Microsoft Word - 18-26 Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020   18    Determine Most Stable Isobar for Nuclides with A= (15-30) & (101- 115) Murtadha S. Nayyef Naz T. Jaralla Department of Physics, College of Education for Pure Science (Ibn Al-Haitham), University of Baghdad, Iraq. Mafiz1993@gmail.com naztalab2016@yahoo.com Article history: Received 30 December 2019, Accepted 16 February 2020, Published in October 2020. Abstract In this study the  most stable isobar for some isobaric families (light and intermediate ) nuclei with mass number (A) equals to (15-30) & (101- 115) have been determined. This determination of stable nuclide can help to determine the suitable nuclide, which can be used in different fields. Most stable isobar can be determined by two means. First: plot mass parabolas (plotting the binding energy (B.E) as a function of the atomic number (Z)) for these isobaric families, in this method most stable isobars represent the lowest point in mass parabola (the nuclide with the highest value of binding energy). Second: calculated the atomic number for most stable isobar (ZA) value. Our results show that there is only one stable nuclide for isobars with odd mass number (A) (one mass parabolas), while for nuclides with an even mass number (A) there is more than one stable nuclide (two mass parabola). Also, our results show that nuclides representing the most stable isobars in the two methods, which used in this study practically, are the same nuclide. Keywords: Binding Energy, Weizsäcker equation, Mass Parabolas, Isobaric nuclides. 1.Introduction The minimum portion of the elements that the keeps the basic properties are the atom. An atom is made of a small massive central called the nucleus, this nucleus is surrounded by orbiting electrons[1] .  Doi: 10.30526/33.4.2520 Ibn Al Haitham Journal for Pure and Applied Science Journal homepage: http://jih.uobaghdad.edu.iq/index.php/j/index       19  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 These nucleons are amounts of neutrons and protons, which are grouped in two collections. These neutrons and protons are independently spread during sure energy statuses, and they are being together with their public reacts [2]. These protons and neutrons are much heavier than electrons, which move around the nucleus. Protons have a positive charge equal in quantity to the negative charge of the electron, while neutrons have practically the equivalent mass as a proton with no charge [3]. Isobars are nuclei, which have similar atomic mass number (A), but atomic numbers (Z) are different. An instance of a pair of isobars is: 1H3 & 2He3 These isobars are with two neutrons, one proton for hydrogen nuclei, one neutron and two protons for helium nuclide respectively. Isobaric nuclei show a projecting part in beta decay and electron capture[4]. Beta particles (β) are electrons, which carry a negative or positive charge (e- & e+). In the situation of (β-) decay atomic number (Z) growths by one unit. But in the case of (β+) decay the atomic number (Z) will be decreased by one unit. Some nuclei go through a radioactive change by taking an atomic electron, normally from the K shell, releasing a neutrino as well as reductions atomic number (Z) by one unit[5]. 2. Theoretical Part In nuclear physics, one of the elementary and significant models is the liquid drop model (LDM). This model the nucleus assumes like a liquid drop collected with its related properties. In this model, binding energy (BE) of the nuclide has volume term (the react of nucleons with near nucleons regardless of reduction in interaction of external nucleons), surface term (the effect of the reduction in interactions of outward nucleons), Coulomb term (the react of coulomb repulsion amongst protons), asymmetry term (unlike quantity of energy in equivalent and unlike styles of neutrons and protons numbers), and parity term (additional stability and resultantly extra negative energy of the nucleus for pair-pair nuclei) [6]. 