330 Β© 2025 The Author(s). Published by College of Education for Pure Science (Ibn Al-Haitham), University of Baghdad. This is an open-access article distributed under the terms of the Creative Commons Attribution 4.0 International License Some Results on Double Centralizer for Prime and Semiprime Π“- rings Aya Hussein Khudair 1* , Abdulrahman H. Majeed 2 , Shrooq Bahjat Smeein 3 and Azza I.M.S. Abu-Shams 4 1 Department of Mathematics, College of Science, University of Baghdad, Baghdad, Iraq. 2 Department of Mathematic, Al-Mamoun University College, Baghdad, Iraq. 3 Department of Information Technology -Section Mathematics, University of Technology and Applied Science - Muscat, Sultanate of Oman. doi.org/10.30526/38.2.3594 Abstract The goal of this work, is to examine the concept of a double centralizer ( T, S ), and double Jordan centralizer on prime and semiprime Π“-rings, this is done by studying examples ,remarks and results related to that concepts and looking for the conditions under which T equal S, we prove the results, the first result , let A be a semiprime Ξ“-ring and T is a left centralizer, S is a right centralizer, and they fulfilling x 𝛼 T(y) = S (x) 𝛼 y, for each x ∈ A, 𝛼 ∈ Ξ“, thence (T,S) is a double centralizer. The second, let A be a prime Ξ“-ring, U be a not equal zero ideal of A, such that, T is a left centralizer, S is a right centralizer, and fulfilling x 𝛼T(y) = S (x) 𝛼 y, for each x, y ∈ U, 𝛼 ∈ Ξ“, thence (T, S) is a double centralizer. The third, let A be a prime Ξ“-ring, U be a not equal zero ideal of A and we get, if T=S on U, thence T=S on A. Keywords: Prime Π“-rings, Semiprime Π“-rings, centralizer, Jordan centralizer, double centralizer, double Jordan centralizer. 1. Introduction Barnes (1) defined 𝛀-ring. Let A and Ξ“ be two additive abelian groups. It there is a mapping (π‘₯, 𝛼, 𝑦) β†’ (π‘₯ 𝛼 𝑦) of 𝐴 Γ— Π“ Γ— 𝐴 β†’ 𝐴, satisfying the following, for any π‘₯, 𝑦, 𝑧 ∈ A and Ξ±, Ξ² βˆˆπ›€. i. (π‘₯ + 𝑦)𝛼𝑧 = π‘₯𝛼𝑧 + 𝑦𝛼𝑧, π‘₯(Ξ± + Ξ²)y = xΞ±y + xΞ²y, π‘₯𝛼(y + z) = xΞ±y + xΞ±z, ii. (π‘₯𝛼𝑦)𝛽𝑧 = π‘₯𝛼(𝑦𝛽𝑧), thence A is named a 𝛀-ring. *Corresponding