn ∥xn − xn−1∥ ≤ lim n→+∞ ξn = 0. (4.9) Since ∇f is norm-to-norm continuous on subsets of E, we have that lim n→+∞ θn ∥∇f (xn)−∇f (xn−1)∥ = 0. (4.10) Using the three-point identity, Df (p, xn−1)−Df (p, xn) = −Df (xn−1, xn) + ⟨∇f(xn)−∇f(xn−1), xn−1 − p⟩. (4.11) Multiplying (4.11) by θn, we have θn[Df (p, xn−1)−Df (p, xn)] = −θnDf (xn−1, xn) + θn⟨∇f(xn)−∇f(xn−1), xn−1 − p⟩. (4.12) Since ∇f is bounded on bounded sets (Assumption A3), there exists L > 0 such that Df (xn−1, xn) ≤ L∥xn−1 − xn∥. Thus, θnDf (xn−1, xn) ≤ Lθn∥xn−1 − xn∥ → 0. By Cauchy-Schwarz and boundedness of {xn}, we have |θn⟨∇f(xn)−∇f(xn−1), xn−1 − p⟩| ≤ θn∥∇f(xn)−∇f(xn−1)∥ · ∥xn−1 − p∥ → 0. Hence, lim n→∞ θn[Df (p, xn−1)−Df (p, xn)] = 0. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 16 of 32 (ii) Also, since lim n→+∞ ξn βn = 0, we obtain from (4.8) that lim n→+∞ θn βn ∥xn − xn−1∥ ≤ lim n→+∞ ξn βn = 0. (4.13) Since ∇f is norm-to-norm continuous on subsets of E, we obtain lim n→+∞ θn βn ∥∇f (xn)−∇f (xn−1)∥ = 0. (4.14) Multiplying (4.11) by θn βn , we have θn βn [Df (p, xn−1)−Df (p, xn)] = − θn βn Df (xn−1, xn) + θn βn ⟨∇f(xn)−∇f(xn−1), xn−1 − p⟩. From (4.11), (4.13), and (4.14), we have limn→∞ θn βn [Df (p, xn−1) − Df (p, xn)] = 0, which completes the proof. Lemma 16. Let {xn} be a sequence generated by Algorithm 3.2 satisfying Assumption 3.1(A and B). Suppose that p ∈ Ω. Then, the following holds: Df (p, xn+1) ≤ [1− βn(1− αn)]Df (p, xn) + β(1− αn)bn, where bn = 1−βn(1−αn) 1−αn · θn βn [Df (p, xn−1)−Df (p, xn)] + ⟨yn − p,∇f (qn)−∇f(p)⟩ . V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 17 of 32 Proof. Let p ∈ Ω. From (2.7), (4.4), (4.5), we have Df (p, xn+1) = ∇f (p,∇f∗ (αn∇f (wn) + (1− αn)∇f (T (yn)))) ≤ αnDf (p, wn) + (1− αn)Df (p, T (yn)) ≤ αnDf (p, wn) + (1− αn) [Df (p,∇∗βn∇f (qn) + (1− βn)∇f (T (zn))] = αnDf (p, wn) + (1− αn) [Vf (p, βn∇f (qn) + (1− βn)∇f (T (zn)))] ≤ αnDf (p, wn) + (1− αn) [Vf (p, βn∇f (qn) + (1− βn)∇f (T (zn)) − βn (∇f (qn)−∇f(p))− ⟨yn − p,−βn (∇f (qn)−∇f(p)⟩] = αnDf (p, wn) + (1− αn) [Vf (p, βn∇f(p) + (1− βn)∇f (T (zn))) + βn ⟨yn − p,∇f (qn)−∇f(p)⟩ ≤ αnDf (p, wn) + (1− αn) [βnDf (p, p) + (1− βn)Df (p, T (zn)) + βn ⟨yn − p,∇f (qn)−∇f(p)⟩ = αnDf (p, wn) + (1− αn) [(1− βn)Df (p, T (zn)) + βn ⟨yn − p,∇f (qn)−∇f(p)⟩ ≤ αnDf (p, wn) + (1− αn) [(1− βn)Df (p, zn) + βn ⟨yn − p,∇f (qn)−∇f(p)⟩ ≤ [αn + (1− αn) (1− βn)]Df (p, wn) + (1− αn)βn ⟨yn − p,∇f (qn)−∇f(p)⟩ = [1− βn (1− αn)]Df (p, wn) + (1− αn)βn ⟨yn − p,∇f (qn)−∇f(p)⟩ ≤ [1− βn (1− αn)] [(1− θn)Df (p, xn) + θnDf (p, xn−1)] + (1− αn)βn ⟨yn − p,∇f (qn)−∇f(p)⟩ = [1− βn (1− αn)]Df (p, xn) + [1− βn (1− αn)] θn [Df (p, xn−1)−Df (p, xn)] + βn (1− αn) ⟨yn − p,∇f (qn)−∇f(p)⟩ = [1− βn (1− αn)]Df (p, xn) + βn (1− αn) [1− βn (1− αn) (1− αn) · θn βn (Df (p, xn−1)−Df (p, xn) + ⟨yn − p,∇f(qn)−∇f (p)⟩ ] , which completes the proof. Theorem 1. Let {xn} be a sequence generated by Algorithm 3.2 satisfying Assumption 3.1 (A and B). Then, {xn} converges strongly to p∗ in Ω. Proof. Let p∗ ∈ Ω. Then, from Lemma 16, we have Df (p, xn+1) ≤ [1− βn (1− αn)]Df (p, xn) +βn (1− αn) [1− βn(1− αn) (1− αn) · θn βn [Df (p, xn−1)−Df (p, xn)](4.15) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 18 of 32 + ⟨yn − p,∇f(qn)−∇f (p)⟩ ] = [1− βn (1− αn)]Df (p, xn) + βn (1− αn) bn, (4.16) where bn = 1−βn(1−αn) 1−αn · θn βn [Df (p, xn−1)−Df (p, xn)] + ⟨yn − p,∇f (qn)−∇f(p)⟩ . Next, we show that {Df (p ∗, xn)} converges to zero. To show this, by Lemma 12, we need to show that lim sup k→+∞ bnk ≤ 0 for every subsequence {Df (p ∗, xnk )} of {Df (p ∗, xn)} satisfying lim inf k→+∞ ( Df (p ∗, xnk+1 )−Df (p ∗, xnk ) ) ≥ 0. (4.17) Suppose {Df (p ∗, xnk )} is a subsequence of {Df (p ∗, xn)} such that (4.17) holds. From Lemma 7, Lemma 15 and the definition of znk , we have lim k→+∞ Df (xnk , znk ) = lim k→+∞ Df ( xnk , ResfBθN ◦ . . . ◦ResfBθ1 (wnk ) ) ≤ lim k→+∞ Df ( xnk , ResfBθN−1 ◦ · · · ◦ResfBθ1 (wnk ) ) ≤ lim k→+∞ Df ( xnk , ResfBθ1 (wnk ) ) (4.18) ≤ lim k→+∞ [ Df ( p∗, ResfBθ1 (wnk ) ) −Df (p ∗, xnk ) ] ≤ lim k→+∞ [Df (p ∗, wnk )−Df (p ∗, xnk )] (4.19) ≤ lim k→+∞ [ (1− θnk )Df (p ∗, xnk ) + θnk Df ( p∗, xnk−1 ) −Df (p ∗, xnk ) ] = lim k→+∞ [ θnk Df ( p∗, xnk−1 ) − θnk Df (p ∗, xnk ) ] = lim k→+∞ θnk [ Df ( p∗, xnk−1 ) −Df (p ∗, xnk ) ] = 0. (4.20) From Lemma 1, we obtain lim k→+∞ ∥xnk − znk ∥ = 0. (4.21) Since f is uniformly Fréchet differentiable on bounded subsets of E, by Lemma 5, ∇f is norm-to-norm uniformly continuous on bounded subsets of E. Hence, lim k→+∞ ∥∇f (xnk )−∇f (znk )∥⋆ = 0. (4.22) Also, since f is uniformly Fréchet differentiable, it is also uniformly continuous, hence we obtain that lim k→+∞ ∥f (xnk )− f (znk )∥ = 0. (4.23) Using the Bregman