International Journal of Analysis and Applications Volume 18, Number 4 (2020), 614-623 URL: https://doi.org/10.28924/2291-8639 DOI: 10.28924/2291-8639-18-2020-614 ON JANOWSKI CLOSE-TO-CONVEX FUNCTIONS ASSOCIATED WITH CONIC REGIONS AFIS SALIU∗, KHALIDA INAYAT NOOR Department of Mathematics, COMSATS University Islamabad, Park Road, Tarlai Kalan, Islamabad 45550, Pakistan ∗Corresponding author: saliugsu@gmail.com Abstract. In this work, we introduce and investigate a class of analytic functions which is a subclass of close-to-convex functions of Janowski type and related to conic regions. Length of the image curve |z| = r < 1 under the generalized Janowski close-to-convex function is derived. Furthermore, rate of growth of coefficients and Hankel determinant for this class are obtained. Relevant connections of our results with the earlier known results are also pointed out. 1. Introduction Let E = {z : |z | < 1} and H be the class of functions f(z) defined as f(z) = z + ∞∑ n=2 anz n (1.1) which are analytic in E. A function f(z) is subordinate to another function g(z) (written as f(z) ≺ g(z)) if there exists an analytic function w(z) in E with w(0) = 1 and |w(z)| < 1 for z ∈ E such that f(z) = g(w(z)). Let Pm(α) be the class of analytic functions p(z) in E satisfying the condition p(0) = 1 and∫ 2π 0 ∣∣∣Re p(z) −α 1 −α ∣∣∣dθ ≤ mπ, (1.2) Received March 5th, 2020; accepted April 13th, 2020; published May 14th, 2020. 2010 Mathematics Subject Classification. 30C45, 30C50, 30C55. Key words and phrases. analytic functions; open unit disk; Janowski functions; subordination; univalent functions; conic domains. ©2020 Authors retain the copyrights of their papers, and all open access articles are distributed under the terms of the Creative Commons Attribution License. 614 https://doi.org/10.28924/2291-8639 https://doi.org/10.28924/2291-8639-18-2020-614 Int. J. Anal. Appl. 18 (4) (2020) 615 where m ≥ 2,z = reiθ, 0 ≤ α < 1, see [12]. The case α = 0 gives the class Pm introduced by Pinchuk [13]. For α = 0, m = 2, we obtain the well-known class P of Carathéodory functions and for m = 2, P2(α) ≡ P(α) is the class of functions whose real parts are greater than α. It is known in [12] that p ∈ Pm(α) has the integral representation p(z) = 1 2π ∫ 2π 0 1 + (1 − 2α)ze−it 1 −ze−it dv(t), (1.3) where v(t) is a function of bounded variation on [0, 2π] such