Author. Received: 11 June 2023 Accepted: 10 September 2023 Published: 20 April 2025 4 Department of Mathematics, College of Science, Philadelphia University, Ammaan ,Jordan. https://creativecommons.org/licenses/by/4.0/ https://creativecommons.org/licenses/by/4.0/ https://orcid.org/0009-0002-8259-4959 mailto:aya.hussein.g@gmail.com https://orcid.org/0000-0001-8534-0749 mailto:dulrahman.h.majeed@almamonuc.edu.iq https://orcid.org/0009-0002-9351-4176 mailto:shrooq.smeein@hct.edu.om https://orcid.org/0009-0003-1741-1447 mailto:aabushams@philadelphia.edu.jo IHJPAS. 2025, 38(2) 331 OZDEN et al. (2) defined the subring. A subring of Π“-ring A is additive subgroup S of A such that 𝑆Г𝑆 βΈ¦ 𝑆 . Let A be a 𝛀-ring, thence A is named a commutative gamma-ring if, π‘₯α𝑦 = 𝑦𝛼π‘₯, holds for any π‘₯, 𝑦 ∈ 𝐴 and Ξ± βˆˆπ›€, Kandamar et al. (3). A subset π‘ˆ of the 𝛀-ring A is a right (left) ideal of A if U is an additive subgroup of A and π‘ˆΠ“π΄ = {π‘ŽΞ±x: a ∈ π‘ˆ, 𝛼 ∈ Ξ“, π‘₯ ∈ A} ( AΠ“U) is contained in U. If U is both a left and a right ideal, thence U is a two-sided ideal, or simply is an ideal of A. Barnes (1). A 𝛀-ring A is named prime if π‘šΠ“π΄Π“π‘› = (0) with π‘š, 𝑛 ∈ A implies π‘š = 0 π‘œπ‘Ÿ 𝑛 = 0 and semiprime if π‘šΠ“π΄Π“π‘š = 0 with π‘š ∈ 𝐴 implies π‘š = 0 (4, 5). An ideal P of a gamma-ring A is prime ideal if for any ideals N,MβŠ†A, N𝛀MβŠ† 𝑃 implies NβŠ† 𝑃 or MβŠ† 𝑃, Kyuno (5). A gamma-ring A is said to be prime 𝛀-ring if the zero ideal is prime ideal, Kyuno (5). Let A be a 𝛀-ring, thence A is named n-torsion free if 𝑛 π‘₯ = 0, yields π‘₯ = 0, for every π‘₯ ∈ A, where 𝑛 is positive integer, Chakraborty et al. (6). Let A be a gamma-semiring, an element 1 ∈ A , is named unity for any π‘₯ ∈ 𝐴 there are 𝛼 ∈ 𝛀 such that π‘₯ 𝛼 1 = 1 𝛼 π‘₯ = π‘₯, RAO (7). Γ–zkum et al. (8) defined the derivation and (Jordan derivation), let A be a gamma-ring and 𝐷 ∢ 𝐴 β†’ A and additive map. Thence D is derivation (resp. Jordan derivation), if 𝐷 (π‘š 𝛼𝑛 ) = 𝐷 (π‘š) 𝛼 𝑛 + π‘šπ›Ό 𝐷 (𝑛) (resp. 