International Journal of Analysis and Applications ISSN 2291-8639 Volume 4, Number 1 (2014), 36-44 http://www.etamaths.com ON THE BEHAVIOR NEAR THE ORIGIN OF A SINE SERIES WITH COEFFICIENTS OF MONOTONE TYPE XHEVAT Z. KRASNIQI Abstract. In this paper we have obtained some asymptotic equalities of the sum function of a trigonometric sine series expressed in terms of its special type of coefficients. 1. Introduction Let us consider the sine series (1.1) ∞∑ m=1 am sin mx with coefficients tending to zero and such that the sequence {am} satifsies condition 4am = am−am+1 ≥ 0 or 42am = 4am−4am+1 ≥ 0 for all m. It is a well-known fact that under such conditions the series (1.1) converges for all x (see [12], page 95). We denote by g(x) its sum. As usually we write g(u) ∼ h(u),u → 0 if there exist absolute positive constants A and B such that Ah(u) ≤ g(u) ≤ Bh(u) is in a neighborhood of the point u = 0, and write g(u) ≈ h(u) if limu→0 g(u) h(u) = 1. Likewise, throughout this paper the constants in the O-expression denote positive absolute constants and they may be different in different relations. Several authors have investigated the behavior of the sum g(x) near the origin expressed in terms of the coefficients am. Seemingly, the first was Young [11] who consider this problem, and he was concerned solely about estimates of |g(x)| from above. Then Salem ([3], [4], Theorem 1) proved that if the sequence {mam} is monotone decreasing, then the following order equality holds g(x) ∼ ∑̀ m=1 mamx, where x ∈ I` := ( π `+1 , π ` ] ,` = 1, 2, . . . , x → 0. Later on, Aljančić, Bojanić and Tomić ([5], Theorem 2) give asymptotic expres- sion for g(x) as x → 0, when the coefficients am are convex (42am ≥ 0) and can be represent as the values A(m) of a slowly varying (in Karamata’s sense) function 2010 Mathematics Subject Classification. 42A20, 42A32. Key words and phrases. Sine series, (k, s)-monotone, convex sequence, asymptotic equality. c©2014 Authors retain the copyrights of their papers, and all open access articles are distributed under the terms of the Creative Commons Attribution License. 36 ON THE BEHAVIOR NEAR THE ORIGIN OF A SINE SERIES 37 A(z), i.e. for each t > 0 (1.2) lim z→∞ A(tz) A(z) = 1. Their result is equivalent to the following statement which can be deduce from one result given by Telyakovskĭı ([6], Theorem 2) and it is formulated as a corollary in this form: Corollary 1.1. Suppose that the coefficients am of the series (1.1) are convex and that am = A(m), for a slowly varying function A(z). Then the following asymptotic equality holds true: g(x) ≈ a` 1 x , x ∈ I`, x → 0. Telyakovskĭı deduced this result after the proof, in the same paper, of the fol- lowing two theorems: Theorem 1.1. Assume that am ↓ 0. Then for x ∈ I` the following estimate is valid g(x) = ∑̀ m=1 mamx + O ( 1 `3 ∑̀ m=1 m3am ) . Theorem 1.2. Let am → 0 and let the sequence {am} be convex. If x ∈ I`, where ` ≥ 11, then the following estimate holds true a` 2 cot x 2 + 1 2` `−1∑ m=1 m24am ≤ g(x) ≤ a` 2 cot x 2 + 6 ` `−1∑ m=1 m24am. Note also that the above theorems as well as some of [1] are generalized and extended in [7]-[10]. For an integer k ≥ 0 and a real sequence {am}∞m=0 denote 4kam = k∑ i=0 (−1)iCikam+i (40am = am), {4}k am = k∑ i=0 Cikam+i ({4}0 am = am). Definition 1.1 ([2]). A sequence {am}∞m=0 is said to be (k,s)-monotone if am → 0 as m →∞ and 4k ({4}s am) ≥ 0, for some k ≥ 0,s ≥ 0 and all m. It is easy to see that that if a sequence {am} (am → 0 as m → ∞) is non- increasing, then it is (1,s)-monotone for all s = 0, 1, 2, . . . . The converse statement is not always true. For example, if we consider the sequence {am} such that am → 0 as m →∞ and a2m = 0, a2m+1 ≥ a2m+3 for m = 0, 1, 2, . . . , then this sequence is not non-increasing but it is (1, 1)-monotone. Chronologically this definition arises the following question: What is the behav- ior near the origin of the series (1.1) with (k,s)-monotone coefficients? The answer to this question is the main goal of this paper. Precisely, we shall answer to this question only considering the cases when the series (1.1) has: (1, 1)-monotone, or (1, 2)-monotone, or (2, 1)-monotone, or (2, 2)-monotone coefficients. For the proof of our results we need the following two lemmas proved in [2]. 38 XHEVAT Z. KRASNIQI Lemma 1.1. Let {am}∞m=0 be a sequence such that am → 0 as m → ∞ and 4kam ≥ 0 for some k ≥ 1 and all m. Then for all r = 0, 1, . . . ,k−1 and all m the following inequality 4ram ≥ 0 holds. Lemma 1.2. Let {am}∞m=0 be a (k,s)-monotone sequence. If k = 1,s = 1 or s = 2, then g(x) = a0 2 ( 1 − tan x 2 ) + 1( 2 cos x 2 )s ∞∑ m=1 {4}sam−1 sin (ms− 2 + s) x 2 , allmost everywhere. Lemma 1.3. Let Bm(x) = ∑m i=0 sin (i− 1) x 2 . Then the following estimates hold:∣∣Bm(x)∣∣ ≤ 2π x , 0 < x ≤ π. Proof. After some elementary calculation we have∣∣Bm(x)∣∣ = ∣∣∣∣ 12 sin x 2 m∑ i=0 [ cos (i− 2) x 2 − cos ix 2 ]∣∣∣∣ = ∣∣∣∣cos x2 + cos x− cos (m− 1) x2 − cos mx22 sin x 2 ∣∣∣∣ ≤ 2∣∣ sin x 2 ∣∣ ≤ 2πx , 0 < x ≤ π. � 2. Main Results The following theorem considers sine series with (1, 1)-monotone sequence. Theorem 2.1. Assume that {am}∞m=1 is a (1, 1)-monotone sequence. Then for x ∈ I` the following estimate is valid g(x) = 1 2 cos x 2 { 1 2 ∑̀ m=1 m{4}1amx + O ( 1 `3 ∑̀ m=1 m3{4}1am )} .(2.1) Proof. By the Lemma 1.2 (a0 = 0) we have g(x) = 1 2 cos x 2 ∞∑ m=1 {4}1am−1 sin (m− 1) x 2 .(2.2) Then the use of Abel’s transformation gives H(x) = lim p→∞ { p−1∑ m=1 4({4}1am−1) Bm(x) + {4}1ap−1Bp(x) + {4}1a0 sin x 2 } = ∞∑ m=1 4({4}1am−1) Bm(x) + {4}1a0 sin x 2 := H (1) ` (x) + H (2) ` (x),(2.3) where H (1) ` (x) = `+1∑ m=1 4({4}1am−1) Bm(x) + {4}1a0 sin x 2 , ON THE BEHAVIOR NEAR THE ORIGIN OF A SINE SERIES 39 and H (2) ` (x) = ∞∑ m=`+2 4({4}1am−1) Bm(x). Let us estimate first H (1) ` (x). Based on Lemma 1.3, our assumption 4({4}1am) ≥ 0 for all m, the well-known relation sin t = t + O(t3), as t → 0, and x ∈ I` we have H (1) ` (x) = `+1∑ m=1 ({4}1am−1 −{4}1am) Bm(x) + {4}1a0 sin x 2 = ∑̀ m=0 {4}1am [ Bm+1(x) −Bm(x) ] −{4}1a`+1B`+1(x) = ∑̀ m=1 {4}1am sin mx 2 + 2π x {4}1a`+1 = 1 2 ∑̀ m=1 m{4}1amx + O ( 1 `3 ∑̀ m=1 m3{4}1am ) + O (`{4}1a`) . By virtue of monotonicity of {4}1am we obtain `{4}1a` ≤ 4 `3 { `(` + 1) 2 }2 {4}1a` ≤ 4 `3 ∑̀ m=1 m3{4}1am. Thus, H (1) ` (x) = 1 2 ∑̀ m=1 m{4}1amx + O ( 1 `3 ∑̀ m=1 m3{4}1am ) .