that∫ 2π 0 dv(t) = 2π and ∫ 2π 0 |dv(t)| ≤ mπ. (1.4) It is seen from (1.3) and (1.4) that p ∈ Pm(α) has a representation p(z) = m + 2 4 p1(z) − m− 2 4 p2(z), (1.5) where pi ∈ P(α) for i = 1, 2. Denote by CV ,S∗,K,CV (α),S∗(α), K(α), are the subclasses of S (the class of univalent functions in E) which consist of functions that are convex, starlike, close-to-convex, convex of order α, starlike of order α and close-to-convex of order α (0 ≤ α < 1) respectively. We have the following class of analytic functions in E : Vm(α) = { f ∈ H : (zf′)′ f′ ∈ Pm(α), z ∈ E, m ≥ 2, 0 ≤ α < 1 } , see [12] (1.6) and note that V2(α) ≡ CV (α) and V2(0) ≡ CV . Recently, Noor [11] extended the conic domain Ωk,k ≥ 0 introduced by Kanas and Wisniowska [2, 3] to that of Janowski type, Ωk[A,B], −1 ≤ B < A ≤ 1 and defined it as Ωk[A,B] = { u + iv = [(B2 − 1)(u2 + v2) − 2(AB − 1)u + (A2 − 1)]2 >k2[(−2(B + 1)(u2 + v2) + 2(A + B + 2)u− 2(A + 1))2 + 4(A−B)2v2] } . (1.7) Denoted by k − P(A,B), the class of functions p(z) that map E onto Ωk[A,B]. Equivalently, we say p ∈ k −P(A,B) if and only if p(z) ≺ (A + 1)pk(z) − (A− 1) (B + 1)pk(z) − (B − 1) , k ≥ 0, −1 ≤ B < A ≤ 1, (1.8) where the definition of pk is given in [2]. Also, it is worthy mentioning that p ∈ k−P(A,B) ⊂ P(γ1) which implies that p(z) = (1 −γ1)h1(z) + γ1, (see [11]) where h1 ∈ P and γ1 is given by γ1 = 2k + 1 −A 2k + 1 −B . (1.9) If in (1.5), p1,p2 ∈ k−P(A,B), we say p ∈ k−Pm(A,B) and if Pm(α) in (1.6) is replaced with k−Pm(A,B), we say f belongs to the class k −UVm(A,B). We note that k −Pm(A,B) ⊂ Pm(γ1), where γ1 is given by (1.9). Thus, k −UVm(A,B) ⊂ Vm(γ1). Int. J. Anal. Appl. 18 (4) (2020) 616 We introduce the following class of functions. Definition 1.1. Let f ∈ H,−1 ≤ B < A ≤ 1, −1 ≤ D < C ≤ 1, k ≥ 0 and m1,m2 ≥ 2. Then f ∈ k −Hm1m2 (A,B,C,D) if there exists g ∈ k −UVm2 (C,D) such that f′(z) g′(z) ∈ k −Pm1 (A,B). In particular, (i) for k = 0, m1 = m = m2,A = 1,B = −1,C = 1 − 2α,D = −1, k − Hm1m2 (1,−1, 1 − 2α,−1) ≡ Hmm(α) is the class of analytic functions studied by Noor [9], (ii) for k = 0, m1 = m = m2,A = 1,B = −1,C = 1,D = −1, k −Hm1m2 (1,−1, 1,−1) ≡ Kmm is the class of analytic functions investigated by Noor [8], (iii) for k = 0, m1 = 2 = m2,A = 1,B = −1,C = 1,D = −1, k−H22(1,−1, 1,−1) ≡ K is the class of close to convex functions first introduced and examined by Kaplan [4] (iv) for k = 0, m1 = 2 = m2,H22(A,B,C,D) ≡ k − UK(A,B,C,D)) is the class of analytic functions examined by Mahmood et al [5]. We note that k −Hm1m2 (A,B, 1,−1) ≡ Hm1m2 (γ1,σ), where σ = k k+1 . 