𝐷 (π‘š 𝛼 π‘š) = 𝐷 (π‘š)𝛼 π‘š + π‘šπ›Ό 𝐷(π‘š)), for any π‘š, 𝑛 ∈ A and Ξ± ∈ Π“, Γ–zkum et al. (8). Every derivation of A, is Jordan derivation but the converse in general is not true, see Saleh (9). Barnes (1) defined the 𝛀-homomorphism. Let A and Y both be 𝛀-rings, and βˆ… a map of A in to A. Thence βˆ… is a 𝛀-homomorphism, if and only 𝑖𝑓 βˆ…(π‘₯𝛼𝑦) = βˆ…(π‘₯)𝛼 βˆ… (𝑦) , π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™π‘₯, 𝑦 ∈ 𝐴 and 𝛼 ∈ Π“. If βˆ… is also one-to one and onto thence βˆ… is a 𝛀- isomorphism. An additive mapping βˆ… of 𝛀-ring A into a 𝛀-ring A' is named Jordan homomorphism if βˆ…(π‘₯𝛼𝑦 + 𝑦𝛼π‘₯) = βˆ…(x)Ξ±βˆ…(𝑦) + βˆ…(y)Ξ±βˆ…(π‘₯), for each π‘₯, 𝑦 ∈ A and 𝛼 ∈ Π“, Shaheen (10). Let A be a 𝛀-ring, a mapping d of A, to itself is named 𝛀-centralizing on a subset 𝑆 of A if [ π‘₯, 𝑑 (π‘₯)]𝛼 ∈ Z(A), for every π‘₯ ∈ 𝑆 and Ξ± ∈ Π“,in the special case when [ π‘₯, 𝑑 (π‘₯)]𝛼 = 0, hold for any π‘₯ ∈ S and 𝛼 ∈ Π“, the mapping d is named 𝛀-commuting on 𝑆 , Sameer et al. (11). Many researchers have studied centralizers and derivations in prime and semiprime 𝛀- rings (12- 21) and (22-30). The objective of this paper is to debate, double centralizer ( T, S ), and double Jordan centralizer on prime and semiprime 𝛀- rings, with fulfilling certain identities. 2. Preliminaries and Fundamentals 2.1 Definition Ali et al. (18) Let A be a gamma-ring, for any π‘₯, 𝑦 ∈ A and 𝛼 ∈ Π“, the symbol [π‘Ÿ, 𝑑]π‘Ž = π‘Ÿ Ξ± 𝑑 β€’ 𝑑 𝛼 π‘Ÿ, to symbolize the commutator. 𝑇(π‘Ÿ βƒ˜ 𝑑) = π‘Ÿ Ξ± 𝑑 + 𝑑 𝛼 π‘Ÿ. 2.2 Lemma Ali et al. (18) If A is a gamma-ring, for any π‘Ÿ, 𝑑, 𝑠 ∈ A and Ξ±, 𝛽 ∈ Π“ thence: I. [π‘Ÿ, 𝑑]Ξ± + [𝑑, π‘Ÿ]Ξ± = 0 II. [π‘Ÿ + 𝑑, 𝑠] Ξ± = [π‘Ÿ, 𝑠]Ξ±+[𝑑, 𝑠]Ξ± III. [π‘Ÿ, 𝑑 + 𝑠]Ξ±= [π‘Ÿ, 𝑑]Ξ±+[π‘Ÿ, 𝑠]Ξ± IV. [π‘Ÿ, 𝑑]Ξ±+Ξ²= [π‘Ÿ, 𝑑]Ξ±+[π‘Ÿ, 𝑑]ᡦ V. [π‘Ÿπ›½π‘‘ , 𝑠]Ξ± = π‘Ÿπ›½[𝑑, 𝑠]Ξ± + [π‘Ÿ, 𝑠]Ξ± 𝛽𝑑 + π‘Ÿ 𝛽 𝑠 Ξ± t β€’ π‘Ÿ Ξ± s 𝛽 𝑑 . 2.3 Definition Hoque 20(19) An additive mapping 𝑇: A β†’ A is a left (right)centralizer, if 𝑇(π‘Ÿπ›Ό 𝑑 ) = 𝑇 (π‘Ÿ) 𝛼 𝑑 ( 𝑇 (π‘Ÿ 𝛼 𝑑 ) = π‘Ÿ 𝛼 𝑇 (𝑑)) holds for any π‘Ÿ , 𝑑 ∈ A and 𝛼 ∈ Π“. A centralizer is both a left and right centralizer. IHJPAS. 