distance, we obtain Df (p ∗, xnk )−Df (p ∗, znk ) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 19 of 32 = f(p∗)− f (xnk )− ⟨∇f (xnk ) , p∗ − xnk ⟩ − f(p∗) + f (znk ) + ⟨∇f (znk ) , p∗ − znk ⟩ = f (znk )− f (xnk ) + ⟨∇f (znk ) , p∗ − znk ⟩ − ⟨∇f (xnk ) , p∗ − xnk ⟩ = f (znk )− f (xnk ) + ⟨∇f (znk ) , xnk − znk ⟩ − ⟨∇f (znk )−∇f (xnk ) , p∗ − xnk ⟩ , for p∗ ∈ F (T ). From (4.21) and (4.23), we obtain lim k→+∞ [Df (p, xnk )−Df (p, znk )] = 0. (4.24) Also, since βnk → 0 as k → +∞, we obtain Df (znk , ynk ) = Df (p ∗, ynk )−Df (p ∗, znk ) = Df (p ∗,∇f∗ (βnk ∇f (qnk ) + (1− βnk )∇f (T (znk ))))−Df (p ∗, znk ) ≤ βnk Df (p ∗, qnk ) + (1− βnk )Df (p ∗, T (znk ))−Df (p ∗, znk ) ≤ βnk Df (p ∗, qnk ) + (1− βnk)Df (p ∗, znk )−Df (p ∗, znk ) = βnk [Df (p ∗, qnk )−Df (p ∗, znk )] → 0, as k → +∞. (4.25) Hence, lim k→+∞ Df (znk , ynk ) = 0. From 2.4, we obtain lim k→+∞ ∥znk − ynk ∥ = 0. (4.26) Consequently, we have lim k→+∞ ∥∇f(znk )−∇f(ynk )∥ = lim k→+∞ ∥f(znk )− f(ynk )∥ = 0. From (4.21) and (4.26), we obtain ∥xnk − ynk ∥ = ∥xnk − znk + znk − ynk ∥ ≤ ∥xnk − znk ∥+ ∥znk − ynk ∥ = 0, as k → +∞. Therefore, lim k→+∞ ∥xnk − ynk ∥ = 0. (4.27) Since f is uniformly Fréchet differentiable on bounded subsets of E, by Lemma 5, ∇f is norm-to-norm uniformly continuous on bounded subsets of E. Hence lim k→+∞ ∥∇f (xnk )−∇f (ynk )∥∗ = 0. (4.28) On the other hand, since f is uniformly Fréchet differentiable, we have that f is also uniformly continuous. Hence, lim k→+∞ ∥f (xnk )− f (ynk )∥ = 0. (4.29) V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 20 of 32 Applying the Bregman distance, we obtain Df (p ∗, wnk )−Df (p ∗, ynk ) = f(p∗)− f (wnk )− ⟨∇f (wnk ) , p∗ − wnk ⟩ − f(p∗) + f (ynk ) + ⟨∇f (ynk ) , p∗ − ynk ⟩ = f (ynk )− f (wnk ) + ⟨∇f (ynk ) , p∗ − ynk ⟩ − ⟨∇f (wnk ) , p∗ − wnk ⟩ = f (ynk )− f (wnk ) + ⟨∇f (ynk ) , wnk − ynk ⟩+ ⟨∇f (ynk )−∇f (wnk ) , p∗ − wnk ⟩ ,(4.30) for p∗ ∈ F (T ). From the definition of wnk and (4.10), we have ∥∇f (wnk )−∇f (xnk )∥ = ∥∥∇f (xnk ) + θnk ( ∇f ( xnk−1 ) −∇f (xnk ) ) −∇f (xnk ) ∥∥ = θnk ∥∥∇f ( xnk−1 ) −∇f (xnk ) ∥∥→ 0 as k → +∞. (4.31) From (4.28) and (4.31), we can write lim k→+∞ ∥∇f (wnk )−∇f (ynk )∥ ≤ lim k→+∞ [∥∇f (wnk )−∇f (xnk )∥+ ∥∇f(xnk )−∇f(ynk )] = 0 (4.32) Combining (4.30) and (4.32), we have lim k→+∞ (Df (p ∗, wnk )−Df (p ∗, ynk )) = 