2.1 Bethe– Weizsäcker formula In 1935, Bethe and Weizsäcker projected an excellent parameterization of the binding energies of nuclei in their ground state. This formula depended on the liquid-drop analogy but also combined two quantum ingredients. Asymmetry energy is one, which is likely favors of same neutrons and proton numbers. A pairing energy is the next one which favors arrangements where two same fermions are paired[7]. The formula of Bethe and Weizsäcker is: B.E(A,Z) = av A - asA2/3 - ac Z(Z − 1)A−1/3 – aa(A − 2Z)2A−1 ± δA-1/2 +ȵ (1) where: av, as, ac, aa, δ and ȵ are the energy constants that represent to the volume, surface, Coulomb, asymmetry, pairing and shell energy terms, respectively[8]. One set of this factors is[8]: av=15.8Mev, as=18.3Mev, ac=0.72Mev, aa=23.2MeV. And δ = 11.2 MeV for even N, even Z . 0 for even N odd Z, or even Z, odd N 11.2 MeV for odd N, odd Z . .       20  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 And ȵ= ⎩ ⎨ ⎧ 3 Mev N and Z magic number . 2 Mev N or Z magic number and other is odd . 1 Mev N or Z magic number and other is even . 0 N or Z no magic number . 2.2 Applications of Bethe– Weizsäcker Formula 2.2.1 Mass Parabola One of the important uses of Bethe-Weizsäcker semi empirical formula is to limit the most stable isobar of an assumed mass number (A) against beta decay by plotting the binding energy as a function to the atomic number (Z) [9]. Mass parabolas for the different isobars fall into two clusters according to whether the mas number (A) is even or odd.[9] The isobars are placed on the sides of the parabola unstable, so these nuclides will be decayed to be more stable and lower on the parabola. [10]. The mass number (A) of nuclei with (Z > ZA) can decay by emitting positive Beta (ꞵ+) and neutrino (ⱱ) or electron capture (EC). While the mass number (A) of nucleus with (Z ˂ ZA ) can decay by emitting negative beta (ꞵ-) and antineutrino (ⱱ )[11]. 2.2.2 Atomic numbers for most stable isobar (ZA) value. The presence of the Coulomb term and the asymmetric term refers to a nucleus with the highest binding energy found by setting (∂B/∂Z = 0) for every mass number (A). The greatly bound nuclide has (Z = N = A/2) for nucleus with a low mass number (A) where the asymmetry term controls, but the Coulomb term favors (N >Z) for a large mass number (A) [7]. The neutron and proton number which agrees to the highest binding energy of the nucleus provides the value of atomic number Z (A) for the most bound isobars [12]: ∂B/∂Z= 0 ⇒ Z (A) = 𝑍 𝐴 (2) Z (A) ∼ / . / (3) This value of (Z) is near to, but not essentially same to the value of atomic number (Z) that takes the stable isobar for an assumed mass number (A).the reason for that (one must also take into account) is the difference of neutron–proton mass [7]. 3.Results and Discussion The results of this study will be presented and discussed in detail, whereas this study aims to determine the most stable isobar for (light and intermediate) nuclei with mass number (A) equals to (15-30) and (101- 115) . The most stable isobar for isobars under this study has been determined by two different methods: first by plotting mass parabola (values of binding energy (B.E) which are plotted as a function to the atomic number (Z) for each isobar under this study and second by calculating the atomic number (ZA) for most stable isobars. 3.1 determined the most stable isobar by mass parabola Binding energy (B.E) for light and intermediate nuclei with mass number (A) equals to (15-30) and (101-115) were calculated by using equation (1).       21  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 These values of binding energy (B.E) increased with increasing the mass number (A) of nuclides, the values of binding energy (B.E) which were ranging between (46-255) MeV for nuclides with mass number (A= 15-30) and (810-978) MeV for nuclides with mass number (A= 101-115) which were plotted as a function to the atomic number (Z) for each isobar in isobaric family, so we get mass parabolas for different isobars as shown in the Figures (1 & 2).                                 (a) (b) Figure 1. Mass parabolas for isobars with mass number (15-30) (a) odd (A) (b) even (A).       22  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020               (a)           (b) Figure 2.Mass parabolas for isobars with mass number (101-115) (a) odd (A) (b) even (A). Here, mass parabolas for isobars with odd and even mass number (A) are drawn separately because we have only one mass parabola for nuclei with an odd mass number (A) which are coming from (even- odd) or (odd-even) nuclide, also the term of pairing equivalents to zero in these isobars. While there are two mass parabolas for nuclei with an even mass number (A); one of these mass parabola for (odd-odd) nuclei and second for (even-even) nuclide which located under the parabola of (odd-odd) nuclide, for these nuclide the pairing term (is positive for even-even nuclei and negative for odd-odd nucleus) in the binding energy formula . So, we can see clearly from Figures (1(a) & 2(a)) of mass parabola for an odd mass number (A) that we have only one mass parabola as well as one stable isobar. While Figures (1(b) & 2(b)) of mass parabola for an even mass number (A) show that they are more than one stable isobar. The most stable isobars for nuclide with odd and even mass number (A) have the highest value of binding energy (B.E.) and lie at or near the bottom of the mass parabola. Some of most stable isobars which are determined for isobaric family with mass number A= [(15-30) & (101-115)] are the same in the case of isobars with odd mass number and even mass number, such as (Oxygen) which represents the stable nuclide for odd isobar with mass number equal to (A=17) as well as for even isobar with mass number equals to (A=16 & 18) 36 38 40 42 44 46 48 50 Atomic Number (Z) 800 810 820 830 840 850 860 870 B in d in g E n e rg y (B .E ) M e V A = 101 Tc 40 45 50 Atomic Number (Z) 820 830 840 850 860 870 880 890 B in d in g E n e rg y (B .E ) M e V A = 103 Ru 38 40 42 44 46 48 50 52 Atomic Number (Z) 840 850 860 870 880 890 900 B in d in g E n e rg y (B .E ) M e V A = 105 Rh 38 40 42 44 46 48 50 52 Atomic Number (Z) 850 860 870 880 890 900 910 920 B in d in g E n e rg y (B .E ) M e V A = 107 Pd 40 45 50 Atomic Number (Z) 870 880 890 900 910 920 930 940 B in d in g E n e rg y (B .E ) M e V A = 109 Pd 40 42 44 46 48 50 52 54 Atomic Number (Z) 890 900 910 920 930 940 950 B in d in g E n e rg y (B .E ) M e V A = 111 Ag 40 45 50 55 Atomic Number (Z) 910 920 930 940 950 960 970 B in d in g E n e rg y (B .E ) M e V A = 113 Cd 40 45 50 55 Atomic Number (Z) 920 930 940 950 960 970 980 B in d in g E n e rg y (B .E ) M e V A = 115 Sn 36 38 40 42 44 46 48 50 Atomic Number (Z) 820 830 840 850 860 870 880 B in d in g E n e rg y (B .E ) M e V A = 102 Ru even-even odd-odd 38 40 42 44 46 48 50 52 Atomic Number (Z) 850 860 870 880 890 900 910 B in d in g E n e rg y (B .E ) M e V A = 106 Pd even-even odd-odd 40 45 50 Atomic Number (Z) 870 880 890 900 910 920 930 B in d in g E n e rg y (B .E ) M e V A = 108 Pd even-even odd-odd 40 42 44 46 48 50 52 54 Atomic Number (Z) 880 890 900 910 920 930 940 950 B in d in g E n e rg y (B .E ) M e V A = 110 Pd even-even odd-odd 40 45 50 55 Atomic Number (Z) 890 900 910 920 930 940 950 960 B in d in g E n e rg y (B .E ) M e V A = 112 Cd even-even odd-odd       23  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 in first range, and (Ruthenium) nuclide which represent the stable isobar in the case of odd mass number (A=103) and even mass number (A=102 &104) for second range. The reason for this behavior is that these nuclides have high value of binding energy (B.E) comparison with adjacent nuclide. 