2025, 38(2) 332 2.4 Example Let F be a field, and 𝐷2 (𝐹)be a diagonal matrices 2 by 2 over F and Ξ“ = { [ 0 0 0 𝑛 ] , 𝑛 ∈ 𝑍}, define 𝑇: 𝐷2 (𝐹) β†’ 𝐷2 (𝐹) as 𝑇 ([ π‘Ž 0 0 𝑏 ]) = [ 0 0 0 𝑏 ] , for any π‘Ž, 𝑏 ∈ 𝐹. Thence T is a centralizer. 2.5 Definition Hoque (19)An additive mapping 𝑇: 𝐴 β†’ 𝐴, is Jordan left (right) centralizer, if 𝑇(π‘₯Ξ± x) = T(π‘₯)𝛼π‘₯ (𝑇(π‘₯𝛼π‘₯) = π‘₯𝛼𝑇(π‘₯),for any π‘₯ ∈ A and Ξ± ∈ Π“. 2.6 Definition Let A be gamma-ring, let 𝑇, 𝑆: 𝐴 β†’ 𝐴, be an additive mappings, thence a mate ( T, S ) is named a double centralizer, if 𝑇 is a left centralizer, S is a right centralizer, and they satisfy a balanced requirement, π‘₯Ξ± T(𝑦) = 𝑆(π‘₯) 𝛼𝑦 , for any π‘₯, 𝑦 ∈ 𝐴, 𝛼 ∈ Π“. 2.7 Definition Let A be gamma-ring, and let 𝑇, 𝑆: 𝐴 β†’ 𝐴, be an additive mapping, thence a mate ( T, S ) is named a double Jordan centralizer, if T is a left Jordan centralizer, S is a right Jordan centralizer, and they satisfy a balanced requirement, (π‘₯𝛼 𝑇(π‘₯) = 𝑆(π‘₯) 𝛼 π‘₯), for any π‘₯ ∈ 𝐴, 𝛼 ∈ Π“. 3. Main Results In the following, we give the definition of commuting double centralizer: 3.1 Definition Let A be a 𝛀-ring, and (T, S), be a double centralizer. Thence (T, S), is named commuting double centralizer, if T and S are commuting. Now, we shall give an example for a commuting double centralizer. 3.2 Example Let F be a field, and A be a 𝛀-ring of all triangular matrices of the from π‘₯ = {[ 𝑑 0 0 0 π‘Ž 𝑑 0 0 𝑐 0 𝑑 0 𝑏 𝑐 βˆ’π‘Ž 𝑑 ] , π‘“π‘œπ‘Ÿπ‘Žπ‘™π‘™ π‘Ž, 𝑏, 𝑐, 𝑑 ∈ 𝐹}, and Π“ = { [ 0 0 0 0 0 0 0 0 0 0 0 0 𝑛 0 0 0 ] , π‘“π‘œπ‘Ÿπ‘Žπ‘™π‘™ 𝑛 ∈ Z} . In connection to the frequent process of addition and multiplication and let T, S: Aβ†’A be additive mappings defined by 𝑇(π‘₯) = 𝑦𝛼π‘₯ and 𝑆(π‘₯) = π‘₯𝛼𝑦, for each π‘₯, 𝑦 ∈ A and 𝛼 ∈ Π“. Where; 𝑦 = [ 0 0 0 0 0 0 0 0 0 0 0 0 𝑏 0 0 0 ] , π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ 𝑏 ∈ F. It is clear that T and S are commuting double centralizer. In the following results, we give some certain conditions to obtain (T,S) is a double centralizer, where T and S are from A to A. 3.3 Theorem Let A be a semiprime 𝛀-ring and T, S: Aβ†’ A be a mapping fulfilling. π‘₯𝛼𝑇(𝑦) = 𝑆(π‘₯)𝛼𝑦, for each π‘₯, 𝑦 ∈ A and Ξ± ∈ Π“. (1) Thence (T, S) is a double centralizer. IHJPAS. 