(2.4) Furthermore, since x ∈ I` and |Bm(x)| = O ( 1 x ) by the Lemma 1.2, we notice that H (2) ` (x) = O ( 1 x ∞∑ m=`+2 ({4}1am−1 −{4}1am) ) = O ((` + 1){4}1a`+1) = O (`{4}1a`) = O ( 1 `3 ∑̀ m=1 m3{4}1am ) .(2.5) Finally, relations (2.2)-(2.5) prove completely estimation (2.1). � Corollary 2.1. Let {am}∞m=1 be a (1, 1)-monotone sequence and the series ∞∑ m=1 m (am + am+1) converges. Then the following asymptotic equality lim x→0 g(x) x = 1 4 ∞∑ m=1 m (am + am+1) holds true. 40 XHEVAT Z. KRASNIQI Proof. In accordance with Theorem 2.1 it is enough to prove that 1 `2 ∑̀ m=1 m3{4}1am → 0, as ` →∞. Indeed, for an arbitrary natural number M we can write 1 `2 ∑̀ m=1 m3{4}1am ≤ 1 `2 M∑ m=1 m3{4}1am + ∞∑ m=M+1 m{4}1am. If a number ε > 0 be chosen, then by hypotesis a number M = M(ε) exists, such that ∞∑ m=M+1 m{4}1am < ε 2 . Likewise, for all sufficiently large ` 1 `2 M∑ m=1 m3{4}1am < ε 2 . Then obviously, for such ` we have 1 `2 ∑̀ m=1 m3{4}1am < ε 2 + ε 2 = ε. � The following statements can be proved similarly therefore we will skip their proofs. Theorem 2.2. Assume that {am}∞m=1 is a (1, 2)-monotone sequence. Then for x ∈ I` the following estimate is valid g(x) = 1( 2 cos x 2 )2 {∑̀ m=0 (m + 1){4}2amx + O ( 1 `3 ∑̀ m=0 (m + 1)3{4}2am )} . Corollary 2.2. Suppose that {am}∞m=1 is a (1, 2)-monotone sequence and the series ∞∑ m=0 (m + 1) (am + 2am+1 + am+2) converges. Then the following asymptotic equality lim x→0 g(x) x = 1 4 ∞∑ m=0 (m + 1) (am + 2am+1 + am+2) holds true. The proof of the next statement is more complicated and that is why we will sketch it in more details. ON THE BEHAVIOR NEAR THE ORIGIN OF A SINE SERIES 41 Theorem 2.3. Assume that {am}∞m=1 is a (2, 2)-monotone sequence. Then for x ∈ I`, ` ≥ 11 the following estimate is valid {4}2a`−1 2 cot x 2 + 1 2` `−1∑ m=1 m24({4}2am−1) ≤ g(x) ( 2 cos x 2 )2 ≤ {4}2a`−1 2 cot x 2 + 6 ` `−1∑ m=1 m24({4}2am−1) . Proof. By the Lemma 1.1 the condition 42 ({4}2am) ≥ 0 implies 4({4}2am) ≥ 0. Therefore by the Lemma 1.2 we have g(x) = 1( 2 cos x 2 )2 ∞∑ m=1 {4}2am−1 sin mx. Applying Abel’s transformation we obtain (2.6) g(x) = 1( 2 cos x 2 )2 ∞∑ m=1 4({4}2am−1) D̃m(x), where D̃m(x) = ∑m i=1 sin ix is the conjugate Dirichlet kernel. For x ∈ (0,π] and m = 0, 1, 2, . . . , introduce the functions ϕm(x) := − cos (m + 1/2) x 2 sin x/2 and ψm(x) := m∑ i=0 ϕi(x) = − sin (m + 1) x 4 sin2(x/2) . Denoting H(x) := ∑∞ m=1 4({4}2am−1) D̃m(x) one can write H(x) = `−1∑ m=1 4({4}2am−1) D̃m(x) + ∞∑ m=` 4({4}2am−1) ( 1 2 cot x 2 + ϕm(x) ) = {4}2a` 2 cot x 2 + `−1∑ m=1 4({4}2am−1) D̃m(x) + ∞∑ m=` 4({4}2am−1) ϕm(x) = a`−1 + 2a` + a`+1 2 cot x 2 + E`(x) + F`(x).