2. Some Preliminary Lemmas We need the following lemmas to investigate our results. Lemma 2.1. [10] let p ∈ Pm(γ), 0 ≤ γ < 1,m ≥ 2. Then for z = reiθ, (i) 1 2π ∫ 2π 0 |p(z) |2 dθ ≤ 1 + ( m2(1 −γ)2 − 1 ) r2 1 −r2 , (2.1) (ii) 1 2π ∫ 2π 0 |p ′(z) | dθ ≤ m(1 −γ) 1 −r2 . (2.2) Lemma 2.2. [12] (i) f ∈ Vm(α) if and only if there exist f1,f2 ∈ S∗ such that f′(z) = ( f1(z) z )( m+2 4 )(1−α) ( f2(z) z )( m−2 4 )(1−α) . (2.3) (ii) Let f ∈ Vm(α). Then r ( (1 −r)( m−2 4 ) (1 + r)( m+2 4 ) )(1−α) ≤ |zf′(z) | ≤ r ( (1 + r)( m−2 4 ) (1 −r)( m+2 4 ) )(1−α) . (2.4) Int. J. Anal. Appl. 18 (4) (2020) 617 We will need the hypergeometric function Γ(a)Γ(c−a) Γ(c) G(a,b,c; z) = ∫ 1 0 ua−1(1 −u)c−a−1(1 −zu)−b du. (2.5) Unless otherwise stated, we assume, m1,m2 ≥ 2,k ≥ 0 − 1 ≤ B < A ≤ 1, and − 1 ≤ D < C ≤ 1. 3. Main Results Theorem 3.1. Let f ∈ k −Hm1m2 (A,B,C,D). Then for 0 < r < 1, L(r,f) ≤ π { C(m2,k,γ2,C,D)M(r) log 1 1 −r + 2b+1γ1 a [ [G(a,b,c,−1) − 2G(a, 1 + b,c− 1)] (3.1) +ra1 [2G(a, 1 + b,c,−r1) −G(a,b,c,−r1)] ]} , (3.2) where M(r) = max θ |f(reiθ)|, C(m2,k,γ2,C,D) is a constant depending on m2,k,γ2,C and D, a = (m2 2 − 1 ) (1 −γ2), b = 2(γ2 − 1), c = a + 1 and r1 = 1 −r 1 + r , where γ1 = 2k + 1 −A 2k + 1 −B , γ2 = 2k + 1 −C 2k + 1 −D . (3.3) Proof. Let z = reiθ. Then L(r,f) = ∫ 2π 0 |zf′(z) |dθ = ∫ 2π 0 |zg′(z)p(z) |dθ, where g ∈ k −Vm2 (C,D) and p ∈ k −Pm1 (A,B) ≤ r∫ 0 2π∫ 0 (zg′(z))′p(z) |dθdρ + r∫ 0 2π∫ 0 |zg′(z)p ′(z) |dθdρ =J1(r) + J2(r). (3.4) Let (zg′)′(z) g′(z) = H(z) = 1 + ∞∑ n=1 dnz n ∈ k −Pm2 (C,D). Then by Schwarz inequality and Perseval’s theorem, we have J1(r) ≤2π   r∫ 0 2π∫ 0 |f′(z) |2 dθdρ   1 2   r∫ 0 2π∫ 0 |H(z) |2 dθdρ   1 2 =2π (∫ r 0 ∞∑ n=1 n2|an |2ρ2n−2dρ )1 2 (∫ r 0 ∞∑ n=0 |dn |2ρ2ndρ )1 2 . Int. J. Anal. Appl. 18 (4) (2020) 618 It is easy to see that |dn | ≤ m2(C −D)|δk | 4 , where δk has its definition given in [11]. Therefore, J1(r) ≤ √ 2πm2(C −D)|δk | 4 ( 1 r ∞∑ n=1 n2 2n− 1 |an |2r2n )1 2 ( log 1 + r 1 −r )1 2 ≤ √ 2πm2(C −D)|δk | 4 M(r) (1 r log 1 + r 1 −r )1 2 , (3.5) where we used the fact that A(r) = π ∞∑ n=1 n|an |2r2n is the area of the image of |z | < r bounded by w = f(z) and A(r) ≤ πM2(r). Next, we estimate J2(r). Since p ∈ k −Pm1 (A,B) ⊂ Pm1 (γ1), then using (1.3), we get p ′(z) = (1 −γ1) π ∫ 2π 0 eit (1 −zeit)2 dv(t) and ∫ 2π 0 1 −ρ2 |1 −zeit |2 dv(t) = 2π(Rep(z) −γ1) 1 −γ1 . Therefore, J2(r) ≤ (1 −γ1) π r∫ 0 2π∫ 0 2π∫ 0 |zg′(z) | |1 −ze−it |2 dv(t)dθdρ =2 r∫ 0 2π∫ 0 |zg′(z) |(Rep(z) −γ1) 1 1 −ρ2 dθdρ =2 r∫ 0 2π∫ 0 Re ( zg′(z)e−i arg zg ′(z)p(z) ) 1 1 −ρ2 dθdρ− 2γ1 r∫ 0 2π∫ 0 |zg′(z) |dθdρ. Integration by parts, application of (1.2) and Lemma 2.2(ii) give J2(r) ≤2π(m2(1 −γ2) + 2γ2) ∫ r 0 M(ρ) 1 −ρ2 dρ− 4πγ1 ∫ r 0 ρ (1 −ρ)( m−2 4 )(1−γ2)−1 (1 + ρ)( m+2 4 )(1−γ2)+1 dρ ≤π(m2(1 −γ2) + 2γ2)M(r) log 1 + r 1 −r + 4πγ1(L1(r) −L2(r)), (3.6) where L1(r) = ∫ r 0 (1 −ρ)( m−2 4 )(1−γ2)−1 (1 + ρ)( m+2 4 )(1−γ2)+1 dρ and L2(r) = ∫ r 0 (1 −ρ)( m−2 4 )(1−γ2)−1 (1 + ρ)( m+2 4 )(1−γ2) dρ. Let u = 1−ρ 1+ρ , so that dρ = − 2 (1+u)2 . Then L1(r) = ( 1 2 )2(2−γ2)−1 [∫ 1 0 u( m2 2 −1)(1−γ2)−1(1 + u)2(1−γ2)du− ∫ r1 0 u( m2 2 −1)(1−γ2)−1(1 + u)2(1−γ2)du ] = 1 a G(a,b,c,−1) − ∫ r1 0 u( m2 2 −1)(1−γ2)−1(1 + u)2(1−γ2)du, (3.7) where a,b,c and r1 are given in Theorem 3.1. For the second integral in (3.7), we let u = r1v. Then L1(r) = 2b−1 a [G(a,b,c,−1) −ra1G(a,b,c,−r1)] (3.8) Int. J. Anal. Appl. 18 (4) (2020) 619 In a similar way, we obtain L2(r) = 2b a [G(a, 1 + b,c,−1) −ra1G(a, 1 + b,c,−r1)] . (3.9) Using (3.8), (3.9) in (3.6), we get J2(r) ≤π(m2(1 −γ2) + 2γ2)M(r) log 1 + r 1 −r + π2b+1γ1 a { [G(a,b,c,−1) − 2G(a, 1 + b,c− 1)] + ra1 [2G(a, 1 + b,c,−r1) −G(a,b,c,−r1)] } . (3.10) The estimates for J1(r) and J2(r) yield the required result. � Corollary 3.1. Let f ∈ Km1m2, Then for 0 ≤ r < 1, L(r,f) ≤ C(m2)M(r) log 1 1 −r , where M(r) = max θ |f(reiθ)|, C(m2) is a constant depending on m2. Corollary 3.2. Let f ∈ Hmm(α), Then for 0 ≤ r < 1, L(r,f) ≤ C(m,α)M(r) log 1 1 −r , where M(r) = max θ |f(reiθ)|, C(m,α) is a constant depending on m and α. Corollary 3.3. Let f ∈ K. Then for 0 ≤ r < 1, L(r,f) ≤ CM(r) log 1 1 −r , where M(r) = max θ |f(reiθ)|, C is a constant. Theorem 3.2. Let f(z) be of the form (1.1) and f ∈ k −Hm1m2 (A,B,C,D). Then |an | ≤ π n ( C1(m2,k,γ2,C,D)M (n− 1 n ) log n + 2b+1γ1 a { [G(a,b,c,−1) − 2G(a, 1 + b,c− 1)] + ra1 [ 2G ( a, 1 + b,c,− 1 2n− 1 ) −G ( a,b,c,− 1 2n− 1 )]}) , where γ1,γ2,a,b and c are given as in Theorem 3.1. Noonan and Thomas [6] define for q ≥ 1,n ≥ 1, the qth Hankel determinant of f(z) ∈ H as follows : Hq(n) = ∣∣∣∣∣∣∣∣∣∣∣∣∣ an an+1 . . . an+q−1 an+1 an+2 . . . an+q−2 ... ... ... ... an+q−1 an+q−2 . . . an+2q−2 ∣∣∣∣∣∣∣∣∣∣∣∣∣ . (3.11) Int. J. Anal. Appl. 18 (4) (2020) 620 To estimate the growth rate of Hankel determinant for f ∈ k − Hm1m2 (A,B,C,D), we need the following results due to Noonan and Thomas [6]. Lemma 3.1. let f ∈ H and suppose the qth Hankel determinant of f(z) for q ≥ 1,n ≥ 1 is given by (3.11). Then writing ∆j(n) = ∆j(n,z1,f), we have Hq(n) = ∣∣∣∣∣∣∣∣∣∣∣∣∣ ∆2q−2(n) ∆2q−3(n + 1) . . . ∆q−1(n + q − 1) ∆2q−3(n + 1) ∆2q−4(n + 2) . . . ∆q−2(n + q − 2) ... ... ... ... ∆q−1(n + q − 1) ∆q−2(n + q − 2) . . . ∆q(n + 2q − 2) ∣∣∣∣∣∣∣∣∣∣∣∣∣ , (3.12) where with ∆0(n,z1,F) = an, we define for j ≥ 1, ∆j(n,z1,f) = ∆j−1(n,z1,f) −z1∆j−1(n + 1,z1,f). (3.13) Lemma 3.2. With x = ( n n+1 )y,u ≥ 0 an integer, ∆j(n + u,u,x,zf ′(z)) = j∑ i=0 ( j i ) yi(u− (i− 1)n) (n + 1)i · ∆j−i(n + u + i,y,f). (3.14) Remark 3.1. Consider any determinant of the form D = ∣∣∣∣∣∣∣∣∣∣∣∣∣ y2q−2 y2q−3 . . . yq−1 y2q−3 y2q−4 . . . yq−2 ... ... ... ... yq−1 yq−2 . . . y0 ∣∣∣∣∣∣∣∣∣∣∣∣∣ . (3.15) with 1 ≤ i, j ≤ q and αij = y2q−(i+j), D = det(αij). Thus D = ∑ v1∈Sq (sgn v1) q∏ j=1 (y2q − (v1(j) + j) , where Sq is the symmetric group on q elements and sgn v1 is either +1 or −1. Thus, in the expansion of D, each summand has q factor and the sum of the subscripts of the factor of each summand is q2 −q. Now let n be given and Hq(n) is as Lemma 3.1, then each summand in the expression of Hq(n) is of the form q∏ i=1 ∆v1(i) (n + 2q − 2 −v1i) , where v1 ∈ Sq and q∑ i=1 v1(i) = q 2 −q; 0 ≤ v1(i) ≤ 2q − 2. Int. J. Anal. Appl. 18 (4) (2020) 621 Theorem 3.3. Let f ∈ Hm1m2 (γ1,σ) and (m2 + 2)(1−γ2) ≥ 4j. If the qth Hankel determinant of f(z) for q ≥ 1,n ≥ 1 is given by (3.11), then Hq(n) = O(1)   n ( m2 2 +1)( 1k+1 )−1, q = 1, n( m2 2 +1)( 1k+1 )q−q 2 , q ≥ 2, m2 ≥ 8(k + 1)(q − 1) − 2 , (3.16) where O(1) is a constant that depends on m1,m2,j,γ1,k only, with γ1 given by (3.3). Proof. Since f ∈ Hm1m2 (γ1,σ), then f′(z) = p(z)g′(z), where g′(z) ∈ k −Vm2 (1,−1) ⊂ Vm2 (σ) and p(z) ∈ k −Pm1 (A,B) ⊂ Pm1 (γ1). Setting F(z) = (zf′(z))′, and (zg′(z))′ g′(z) = h(z), then F(z) = g′(z)(h(z)p(z) + zp′(z)). Now, for j ≥ 0,z1 any nonzero complex number, consider ∆j(n,z1,F(z)) as defined by (3.13). Then ∆j(n,z1,F(z)) ≤ 1 2πrn+j ∣∣∣∣∣ ∫ 2π 0 (z −z1)jF(z)e−i(n+j)θ dθ ∣∣∣∣∣ ≤ 1 2πrn+j ∫ 2π 0 |z −z1 |j|g′(z) ||h(z)p(z) + zp ′(z) |dθ. Using Lemma 2.2(i) and