2025, 38(2) 333 Proof: We need to show that T, S are additive mapping, and 𝑇 (π‘₯ 𝛼 𝑦) = 𝑇 (π‘₯) 𝛼 𝑦, π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. 𝑆 (π‘₯ 𝛼 𝑦) = π‘₯ 𝛼 𝑆 (𝑦), π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ π‘₯, 𝑦 ∈ 𝐴, 𝛼 ∈ 𝛀. Now replace 𝑦 by 𝑦 + z in (1), we imply π‘₯𝛼 𝑇(𝑦 + 𝑧) = 𝑆(π‘₯)𝛼𝑦 + 𝑆 (π‘₯)𝛼𝑧, for each π‘₯, 𝑦, 𝑧 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. Hence π‘₯𝛼( 𝑇(𝑦 + 𝑧) βˆ’ 𝑇 (𝑦) βˆ’ 𝑇(𝑧)) = 0, for π‘Žπ‘™π‘™ π‘₯, 𝑦, 𝑧 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. By the semiprimeness of A, we imply 𝑇(𝑦 + 𝑧) = 𝑇(𝑦) + 𝑇 (𝑧), for each 𝑦, 𝑧 ∈ 𝐴. Similarly, we can show that 𝑆(π‘₯ + 𝑦) = 𝑆 (π‘₯) + 𝑆 (𝑦), for each π‘₯, 𝑦, ∈ 𝐴. Now, replacing 𝑦 with 𝑦𝛽𝑧 in (1) we obtain π‘₯ 𝛼 (𝑇 (𝑦 𝛽𝑧) βˆ’ 𝑇 (𝑦) 𝛽𝑧) = 0, for each π‘₯, 𝑦, 𝑧 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽 ∈ 𝛀. By the semiprimeness of A, we imply 𝑇 (𝑦 𝛽 𝑧) = 𝑇 (𝑦) 𝛽 𝑧, for each 𝑦, 𝑧 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛽 ∈ 𝛀. Similarly, we can show 𝑆 (π‘₯ 𝛼 𝑦) = π‘₯ 𝛼 𝑆 (𝑦) , for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. Thence (T, S) is a double centralizer. Now, we give some results which make T=S under different conditions, where (T,S) is double centralizer. 3.4 Theorem Let A be a prime 𝛀-ring, U be a not equal zero ideal of A. Let 𝑇, 𝑆: 𝐴 β†’ 𝐴 be additive mappings such that T is a left centralizer, S is a right centralizer and they gratify π‘₯𝛼𝑇(𝑦) = 𝑆(π‘₯)𝛼𝑦, for each π‘₯, 𝑦 ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼 ∈ Π“. Thence (T,S) is a double centralizer. Proof: We have π‘₯ 𝛼 𝑇(𝑦) = 𝑆 (π‘₯) 𝛼 𝑦, for each π‘₯, 𝑦 ∈ π‘ˆ, 𝛼 ∈ 𝛀. (2) Replace x with π‘₯π›½π‘Ÿ in (2) when π‘₯ ∈ U, Ξ² ∈ Π“ π‘Žπ‘›π‘‘ π‘Ÿ ∈ 𝐴, we imply π‘₯ 𝛽 (π‘Ÿ 𝛼 𝑇(𝑦) βˆ’ 𝑆 (π‘Ÿ) 𝛼 𝑦) = 0, for each π‘Ÿ ∈ 𝐴, π‘₯, 𝑦 ∈ π‘ˆπ‘Žπ‘›π‘‘ 𝛼 , 𝛽 ∈ 𝛀. i.e. π‘₯ 𝛾 𝐴 𝛽 (π‘Ÿ 𝛼 𝑇(𝑦) βˆ’ 𝑆 (π‘Ÿ)𝛼 𝑦) = 0 , for each π‘Ÿ ∈ 𝐴, π‘₯, 𝑦 ∈ π‘ˆπ‘Žπ‘›π‘‘ 𝛼 , 𝛽, 𝛾 ∈ 𝛀. By primeness of A and since U be a not equal zero ideal of A, we imply π‘Ÿπ›Όπ‘‡(𝑦) = 𝑆(π‘Ÿ)𝛼𝑦, for each π‘Ÿ ∈ 𝐴, 𝑦 ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. (3) Replacing 