0. (4.33) Also, from (4.27) and (4.32), we have that lim k→+∞ ∥wnk − xnk ∥ = 0. (4.34) From (4.33) and the definition of xnk+1 , we have Df ( ynk , xnk+1 ) = Df ( p∗, xnk+1 ) −Df (p ∗, ynk ) = Df (p ∗,∇f∗ (αnk ∇f (wnk ) + (1− αnk )∇f (T (ynk ))))−Df (p ∗, ynk ) ≤ Df (p ∗,∇f∗ (αnk ∇f (wnk ) + (1− αnk )∇f (T (ynk ))−Df (p, ynk ))) ≤ αnk Df (p ∗, wnk ) + (1− αnk )Df (p ∗, T (ynk ))−Df (p ∗, ynk ) ≤ αnk Df (p ∗, wnk ) + (1− αnk )Df (p ∗, ynk )−Df (p ∗, ynk ) = αnk [Df (p ∗, wnk )−Df (p ∗, ynk )] → 0 as k → +∞. From Lemma 1, he have lim k→+∞ ∥∥ynk − xnk+1 ∥∥ = 0. (4.35) From (4.25), and the fact that βnk → 0 as k → +∞, we have Df (Tynk , ynk ) = Df (p ∗, ynk )−Df (p ∗, T ynk ) ≤ βnk Df (p ∗, qnk ) + (1− βnk )Df (p ∗, T (znk ))−Df (p ∗, T ynk ) ≤ βnk Df (p ∗, qnk ) + (1− βnk )Df (p ∗, znk )−Df (p ∗, ynk ) = βnk [Df (p ∗, qnk )−Df (p ∗, znk )] + [Df (p ∗, znk )−Df (p ∗, ynk )] → 0 as k → +∞. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 21 of 32 Therefore, lim k→+∞ Df (Tynk , ynk ) = 0. From Lemma 1, we obtain lim k→+∞ ∥Tynk − ynk ∥ = 0. (4.36) From (4.35) and (4.36), we have∥∥xnk+1 − Tynk ∥∥ ≤ ∥∥xnk+1 − ynk ∥∥+ ∥ynk − Tynk ∥ → 0, as k → +∞. In other words, lim k→+∞ ∥∥xnk+1 − Tynk ∥∥ = 0. (4.37) From (4.27) and (4.36) we have ∥xnk − Txnk ∥ ≤ ∥xnk − ynk ∥+ ∥ynk − Tynk ∥+ ∥Tynk − Txnk ∥ → 0 as k → +∞. Hence, lim k→+∞ ∥xnk − Txnk ∥ = 0. (4.38) From (4.27)-(4.38) we have lim n→+∞ ∥xnk+1 − xnk ∥ = 0. (4.39) Since {xn} is bounded, there exists a subsequence {xnk } of {xn} such that {xnk } ⇀ p∗. From (4.38), we have ∥xnk − T (xnk )∥ → 0 as k → +∞. Hence, p∗ ∈ F (T ). For any w ∈ ( F (T ) ∩ (⋂N j=1B −1 θj (0∗) )) , it follows from the there point identity that |Df (w,wnk )−Df (w, ynk )| = |Df (w, ynk ) +Df (ynk , wnk ) + ⟨w − ynk ,∇f (ynk )−∇f (wnk )⟩ −Df (w, ynk )| = |Df (ynk , wnk ) + ⟨w − ynk ,∇f (ynk )−∇f (wnk )⟩| ≤ Df (ynk , wnk ) + ∥w − ynk ∥ ∥∇f (ynk )−∇f (wnk )∥ ≤ ∥ynk − wnk ∥+ ∥w − ynk ∥ ∥∇f (ynk )−∇f (wnk )∥ → 0 as k → +∞ by (4.32). Hence, lim k→+∞ |Df (w,wnk )−Df (w, ynk )| = 0. Since ResfBθ is BQFNE, we have Df ( ResfBθj ◦ · · · ◦ResfBθ1 (wnk ) , ResfBθj−1 ◦ . . . ◦ResfBθ1 (wnk ) ) = Df ( ResfBθj ◦ResfBθj−1 ◦ . . . ◦ResfBθ1 (wnk ) , ResfBθj−1 ◦ . . . ◦ResfBθ1 (wnk ) ) ≤ Df (w,wnk )−Df (w,wnk ) → 0 V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 22 of 32 as k → +∞ for all j ∈ {1, 