the distortion theorems for starlike function, then for (m2 + 2)(1 − σ) ≥ 4j, we obtain ∆j(n,z1,F(z)) ≤ 1 2πrn+j ∫ 2π 0 |(z −z1)f1(z)|j |f1(z)|( m2+2 4 )(1−σ)−j |f2(z)|( m2−2 4 )(1−σ) |h(z)p(z) + zp′(z)|dθ ≤ 1 2πrn+j−σ 2π∫ 0 |(z −z1)f1(z)|j ( r (1 −r)2 )( m2+2 4 )(1−σ)−j ( (1 + r)2 r )( m2−2 4 )(1−σ) ×|h(z)p(z) + zp ′(z) |dθ. Using the result of Golusin [1] and Schwarz inequality, we arrive at |∆j(n,z1,F(z)) | ≤ 2( m2−2 2 )(1−σ)+j rn−1 ( 1 1 −r )( m2−22 )(1−σ)−j × {( 1 2π ∫ 2π 0 |h(z) |2 )1 2 ( 1 2π ∫ 2π 0 |p(z) |2 )1 2 + 1 2π ∫ 2π 0 |zp ′(z) | } dθ. Int. J. Anal. Appl. 18 (4) (2020) 622 In view of Lemma 2.1, we get |∆j(n,z1,F(z)) | ≤ 2( m2−2 2 )(1−σ)+j rn−1 ( 1 1 −r )( m2+22 )(1−σ)−j {[1 + (m22(1 −σ)2 − 1)r2 1 −r2 ]1 2 × [ 1 + ( m21(1 −γ1)2 − 1 ) r2 1 −r2 ]1 2 + rm1(1 −γ1) 1 −r2 } ≤ 2( m2−2 2 )(1−γ2)+j ( m1(1 −γ1) + (m21(1 −γ1)2 + 1) 1 2 (m22(1 −σ)2 + 1) 1 2 ) rn−1 × ( 1 1 −r )( m2−22 )(1−σ)−j+1 . Applying Lemma 3.2 with z1 = ( n 1+n )2 eiθn, (n →∞), r = 1 − 1 n , we have for (m2 + 2)(1 −γ2) ≥ 4j, ∆j(n,e iθn,F(z)) = O(1)n( m2+2 2 )(1−σ)−j+1, where O(1) is a constant that depends on m1,m2,γ1 and σ. We estimate the rate of growth of Hq(n) for f ∈ Hm1m2 (γ1,σ). Then, for q=1, H1(n) = an = ∆0(n) and H1(n) = O(1)n( m2+2 2 )( 1 1+k )−1. For q ≥ 2, we use similar arguments from Noonan and Thomas [6] along with Lemma 3.1 and Remark 3.1 to arrive at Hq(n) = O(1)n( m2+2 2 )( 1 1+k )q−q2, m2 ≥ 8(k + 1)(q − 1) − 2. � Corollary 3.4. [8] If f ∈ Kmm, then Hq(n) = O(1)   n m2 2 , q = 1, n( m2 2 +1)q−q2, q ≥ 2, m2 ≥ 8(q − 1) − 2 , where O(1) is a constant that depends on m and j, only. Corollary 3.5. If f ∈ 1 −Hm1m2(A,B, 1,−1), then Hq(n) = O(1)   n m2 4 −1 2 , q = 1, n( m2 4 + 1 2 )q−q 2 , q ≥ 2, m2 ≥ 16(q − 1) − 2 , where O(1) is a constant that depends on γ1,m1 and j, only. Int. J. Anal. Appl. 18 (4) (2020) 623 4. Conclusion Arc length and rate of growth of Hankel determinant problems have always been the main interests of many researchers in Geometric function theory. Many studies associated to these problems revolved around classes of normalized analytic univalent functions. In this particular work, length of the image curve |z| = r < 1 under the generalized Janowski close-to-convex function was proved; rate of growth of coefficients and Hankel determinant for this class were also obtained. 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