𝑦 with π‘‘πœŽπ‘¦ in (3), where 𝑑 ∈ 𝐴, 𝑦 ∈ π‘ˆ, and Οƒ ∈ Π“. (π‘Ÿ 𝛼 𝑇(𝑑) βˆ’ 𝑆 (π‘Ÿ)𝛼 𝑑 )𝜎 𝑦 = 0 , for each t, π‘Ÿ ∈ 𝐴, 𝑦 ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼, 𝜎 ∈ 𝛀. Implies that (π‘Ÿπ›Όπ‘‡(𝑑) βˆ’ S(r)Ξ±t)𝜎U𝛿𝐴 = 0, for each 𝑑, π‘Ÿ ∈ A and 𝛼, 𝜎, Ξ΄ ∈ Π“. By the primeness of A, we imply π‘Ÿ 𝛼 𝑇(𝑑) = 𝑆 (π‘Ÿ)𝛼 𝑑, for each 𝑑, π‘Ÿ ∈ 𝐴, π‘Žπ‘›π‘‘, 𝛼 ∈ 𝛀. 3.5 Theorem Let A be a prime gamma-ring, U be a not equal zero ideal of A, and (T,S) be a double centralizer. If T=S on U, thence T=S on A. Proof: We have 𝑇 (π‘₯) = 𝑆 (π‘₯), for each π‘₯ ∈ π‘ˆ. (4) By replacing π‘₯ with π‘Ÿπ›Όπ‘₯ in (4), when π‘Ÿ ∈ A , π‘₯ ∈ U and 𝛼 ∈ Π“ , we imply IHJPAS. 2025, 38(2) 334 𝑇(π‘Ÿ)𝛼 π‘₯ = π‘Ÿ 𝛼 𝑆(π‘₯) = π‘Ÿπ›Όπ‘‡(π‘₯ ), for each ∈ 𝐴, π‘₯ ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀 . (5) Since (T, S) are a double centralizer, (5) leads to 𝑇(π‘Ÿ)𝛼 π‘₯ = 𝑆 (π‘Ÿ)𝛼 π‘₯, for each π‘₯ ∈ π‘ˆ, π‘Ÿ ∈ 𝐴, π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀.i.e. (𝑇 (π‘Ÿ) βˆ’ 𝑆 (π‘Ÿ))π›Όπ‘ˆπ›½π΄ = 0, for each π‘Ÿ ∈ A, and 𝛼, 𝛽 ∈ Π“. Since A is a prime 𝛀-ring and U be a not equal zero ideal of A, we imply T = S. From Theorem above, we imply the following: 3.6 Corollary Let A be a prime gamma-ring, U be an ideal of A and (T, S) be a double centralizer. If, T = S = 0 on U, thence T = S = 0 on A. In the following theorem, we shall prove that T=S in case T acts as a homomorphism on A. 3.7 Theorem Let A be a semiprime gamma-ring and let (T,S) be a double centralizer, if T acts as a homomorphism on A, thence T = S. Proof: We have 𝑇(π‘₯𝛼𝑦) = 𝑇(π‘₯)𝛼 𝑦 , for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ Π“. Since T is acts homomorphism on A, thence T (x) 𝛼 T(y) = T (x) 𝛼 y, for any π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. (6) On the other hand; π‘₯ 𝛼 𝑇(𝑦) = 𝑆 (π‘₯) 𝛼 𝑦 , for π‘Žπ‘™π‘™ π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. (7) The substation 𝑇(π‘₯) for π‘₯ in (7), gives 𝑇(π‘₯) 𝛼 𝑇(𝑦) = 𝑆(𝑇(π‘₯)) 𝛼 𝑦, for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. (8) By comparing (6) with (8), we arrive at (𝑆(𝑇(π‘₯)) βˆ’ 𝑇(π‘₯)) 𝛼 𝑦 = 0 Multiply