2, . . . , N}. It then follows that lim k→+∞ Df ( (ResfBΘj ◦ . . . ◦ResfBΘ1 (wnk ), wnk ) ) = 0 for all j ∈ {1, 2, . . . , N}. So, lim k→+∞ ∥ResfBΘj ◦ . . . ◦ResfBΘ1 (wnk )− wnk ∥ = 0 (4.40) for all j ∈ {1, 2, . . . , N}. From the definition of the f -resolvent, we have ∇f ( ResfBΘj−1 ◦ . . . ◦ResfBΘ1 (wnk ) ) ∈ ( ∇f + λj nk BΘj ) ( ResfBΘj ◦ . . . ◦ResfBΘ1 (wnk ) ) . Hence ζjnk := 1 λj nk ( ∇f(ResfBΘj−1 ◦ . . . ◦ResfBΘ1 (wnk ))−∇f(ResfBΘj ◦ . . . ◦ResfBΘ1 (wnk )) ) for all j ∈ {1, 2, . . . , N}. It follows from the above equations that lim k→+∞ ∥ζjnk∥ = 0 for any j ∈ {1, 2, . . . , N}. Since xnk ⇀ p∗, we obtain from (4.34) that wnk ⇀ p∗. From (4.40) and the fact that wnk ⇀ p∗, we obtain ResfBΘj ◦ . . . ◦ResfBΘ1 (wnk ) ⇀ p∗ for any j ∈ {1, 2, . . . , N}. Consequently, we have ResfBΘj ◦ . . . ◦ResfBΘ1 (xnk ) ⇀ p∗ for any j ∈ {1, 2, . . . , N}. From the monotonicity of BΘ, we have ⟨η − ζjnk , x−ResfBΘj ◦ . . . ◦ResfBΘ1 (xnk )⟩ ≥ 0. for all (x, η) ∈ graph(BΘj ). This implies that ⟨η, x − p∗⟩ ≥ 0 for all (x, η) ∈ graph(BΘj ) and for all j ∈ {1, 2, . . . , N}. So, by the maximal monotonicity of BΘj we have p ∗ ∈ B−1 Θj (0) for all j ∈ {1, 2, . . . , N}. Therefore p∗ ∈ ∩N j=1B −1 Θj (0). Hence, we have shown that p∗ ∈ ( F (T ) ∩ ( ∩N j=1B −1 Θj (0∗) )) . Since E is reflexive and {xnk } is bounded, there exists a subsequence {xnkj } of {xnk } such that {xnkj } ⇀ u ∈ C and lim j→+∞ 〈 ∇f(qnk )−∇f(p̂), xnkj − p̂ 〉 = lim sup k→+∞ ⟨∇f(qnk )−∇f(p̂), xnk − p̂⟩ = lim sup k→+∞ ⟨∇f(qnk )−∇f(p̂), ynk − p̂⟩. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 23 of 32 It follows from the definition of the Bregman projection that lim sup k→+∞ ⟨∇f(qnk )−∇f(p̂), ynk − p̂⟩ = lim j→+∞ 〈 ∇f(qnk )−∇f(p̂), xnkj − p̂ 〉 (4.41) = ⟨∇f(q)−∇f(p̂), u− p̂⟩ ≤ 0. (4.42) By Lemma 15, (4.41) and the condition on α, we can conclude that lim sup k→+∞ bnk ≤ 0. From Lemma 4.17 and (4.15) we have limn→+∞Df (p̂, xn) = 0. Therefore, by Lemma 11, we have lim n→+∞ xn = p̂. This completes the proof. Using Theorem 1 and Lemma 13, we have the following result. Let φ = Ψ = θn = 0 and T = I then we have the following corollary which was obtained in [56]. Corollary 1. Let E be a real reflexive Banach space, C be a nonempty, closed and convex subset of int(domf). Let f : E → R be a super coercive Legendre function which is