(2.7) We shall make use of the representation (2.7) for x ∈ I`, and from now and till the end of the proof of our theorem we supose that x ∈ I` but we shall not remind of it. The following estimate is true in view of the monotonous decay of 4({4}2am−1) and the positivity of D̃m(x) for m ≤ `: E`(x) ≥ 4({4}2a`−1) `−1∑ m=1 ( 1 2 cot x 2 + ϕm(x) ) = 4({4}2a`−1) ( ` 2 cot x 2 + ψ`−1(x) ) = 4({4}2a`−1) 4 sin2(x/2) (` sin x− sin `x) .(2.8) 42 XHEVAT Z. KRASNIQI Let us estimate F`(x) from above. Applying Abel’s transformation we have |F`(x)| = ∣∣∣∣∣ limn→∞ { n−1∑ m=` 42 ({4}2am−1) ψm(x) +4({4}2an−1) ψn(x) −4({4}2a`−1) ψ`−1(x) }∣∣∣∣∣ ≤ ∞∑ m=` 42 ({4}2am−1) |ψm(x) −ψ`−1(x)| ≤ 4({4}2a`−1) 4 sin2(x/2) (1 + sin `x) .(2.9) From (2.8) and (2.9), in a similiar way as Telyakovskĭı did [6], for ` ≥ 11 we can show that 1 2 E`(x) + F`(x) > 0. Further, if m < `, then D̃m(x) ≥ m∑ i=1 2 π ix ≥ m(m + 1) ` + 1 > m2 ` . Therefore, (2.10) 1 2 E`(x) ≥ 1 2` `−1∑ m=1 m24({4}2am−1) . From (2.10), (2.7), and (2.6) we obtain the estimate of g(x) from below g(x) ≥ 1( 2 cos x 2 )2 ( a`−1 + 2a` + a`+1 2 cot x 2 + 1 2` `−1∑ m=1 m24({4}2am−1) ) . Since D̃m(x) ≤ m2x ≤ πm2 ` , then (2.11) E`(x) ≤ π ` `−1∑ m=1 m24({4}2am−1) . For the estimate (2.9) we can write |F`(x)| ≤ 4({4}2a`−1) 2 sin2(x/2) ≤4({4}2a`−1) π2 2x2 ≤ (` + 1)2 2 4({4}2a`−1) , and for ` ≥ 11 (` + 1)2 2 < 2, 4 ` `−1∑ m=1 m2, hence, by reason of the monotonicity of 4({4}2a`−1) we get |F`(x)| ≤ 2, 4 ` `−1∑ m=1 m24({4}2am−1) .(2.12) ON THE BEHAVIOR NEAR THE ORIGIN OF A SINE SERIES 43 Estimates (2.12), (2.13), and (2.7) give the estimate of g(x) from above g(x) ≤ 1( 2 cos x 2 )2 ( a`−1 + 2a` + a`+1 2 cot x 2 + 6 ` `−1∑ m=1 m24({4}2am−1) ) . The proof is completed. � It follows from Theorem 2.3 that for x ∈ I` in a sufficiently small neighbourhood of the origin we have g(x) = 1 2 (1 + cos x) ( {4}2a`−1 2 cot x 2 + O ( 1 ` `−1∑ m=1 m24({4}2am−1) )) .(2.13) Corollary 2.3. Assume that {am}∞m=1 is a (2, 2)-monotone sequence. Then the following order equality is true g(x) ∼ (`− 1){4}2a`−1 + 1 ` `−1∑ m=1 m{4}2am−1. Proof. Since limx→0 x cot x = 1, then it is enough to prove that 1 ` `−1∑ m=1 (2m− 1){4}2am−1 − (`− 1){4}2a`−1 ≤ 1 ` `−1∑ m=1 m24({4}2am−1) and 1 ` `−1∑ m=1 m24({4}2am−1) ≤ 1 ` `−1∑ m=1 (2m− 1){4}2am−1. Indeed, putting {4}2am−1 := bm−1, we can write 1 ` `−1∑ m=1 m24bm−1 = 1 ` [ b0 + 3b1 + 5b2 + · · · + (2`− 3)b`−2 − (`− 1)2b`−1 ] ≤ 1 ` `−1∑ m=1 (2m− 1)bm−1 ≤ 1 ` `−1∑ m=1 (2m− 1){4}2am−1,(2.14) because by the Lemma 1.1, bm−1 ≥ 0 holds true. On the other hand we get (`− 1)2b`−1 ≤ `(`− 1)b`−1, therefore the proof of the corollary is completed. � Remark 2.1. Similar statement with Theorem 2.3 holds true for the series (1.1) with (2, 1)-monotone coefficients. References [1] A. Yu. Popov, Estimates for the sums of sine series with monotone coefficients of certain classes, (Russian) Mat. Zametki 74 (2003), no. 6, 877–888; translation in Math. Notes 74 (2003), no. 5-6, 829–840. [2] B. V. Simonov, On trigonometric series with (k, s)-monotone coefficients in weighted spaces, Izv. Vyssh. Uchebn. 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