3.2 determined the atomic number (ZA) value for most stable isobars The most stable isobar for isobars families under this study are also determined by calculating the (ZA) from equation (3). The results are presented in column (2) of Tables (1 &2). Then the atomic number of the most stable isobar (ZA) is plotted as a function to the mass number (A) as shown in Figures (3 & 4). Table 1. Mass number (A), the atomic number for most stable isobar (ZA) calculated from equation (3) for isobar with (A=15-30). Mass number (A) Atomic number for stable isobar (ZA) 15 7.162028 16 7.624391 17 8.085258 18 8.544668 19 9.002655 20 9.459252 21 9.91449 22 10.3684 23 10.821 24 11.27232 25 11.72239 26 12.17123 27 12.61886 28 13.06529 29 13.51056 30 13.95467 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 7 8 9 10 11 12 13 14 A to m ic n u m b e r fo r m o s t s ta b le i s o b a r (Z A ) Mass number (A) A=15-30 Figure 3. The relationship between atomic number for most stable isobar (ZA) and mass number (A) for (A=15- 30).       24  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 Table 2. Mass number (A), the atomic number for most stable isobar (ZA) calculated from equation (3) for isobar with (A=101-115). Mass number (A) Atomic number for stable isobar (ZA) 101 43.22642 102 43.61301 103 43.99901 104 44.38441 105 44.76922 106 45.15344 107 45.53708 108 45.92014 109 46.30263 110 46.68454 111 47.06589 112 47.44666 113 47.82688 114 48.20653 115 48.58563 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 43 44 45 46 47 48 49 A to m ic n u m b e r fo r m o s t s ta b le i s o b a r (Z A ) Mass number (A) A=101-115 Figure 4.The relationship between atomic number for most stable isobar (ZA) and mass number (A) for (A=101- 115). Figures (3&4) show a linear relationship among atomic number for most stable isobar (ZA) and mass number. 3.3 comparison between most stable isobar determined by two methods (mass parabola and atomic number (ZA)). A Comparison has been done between the most stable isobars determined by the two methods which are described above (the lowest point of the mass parabola for each isobars and these which are determined from the calculating of the atomic number for most stable isobars (ZA)) .This comparison is explained in tables (3 & 4) for isobaric family (A) = (15-30 & 101-115) respectively.       25  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 Table 3 . comparison between the most stable nuclide determined from mass parabola and atomic number for the most stable isobar (ZA) value from the equation (3) for nuclides with (A=15-30). Mass number (A) Nuclide –Atomic number for stable isobar from mass parabola Atomic number for stable isobar (ZA) from eq.(3) 15 N-7 7.162028 16 N-7, O-8 7.624391 17 O-8 8.085258 18 O-8, F-9 8.544668 19 F-9 9.002655 20 F-9, Ne-10 9.459252 21 Ne-10 9.91449 22 Ne-10, Na-11 10.3684 23 Na-11 10.821 24 Na-11, Mg-12 11.27232 25 Mg-12 11.72239 26 Mg-12,Al-13 12.17123 27 Al-13 12.61886 28 Al-13, Si-14 13.06529 29 Si-14 13.51056 30 Al-13, Si-14 13.95467 Table 4.comparison between the most stable nuclide determined from mass parabola and atomic number for the most stable isobar (ZA) value from the equation (3) for nuclides with (A=101-115). Mass number (A) Nuclide –Atomic number for stable isobar from mass parabola Atomic number for stable isobar (ZA) from eq.(3) 101 Tc-43 43.22642 102 Tc-43, Ru-44 43.61301 103 Ru-44 43.99901 104 Ru-44, Rh-45 44.38441 105 Rh-45 44.76922 106 Rh-45, Pd-46 45.15344 107 Pd-46 45.53708 108 Rh-45, Pd-46 45.92014 109 Pd-46 46.30263 110 Pd-46, Ag-47 46.68454 111 Ag-47 47.06589 112 Ag-47, Cd-48 47.44666 113 Cd-48 47.82688 114 Cd-48, In-49 48.20653 115 In-49 48.58563 From these Tables, we can note that the stable isobars are always the same nuclide for isobars with an odd mass number in the two methods, but in cases of even isobars which have two stable isobars (in mass parabola method) only one of them is same stable isobars in comparison to second method.       26  Ibn Al-Haitham Jour. for Pure & Appl. Sci. 33 (4) 2020 4. Conclusions 1. Most stable isobars located at the bottom of mass parabolas and have the highest value of binding energy (B.E). 2. 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