bounded, uniformly Fréchet differentiable and totally convex on bounded subsets of E. Let BΘj : E → 2E ∗ , j = 1, 2, . . . , N be N maximal monotone mapping with dom(B) ⊂ C. Assume that ( ∩N j=1B −1 Θj (0∗) ) ̸= ∅, {αn} and {βn} be sequences in [0, 1] satisfying the following conditions: (i) lim n→+∞ βn = 0; (ii) +∞∑ n=1 βn = +∞; (iii) 0 < lim inf n→+∞ αn ≤ lim supn→+∞ αn < 1. Let {xn} be a sequence generated by u ∈ E, x1 ∈ E chosen arbitrarily, zn = ResfBΘN ◦ . . . ◦ResfBΘ1 (xn), yn = ∇f∗ (βn∇f(qn) + (1− βn)∇f(zn)) xn+1 = ∇f∗ (αn∇f(xn) + (1− αn)∇f(yn)) , (4.43) where ∇f is the gradient of f . Then the sequence {xn} generated by (4.43) converges to projf∩N j=1B −1 Θj (0∗) x as n → +∞. 5. Numerical Experiment In this section, we present numerical experiments to illustrate the performance of our proposed method. In all our experiments, we use ∥xn+1 − xn∥ < 10−4 as our stopping criterion. All the numerical computations were carried out using using Matlab version R2024(b). Being a non-accelerated version of our method, we made a comparison with Algorithm (1.5) in [23] with a short name ”EsRa”. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 24 of 32 Example 1. Let E = R and C = [−1, 1]. Let Θi(x, y) = −9ix2+xy+(9i−1)y2,Ψi(x, y) = (9i−3)x, φi(x, y) = (9i−6)x, i = 1, 2, 3, · · · , N, we have ResfBΘi (x) = x 5(9i−3) . Let f = ∥x∥2 and T (x) = PC(x) where PC(x) =  −1, x < −1 x, x ∈ [−1, 1] 1, x > 1. Clearly, we observe that the bifunction Θ satisfies (A1)-(A4), Ψ is monotone and T is Bregman strongly nonexpansive mapping. In this example, we select αn = 1 2n+3 , βn = n n+1 , qn = 1 n+1 , ϵ = 1 n3.1 , θ = 0.1 and set N = 100. As a stopping criterion, we use ∥xn+1 − xn∥ ≤ ϵ where ϵ = 10−4. The experiment was conducted for the following initial values of x0 and x1 given as Cases I-IV: (Case I) : x0 = 0.96 and x1 = 0.59; (Case II) : x0 = 1.1 and x1 = 1.3; (Case III) : x0 = 2.1 and x1 = 1.7; (Case IV) : x0 = 0.69 and x1 = 0.09. The report appears in the form of Figures 1- 4 showing that our method converges faster in terms of number iteration than the non-accelerated version. 