from the right by (𝑆(𝑇(π‘₯)) βˆ’ 𝑇(π‘₯)), we get (𝑆(𝑇(π‘₯)) βˆ’ 𝑇(π‘₯))𝛽 𝑦 𝛼 (𝑆(𝑇(π‘₯)) βˆ’ (𝑇(π‘₯)) = 0, for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽 ∈ Π“. By semiprimeness of A, we have 𝑆 (𝑇(π‘₯)) = 𝑇(π‘₯), for each π‘₯ ∈ 𝐴. (9) From (9) and using (7), we imply 𝑇(π‘₯)𝛼𝑇(𝑦) = 𝑇(π‘₯)𝛼𝑆(𝑦), for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. (10) Replace π‘₯ by π‘₯𝛽𝑧 and 𝑦 by π‘¦πœŽπ‘€ in (7) and using (10), we arrive at π‘₯𝛽𝑧 𝛼𝑇(𝑦)πœŽπ‘† (𝑀) = 𝑆(π‘₯ 𝛽 𝑧) 𝛼 𝑦 𝜎 𝑀, for each π‘₯, 𝑦, 𝑧, 𝑀 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽, 𝜎, ∈ 𝛀. (11) Thence by (11), we imply π‘₯𝛽𝑆(𝑧)𝛼 𝑦 𝜎 𝑆 (𝑀) = 𝑆 (π‘₯ 𝛽 𝑧)π›Όπ‘¦πœŽπ‘€, for π‘Žπ‘™π‘™ π‘₯, 𝑦, 𝑧, 𝑀 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽, 𝜎 ∈ 𝛀. Whence it follows that π‘₯𝛽𝑆(𝑧)π›Όπ‘¦πœŽ(𝑆(𝑀) βˆ’ w) = 0, for each π‘₯, 𝑦, 𝑧, 𝑀 ∈ π΄π‘Žπ‘›π‘‘ 𝛼 , 𝛽, 𝜎 ∈ 𝛀. (12) The substitution on S (w)βˆ’ w for x in (12), gives us ( 𝑆(𝑀) βˆ’ 𝑀)𝛽𝑆(𝑧)π›Όπ‘¦πœŽ(𝑆(𝑀) βˆ’ 𝑀) = 0, for each 𝑦, 𝑧, 𝑀 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽, 𝜎 ∈ Ξ“. Right multiplication the above relation by S(z), yields (𝑆(𝑀) βˆ’ 𝑀)𝛽𝑆(𝑧)π›Όπ‘¦πœŽ(𝑆(𝑀) βˆ’ 𝑀)𝛾𝑆(𝑧) = 0, for π‘Žπ‘™π‘™ 𝑦, 𝑧, 𝑀 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽, 𝜎, 𝛾 ∈ Ξ“. By the semiprimeness of A, we obtain (𝑆(𝑀) βˆ’ w)Ξ²S(𝑧) = 0, for each 𝑀, 𝑧 ∈ A and Ξ² ∈ Π“. This gives 𝑆(𝑀) 𝛽 𝑆(𝑧) = 𝑀 𝛽 𝑆(𝑧), for each 𝑀, 𝑧 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛽 ∈ 𝛀. (13) From (7) and (13), we obtain IHJPAS. 2025, 38(2) 335 π‘₯ 𝛼 𝑇(𝑦) = 𝑆(π‘₯) 𝛼 𝑆(𝑦) = π‘₯ 𝛼 𝑆(𝑦), for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ Π“. Of course, we have also, π‘₯𝛼(𝑇(𝑦) βˆ’S(y)) = 0, for each x, y ∈ A, and 𝛼 ∈ Π“. By the semiprimeness of A, we imply T=S. In the following theorem, we gives a relation between T and S, where (T,S) is a double centralizer on prime Ξ“-ring. 3.8 Theorem Let A be a prime 𝛀-ring, and U be a not equal zero ideal of A, we imply (T,S) be a double centralizer. If 𝑇(π‘Ÿ 𝛼 π‘₯) = 𝑆(π‘Ÿ)𝛼π‘₯ π‘“π‘œπ‘Ÿ π‘Žπ‘™π‘™ π‘Ÿ ∈ 𝐴, π‘₯ ∈ π‘ˆ, π‘‘β„Žπ‘’π‘› 𝑇 = 𝑆. Proof: We have 𝑇(π‘Ÿπ›Όπ‘₯) = 𝑇(π‘Ÿ)𝛼π‘₯ = 𝑆(π‘Ÿ)𝛼π‘₯ for each π‘Ÿ, 𝑑 ∈ A , π‘₯ ∈ U and 𝛼 ∈ Π“. This reduces to (𝑇(π‘Ÿ) βˆ’ 𝑆(π‘Ÿ))𝛼π‘₯ = 0, for each π‘Ÿ ∈ A , π‘₯ ∈ U and 𝛼 ∈ Π“. (14) Replacing x with 𝑑𝛽π‘₯ in (14), when 𝑑 ∈ A, π‘₯ ∈ U, 𝛼 ∈ Π“, leads to (𝑇(π‘Ÿ) βˆ’ 𝑆(π‘Ÿ))𝛼𝑑𝛽π‘₯ = 0, for each π‘Ÿ ∈ 𝐴, π‘₯ ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼, 𝛽 ∈ Π“. i.e. (𝑇(π‘Ÿ) βˆ’ 𝑆(π‘Ÿ))𝛼𝐴 π›½π‘ˆ =, for each π‘Ÿ ∈ A and 𝛼 , 𝛽 ∈ Π“. Since A is a prime gamma-ring, and U be a not equal zero ideal, we have T = S. 3.9 Theorem Let A be a prime 𝛀-ring, and (T, S) be a double centralizer, if T acts as a not equal zero Jordan homomorphism (𝑇(π‘₯𝛼π‘₯) = 𝑇(π‘₯)𝛼 𝑇(π‘₯)) for each π‘₯ ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. Thence T=S=id. Proof : We have 𝑇(π‘₯𝛼π‘₯) = 𝑇(π‘₯)𝛼π‘₯, for each π‘₯ ∈ A and 𝛼 ∈ Π“. Thence from above relation and since T is acts as Jordan homomorphism. Yields, 𝑇(π‘₯) 𝛼 (𝑇(π‘₯) – π‘₯) = 0, for each π‘₯ ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ Π“. (15) Replace π‘₯ by π‘₯𝛽 𝑦 in (15), we imply 𝑇(π‘₯)𝛽 𝑦 𝛼 (𝑇(π‘₯)– π‘₯)𝛽 𝑦 = 0, for each π‘₯, 𝑦 ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼, 𝛽 ∈ 𝛀. (16) Linearization (16), we imply (𝑇(π‘₯) 𝛽 𝑦 𝛼 ( 𝑇(π‘₯) – π‘₯)𝛽 𝑧 + 𝑇(π‘₯) 𝛽 𝑧 𝛼( 𝑇(π‘₯) – π‘₯)𝛽 𝑦 = 0 (17) Now, replacing 𝑧 by π‘¦πœŽπ‘§ in (17) and using (16), we obtain (𝑇(π‘₯) 𝛽 𝑦 𝛼 𝐴 𝛾 ( 𝑇(π‘₯) – π‘₯)𝛽𝑦, for each π‘₯, 𝑦 ∈ 𝐴, 𝛼, 𝛽, 𝛾 ∈ Π“. By the primeness of A, we imply 𝑇(π‘₯) = π‘₯, for each π‘₯ ∈ A. (18) Otherwise, T=0. From π‘₯𝛼𝑇(𝑦) = S(x)𝛼𝑦, and by (18), we imply T = S = id. 4. Conclusion This work is to discuss double centralizer ( T, S ), and double Jordan centralizer on prime and semiprime Π“- rings, with fulfilling certain identities. We prove that; when T is a left centralizer, S is a right centralizer, and they fulfilling π‘₯𝛼𝑇(𝑦) = 𝑆(π‘₯)𝛼𝑦, for each π‘₯, 𝑦 ∈ π‘ˆ π‘Žπ‘›π‘‘ 𝛼 ∈ Π“. Then (T,S) is a double centralizer. Also if (T, S) be a double centralizer, T acts as a homomorphism on A, then T=S, and if T acts as a not equal zero Jordan homomorphism (𝑇(π‘₯𝛼π‘₯) = 𝑇(π‘₯)𝛼 𝑇(π‘₯)) for each π‘₯ ∈ 𝐴 π‘Žπ‘›π‘‘ 𝛼 ∈ 𝛀. Then T = S = id. 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