0 2 4 6 8 10 12 14 Number of iterations 10-4 10-3 10-2 10-1 100 T o l Case I Our Algorithm EsRa Figure 1: Example 1. Case I. V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 25 of 32 0 2 4 6 8 10 12 14 Number of iterations 10-4 10-3 10-2 10-1 100 101 T o l Case II Our Algorithm EsRa Figure 2: Example 1. Case II. 0 2 4 6 8 10 12 14 Number of iterations 10-4 10-3 10-2 10-1 100 101 T o l Case III Our Algorithm EsRa Figure 3: Example 1. Case III. Example 2. Let E = (ℓ2(R), ∥ · ∥) , where ℓ2(R) := { x : x = {xi}+∞ i=1 , +∞∑ i=1 |xi|2 < +∞ } , with an inner product ⟨·, ·⟩ : ℓ2 × ℓ2 → R given by ⟨x, y⟩ = +∞∑ i=1 xiyi where x = {xi}+∞ i=1 , y = {yi}+∞ i=1 and the norm ∥ · ∥ : ℓ2 → R is given by ∥x∥2 = √( +∞∑ i=1 |xi|2 ) . Let f(x) = x2 2 , then f satisfies Assumption 3.1 Let C := {x ∈ ℓ2(R) : ∥x∥2 ≤ 1} and Θi : E × E → R be defined by Θi(x, y) = −3ix2 + 2ixy + iy2 for all i and x, y ∈ ℓ2. Let Ψi : ℓ2 → R and φi : ℓ2 → R for all i and x ∈ ℓ2 be given by Ψi = ix2 and φi = ix, respectively. We have that ResfBΘi (x) = x 1+7j . Let T = x+2 2 . Clearly, we observe that the bifunction Θ satisfies V. Darvish et al. / Eur. J. Pure Appl. Math, 18 (3) (2025), 6173 26 of 32 0 2 4 6 8 10 12 14 Number of iterations 10-4 10-3 10-2 10-1 T o l Case IV Our Algorithm EsRa Figure 4: Example 1. Case IV. (A1)-(A4), Ψ is monotone and T is Bregman strongly nonexpansive mapping. For example 2, we choose αn = 1 2n+3 , βn = 1 n+1 , qn = 1 5 , ϵ = 1 n3.1 , θ = 0.1 and set N = 100. As a stopping criterion, we use ∥xn+1−xn∥ ≤ ϵ where ϵ = 10−4. The experiment was conducted for the following initial values of x0 and x1 given as Cases A-D: (Case A) : x0 = [0.25, 0.25, 0.33, · · · , 0, 0, · · · ] and x1 = [0.2, 0.2, 0.3, · · · , 0, 0, · · · ]; (Case B) : x0 = [1, 0.5, 0.25, · · · , 0, 0, · · · ] and x1 = [0.2, 0.25, 0.125, · · · , 0, 0, · · · ]; (Case C) : x0 = [0.91, 0.55, 0.53, · · · , 0, 0, · · · ] and x1 = [0.85, 0.65, 0.65, · · · , 0, 0, · · · ]; (Case D) : x0 = [1.2, 0, 0.38, · · · , 0, 0, · · · ] and x1 = [0.8, 0, 1.2, · · · , 0, 0, · · · ]. The report of this experiment is displayed Figures 5- 8 showing that our method converges faster in terms of number iteration than the non-accelerated version presented in [23]. 6. Conclusion In this paper, we studied the generalized mixed equilibrium problem and the fixed point problem in the framework of real reflexive Banach spaces. We introduce an inertial method for approximating the common solution of the above mentioned problems. 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